Number of self avoiding paths on a grid graph?

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Let $G$ be an $n times n$ grid graph. Is there anything known about the asymptotic growth rate of the number of self avoiding paths from $(0,0)$ to $(n,b)$ (from the lower left corner to some arbitrary point on the right hand side)?



For example, is there anything known about the $b$ that maximizes this number? A limiting probability distribution on $[0,1]$ for the value of $b$ (if we pick a self avoiding walk from $(0,0)$ to $x = n$ uniformly at random)?



Some similar questions go unanswered:



Any approximation algorithms for self-avoiding walks?



How does the number of self-avoiding paths between two points scale, in a square/cubic lattice?



Thank you!










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  • math.stackexchange.com/questions/110729/…
    – Josiah Park
    4 hours ago














up vote
1
down vote

favorite












Let $G$ be an $n times n$ grid graph. Is there anything known about the asymptotic growth rate of the number of self avoiding paths from $(0,0)$ to $(n,b)$ (from the lower left corner to some arbitrary point on the right hand side)?



For example, is there anything known about the $b$ that maximizes this number? A limiting probability distribution on $[0,1]$ for the value of $b$ (if we pick a self avoiding walk from $(0,0)$ to $x = n$ uniformly at random)?



Some similar questions go unanswered:



Any approximation algorithms for self-avoiding walks?



How does the number of self-avoiding paths between two points scale, in a square/cubic lattice?



Thank you!










share|cite|improve this question





















  • math.stackexchange.com/questions/110729/…
    – Josiah Park
    4 hours ago












up vote
1
down vote

favorite









up vote
1
down vote

favorite











Let $G$ be an $n times n$ grid graph. Is there anything known about the asymptotic growth rate of the number of self avoiding paths from $(0,0)$ to $(n,b)$ (from the lower left corner to some arbitrary point on the right hand side)?



For example, is there anything known about the $b$ that maximizes this number? A limiting probability distribution on $[0,1]$ for the value of $b$ (if we pick a self avoiding walk from $(0,0)$ to $x = n$ uniformly at random)?



Some similar questions go unanswered:



Any approximation algorithms for self-avoiding walks?



How does the number of self-avoiding paths between two points scale, in a square/cubic lattice?



Thank you!










share|cite|improve this question













Let $G$ be an $n times n$ grid graph. Is there anything known about the asymptotic growth rate of the number of self avoiding paths from $(0,0)$ to $(n,b)$ (from the lower left corner to some arbitrary point on the right hand side)?



For example, is there anything known about the $b$ that maximizes this number? A limiting probability distribution on $[0,1]$ for the value of $b$ (if we pick a self avoiding walk from $(0,0)$ to $x = n$ uniformly at random)?



Some similar questions go unanswered:



Any approximation algorithms for self-avoiding walks?



How does the number of self-avoiding paths between two points scale, in a square/cubic lattice?



Thank you!







co.combinatorics graph-theory random-walks






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asked 4 hours ago









Lorenzo

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  • math.stackexchange.com/questions/110729/…
    – Josiah Park
    4 hours ago
















  • math.stackexchange.com/questions/110729/…
    – Josiah Park
    4 hours ago















math.stackexchange.com/questions/110729/…
– Josiah Park
4 hours ago




math.stackexchange.com/questions/110729/…
– Josiah Park
4 hours ago










2 Answers
2






active

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up vote
6
down vote



accepted










Lawler, Schramm and Werner conjectured that the number $R_n$ of self-avoiding walks in the rectangle $[-N;N]times[0;N]$ connecting the origin to the point $(0;N)$ behaves like
$$
R_nsim ccdot N^-2amu^N,
$$

