Why there are two diodes instead of one used for an LM35 negative temperature circuit?

Clash Royale CLAN TAG#URR8PPP
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See the system examples of the LM35 temperature sensor datasheet on page 16, see picture.
This should be used for negative temperatures. However, the voltage change is 10 mV/C and it supports -55 C minimum, resulting in -550 mV. A diode (1N914) has a typical drop of 600 or 700 mV .... why are two diodes used, and not one?
(I play to use a 1N4001 or 1N4148 since I have plenty of them).

sensor diodes lm35
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add a comment |
$begingroup$
See the system examples of the LM35 temperature sensor datasheet on page 16, see picture.
This should be used for negative temperatures. However, the voltage change is 10 mV/C and it supports -55 C minimum, resulting in -550 mV. A diode (1N914) has a typical drop of 600 or 700 mV .... why are two diodes used, and not one?
(I play to use a 1N4001 or 1N4148 since I have plenty of them).

sensor diodes lm35
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3
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A "typical" drop is irrelevant here. You need to ask yourself: what is the minimum diode forward voltage when passing the minimum current from the sensor?
$endgroup$
– Elliot Alderson
Feb 7 at 13:14
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Yes, just checked, for an 1N4148 the minimum is around 0.4-0.5V, which could be too less, thanks! It also answers my question that I can use 1N4148 instead.
$endgroup$
– Michel Keijzers
Feb 7 at 13:17
add a comment |
$begingroup$
See the system examples of the LM35 temperature sensor datasheet on page 16, see picture.
This should be used for negative temperatures. However, the voltage change is 10 mV/C and it supports -55 C minimum, resulting in -550 mV. A diode (1N914) has a typical drop of 600 or 700 mV .... why are two diodes used, and not one?
(I play to use a 1N4001 or 1N4148 since I have plenty of them).

sensor diodes lm35
$endgroup$
See the system examples of the LM35 temperature sensor datasheet on page 16, see picture.
This should be used for negative temperatures. However, the voltage change is 10 mV/C and it supports -55 C minimum, resulting in -550 mV. A diode (1N914) has a typical drop of 600 or 700 mV .... why are two diodes used, and not one?
(I play to use a 1N4001 or 1N4148 since I have plenty of them).

sensor diodes lm35
sensor diodes lm35
asked Feb 7 at 13:12
Michel KeijzersMichel Keijzers
6,45692968
6,45692968
3
$begingroup$
A "typical" drop is irrelevant here. You need to ask yourself: what is the minimum diode forward voltage when passing the minimum current from the sensor?
$endgroup$
– Elliot Alderson
Feb 7 at 13:14
$begingroup$
Yes, just checked, for an 1N4148 the minimum is around 0.4-0.5V, which could be too less, thanks! It also answers my question that I can use 1N4148 instead.
$endgroup$
– Michel Keijzers
Feb 7 at 13:17
add a comment |
3
$begingroup$
A "typical" drop is irrelevant here. You need to ask yourself: what is the minimum diode forward voltage when passing the minimum current from the sensor?
$endgroup$
– Elliot Alderson
Feb 7 at 13:14
$begingroup$
Yes, just checked, for an 1N4148 the minimum is around 0.4-0.5V, which could be too less, thanks! It also answers my question that I can use 1N4148 instead.
$endgroup$
– Michel Keijzers
Feb 7 at 13:17
3
3
$begingroup$
A "typical" drop is irrelevant here. You need to ask yourself: what is the minimum diode forward voltage when passing the minimum current from the sensor?
$endgroup$
– Elliot Alderson
Feb 7 at 13:14
$begingroup$
A "typical" drop is irrelevant here. You need to ask yourself: what is the minimum diode forward voltage when passing the minimum current from the sensor?
$endgroup$
– Elliot Alderson
Feb 7 at 13:14
$begingroup$
Yes, just checked, for an 1N4148 the minimum is around 0.4-0.5V, which could be too less, thanks! It also answers my question that I can use 1N4148 instead.
$endgroup$
– Michel Keijzers
Feb 7 at 13:17
$begingroup$
Yes, just checked, for an 1N4148 the minimum is around 0.4-0.5V, which could be too less, thanks! It also answers my question that I can use 1N4148 instead.
$endgroup$
– Michel Keijzers
Feb 7 at 13:17
add a comment |
1 Answer
1
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oldest
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$begingroup$
The whole point about this circuit is that the 18 kohm resistor is tied to a negative voltage relative to Vout- and this ensures that the LM35 can produce a signal that reflects negative temperatures. Without the bias resistor to a negative supply rail (relative to Vout-), the LM35 only works from +1 or 2 degC.
2 diodes are used because despite what people simplistically call "the standard volt drop of 0.5 volts to 0.9 volts for a range of diodes", the actual volt-drop depends on the current through the diode and, if it is low (as per the case of this circuit - circa micro amps) then you'll probably need two diode drops to produce something in excess of 0.55 volts.
Here's an extrapolation of what a 1N4148 diode might produce at 1uA of current: -

