How to correct visualization of mathematical expressions?

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This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say




2 + 3 = ?




and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.



How can I address this issue?




2 + 3 = 3 + 2





more examples,



I was explaining cross-cancellation and this is the visualization




$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$




instead, they visualize the following




$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out





so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.




Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.



Instead of sitting down and computing hard, compute smarter kind of idea.




$ sum_i=0^n i = dfracntimes(n+1)2$



$ sum_i=0^100 i = dfrac100 cdot 1012$











share|improve this question



















  • 12




    $2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
    – BPP
    Sep 16 at 14:55







  • 2




    Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
    – Joel Reyes Noche
    Sep 16 at 15:10






  • 3




    @Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
    – Jessica B
    Sep 16 at 18:07






  • 2




    I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
    – Joel Reyes Noche
    Sep 16 at 23:03







  • 1




    When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
    – Bill Dubuque
    Sep 16 at 23:31















up vote
4
down vote

favorite












This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say




2 + 3 = ?




and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.



How can I address this issue?




2 + 3 = 3 + 2





more examples,



I was explaining cross-cancellation and this is the visualization




$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$




instead, they visualize the following




$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out





so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.




Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.



Instead of sitting down and computing hard, compute smarter kind of idea.




$ sum_i=0^n i = dfracntimes(n+1)2$



$ sum_i=0^100 i = dfrac100 cdot 1012$











share|improve this question



















  • 12




    $2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
    – BPP
    Sep 16 at 14:55







  • 2




    Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
    – Joel Reyes Noche
    Sep 16 at 15:10






  • 3




    @Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
    – Jessica B
    Sep 16 at 18:07






  • 2




    I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
    – Joel Reyes Noche
    Sep 16 at 23:03







  • 1




    When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
    – Bill Dubuque
    Sep 16 at 23:31













up vote
4
down vote

favorite









up vote
4
down vote

favorite











This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say




2 + 3 = ?




and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.



How can I address this issue?




2 + 3 = 3 + 2





more examples,



I was explaining cross-cancellation and this is the visualization




$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$




instead, they visualize the following




$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out





so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.




Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.



Instead of sitting down and computing hard, compute smarter kind of idea.




$ sum_i=0^n i = dfracntimes(n+1)2$



$ sum_i=0^100 i = dfrac100 cdot 1012$











share|improve this question















This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say




2 + 3 = ?




and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.



How can I address this issue?




2 + 3 = 3 + 2





more examples,



I was explaining cross-cancellation and this is the visualization




$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$




instead, they visualize the following




$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out





so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.




Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.



Instead of sitting down and computing hard, compute smarter kind of idea.




$ sum_i=0^n i = dfracntimes(n+1)2$



$ sum_i=0^100 i = dfrac100 cdot 1012$








primary-education arithmetic-operations






share|improve this question















share|improve this question













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edited Sep 18 at 0:31

























asked Sep 16 at 14:30









Lenny

1937




1937







  • 12




    $2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
    – BPP
    Sep 16 at 14:55







  • 2




    Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
    – Joel Reyes Noche
    Sep 16 at 15:10






  • 3




    @Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
    – Jessica B
    Sep 16 at 18:07






  • 2




    I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
    – Joel Reyes Noche
    Sep 16 at 23:03







  • 1




    When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
    – Bill Dubuque
    Sep 16 at 23:31













  • 12




    $2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
    – BPP
    Sep 16 at 14:55







  • 2




    Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
    – Joel Reyes Noche
    Sep 16 at 15:10






  • 3




    @Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
    – Jessica B
    Sep 16 at 18:07






  • 2




    I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
    – Joel Reyes Noche
    Sep 16 at 23:03







  • 1




    When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
    – Bill Dubuque
    Sep 16 at 23:31








12




12




$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
– BPP
Sep 16 at 14:55





$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
– BPP
Sep 16 at 14:55





2




2




Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
– Joel Reyes Noche
Sep 16 at 15:10




Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
– Joel Reyes Noche
Sep 16 at 15:10




3




3




@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
– Jessica B
Sep 16 at 18:07




@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
– Jessica B
Sep 16 at 18:07




2




2




I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
– Joel Reyes Noche
Sep 16 at 23:03





I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
– Joel Reyes Noche
Sep 16 at 23:03





1




1




When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
– Bill Dubuque
Sep 16 at 23:31





When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
– Bill Dubuque
Sep 16 at 23:31











5 Answers
5






active

oldest

votes

















up vote
8
down vote



accepted










The problem is due to imprecise specification of the intended result. Here's a more precise way.



$textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.



$textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.



Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.




Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.



Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares



$$123^2 - 122^2 = (123-122)(123+122) = 245$$



This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.



Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows



$$beginalign
1 + 2 + 3\
+ 6 + 5 + 4\
hline
= 7 + 7 + 7
endalign$$



which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).



Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.






share|improve this answer






















  • ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
    – Lenny
    Sep 18 at 0:21










  • @Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
    – Bill Dubuque
    Sep 18 at 0:25


















up vote
10
down vote













One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
$$2+3=3+__$$
$$2+3=__+2$$
$$2+__=3+2$$
$$__+3=3+2$$






share|improve this answer





























    up vote
    3
    down vote













    One way to address this




    students cannot comprehend that it isn't necessary to always work out the
    arithmetic right away but can keep them as expressions to observe
    patterns.




    is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.



    Often considering a few problems in depth is more useful than a list of many where you just check for correctness.






    share|improve this answer



























      up vote
      1
      down vote













      Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.



      Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.






      share|improve this answer



























        up vote
        0
        down vote













        You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.



        For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.



        https://www.youtube.com/watch?v=twGipANcIqg






        share|improve this answer






















        • The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
          – Bill Dubuque
          Sep 17 at 18:04







        • 1




          I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
          – Steven Gubkin
          Sep 17 at 19:14










        • I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
          – Bill Dubuque
          Sep 17 at 19:22







        • 1




          @Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
          – Steven Gubkin
          Sep 17 at 22:15










        • I stated the elementary grade level...meaning K-5
          – Lenny
          Sep 18 at 0:04










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        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes








        up vote
        8
        down vote



        accepted










        The problem is due to imprecise specification of the intended result. Here's a more precise way.



        $textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.



        $textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.



        Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.




        Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.



        Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares



        $$123^2 - 122^2 = (123-122)(123+122) = 245$$



        This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.



        Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows



        $$beginalign
        1 + 2 + 3\
        + 6 + 5 + 4\
        hline
        = 7 + 7 + 7
        endalign$$



        which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
        so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).



        Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.






        share|improve this answer






















        • ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
          – Lenny
          Sep 18 at 0:21










        • @Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
          – Bill Dubuque
          Sep 18 at 0:25















        up vote
        8
        down vote



        accepted










        The problem is due to imprecise specification of the intended result. Here's a more precise way.



        $textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.



        $textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.



        Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.




        Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.



        Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares



        $$123^2 - 122^2 = (123-122)(123+122) = 245$$



        This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.



        Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows



        $$beginalign
        1 + 2 + 3\
        + 6 + 5 + 4\
        hline
        = 7 + 7 + 7
        endalign$$



        which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
        so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).



        Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.






        share|improve this answer






















        • ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
          – Lenny
          Sep 18 at 0:21










        • @Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
          – Bill Dubuque
          Sep 18 at 0:25













        up vote
        8
        down vote



        accepted







        up vote
        8
        down vote



        accepted






        The problem is due to imprecise specification of the intended result. Here's a more precise way.



        $textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.



        $textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.



        Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.




        Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.



        Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares



        $$123^2 - 122^2 = (123-122)(123+122) = 245$$



        This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.



        Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows



        $$beginalign
        1 + 2 + 3\
        + 6 + 5 + 4\
        hline
        = 7 + 7 + 7
        endalign$$



        which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
        so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).



        Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.






        share|improve this answer














        The problem is due to imprecise specification of the intended result. Here's a more precise way.



        $textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.



        $textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.



        Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.




        Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.



        Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares



        $$123^2 - 122^2 = (123-122)(123+122) = 245$$



        This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.



        Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows



        $$beginalign
        1 + 2 + 3\
        + 6 + 5 + 4\
        hline
        = 7 + 7 + 7
        endalign$$



        which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
        so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).



        Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Sep 19 at 17:23

























        answered Sep 16 at 16:18









        Bill Dubuque

        8871711




        8871711











        • ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
          – Lenny
          Sep 18 at 0:21










        • @Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
          – Bill Dubuque
          Sep 18 at 0:25

















        • ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
          – Lenny
          Sep 18 at 0:21










        • @Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
          – Bill Dubuque
          Sep 18 at 0:25
















        ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
        – Lenny
        Sep 18 at 0:21




        ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
        – Lenny
        Sep 18 at 0:21












        @Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
        – Bill Dubuque
        Sep 18 at 0:25





        @Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
        – Bill Dubuque
        Sep 18 at 0:25











        up vote
        10
        down vote













        One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
        $$2+3=3+__$$
        $$2+3=__+2$$
        $$2+__=3+2$$
        $$__+3=3+2$$






        share|improve this answer


























          up vote
          10
          down vote













          One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
          $$2+3=3+__$$
          $$2+3=__+2$$
          $$2+__=3+2$$
          $$__+3=3+2$$






          share|improve this answer
























            up vote
            10
            down vote










            up vote
            10
            down vote









            One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
            $$2+3=3+__$$
            $$2+3=__+2$$
            $$2+__=3+2$$
            $$__+3=3+2$$






            share|improve this answer














            One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
            $$2+3=3+__$$
            $$2+3=__+2$$
            $$2+__=3+2$$
            $$__+3=3+2$$







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Sep 16 at 22:52

























            answered Sep 16 at 15:18









            Joel Reyes Noche

            4,92511650




            4,92511650




















                up vote
                3
                down vote













                One way to address this




                students cannot comprehend that it isn't necessary to always work out the
                arithmetic right away but can keep them as expressions to observe
                patterns.




                is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.