where $a=5/8$ and $mu$ is a lattice-dependent quantity known as the connective constant (it is known to be $sqrt2+sqrt2$ for hexagonal lattice and only numerically known for other lattices). Moreover, they conjectured that the measure should have a conformally covariant scaling limit, meaning that if $Omega$ is another simply-connected domain and $x,yin partial Omega$, with the boundary being nice (say, horizontal or vertical straight lines) near $x,y$, then the number of SAW from $a$ to $b$ in a $delta$-mesh lattice approximation to $Omega$ should behave like
$$
R^Omega_n sim c |varphi'(x)|^a|varphi'(y)|^adelta^2amu^delta^-1,
$$

where $varphi$ is a conformal map from $Omega$ to the rectangle $(-1,1)times(0,1)$ that maps $x$ to the origin and $y$ to $i$. (We can also fix $|varphi'(x)|=1$, and then $|varphi'(y)|$ is proportional to the normal derivative of the Poisson kernel with a pole at $x$.) A straightforward extension of their conjecture would be that the number of SAW from the origin to $(N,b)$, with a given $b$, behaves like
$$
P'_nsim c(theta)^acdot N^-3amu^N,
$$

where $c(theta)$ is proportional to the normal derivative at $(1;theta)$ of the Poisson kernel in $(0;1)^2$ with a "pole" at the origin, and we are in the regime $b/Nto thetain (0,1)$. (If $bequiv N$ or $bequiv 0$, the power law exponent should change to $-4a$.)



No-one doubts the conformal covariance ansatz of Lawler, Schramm and Werner; but it is wide open to prove it rigorously. The best you can do rigorously is, probably,
$$
log P'_nsim nlogmu.
$$

I am not sure this is explicitly done anywhere, but the general idea is that all 'reasonable' models of planar SAW should obey this property with the same $mu$; for instance, here it is done for arbitrary paths, bridges, and closed paths.






share|cite|improve this answer






















  • Great answer, thanks! Do you think you could say a little more explicitly what $c(b)$ is? Which Poisson kernel? I'm also a little confused by the notation: $P_n'(b)$ refers to the number of SAW from $(0,0)$ to $(n,b)$?
    – Lorenzo
    1 hour ago











  • So the conjecture is that probability distribution is going to be proportional to $c(theta)^a$ (in the regime $theta in (0,1)$)? It would be helpful for me if you could write the conjectured probability distribution a little more explicitly, since I'm not too familiar with this stuff. I will try to read the papers you suggest, thank you!
    – Lorenzo
    1 hour ago










  • yes, the notation was perhaps unclear, I edited the text. The Poisson kernel refers to the unique non-negative harmonic function in the domain that extends continuously to all points of the boundary except for $x$; the normalization may be whatever it is - the asymptotics includes some unknown, lattice-dependent multiplicative constant anyways. For the square, I guess, you can write the Poisson kernel explicitly using elliptic functions.
    – Kostya_I
    22 mins ago

















up vote
2
down vote













The problem you are interested in is related to enumerating self-avoiding walks in a graph (one can consider self-avoiding polygons, which are closed SAWs, also) and is a difficult problem computationally.



For an infinite graph, the asymptotic behavior of the number of length $n$ self-avoiding walks (or self-avoiding polygons) is denoted $c_n$ ($p_n$ resp.) and depends on the structure of one's graph namely on the connective constant $mu=limlimits_nin mathbbN c_n^frac1n=limlimits_nin 2mathbbN p_n^frac1n$.
According to Madras' paper here an upper bound for $mathbbZ^2$ is given by $p_n leq Cn^−1/2mu^n$ with a better estimate anticipated (see @Kostya_I's answer).



Edit: @Kostya_I's comments on conformal mappings supercedes most of the information here. The best estimate that was found after looking through a few papers improves Madras' $p_n leq Cn^−1/2mu^n$ mentioned above to $p_n ≤ n^−3/2+o(1)mu^n$ by A. Hammond here (for a set of even $n$ of full density).