Given that an LM35 might only draw about 10 uA at -55 degC, you can imagine each diode dropping maybe 0.4 volts hence two diodes are needed.
$endgroup$
add a comment |
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$begingroup$
The whole point about this circuit is that the 18 kohm resistor is tied to a negative voltage relative to Vout- and this ensures that the LM35 can produce a signal that reflects negative temperatures. Without the bias resistor to a negative supply rail (relative to Vout-), the LM35 only works from +1 or 2 degC.
2 diodes are used because despite what people simplistically call "the standard volt drop of 0.5 volts to 0.9 volts for a range of diodes", the actual volt-drop depends on the current through the diode and, if it is low (as per the case of this circuit - circa micro amps) then you'll probably need two diode drops to produce something in excess of 0.55 volts.
Here's an extrapolation of what a 1N4148 diode might produce at 1uA of current: -

Given that an LM35 might only draw about 10 uA at -55 degC, you can imagine each diode dropping maybe 0.4 volts hence two diodes are needed.
$endgroup$
add a comment |
$begingroup$
The whole point about this circuit is that the 18 kohm resistor is tied to a negative voltage relative to Vout- and this ensures that the LM35 can produce a signal that reflects negative temperatures. Without the bias resistor to a negative supply rail (relative to Vout-), the LM35 only works from +1 or 2 degC.
2 diodes are used because despite what people simplistically call "the standard volt drop of 0.5 volts to 0.9 volts for a range of diodes", the actual volt-drop depends on the current through the diode and, if it is low (as per the case of this circuit - circa micro amps) then you'll probably need two diode drops to produce something in excess of 0.55 volts.
Here's an extrapolation of what a 1N4148 diode might produce at 1uA of current: -

Given that an LM35 might only draw about 10 uA at -55 degC, you can imagine each diode dropping maybe 0.4 volts hence two diodes are needed.
$endgroup$
add a comment |
$begingroup$
The whole point about this circuit is that the 18 kohm resistor is tied to a negative voltage relative to Vout- and this ensures that the LM35 can produce a signal that reflects negative temperatures. Without the bias resistor to a negative supply rail (relative to Vout-), the LM35 only works from +1 or 2 degC.
2 diodes are used because despite what people simplistically call "the standard volt drop of 0.5 volts to 0.9 volts for a range of diodes", the actual volt-drop depends on the current through the diode and, if it is low (as per the case of this circuit - circa micro amps) then you'll probably need two diode drops to produce something in excess of 0.55 volts.
Here's an extrapolation of what a 1N4148 diode might produce at 1uA of current: -

Given that an LM35 might only draw about 10 uA at -55 degC, you can imagine each diode dropping maybe 0.4 volts hence two diodes are needed.
$endgroup$
The whole point about this circuit is that the 18 kohm resistor is tied to a negative voltage relative to Vout- and this ensures that the LM35 can produce a signal that reflects negative temperatures. Without the bias resistor to a negative supply rail (relative to Vout-), the LM35 only works from +1 or 2 degC.
2 diodes are used because despite what people simplistically call "the standard volt drop of 0.5 volts to 0.9 volts for a range of diodes", the actual volt-drop depends on the current through the diode and, if it is low (as per the case of this circuit - circa micro amps) then you'll probably need two diode drops to produce something in excess of 0.55 volts.
Here's an extrapolation of what a 1N4148 diode might produce at 1uA of current: -

Given that an LM35 might only draw about 10 uA at -55 degC, you can imagine each diode dropping maybe 0.4 volts hence two diodes are needed.
edited Feb 7 at 13:36
answered Feb 7 at 13:21
Andy akaAndy aka
242k11182416
242k11182416
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$begingroup$
A "typical" drop is irrelevant here. You need to ask yourself: what is the minimum diode forward voltage when passing the minimum current from the sensor?
$endgroup$
– Elliot Alderson
Feb 7 at 13:14
$begingroup$
Yes, just checked, for an 1N4148 the minimum is around 0.4-0.5V, which could be too less, thanks! It also answers my question that I can use 1N4148 instead.
$endgroup$
– Michel Keijzers
Feb 7 at 13:17