How to correct visualization of mathematical expressions?

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This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say
2 + 3 = ?
and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.
How can I address this issue?
2 + 3 = 3 + 2
more examples,
I was explaining cross-cancellation and this is the visualization
$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$
instead, they visualize the following
$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out
so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.
Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.
Instead of sitting down and computing hard, compute smarter kind of idea.
$ sum_i=0^n i = dfracntimes(n+1)2$
$ sum_i=0^100 i = dfrac100 cdot 1012$
primary-education arithmetic-operations
 |Â
show 13 more comments
up vote
4
down vote
favorite
This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say
2 + 3 = ?
and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.
How can I address this issue?
2 + 3 = 3 + 2
more examples,
I was explaining cross-cancellation and this is the visualization
$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$
instead, they visualize the following
$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out
so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.
Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.
Instead of sitting down and computing hard, compute smarter kind of idea.
$ sum_i=0^n i = dfracntimes(n+1)2$
$ sum_i=0^100 i = dfrac100 cdot 1012$
primary-education arithmetic-operations
12
$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
â BPP
Sep 16 at 14:55
2
Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
â Joel Reyes Noche
Sep 16 at 15:10
3
@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
â Jessica B
Sep 16 at 18:07
2
I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
â Joel Reyes Noche
Sep 16 at 23:03
1
When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
â Bill Dubuque
Sep 16 at 23:31
 |Â
show 13 more comments
up vote
4
down vote
favorite
up vote
4
down vote
favorite
This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say
2 + 3 = ?
and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.
How can I address this issue?
2 + 3 = 3 + 2
more examples,
I was explaining cross-cancellation and this is the visualization
$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$
instead, they visualize the following
$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out
so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.
Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.
Instead of sitting down and computing hard, compute smarter kind of idea.
$ sum_i=0^n i = dfracntimes(n+1)2$
$ sum_i=0^100 i = dfrac100 cdot 1012$
primary-education arithmetic-operations
This happens a lot when I try to explain the commutative property, mostly in elementary grade levels. I say
2 + 3 = ?
and then the student usually replies with 5. Albeit they're not wrong, it's not the idea of commutative property. I feel that students so conditioned early on to see that 2 + 3 is necessarily 5 as opposed to understanding that 2 + 3 can just be that: 2 + 3. I had this problem myself growing up.
How can I address this issue?
2 + 3 = 3 + 2
more examples,
I was explaining cross-cancellation and this is the visualization
$frac27 cdot frac73 = frac2 cdot77 cdot 3 = frac2 cdot requirecancel cancel7requirecancel cancel7 cdot3$
instead, they visualize the following
$frac27 cdot frac73 = frac1421$ we are stuck here since we cannot see the cancellation working out
so what I mean is that students cannot comprehend that it isn't necessary to always work out the arithmetic right away but can keep them as expressions to observe patterns. I hope this is a bit more clear.
Addition of a story:
A famous example, the story of Gauss. Once upon a time, there was a teacher who was bored and asked the class, included Gauss, who asked students to sum up from 1 to 100. While the rest of the class struggled to solve it, Gauss got it with ease. This is the idea I was trying to convey.
Instead of sitting down and computing hard, compute smarter kind of idea.
$ sum_i=0^n i = dfracntimes(n+1)2$
$ sum_i=0^100 i = dfrac100 cdot 1012$
primary-education arithmetic-operations
primary-education arithmetic-operations
edited Sep 18 at 0:31
asked Sep 16 at 14:30
Lenny
1937
1937
12
$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
â BPP
Sep 16 at 14:55
2
Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
â Joel Reyes Noche
Sep 16 at 15:10
3
@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
â Jessica B
Sep 16 at 18:07
2
I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
â Joel Reyes Noche
Sep 16 at 23:03
1
When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
â Bill Dubuque
Sep 16 at 23:31
 |Â
show 13 more comments
12
$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
â BPP
Sep 16 at 14:55
2
Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
â Joel Reyes Noche
Sep 16 at 15:10
3
@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
â Jessica B
Sep 16 at 18:07
2
I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
â Joel Reyes Noche
Sep 16 at 23:03
1
When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
â Bill Dubuque
Sep 16 at 23:31
12
12
$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
â BPP
Sep 16 at 14:55
$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
â BPP
Sep 16 at 14:55
2
2
Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
â Joel Reyes Noche
Sep 16 at 15:10
Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
â Joel Reyes Noche
Sep 16 at 15:10
3
3
@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
â Jessica B
Sep 16 at 18:07
@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
â Jessica B
Sep 16 at 18:07
2
2
I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
â Joel Reyes Noche
Sep 16 at 23:03
I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
â Joel Reyes Noche
Sep 16 at 23:03
1
1
When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
â Bill Dubuque
Sep 16 at 23:31
When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
â Bill Dubuque
Sep 16 at 23:31
 |Â
show 13 more comments
5 Answers
5
active
oldest
votes
up vote
8
down vote
accepted
The problem is due to imprecise specification of the intended result. Here's a more precise way.
$textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.
$textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.
Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.
Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.
Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares
$$123^2 - 122^2 = (123-122)(123+122) = 245$$
This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.
Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows
$$beginalign
1 + 2 + 3\
+ 6 + 5 + 4\
hline
= 7 + 7 + 7
endalign$$
which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).
Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.
ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
â Lenny
Sep 18 at 0:21
@Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
â Bill Dubuque
Sep 18 at 0:25
add a comment |Â
up vote
10
down vote
One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
$$2+3=3+__$$
$$2+3=__+2$$
$$2+__=3+2$$
$$__+3=3+2$$
add a comment |Â
up vote
3
down vote
One way to address this
students cannot comprehend that it isn't necessary to always work out the
arithmetic right away but can keep them as expressions to observe
patterns.
is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.
Often considering a few problems in depth is more useful than a list of many where you just check for correctness.
add a comment |Â
up vote
1
down vote
Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.
Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.
add a comment |Â
up vote
0
down vote
You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.
For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.
https://www.youtube.com/watch?v=twGipANcIqg
The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
â Bill Dubuque
Sep 17 at 18:04
1
I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
â Steven Gubkin
Sep 17 at 19:14
I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
â Bill Dubuque
Sep 17 at 19:22
1
@Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
â Steven Gubkin
Sep 17 at 22:15
I stated the elementary grade level...meaning K-5
â Lenny
Sep 18 at 0:04
add a comment |Â
5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
8
down vote
accepted
The problem is due to imprecise specification of the intended result. Here's a more precise way.
$textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.
$textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.
Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.
Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.
Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares
$$123^2 - 122^2 = (123-122)(123+122) = 245$$
This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.
Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows
$$beginalign
1 + 2 + 3\
+ 6 + 5 + 4\
hline
= 7 + 7 + 7
endalign$$
which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).
Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.
ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
â Lenny
Sep 18 at 0:21
@Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
â Bill Dubuque
Sep 18 at 0:25
add a comment |Â
up vote
8
down vote
accepted
The problem is due to imprecise specification of the intended result. Here's a more precise way.
$textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.
$textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.
Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.
Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.
Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares
$$123^2 - 122^2 = (123-122)(123+122) = 245$$
This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.
Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows
$$beginalign
1 + 2 + 3\
+ 6 + 5 + 4\
hline
= 7 + 7 + 7
endalign$$
which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).
Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.
ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
â Lenny
Sep 18 at 0:21
@Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
â Bill Dubuque
Sep 18 at 0:25
add a comment |Â
up vote
8
down vote
accepted
up vote
8
down vote
accepted
The problem is due to imprecise specification of the intended result. Here's a more precise way.
$textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.
$textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.
Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.
Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.
Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares
$$123^2 - 122^2 = (123-122)(123+122) = 245$$
This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.
Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows
$$beginalign
1 + 2 + 3\
+ 6 + 5 + 4\
hline
= 7 + 7 + 7
endalign$$
which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).
Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.
The problem is due to imprecise specification of the intended result. Here's a more precise way.
$textRecall that the bf commutative law color#c00X+ color#0a0Y = Y + X text is true for all reals X,Y$.
$textUse the above law to $ $ simplify 2, +, color#c00pi, +, color#0a03 text to the form , n + pi,text for some integer n$.
Update $ $ In case it wasn't obvious, the idea is to choose a sum where it is clear that performing the commutation simplifies the addition. If you can't use $,color#c00pi,$ (or $x)$ then it is clear how to tweak it to use "simpler" numbers, e.g. $ 9 + 1/123 - 9 $ or $ 1/11+123+10/11,,$ etc. But these forms have the disadvantage that they don't prohibit the student from diving head-first into computation, i.e they might try computing $9 + 1/123$ before commuting - something they can't do with $,2+pi,$ or $,2+x$. Hence using a transcendental forcefully guides the student along the correct solution path.
Update $ $ You added a new problem exhibiting the utility of lazy (vs. eager) evaluation (of arithmetic) in order to help apply simplifying transformations. This idea should be explicitly taught using multiple types of examples to better lend intuition, e.g. besides your example of delaying multiplication in order to exploit cancellations, it would help to give other examples where one can exploit innate arithmetical structure before diving head-first into brute-force arithmetical computation. Below are some further complementary examples.
Special Polynomial structure $ $ If we notice that the arithmetical expression has the form of a well-known polynomial formula then applying that first may simplify the arithmetic. For a simple example consider differences of squares
$$123^2 - 122^2 = (123-122)(123+122) = 245$$
This is simpler than brute-force arithmetic computation, i.e. squaring both $123$ and $122$ then taking their difference. It will be much simpler for analogous examples with much larger numbers.