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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    6
    down vote



    accepted










    Lawler, Schramm and Werner conjectured that the number $R_n$ of self-avoiding walks in the rectangle $[-N;N]times[0;N]$ connecting the origin to the point $(0;N)$ behaves like
    $$
    R_nsim ccdot N^-2amu^N,
    $$

    where $a=5/8$ and $mu$ is a lattice-dependent quantity known as the connective constant (it is known to be $sqrt2+sqrt2$ for hexagonal lattice and only numerically known for other lattices). Moreover, they conjectured that the measure should have a conformally covariant scaling limit, meaning that if $Omega$ is another simply-connected domain and $x,yin partial Omega$, with the boundary being nice (say, horizontal or vertical straight lines) near $x,y$, then the number of SAW from $a$ to $b$ in a $delta$-mesh lattice approximation to $Omega$ should behave like
    $$
    R^Omega_n sim c |varphi'(x)|^a|varphi'(y)|^adelta^2amu^delta^-1,
    $$

    where $varphi$ is a conformal map from $Omega$ to the rectangle $(-1,1)times(0,1)$ that maps $x$ to the origin and $y$ to $i$. (We can also fix $|varphi'(x)|=1$, and then $|varphi'(y)|$ is proportional to the normal derivative of the Poisson kernel with a pole at $x$.) A straightforward extension of their conjecture would be that the number of SAW from the origin to $(N,b)$, with a given $b$, behaves like
    $$
    P'_nsim c(theta)^acdot N^-3amu^N,
    $$

    where $c(theta)$ is proportional to the normal derivative at $(1;theta)$ of the Poisson kernel in $(0;1)^2$ with a "pole" at the origin, and we are in the regime $b/Nto thetain (0,1)$. (If $bequiv N$ or $bequiv 0$, the power law exponent should change to $-4a$.)



    No-one doubts the conformal covariance ansatz of Lawler, Schramm and Werner; but it is wide open to prove it rigorously. The best you can do rigorously is, probably,
    $$
    log P'_nsim nlogmu.
    $$

    I am not sure this is explicitly done anywhere, but the general idea is that all 'reasonable' models of planar SAW should obey this property with the same $mu$; for instance, here it is done for arbitrary paths, bridges, and closed paths.






    share|cite|improve this answer






















    • Great answer, thanks! Do you think you could say a little more explicitly what $c(b)$ is? Which Poisson kernel? I'm also a little confused by the notation: $P_n'(b)$ refers to the number of SAW from $(0,0)$ to $(n,b)$?
      – Lorenzo
      1 hour ago











    • So the conjecture is that probability distribution is going to be proportional to $c(theta)^a$ (in the regime $theta in (0,1)$)? It would be helpful for me if you could write the conjectured probability distribution a little more explicitly, since I'm not too familiar with this stuff. I will try to read the papers you suggest, thank you!
      – Lorenzo
      1 hour ago










    • yes, the notation was perhaps unclear, I edited the text. The Poisson kernel refers to the unique non-negative harmonic function in the domain that extends continuously to all points of the boundary except for $x$; the normalization may be whatever it is - the asymptotics includes some unknown, lattice-dependent multiplicative constant anyways. For the square, I guess, you can write the Poisson kernel explicitly using elliptic functions.
      – Kostya_I
      22 mins ago














    up vote
    6
    down vote



    accepted










    Lawler, Schramm and Werner conjectured that the number $R_n$ of self-avoiding walks in the rectangle $[-N;N]times[0;N]$ connecting the origin to the point $(0;N)$ behaves like
    $$
    R_nsim ccdot N^-2amu^N,
    $$

    where $a=5/8$ and $mu$ is a lattice-dependent quantity known as the connective constant (it is known to be $sqrt2+sqrt2$ for hexagonal lattice and only numerically known for other lattices). Moreover, they conjectured that the measure should have a conformally covariant scaling limit, meaning that if $Omega$ is another simply-connected domain and $x,yin partial Omega$, with the boundary being nice (say, horizontal or vertical straight lines) near $x,y$, then the number of SAW from $a$ to $b$ in a $delta$-mesh lattice approximation to $Omega$ should behave like
    $$
    R^Omega_n sim c |varphi'(x)|^a|varphi'(y)|^adelta^2amu^delta^-1,
    $$