                Often considering a few problems in depth is more useful than a list of many where you just check for correctness.






                share|improve this answer
























                  up vote
                  3
                  down vote













                  One way to address this




                  students cannot comprehend that it isn't necessary to always work out the
                  arithmetic right away but can keep them as expressions to observe
                  patterns.




                  is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.



                  Often considering a few problems in depth is more useful than a list of many where you just check for correctness.






                  share|improve this answer






















                    up vote
                    3
                    down vote










                    up vote
                    3
                    down vote









                    One way to address this




                    students cannot comprehend that it isn't necessary to always work out the
                    arithmetic right away but can keep them as expressions to observe
                    patterns.




                    is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.



                    Often considering a few problems in depth is more useful than a list of many where you just check for correctness.






                    share|improve this answer












                    One way to address this




                    students cannot comprehend that it isn't necessary to always work out the
                    arithmetic right away but can keep them as expressions to observe
                    patterns.




                    is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.



                    Often considering a few problems in depth is more useful than a list of many where you just check for correctness.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Sep 16 at 23:56









                    Ethan Bolker

                    43125




                    43125




















                        up vote
                        1
                        down vote













                        Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.



                        Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.






                        share|improve this answer
























                          up vote
                          1
                          down vote













                          Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.



                          Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.






                          share|improve this answer






















                            up vote
                            1
                            down vote










                            up vote
                            1
                            down vote









                            Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.



                            Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.






                            share|improve this answer












                            Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.



                            Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Sep 17 at 16:55









                            Rusty Core

                            1345




                            1345




















                                up vote
                                0
                                down vote













                                You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.



                                For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.



                                https://www.youtube.com/watch?v=twGipANcIqg






                                share|improve this answer






















                                • The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
                                  – Bill Dubuque
                                  Sep 17 at 18:04







                                • 1




                                  I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
                                  – Steven Gubkin
                                  Sep 17 at 19:14










                                • I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
                                  – Bill Dubuque
                                  Sep 17 at 19:22







                                • 1




                                  @Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
                                  – Steven Gubkin
                                  Sep 17 at 22:15










                                • I stated the elementary grade level...meaning K-5
                                  – Lenny
                                  Sep 18 at 0:04














                                up vote
                                0
                                down vote













                                You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.



                                For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.



                                https://www.youtube.com/watch?v=twGipANcIqg






                                share|improve this answer






















                                • The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
                                  – Bill Dubuque
                                  Sep 17 at 18:04







                                • 1




                                  I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
                                  – Steven Gubkin
                                  Sep 17 at 19:14










                                • I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
                                  – Bill Dubuque
                                  Sep 17 at 19:22







                                • 1




                                  @Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
                                  – Steven Gubkin
                                  Sep 17 at 22:15










                                • I stated the elementary grade level...meaning K-5
                                  – Lenny
                                  Sep 18 at 0:04












                                up vote
                                0
                                down vote










                                up vote
                                0
                                down vote









                                You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.



                                For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.



                                https://www.youtube.com/watch?v=twGipANcIqg






                                share|improve this answer














                                You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.



                                For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.



                                https://www.youtube.com/watch?v=twGipANcIqg







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited Sep 19 at 16:39

























                                answered Sep 17 at 12:44









                                Steven Gubkin

                                7,78412247




                                7,78412247











                                • The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
                                  – Bill Dubuque
                                  Sep 17 at 18:04







                                • 1




                                  I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
                                  – Steven Gubkin
                                  Sep 17 at 19:14










                                • I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
                                  – Bill Dubuque
                                  Sep 17 at 19:22







                                • 1




                                  @Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
                                  – Steven Gubkin
                                  Sep 17 at 22:15










                                • I stated the elementary grade level...meaning K-5
                                  – Lenny
                                  Sep 18 at 0:04
















                                • The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
                                  – Bill Dubuque
                                  Sep 17 at 18:04







                                • 1




                                  I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
                                  – Steven Gubkin
                                  Sep 17 at 19:14










                                • I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
                                  – Bill Dubuque
                                  Sep 17 at 19:22







                                • 1




                                  @Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
                                  – Steven Gubkin
                                  Sep 17 at 22:15










                                • I stated the elementary grade level...meaning K-5
                                  – Lenny
                                  Sep 18 at 0:04















                                The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
                                – Bill Dubuque
                                Sep 17 at 18:04





                                The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
                                – Bill Dubuque
                                Sep 17 at 18:04





                                1




                                1




                                I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
                                – Steven Gubkin
                                Sep 17 at 19:14




                                I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
                                – Steven Gubkin
                                Sep 17 at 19:14












                                I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
                                – Bill Dubuque
                                Sep 17 at 19:22





                                I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
                                – Bill Dubuque
                                Sep 17 at 19:22





                                1




                                1




                                @Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
                                – Steven Gubkin
                                Sep 17 at 22:15




                                @Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
                                – Steven Gubkin
                                Sep 17 at 22:15












                                I stated the elementary grade level...meaning K-5
                                – Lenny
                                Sep 18 at 0:04




                                I stated the elementary grade level...meaning K-5
                                – Lenny
                                Sep 18 at 0:04

















                                 

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