mjhjmtu

How can I remove all empty directories in a subtree? I used something like

find . -type d -exec rmdir 2>/dev/null ;

but I needs to be run multiple times in order to remove directories containing empty directories only. Moreover, it's quite slow, especially under cygwin.

Combining GNU find options and predicates, this command should do the job:

find . -type d -empty -delete

• 
  -type d restricts to directories


• 
  -empty restricts to empty ones


• 
  -delete removes each directory

The tree is walked from the leaves without the need to specify -depth as it is implied by -delete.

List the directories deeply-nested-first.

find . -depth -type d -exec rmdir ; 2>/dev/null

(Note that the redirection applies to the find command as a whole, not just to rmdir. Redirecting only for rmdir would cause a significant slowdown as you'd need to invoke an intermediate shell.)

You can avoid running rmdir on non-empty directories by passing the -empty predicate to find. GNU find tests the directory when it's about to run the command, so directories that have just been emptied will be picked up.

find . -depth -type d -empty -exec rmdir ;

Another way to speed up would be to group the rmdir invocations. Both are likely to be noticeably faster than the original, especially under Cygwin. I don't expect much difference between these two.

find . -depth -type d -print0 | xargs -0 rmdir 2>/dev/null
find . -depth -type d -exec rmdir + 2>/dev/null

Which method is faster depends on how many non-empty directories you have. You can't combine -empty with methods for grouping invocations, because then the directories that only contain empty directories aren't empty by the time find looks at them.

Another method would be to run multiple passes. Whether this is faster depends on a lot of things, including whether the whole directory hierarchy can remain in the disk cache between find runs.

while [ -n "$(find . -depth -type d -empty -print -exec rmdir +)" ]; do :; done

Alternatively, use zsh. The glob qualifier F matches non-empty directories, so /^F matches empty directories. Directories that only contain empty directories can't be matched so easily.

while rmdir **/*(/N^F); do :; done

(This terminates when rmdir receives an empty command line.)

If you just tack a -p on your rmdir, that'll work in one pass. It won't be pretty or optimal, but it should get everything. That tells rmdir to remove any non-empty parent directories of the one you're removing.

You can save a little bit by adding the -empty test to find, so it doesn't bother with non-empty directories.

find . -depth -type d -exec rmdir +

is the simplest and standard compliant answer to this question.

The other answers given here unfortunately all depend on vendor specific enhancements that do not exist on all systems.

find . -type d -printf "%d %pn" |
sort -nr |
perl -pe 's/^d+s//;' |
while read dir; do
(rmdir "$dir" > /dev/null 2>&1);
done

Here's how it works:

1. Recursively list all the directories along with their depth


2. Sort by descending order of their depth


3. Filter out only the directory paths


4. Run rmdir on the list one by one

rm -r */ command worked easily for me. rm should require -f to forcefully remove directories with files. rm -r should only remove empty directories. I'm open to why this could be wrong. This should also leave files since */ only looks at folders.