    where $varphi$ is a conformal map from $Omega$ to the rectangle $(-1,1)times(0,1)$ that maps $x$ to the origin and $y$ to $i$. (We can also fix $|varphi'(x)|=1$, and then $|varphi'(y)|$ is proportional to the normal derivative of the Poisson kernel with a pole at $x$.) A straightforward extension of their conjecture would be that the number of SAW from the origin to $(N,b)$, with a given $b$, behaves like
    $$
    P'_nsim c(theta)^acdot N^-3amu^N,
    $$

    where $c(theta)$ is proportional to the normal derivative at $(1;theta)$ of the Poisson kernel in $(0;1)^2$ with a "pole" at the origin, and we are in the regime $b/Nto thetain (0,1)$. (If $bequiv N$ or $bequiv 0$, the power law exponent should change to $-4a$.)



    No-one doubts the conformal covariance ansatz of Lawler, Schramm and Werner; but it is wide open to prove it rigorously. The best you can do rigorously is, probably,
    $$
    log P'_nsim nlogmu.
    $$

    I am not sure this is explicitly done anywhere, but the general idea is that all 'reasonable' models of planar SAW should obey this property with the same $mu$; for instance, here it is done for arbitrary paths, bridges, and closed paths.






    share|cite|improve this answer






















    • Great answer, thanks! Do you think you could say a little more explicitly what $c(b)$ is? Which Poisson kernel? I'm also a little confused by the notation: $P_n'(b)$ refers to the number of SAW from $(0,0)$ to $(n,b)$?
      – Lorenzo
      1 hour ago











    • So the conjecture is that probability distribution is going to be proportional to $c(theta)^a$ (in the regime $theta in (0,1)$)? It would be helpful for me if you could write the conjectured probability distribution a little more explicitly, since I'm not too familiar with this stuff. I will try to read the papers you suggest, thank you!
      – Lorenzo
      1 hour ago










    • yes, the notation was perhaps unclear, I edited the text. The Poisson kernel refers to the unique non-negative harmonic function in the domain that extends continuously to all points of the boundary except for $x$; the normalization may be whatever it is - the asymptotics includes some unknown, lattice-dependent multiplicative constant anyways. For the square, I guess, you can write the Poisson kernel explicitly using elliptic functions.
      – Kostya_I
      22 mins ago












    up vote
    6
    down vote



    accepted







    up vote
    6
    down vote



    accepted






    Lawler, Schramm and Werner conjectured that the number $R_n$ of self-avoiding walks in the rectangle $[-N;N]times[0;N]$ connecting the origin to the point $(0;N)$ behaves like
    $$
    R_nsim ccdot N^-2amu^N,
    $$

    where $a=5/8$ and $mu$ is a lattice-dependent quantity known as the connective constant (it is known to be $sqrt2+sqrt2$ for hexagonal lattice and only numerically known for other lattices). Moreover, they conjectured that the measure should have a conformally covariant scaling limit, meaning that if $Omega$ is another simply-connected domain and $x,yin partial Omega$, with the boundary being nice (say, horizontal or vertical straight lines) near $x,y$, then the number of SAW from $a$ to $b$ in a $delta$-mesh lattice approximation to $Omega$ should behave like
    $$
    R^Omega_n sim c |varphi'(x)|^a|varphi'(y)|^adelta^2amu^delta^-1,
    $$