Reflection symmetry $ $ Sums symmmetric about a midpoint can be rearranged as follows
$$beginalign
1 + 2 + 3\
+ 6 + 5 + 4\
hline
= 7 + 7 + 7
endalign$$
which yields an easy proof that the sum is divisible by $7$. If we view the above sum $!bmod 7,$ then it is an additive form of the cancellations in your fractions since $ 6equiv -1, 5equiv -2, 4equiv -3$
so the sum is $equiv 1 + 2 + 3 -1 -2 - 3$. So here the reflection is negation and the key idea is to preprocess the sum by pairing each summand with its negation in order to simplify the arithmetic (this is the key idea behind one proof Wilson's Theorem).
Generally, before diving head-first into brute-force solution methods, it is wise to first perform some "meta level" preprocessing - searching for interesting innate structure that may help simplify it or shed further intuition on the heart of the matter. With that idea in mind I am sure you can come up with many interesting examples appropriate to the level of your class.
edited Sep 19 at 17:23
answered Sep 16 at 16:18
Bill Dubuque
8871711
8871711
ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
â Lenny
Sep 18 at 0:21
@Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
â Bill Dubuque
Sep 18 at 0:25
add a comment |Â
ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
â Lenny
Sep 18 at 0:21
@Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
â Bill Dubuque
Sep 18 at 0:25
ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
â Lenny
Sep 18 at 0:21
ah yes, this reminds me of the story of Gauss. The sum of 1 to 100 is simpler than children think.
â Lenny
Sep 18 at 0:21
@Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
â Bill Dubuque
Sep 18 at 0:25
@Lenny Yes that legend about Gauss is discussed at length in the final link I gave (and its links) on Wilson's Theorem.
â Bill Dubuque
Sep 18 at 0:25
add a comment |Â
up vote
10
down vote
One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
$$2+3=3+__$$
$$2+3=__+2$$
$$2+__=3+2$$
$$__+3=3+2$$
add a comment |Â
up vote
10
down vote
One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
$$2+3=3+__$$
$$2+3=__+2$$
$$2+__=3+2$$
$$__+3=3+2$$
add a comment |Â
up vote
10
down vote
up vote
10
down vote
One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
$$2+3=3+__$$
$$2+3=__+2$$
$$2+__=3+2$$
$$__+3=3+2$$
One way to see if the student understands the commutative property of addition is to have "fill-in-the-blank" questions such as
$$2+3=3+__$$
$$2+3=__+2$$
$$2+__=3+2$$
$$__+3=3+2$$
edited Sep 16 at 22:52
answered Sep 16 at 15:18
Joel Reyes Noche
4,92511650
4,92511650
add a comment |Â
add a comment |Â
up vote
3
down vote
One way to address this
students cannot comprehend that it isn't necessary to always work out the
arithmetic right away but can keep them as expressions to observe
patterns.
is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.
Often considering a few problems in depth is more useful than a list of many where you just check for correctness.
add a comment |Â
up vote
3
down vote
One way to address this
students cannot comprehend that it isn't necessary to always work out the
arithmetic right away but can keep them as expressions to observe
patterns.
is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.
Often considering a few problems in depth is more useful than a list of many where you just check for correctness.
add a comment |Â
up vote
3
down vote
up vote
3
down vote
One way to address this
students cannot comprehend that it isn't necessary to always work out the
arithmetic right away but can keep them as expressions to observe
patterns.
is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.
Often considering a few problems in depth is more useful than a list of many where you just check for correctness.
One way to address this
students cannot comprehend that it isn't necessary to always work out the
arithmetic right away but can keep them as expressions to observe
patterns.
is to do (or have the students do) a problem in as many different ways as possible, then take the time to compare the solutions (to see that they agree) and the methods. Some will be faster, some more conceptual.
Often considering a few problems in depth is more useful than a list of many where you just check for correctness.
answered Sep 16 at 23:56
Ethan Bolker
43125
43125
add a comment |Â
add a comment |Â
up vote
1
down vote
Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.
Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.
add a comment |Â
up vote
1
down vote
Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.
Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.
Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.
Put five counters on the table, separate them into two heaps, three in one, two in another. Combine the heaps by moving the smaller into the larger, then do the same, only move the larger into the smaller, the result is the same. Voila! Also can serve as a basis to start talking in terms of sets.
Regarding your cancellation example, the students must be taught to NOT immediately calculate the value of an expression because it may simply produce extra work, as simple as that.
answered Sep 17 at 16:55
Rusty Core
1345
1345
add a comment |Â
add a comment |Â
up vote
0
down vote
You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.
