split file lines by regex delimeter
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0
I want to split each line from input file by a non-alphanumeric regex W and print all the split chunks in the output file like so:
Input file:
www.wifi.in.ua
YI-HondBrychka
Output file:
www
wifi
in
ua
YI
HondBrynchka
regular-expression
asked Mar 10 at 19:19
dizczadizcza
104
add a comment |
0
I want to split each line from input file by a non-alphanumeric regex W and print all the split chunks in the output file like so:
Input file:
www.wifi.in.ua
YI-HondBrychka
Output file:
www
wifi
in
ua
YI
HondBrynchka
regular-expression
asked Mar 10 at 19:19
dizczadizcza
104
add a comment |
0
0
0
I want to split each line from input file by a non-alphanumeric regex W and print all the split chunks in the output file like so:
Input file:
www.wifi.in.ua
YI-HondBrychka
Output file:
www
wifi
in
ua
YI
HondBrynchka
regular-expression
asked Mar 10 at 19:19
dizczadizcza
104
I want to split each line from input file by a non-alphanumeric regex W and print all the split chunks in the output file like so:
Input file:
www.wifi.in.ua
YI-HondBrychka
Output file:
www
wifi
in
ua
YI
HondBrynchka
regular-expression
regular-expression
asked Mar 10 at 19:19
dizczadizcza
104
asked Mar 10 at 19:19
dizczadizcza
104
asked Mar 10 at 19:19
dizczadizcza
104
asked Mar 10 at 19:19
dizczadizcza
104
asked Mar 10 at 19:19
dizczadizcza
104
104
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
Try using the -o flag, to only print matching strings, e.g.
$ cat <<HEREDOC | grep -Po 'w+'
www.wifi.in.ua
YI-HondBrychka
HEREDOC
www
wifi
in
ua
YI
HondBrychka
answered Mar 10 at 19:29
igaligal
6,1411638
Did you meangrep -Po 'w+' HEREDOC? This works, thank you.
– dizcza
Mar 10 at 19:33
No, I meant what I wrote there - it works for me if I copy-paste it. In practice, I imagine you would use a file instead of a heredoc string, and it would look likegrep -Po 'w+' /path/to/file.
– igal
Mar 10 at 19:55
Substituting HEREDOC for path to file,cat <<HEREDOC | grep -Po 'w+'doesn't work for me whilecat HEREDOC | grep -Po 'w+'(or bettergrep -Po 'w+' HEREDOC) works fine.
– dizcza
Mar 10 at 19:59
It sounds to me like you're confused about what a heredoc is - it's not supposed to represent a file path. You can read more about "here documents" in the Bash manual: gnu.org/software/bash/manual/bashref.html#Here-Documents
– igal
Mar 10 at 20:03
Oh, I see, I didn't know that. Thank you.
– dizcza
Mar 10 at 20:07
|
show 1 more comment
0
Replacing all matches of W with newlines, using Perl (from which the W expression originated):
$ perl -pe '$_ =~ s/W/n/g' <file
www
wifi
in
ua
YI
HondBrychka
Or, more in line with the actual wording of the question:
$ perl -pe '$_ = join("n", split(/W/)) . "n"' <file
www
wifi
in
ua
YI
HondBrychka
Expressing the PCRE W as the ERE [^[:alnum:]] and using GNU awk:
awk -v RS='[^[:alnum:]]' 1 file
The 1 is short for ' print ' and this sets the input record separator to any W character. The records are then printed on individual lines.
Or with GNU sed:
sed 's/[^[:alnum:]]/n/g' file
With tr, it becomes
$ tr -c '[:alnum:]' 'n' <file
www
wifi
in
ua
YI
HondBrychka
where -c makes it replace each character that is not an [:alnum:] with a newline.
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
The last solution has an artifact of empty new lines. Comparetr -c '[:alpha:]' 'n' < HEREDOCwithgrep -Po '[a-zA-Z]+' HEREDOCif we add "Zhenek_Lebed98" to the input file HEREDOC.
– dizcza
Mar 10 at 19:57
@dizcza Add-sto the command line. It will make it squeeze multiple newlines into one. But on the other hand, you do have an empty word between9and8.
– Kusalananda♦
Mar 10 at 20:03
Now it works as well.
– dizcza
Mar 10 at 20:04
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
1
Try using the -o flag, to only print matching strings, e.g.
$ cat <<HEREDOC | grep -Po 'w+'
www.wifi.in.ua
YI-HondBrychka
HEREDOC
www
wifi
in
ua
YI
HondBrychka
answered Mar 10 at 19:29
igaligal
6,1411638
Did you meangrep -Po 'w+' HEREDOC? This works, thank you.
