How can I get the exact answer of the maximum of this function?

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I am trying to find the maximum of a fuction: $ f(x)=sqrtx^2+9-sqrtx^2-sqrt3 x+1 $.



I tried



 Maximize[Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3]*x + 1], x]


and I got




[Sqrt](9 +
Root[-3 + #1^2 &,
243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
71 #1 #2^5 + 35 #2^6 &, 2, 2]^2) - [Sqrt](1 -
Sqrt[3] Root[-3 + #1^2 &,
243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
71 #1 #2^5 + 35 #2^6 &, 2, 2] +
Root[-3 + #1^2 &,
243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
71 #1 #2^5 + 35 #2^6 &, 2, 2]^2), x ->
Root[-3 + #1^2 &,
243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
71 #1 #2^5 + 35 #2^6 &, 2, 2]




The exact answer is $sqrt7$.



How can I get the exact answer of the maximum of this function?










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    up vote
    4
    down vote

    favorite












    I am trying to find the maximum of a fuction: $ f(x)=sqrtx^2+9-sqrtx^2-sqrt3 x+1 $.



    I tried



     Maximize[Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3]*x + 1], x]


    and I got




    [Sqrt](9 +
    Root[-3 + #1^2 &,
    243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
    71 #1 #2^5 + 35 #2^6 &, 2, 2]^2) - [Sqrt](1 -
    Sqrt[3] Root[-3 + #1^2 &,
    243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
    71 #1 #2^5 + 35 #2^6 &, 2, 2] +
    Root[-3 + #1^2 &,
    243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
    71 #1 #2^5 + 35 #2^6 &, 2, 2]^2), x ->
    Root[-3 + #1^2 &,
    243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
    71 #1 #2^5 + 35 #2^6 &, 2, 2]




    The exact answer is $sqrt7$.



    How can I get the exact answer of the maximum of this function?










    share|improve this question

























      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      I am trying to find the maximum of a fuction: $ f(x)=sqrtx^2+9-sqrtx^2-sqrt3 x+1 $.



      I tried



       Maximize[Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3]*x + 1], x]


      and I got




      [Sqrt](9 +
      Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2]^2) - [Sqrt](1 -
      Sqrt[3] Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2] +
      Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2]^2), x ->
      Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2]




      The exact answer is $sqrt7$.



      How can I get the exact answer of the maximum of this function?










      share|improve this question















      I am trying to find the maximum of a fuction: $ f(x)=sqrtx^2+9-sqrtx^2-sqrt3 x+1 $.



      I tried



       Maximize[Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3]*x + 1], x]


      and I got




      [Sqrt](9 +
      Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2]^2) - [Sqrt](1 -
      Sqrt[3] Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2] +
      Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2]^2), x ->
      Root[-3 + #1^2 &,
      243 - 567 #1 #2 + 1557 #2^2 - 702 #1 #2^3 + 485 #2^4 -
      71 #1 #2^5 + 35 #2^6 &, 2, 2]




      The exact answer is $sqrt7$.



      How can I get the exact answer of the maximum of this function?







      calculus-and-analysis mathematical-optimization






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          1 Answer
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          First set the function definition



          Clear[f]
          f[x_] := Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3] x + 1]



          Method I



          The conventional method, by finding the stationary point first:



          Solve[f'[x] == 0, x][[1]]
          f[x] /. %
          (f''[x] /. %%) < 0



          x -> (3 Sqrt[3])/5
          Sqrt[7]
          True




          Method II



          By using ToRadicals to transform Root:



          Maximize[f[x], x] // ToRadicals



          Sqrt[7], x -> (3 Sqrt[3])/5






          share|improve this answer






















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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            7
            down vote



            accepted










            First set the function definition



            Clear[f]
            f[x_] := Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3] x + 1]



            Method I



            The conventional method, by finding the stationary point first:



            Solve[f'[x] == 0, x][[1]]
            f[x] /. %
            (f''[x] /. %%) < 0



            x -> (3 Sqrt[3])/5
            Sqrt[7]
            True




            Method II



            By using ToRadicals to transform Root:



            Maximize[f[x], x] // ToRadicals



            Sqrt[7], x -> (3 Sqrt[3])/5






            share|improve this answer


























              up vote
              7
              down vote



              accepted










              First set the function definition



              Clear[f]
              f[x_] := Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3] x + 1]



              Method I



              The conventional method, by finding the stationary point first:



              Solve[f'[x] == 0, x][[1]]
              f[x] /. %
              (f''[x] /. %%) < 0



              x -> (3 Sqrt[3])/5
              Sqrt[7]
              True




              Method II



              By using ToRadicals to transform Root:



              Maximize[f[x], x] // ToRadicals



              Sqrt[7], x -> (3 Sqrt[3])/5






              share|improve this answer
























                up vote
                7
                down vote



                accepted







                up vote
                7
                down vote



                accepted






                First set the function definition



                Clear[f]
                f[x_] := Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3] x + 1]



                Method I



                The conventional method, by finding the stationary point first:



                Solve[f'[x] == 0, x][[1]]
                f[x] /. %
                (f''[x] /. %%) < 0



                x -> (3 Sqrt[3])/5
                Sqrt[7]
                True




                Method II



                By using ToRadicals to transform Root:



                Maximize[f[x], x] // ToRadicals



                Sqrt[7], x -> (3 Sqrt[3])/5






                share|improve this answer














                First set the function definition



                Clear[f]
                f[x_] := Sqrt[x^2 + 9] - Sqrt[x^2 - Sqrt[3] x + 1]



                Method I



                The conventional method, by finding the stationary point first:



                Solve[f'[x] == 0, x][[1]]
                f[x] /. %
                (f''[x] /. %%) < 0



                x -> (3 Sqrt[3])/5
                Sqrt[7]
                True




                Method II



                By using ToRadicals to transform Root:



                Maximize[f[x], x] // ToRadicals



                Sqrt[7], x -> (3 Sqrt[3])/5







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited yesterday

























                answered yesterday









                Αλέξανδρος Ζεγγ

                2,424725




                2,424725



























                     

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