For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.
https://www.youtube.com/watch?v=twGipANcIqg
The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
â Bill Dubuque
Sep 17 at 18:04
1
I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
â Steven Gubkin
Sep 17 at 19:14
I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
â Bill Dubuque
Sep 17 at 19:22
1
@Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
â Steven Gubkin
Sep 17 at 22:15
I stated the elementary grade level...meaning K-5
â Lenny
Sep 18 at 0:04
add a comment |Â
up vote
0
down vote
You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.
For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.
https://www.youtube.com/watch?v=twGipANcIqg
The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
â Bill Dubuque
Sep 17 at 18:04
1
I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
â Steven Gubkin
Sep 17 at 19:14
I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
â Bill Dubuque
Sep 17 at 19:22
1
@Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
â Steven Gubkin
Sep 17 at 22:15
I stated the elementary grade level...meaning K-5
â Lenny
Sep 18 at 0:04
add a comment |Â
up vote
0
down vote
up vote
0
down vote
You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.
For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.
https://www.youtube.com/watch?v=twGipANcIqg
You have not stated the grade level here, but one way to approach this is by giving problems where commuting actually makes the computation easier. For example $97+26+13$. You could have students do "number talks" on things like this. This also gives them an opportunity to showcase their understanding of place value, which is another major goal at this age.
For some resources on "number talks" I suggest watching the following video by Sherry Parrish. She also has some books on number talks which might be helpful to you.
https://www.youtube.com/watch?v=twGipANcIqg
edited Sep 19 at 16:39
answered Sep 17 at 12:44
Steven Gubkin
7,78412247
7,78412247
The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
â Bill Dubuque
Sep 17 at 18:04
1
I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
â Steven Gubkin
Sep 17 at 19:14
I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
â Bill Dubuque
Sep 17 at 19:22
1
@Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
â Steven Gubkin
Sep 17 at 22:15
I stated the elementary grade level...meaning K-5
â Lenny
Sep 18 at 0:04
add a comment |Â
The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
â Bill Dubuque
Sep 17 at 18:04
1
I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
â Steven Gubkin
Sep 17 at 19:14
I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
â Bill Dubuque
Sep 17 at 19:22
1
@Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
â Steven Gubkin
Sep 17 at 22:15
I stated the elementary grade level...meaning K-5
â Lenny
Sep 18 at 0:04
The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
â Bill Dubuque
Sep 17 at 18:04
The reason I chose $pi$ in the earlier similar example in my answer is that it makes it more obvious why one should do the commutation. Of course we can use any example where commuting "simplifies" the addition.
â Bill Dubuque
Sep 17 at 18:04
1
1
I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
â Steven Gubkin
Sep 17 at 19:14
I think that appropriate examples depend a bit on intended audience. My example would be appropriate for a typical third grader, while your examples probably would not.
â Steven Gubkin
Sep 17 at 19:14
I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
â Bill Dubuque
Sep 17 at 19:22
I thought that it would be obvious how to tweak it for the intended audience. Frankly, I was surprised to see a much later answer consisting only of that minor tweak. I would have posted a comment if I thought that might not be obvious to some readers (but obviously I don't think that).
â Bill Dubuque
Sep 17 at 19:22
1
1
@Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
â Steven Gubkin
Sep 17 at 22:15
@Number I am not sure if it your intention, but I have been feeling a little bit attacked by you lately. My answer was not intended to be a criticism of your answer, and it was not a tweak of your answer. It was simply my own answer.
â Steven Gubkin
Sep 17 at 22:15
I stated the elementary grade level...meaning K-5
â Lenny
Sep 18 at 0:04
I stated the elementary grade level...meaning K-5
â Lenny
Sep 18 at 0:04
add a comment |Â
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12
$2+3= sqrt5+sqrt3+sqrt30+sqrt3-10sqrt5+sqrt3$ or whatever other expression. It depends on the exercise, do you want them to calculate or to use the commutative property? Usually when someone ask me what is 24+87 I add them.
â BPP
Sep 16 at 14:55
2
Is your question essentially "How do I elicit a response from a student that shows understanding of the commutative property of addition?"?
â Joel Reyes Noche
Sep 16 at 15:10
3
@Lenny Of course the students want to solve. That's what they've been told the implicit instruction is in maths lessons. If you want them to do something other than solve, you need to be explicit about it.
â Jessica B
Sep 16 at 18:07
2
I agree with @JessicaB and BPP that you have to be explicit with what you want from the student. If I "asked" you "$2+2+2=$", what would the "correct answer" be? $6$? $2times 3$? $3times 2$?
â Joel Reyes Noche
Sep 16 at 23:03
1
When you alter the question after answers have been posted you should explicitly mark the added content, esp. when it makes the answers seem incomplete.
â Bill Dubuque
Sep 16 at 23:31