– dizcza
Mar 10 at 19:33
No, I meant what I wrote there - it works for me if I copy-paste it. In practice, I imagine you would use a file instead of a heredoc string, and it would look likegrep -Po 'w+' /path/to/file.
– igal
Mar 10 at 19:55
Substituting HEREDOC for path to file,cat <<HEREDOC | grep -Po 'w+'doesn't work for me whilecat HEREDOC | grep -Po 'w+'(or bettergrep -Po 'w+' HEREDOC) works fine.
– dizcza
Mar 10 at 19:59
It sounds to me like you're confused about what a heredoc is - it's not supposed to represent a file path. You can read more about "here documents" in the Bash manual: gnu.org/software/bash/manual/bashref.html#Here-Documents
– igal
Mar 10 at 20:03
Oh, I see, I didn't know that. Thank you.
– dizcza
Mar 10 at 20:07
|
show 1 more comment
1
Try using the -o flag, to only print matching strings, e.g.
$ cat <<HEREDOC | grep -Po 'w+'
www.wifi.in.ua
YI-HondBrychka
HEREDOC
www
wifi
in
ua
YI
HondBrychka
answered Mar 10 at 19:29
igaligal
6,1411638
Did you meangrep -Po 'w+' HEREDOC? This works, thank you.
– dizcza
Mar 10 at 19:33
No, I meant what I wrote there - it works for me if I copy-paste it. In practice, I imagine you would use a file instead of a heredoc string, and it would look likegrep -Po 'w+' /path/to/file.
– igal
Mar 10 at 19:55
Substituting HEREDOC for path to file,cat <<HEREDOC | grep -Po 'w+'doesn't work for me whilecat HEREDOC | grep -Po 'w+'(or bettergrep -Po 'w+' HEREDOC) works fine.
– dizcza
Mar 10 at 19:59
It sounds to me like you're confused about what a heredoc is - it's not supposed to represent a file path. You can read more about "here documents" in the Bash manual: gnu.org/software/bash/manual/bashref.html#Here-Documents
– igal
Mar 10 at 20:03
Oh, I see, I didn't know that. Thank you.
– dizcza
Mar 10 at 20:07
|
show 1 more comment
1
1
1
Try using the -o flag, to only print matching strings, e.g.
$ cat <<HEREDOC | grep -Po 'w+'
www.wifi.in.ua
YI-HondBrychka
HEREDOC
www
wifi
in
ua
YI
HondBrychka
answered Mar 10 at 19:29
igaligal
6,1411638
Try using the -o flag, to only print matching strings, e.g.
$ cat <<HEREDOC | grep -Po 'w+'
www.wifi.in.ua
YI-HondBrychka
HEREDOC
www
wifi
in
ua
YI
HondBrychka
answered Mar 10 at 19:29
igaligal
6,1411638
answered Mar 10 at 19:29
igaligal
6,1411638
answered Mar 10 at 19:29
igaligal
6,1411638
answered Mar 10 at 19:29
igaligal
6,1411638
6,1411638
Did you meangrep -Po 'w+' HEREDOC? This works, thank you.
– dizcza
Mar 10 at 19:33
No, I meant what I wrote there - it works for me if I copy-paste it. In practice, I imagine you would use a file instead of a heredoc string, and it would look likegrep -Po 'w+' /path/to/file.
– igal
Mar 10 at 19:55
Substituting HEREDOC for path to file,cat <<HEREDOC | grep -Po 'w+'doesn't work for me whilecat HEREDOC | grep -Po 'w+'(or bettergrep -Po 'w+' HEREDOC) works fine.
– dizcza
Mar 10 at 19:59
It sounds to me like you're confused about what a heredoc is - it's not supposed to represent a file path. You can read more about "here documents" in the Bash manual: gnu.org/software/bash/manual/bashref.html#Here-Documents
– igal
Mar 10 at 20:03
Oh, I see, I didn't know that. Thank you.
– dizcza
Mar 10 at 20:07
|
show 1 more comment
Did you meangrep -Po 'w+' HEREDOC? This works, thank you.
– dizcza
Mar 10 at 19:33
No, I meant what I wrote there - it works for me if I copy-paste it. In practice, I imagine you would use a file instead of a heredoc string, and it would look likegrep -Po 'w+' /path/to/file.
– igal
Mar 10 at 19:55
Substituting HEREDOC for path to file,cat <<HEREDOC | grep -Po 'w+'doesn't work for me whilecat HEREDOC | grep -Po 'w+'(or bettergrep -Po 'w+' HEREDOC) works fine.