    where $varphi$ is a conformal map from $Omega$ to the rectangle $(-1,1)times(0,1)$ that maps $x$ to the origin and $y$ to $i$. (We can also fix $|varphi'(x)|=1$, and then $|varphi'(y)|$ is proportional to the normal derivative of the Poisson kernel with a pole at $x$.) A straightforward extension of their conjecture would be that the number of SAW from the origin to $(N,b)$, with a given $b$, behaves like
    $$
    P'_nsim c(theta)^acdot N^-3amu^N,
    $$

    where $c(theta)$ is proportional to the normal derivative at $(1;theta)$ of the Poisson kernel in $(0;1)^2$ with a "pole" at the origin, and we are in the regime $b/Nto thetain (0,1)$. (If $bequiv N$ or $bequiv 0$, the power law exponent should change to $-4a$.)



    No-one doubts the conformal covariance ansatz of Lawler, Schramm and Werner; but it is wide open to prove it rigorously. The best you can do rigorously is, probably,
    $$
    log P'_nsim nlogmu.
    $$

    I am not sure this is explicitly done anywhere, but the general idea is that all 'reasonable' models of planar SAW should obey this property with the same $mu$; for instance, here it is done for arbitrary paths, bridges, and closed paths.






    share|cite|improve this answer














    Lawler, Schramm and Werner conjectured that the number $R_n$ of self-avoiding walks in the rectangle $[-N;N]times[0;N]$ connecting the origin to the point $(0;N)$ behaves like
    $$
    R_nsim ccdot N^-2amu^N,
    $$

    where $a=5/8$ and $mu$ is a lattice-dependent quantity known as the connective constant (it is known to be $sqrt2+sqrt2$ for hexagonal lattice and only numerically known for other lattices). Moreover, they conjectured that the measure should have a conformally covariant scaling limit, meaning that if $Omega$ is another simply-connected domain and $x,yin partial Omega$, with the boundary being nice (say, horizontal or vertical straight lines) near $x,y$, then the number of SAW from $a$ to $b$ in a $delta$-mesh lattice approximation to $Omega$ should behave like
    $$
    R^Omega_n sim c |varphi'(x)|^a|varphi'(y)|^adelta^2amu^delta^-1,
    $$

    where $varphi$ is a conformal map from $Omega$ to the rectangle $(-1,1)times(0,1)$ that maps $x$ to the origin and $y$ to $i$. (We can also fix $|varphi'(x)|=1$, and then $|varphi'(y)|$ is proportional to the normal derivative of the Poisson kernel with a pole at $x$.) A straightforward extension of their conjecture would be that the number of SAW from the origin to $(N,b)$, with a given $b$, behaves like
    $$
    P'_nsim c(theta)^acdot N^-3amu^N,
    $$

    where $c(theta)$ is proportional to the normal derivative at $(1;theta)$ of the Poisson kernel in $(0;1)^2$ with a "pole" at the origin, and we are in the regime $b/Nto thetain (0,1)$. (If $bequiv N$ or $bequiv 0$, the power law exponent should change to $-4a$.)



    No-one doubts the conformal covariance ansatz of Lawler, Schramm and Werner; but it is wide open to prove it rigorously. The best you can do rigorously is, probably,
    $$
    log P'_nsim nlogmu.
    $$

    I am not sure this is explicitly done anywhere, but the general idea is that all 'reasonable' models of planar SAW should obey this property with the same $mu$; for instance, here it is done for arbitrary paths, bridges, and closed paths.







    share|cite|improve this answer














    share|cite|improve this answer



    share|cite|improve this answer








    edited 37 mins ago

























    answered 2 hours ago









    Kostya_I

    2,5331225




    2,5331225











    • Great answer, thanks! Do you think you could say a little more explicitly what $c(b)$ is? Which Poisson kernel? I'm also a little confused by the notation: $P_n'(b)$ refers to the number of SAW from $(0,0)$ to $(n,b)$?
      – Lorenzo
      1 hour ago











