Form the biggest squaring number

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You are going to start from any number with distinct digits lower than four digits (such as $a$, $ab$, $abc$) and you will apply the rule below:



  • Take the square any number you want in the number (you may take the square the number itself too). (such as $1(02)$ -> $14$, or $12(3)$ -> $129$ or $(13)$ -> $169$)

  • Every number you found has to have distinct digits. (Fail example: $(12)3$-> $1443$ X)

  • You may apply this as many times as you want. ($(13)$ -> $169$ then $(16)9$->$2569$)


What is the biggest final number you can have?











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  • 1




    Biggest final number? or biggest starting number?
    – SteveV
    Sep 16 at 16:33










  • is there a restriction about how many digits the number which we square can have? like, if I get a number like 1023 as an interim result (even though 1023 itself is not possible), am I allowed to square it all to get to 1046529?
    – elias
    Sep 16 at 17:11










  • @elias "you may take the square the number itself too". written on the first rule. no restriction.
    – Oray
    Sep 16 at 17:12










  • $1(69) -> 14761$. Isn't this a violation of the previous rule?
    – Wais Kamal
    Sep 16 at 17:52










  • @WaisKamal ops true :) fixed it.
    – Oray
    Sep 16 at 17:53















up vote
9
down vote

favorite
1












You are going to start from any number with distinct digits lower than four digits (such as $a$, $ab$, $abc$) and you will apply the rule below:



  • Take the square any number you want in the number (you may take the square the number itself too). (such as $1(02)$ -> $14$, or $12(3)$ -> $129$ or $(13)$ -> $169$)

  • Every number you found has to have distinct digits. (Fail example: $(12)3$-> $1443$ X)

  • You may apply this as many times as you want. ($(13)$ -> $169$ then $(16)9$->$2569$)


What is the biggest final number you can have?











share|improve this question



















  • 1




    Biggest final number? or biggest starting number?
    – SteveV
    Sep 16 at 16:33










  • is there a restriction about how many digits the number which we square can have? like, if I get a number like 1023 as an interim result (even though 1023 itself is not possible), am I allowed to square it all to get to 1046529?
    – elias
    Sep 16 at 17:11










  • @elias "you may take the square the number itself too". written on the first rule. no restriction.
    – Oray
    Sep 16 at 17:12










  • $1(69) -> 14761$. Isn't this a violation of the previous rule?
    – Wais Kamal
    Sep 16 at 17:52










  • @WaisKamal ops true :) fixed it.
    – Oray
    Sep 16 at 17:53













up vote
9
down vote

favorite
1









up vote
9
down vote

favorite
1






1





You are going to start from any number with distinct digits lower than four digits (such as $a$, $ab$, $abc$) and you will apply the rule below:



  • Take the square any number you want in the number (you may take the square the number itself too). (such as $1(02)$ -> $14$, or $12(3)$ -> $129$ or $(13)$ -> $169$)

  • Every number you found has to have distinct digits. (Fail example: $(12)3$-> $1443$ X)

  • You may apply this as many times as you want. ($(13)$ -> $169$ then $(16)9$->$2569$)


What is the biggest final number you can have?











share|improve this question















You are going to start from any number with distinct digits lower than four digits (such as $a$, $ab$, $abc$) and you will apply the rule below:



  • Take the square any number you want in the number (you may take the square the number itself too). (such as $1(02)$ -> $14$, or $12(3)$ -> $129$ or $(13)$ -> $169$)

  • Every number you found has to have distinct digits. (Fail example: $(12)3$-> $1443$ X)

  • You may apply this as many times as you want. ($(13)$ -> $169$ then $(16)9$->$2569$)


What is the biggest final number you can have?








mathematics formation-of-numbers






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edited Sep 17 at 9:24









xhienne

3,337529




3,337529










asked Sep 16 at 16:17









Oray

15.1k435145




15.1k435145







  • 1




    Biggest final number? or biggest starting number?
    – SteveV
    Sep 16 at 16:33










  • is there a restriction about how many digits the number which we square can have? like, if I get a number like 1023 as an interim result (even though 1023 itself is not possible), am I allowed to square it all to get to 1046529?
    – elias
    Sep 16 at 17:11










  • @elias "you may take the square the number itself too". written on the first rule. no restriction.
    – Oray
    Sep 16 at 17:12










  • $1(69) -> 14761$. Isn't this a violation of the previous rule?
    – Wais Kamal
    Sep 16 at 17:52










  • @WaisKamal ops true :) fixed it.
    – Oray
    Sep 16 at 17:53













  • 1




    Biggest final number? or biggest starting number?
    – SteveV
    Sep 16 at 16:33










  • is there a restriction about how many digits the number which we square can have? like, if I get a number like 1023 as an interim result (even though 1023 itself is not possible), am I allowed to square it all to get to 1046529?
    – elias
    Sep 16 at 17:11










  • @elias "you may take the square the number itself too". written on the first rule. no restriction.
    – Oray
    Sep 16 at 17:12










  • $1(69) -> 14761$. Isn't this a violation of the previous rule?
    – Wais Kamal
    Sep 16 at 17:52










  • @WaisKamal ops true :) fixed it.
    – Oray
    Sep 16 at 17:53








1




1




Biggest final number? or biggest starting number?
– SteveV
Sep 16 at 16:33




Biggest final number? or biggest starting number?
– SteveV
Sep 16 at 16:33












is there a restriction about how many digits the number which we square can have? like, if I get a number like 1023 as an interim result (even though 1023 itself is not possible), am I allowed to square it all to get to 1046529?
– elias
Sep 16 at 17:11




is there a restriction about how many digits the number which we square can have? like, if I get a number like 1023 as an interim result (even though 1023 itself is not possible), am I allowed to square it all to get to 1046529?
– elias
Sep 16 at 17:11