– dizcza
Mar 10 at 19:59
It sounds to me like you're confused about what a heredoc is - it's not supposed to represent a file path. You can read more about "here documents" in the Bash manual: gnu.org/software/bash/manual/bashref.html#Here-Documents
– igal
Mar 10 at 20:03
Oh, I see, I didn't know that. Thank you.
– dizcza
Mar 10 at 20:07
Did you mean
grep -Po 'w+' HEREDOC? This works, thank you.– dizcza
Mar 10 at 19:33
Did you mean
grep -Po 'w+' HEREDOC? This works, thank you.– dizcza
Mar 10 at 19:33
No, I meant what I wrote there - it works for me if I copy-paste it. In practice, I imagine you would use a file instead of a heredoc string, and it would look like
grep -Po 'w+' /path/to/file.– igal
Mar 10 at 19:55
No, I meant what I wrote there - it works for me if I copy-paste it. In practice, I imagine you would use a file instead of a heredoc string, and it would look like
grep -Po 'w+' /path/to/file.– igal
Mar 10 at 19:55
Substituting HEREDOC for path to file,
cat <<HEREDOC | grep -Po 'w+' doesn't work for me while cat HEREDOC | grep -Po 'w+' (or better grep -Po 'w+' HEREDOC) works fine.– dizcza
Mar 10 at 19:59
Substituting HEREDOC for path to file,
cat <<HEREDOC | grep -Po 'w+' doesn't work for me while cat HEREDOC | grep -Po 'w+' (or better grep -Po 'w+' HEREDOC) works fine.– dizcza
Mar 10 at 19:59
It sounds to me like you're confused about what a heredoc is - it's not supposed to represent a file path. You can read more about "here documents" in the Bash manual: gnu.org/software/bash/manual/bashref.html#Here-Documents
– igal
Mar 10 at 20:03
It sounds to me like you're confused about what a heredoc is - it's not supposed to represent a file path. You can read more about "here documents" in the Bash manual: gnu.org/software/bash/manual/bashref.html#Here-Documents
– igal
Mar 10 at 20:03
Oh, I see, I didn't know that. Thank you.
– dizcza
Mar 10 at 20:07
Oh, I see, I didn't know that. Thank you.
– dizcza
Mar 10 at 20:07
|
show 1 more comment
0
Replacing all matches of W with newlines, using Perl (from which the W expression originated):
$ perl -pe '$_ =~ s/W/n/g' <file
www
wifi
in
ua
YI
HondBrychka
Or, more in line with the actual wording of the question:
$ perl -pe '$_ = join("n", split(/W/)) . "n"' <file
www
wifi
in
ua
YI
HondBrychka
Expressing the PCRE W as the ERE [^[:alnum:]] and using GNU awk:
awk -v RS='[^[:alnum:]]' 1 file
The 1 is short for ' print ' and this sets the input record separator to any W character. The records are then printed on individual lines.
Or with GNU sed:
sed 's/[^[:alnum:]]/n/g' file
With tr, it becomes
$ tr -c '[:alnum:]' 'n' <file
www
wifi
in
ua
YI
HondBrychka
where -c makes it replace each character that is not an [:alnum:] with a newline.
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
The last solution has an artifact of empty new lines. Comparetr -c '[:alpha:]' 'n' < HEREDOCwithgrep -Po '[a-zA-Z]+' HEREDOCif we add "Zhenek_Lebed98" to the input file HEREDOC.
– dizcza
Mar 10 at 19:57
@dizcza Add-sto the command line. It will make it squeeze multiple newlines into one. But on the other hand, you do have an empty word between9and8.
– Kusalananda♦
Mar 10 at 20:03
Now it works as well.
– dizcza
Mar 10 at 20:04
add a comment |
0
Replacing all matches of W with newlines, using Perl (from which the W expression originated):
$ perl -pe '$_ =~ s/W/n/g' <file
www
wifi
in
ua
YI
HondBrychka
Or, more in line with the actual wording of the question:
$ perl -pe '$_ = join("n", split(/W/)) . "n"' <file
www
wifi
in
ua
YI
HondBrychka
Expressing the PCRE W as the ERE [^[:alnum:]] and using GNU awk:
awk -v RS='[^[:alnum:]]' 1 file
The 1 is short for ' print ' and this sets the input record separator to any W character. The records are then printed on individual lines.
Or with GNU sed:
sed 's/[^[:alnum:]]/n/g' file
With tr, it becomes
$ tr -c '[:alnum:]' 'n' <file
www
wifi
in
ua
YI
HondBrychka
where -c makes it replace each character that is not an [:alnum:] with a newline.
