mjhjmtu

Village in Slovakia Donovaly Village Coat of arms Donovaly Location of Donovaly in the Banská Bystrica Region Show map of Banská Bystrica Region Donovaly Donovaly (Slovakia) Show map of Slovakia Coordinates: 48°53′00″N 19°14′00″E  /  48.88333°N 19.23333°E  / 48.88333; 19.23333 Coordinates: 48°53′00″N 19°14′00″E  /  48.88333°N 19.23333°E  / 48.88333; 19.23333 Country Slovakia Region Banská Bystrica District Banská Bystrica First mentioned 1618 Government  • Mayor Miroslav Daňo Area  • Total 17.5 km 2 (6.8 sq mi) Elevation 960 m (3,150 ft) Population (2005)  • Total 154  • Density 8.8/km 2 (23/sq mi) Postal code 97639 Area code(s) +421-48 Car plate BB Website www.donovaly.sk Donovaly is a village in the Banská Bystrica Region of central Slovakia. [1] Being situated in an important pass between the mountains of Veľká Fatra and Starohorské vrchy, on the route connecting Banská Bystrica with Ružomberok, it became a prominent centre of winter and summer sports. Contents 1 Histo

Clash Royale CLAN TAG #URR8PPP 15 6 $begingroup$ I'm having a hard time reasoning through the formula for combinations $fracn!k!left(n-kright)!$ . I understand the reason for the permutations formula and I know that for the combinations we divide by $k!$ to adjust for the repeated cases, since order does not matter. But what exactly happens when we divide the set of permutations by $k!$ ? I know this may seem like a silly question... I just can't take this for granted, lest I miss a chance to apply it correctly. Can you describe what's happening here step by step, sort like debugging a script? combinatorics permutations share | cite | improve this question edited Feb 20 at 21:36 Bernard 123k 7 41 116 asked Feb 20 at 21:31 Daniel Oscar Daniel Oscar 348 11 $endgroup$ add a comment  |  15 6 $begingroup$ I'm having a hard time reasoning through the formula for combinations $fracn!k!left(n-kri