@elias "you may take the square the number itself too". written on the first rule. no restriction.
– Oray
Sep 16 at 17:12




@elias "you may take the square the number itself too". written on the first rule. no restriction.
– Oray
Sep 16 at 17:12












$1(69) -> 14761$. Isn't this a violation of the previous rule?
– Wais Kamal
Sep 16 at 17:52




$1(69) -> 14761$. Isn't this a violation of the previous rule?
– Wais Kamal
Sep 16 at 17:52












@WaisKamal ops true :) fixed it.
– Oray
Sep 16 at 17:53





@WaisKamal ops true :) fixed it.
– Oray
Sep 16 at 17:53











1 Answer
1






active

oldest

votes

















up vote
8
down vote



accepted










Update:



I've found




9857240136 to be maximal (confirmed with programming).




Many possible ways to reach it, here is one starting with...




(4)2 -> 16(2) -> 1(6)4 -> 1(3)64 -> (1964) -> 3857(2)96 -> 3857(496) -> (3)85724016 -> 98572401(6) -> 9857240136




Previous attempt:



My new record is:




9810362574




which can be reached via




(5)74 -> (25)74 -> (625)74 -> 3(9)062574 -> (3)81062574 -> 9810(6)2574 -> 9810362574




First attempt:



Not proven to be maximal at all, but I managed to reach




10 digits with 4817093625




The steps are:




(705) -> 4(9)7025 -> 48170(25) -> 48170(6)25 -> 48170(3)625 -> 481709(6)25 -> 4817093625







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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    8
    down vote



    accepted










    Update:



    I've found




    9857240136 to be maximal (confirmed with programming).




    Many possible ways to reach it, here is one starting with...




    (4)2 -> 16(2) -> 1(6)4 -> 1(3)64 -> (1964) -> 3857(2)96 -> 3857(496) -> (3)85724016 -> 98572401(6) -> 9857240136




    Previous attempt:



    My new record is:




    9810362574




    which can be reached via




    (5)74 -> (25)74 -> (625)74 -> 3(9)062574 -> (3)81062574 -> 9810(6)2574 -> 9810362574




    First attempt:



    Not proven to be maximal at all, but I managed to reach




    10 digits with 4817093625




    The steps are:




    (705) -> 4(9)7025 -> 48170(25) -> 48170(6)25 -> 48170(3)625 -> 481709(6)25 -> 4817093625







    share|improve this answer


























      up vote
      8
      down vote



      accepted










      Update:



      I've found




      9857240136 to be maximal (confirmed with programming).




      Many possible ways to reach it, here is one starting with...




      (4)2 -> 16(2) -> 1(6)4 -> 1(3)64 -> (1964) -> 3857(2)96 -> 3857(496) -> (3)85724016 -> 98572401(6) -> 9857240136




      Previous attempt:



      My new record is:




      9810362574




      which can be reached via




      (5)74 -> (25)74 -> (625)74 -> 3(9)062574 -> (3)81062574 -> 9810(6)2574 -> 9810362574




      First attempt:



      Not proven to be maximal at all, but I managed to reach




      10 digits with 4817093625




      The steps are:




      (705) -> 4(9)7025 -> 48170(25) -> 48170(6)25 -> 48170(3)625 -> 481709(6)25 -> 4817093625







      share|improve this answer
























        up vote
        8
        down vote



        accepted







        up vote
        8
        down vote



        accepted






        Update:



        I've found




        9857240136 to be maximal (confirmed with programming).




        Many possible ways to reach it, here is one starting with...




        (4)2 -> 16(2) -> 1(6)4 -> 1(3)64 -> (1964) -> 3857(2)96 -> 3857(496) -> (3)85724016 -> 98572401(6) -> 9857240136




        Previous attempt:



        My new record is:




        9810362574




        which can be reached via




        (5)74 -> (25)74 -> (625)74 -> 3(9)062574 -> (3)81062574 -> 9810(6)2574 -> 9810362574




        First attempt:



        Not proven to be maximal at all, but I managed to reach




        10 digits with 4817093625




        The steps are:




        (705) -> 4(9)7025 -> 48170(25) -> 48170(6)25 -> 48170(3)625 -> 481709(6)25 -> 4817093625







        share|improve this answer














        Update:



        I've found




        9857240136 to be maximal (confirmed with programming).




        Many possible ways to reach it, here is one starting with...




        (4)2 -> 16(2) -> 1(6)4 -> 1(3)64 -> (1964) -> 3857(2)96 -> 3857(496) -> (3)85724016 -> 98572401(6) -> 9857240136




        Previous attempt:



        My new record is:




        9810362574




        which can be reached via




        (5)74 -> (25)74 -> (625)74 -> 3(9)062574 -> (3)81062574 -> 9810(6)2574 -> 9810362574




        First attempt:



        Not proven to be maximal at all, but I managed to reach




        10 digits with 4817093625




        The steps are:




        (705) -> 4(9)7025 -> 48170(25) -> 48170(6)25 -> 48170(3)625 -> 481709(6)25 -> 4817093625








        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Sep 16 at 19:06

























        answered Sep 16 at 16:56









        elias

        7,84232151




        7,84232151



























             

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