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
The last solution has an artifact of empty new lines. Comparetr -c '[:alpha:]' 'n' < HEREDOCwithgrep -Po '[a-zA-Z]+' HEREDOCif we add "Zhenek_Lebed98" to the input file HEREDOC.
– dizcza
Mar 10 at 19:57
@dizcza Add-sto the command line. It will make it squeeze multiple newlines into one. But on the other hand, you do have an empty word between9and8.
– Kusalananda♦
Mar 10 at 20:03
Now it works as well.
– dizcza
Mar 10 at 20:04
add a comment |
0
0
0
Replacing all matches of W with newlines, using Perl (from which the W expression originated):
$ perl -pe '$_ =~ s/W/n/g' <file
www
wifi
in
ua
YI
HondBrychka
Or, more in line with the actual wording of the question:
$ perl -pe '$_ = join("n", split(/W/)) . "n"' <file
www
wifi
in
ua
YI
HondBrychka
Expressing the PCRE W as the ERE [^[:alnum:]] and using GNU awk:
awk -v RS='[^[:alnum:]]' 1 file
The 1 is short for ' print ' and this sets the input record separator to any W character. The records are then printed on individual lines.
Or with GNU sed:
sed 's/[^[:alnum:]]/n/g' file
With tr, it becomes
$ tr -c '[:alnum:]' 'n' <file
www
wifi
in
ua
YI
HondBrychka
where -c makes it replace each character that is not an [:alnum:] with a newline.
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
Replacing all matches of W with newlines, using Perl (from which the W expression originated):
$ perl -pe '$_ =~ s/W/n/g' <file
www
wifi
in
ua
YI
HondBrychka
Or, more in line with the actual wording of the question:
$ perl -pe '$_ = join("n", split(/W/)) . "n"' <file
www
wifi
in
ua
YI
HondBrychka
Expressing the PCRE W as the ERE [^[:alnum:]] and using GNU awk:
awk -v RS='[^[:alnum:]]' 1 file
The 1 is short for ' print ' and this sets the input record separator to any W character. The records are then printed on individual lines.
Or with GNU sed:
sed 's/[^[:alnum:]]/n/g' file
With tr, it becomes
$ tr -c '[:alnum:]' 'n' <file
www
wifi
in
ua
YI
HondBrychka
where -c makes it replace each character that is not an [:alnum:] with a newline.
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
edited Mar 10 at 19:53
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
answered Mar 10 at 19:37
Kusalananda♦Kusalananda
140k17261435
140k17261435
The last solution has an artifact of empty new lines. Comparetr -c '[:alpha:]' 'n' < HEREDOCwithgrep -Po '[a-zA-Z]+' HEREDOCif we add "Zhenek_Lebed98" to the input file HEREDOC.
– dizcza
Mar 10 at 19:57
@dizcza Add-sto the command line. It will make it squeeze multiple newlines into one. But on the other hand, you do have an empty word between9and8.
– Kusalananda♦
Mar 10 at 20:03
Now it works as well.
– dizcza
Mar 10 at 20:04
add a comment |
The last solution has an artifact of empty new lines. Comparetr -c '[:alpha:]' 'n' < HEREDOCwithgrep -Po '[a-zA-Z]+' HEREDOCif we add "Zhenek_Lebed98" to the input file HEREDOC.
– dizcza
Mar 10 at 19:57
@dizcza Add-sto the command line. It will make it squeeze multiple newlines into one. But on the other hand, you do have an empty word between9and8.
– Kusalananda♦
Mar 10 at 20:03
Now it works as well.
– dizcza
Mar 10 at 20:04
The last solution has an artifact of empty new lines. Compare
tr -c '[:alpha:]' 'n' < HEREDOC with grep -Po '[a-zA-Z]+' HEREDOC if we add "Zhenek_Lebed98" to the input file HEREDOC.– dizcza
Mar 10 at 19:57
The last solution has an artifact of empty new lines. Compare
tr -c '[:alpha:]' 'n' < HEREDOC with grep -Po '[a-zA-Z]+' HEREDOC if we add "Zhenek_Lebed98" to the input file HEREDOC.– dizcza
Mar 10 at 19:57
@dizcza Add
-s to the command line. It will make it squeeze multiple newlines into one. But on the other hand, you do have an empty word between 9 and 8.– Kusalananda♦
Mar 10 at 20:03
@dizcza Add
-s to the command line. It will make it squeeze multiple newlines into one. But on the other hand, you do have an empty word between 9 and 8.– Kusalananda♦
Mar 10 at 20:03
Now it works as well.
– dizcza
Mar 10 at 20:04
Now it works as well.
– dizcza
Mar 10 at 20:04
add a comment |
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