    • So the conjecture is that probability distribution is going to be proportional to $c(theta)^a$ (in the regime $theta in (0,1)$)? It would be helpful for me if you could write the conjectured probability distribution a little more explicitly, since I'm not too familiar with this stuff. I will try to read the papers you suggest, thank you!
      – Lorenzo
      1 hour ago










    • yes, the notation was perhaps unclear, I edited the text. The Poisson kernel refers to the unique non-negative harmonic function in the domain that extends continuously to all points of the boundary except for $x$; the normalization may be whatever it is - the asymptotics includes some unknown, lattice-dependent multiplicative constant anyways. For the square, I guess, you can write the Poisson kernel explicitly using elliptic functions.
      – Kostya_I
      22 mins ago
















    • Great answer, thanks! Do you think you could say a little more explicitly what $c(b)$ is? Which Poisson kernel? I'm also a little confused by the notation: $P_n'(b)$ refers to the number of SAW from $(0,0)$ to $(n,b)$?
      – Lorenzo
      1 hour ago











    • So the conjecture is that probability distribution is going to be proportional to $c(theta)^a$ (in the regime $theta in (0,1)$)? It would be helpful for me if you could write the conjectured probability distribution a little more explicitly, since I'm not too familiar with this stuff. I will try to read the papers you suggest, thank you!
      – Lorenzo
      1 hour ago










    • yes, the notation was perhaps unclear, I edited the text. The Poisson kernel refers to the unique non-negative harmonic function in the domain that extends continuously to all points of the boundary except for $x$; the normalization may be whatever it is - the asymptotics includes some unknown, lattice-dependent multiplicative constant anyways. For the square, I guess, you can write the Poisson kernel explicitly using elliptic functions.
      – Kostya_I
      22 mins ago















    Great answer, thanks! Do you think you could say a little more explicitly what $c(b)$ is? Which Poisson kernel? I'm also a little confused by the notation: $P_n'(b)$ refers to the number of SAW from $(0,0)$ to $(n,b)$?
    – Lorenzo
    1 hour ago





    Great answer, thanks! Do you think you could say a little more explicitly what $c(b)$ is? Which Poisson kernel? I'm also a little confused by the notation: $P_n'(b)$ refers to the number of SAW from $(0,0)$ to $(n,b)$?
    – Lorenzo
    1 hour ago













    So the conjecture is that probability distribution is going to be proportional to $c(theta)^a$ (in the regime $theta in (0,1)$)? It would be helpful for me if you could write the conjectured probability distribution a little more explicitly, since I'm not too familiar with this stuff. I will try to read the papers you suggest, thank you!
    – Lorenzo
    1 hour ago




    So the conjecture is that probability distribution is going to be proportional to $c(theta)^a$ (in the regime $theta in (0,1)$)? It would be helpful for me if you could write the conjectured probability distribution a little more explicitly, since I'm not too familiar with this stuff. I will try to read the papers you suggest, thank you!
    – Lorenzo
    1 hour ago












    yes, the notation was perhaps unclear, I edited the text. The Poisson kernel refers to the unique non-negative harmonic function in the domain that extends continuously to all points of the boundary except for $x$; the normalization may be whatever it is - the asymptotics includes some unknown, lattice-dependent multiplicative constant anyways. For the square, I guess, you can write the Poisson kernel explicitly using elliptic functions.
    – Kostya_I
    22 mins ago




    yes, the notation was perhaps unclear, I edited the text. The Poisson kernel refers to the unique non-negative harmonic function in the domain that extends continuously to all points of the boundary except for $x$; the normalization may be whatever it is - the asymptotics includes some unknown, lattice-dependent multiplicative constant anyways. For the square, I guess, you can write the Poisson kernel explicitly using elliptic functions.
    – Kostya_I
    22 mins ago










    up vote
    2
    down vote













    The problem you are interested in is related to enumerating self-avoiding walks in a graph (one can consider self-avoiding polygons, which are closed SAWs, also) and is a difficult problem computationally.



    For an infinite graph, the asymptotic behavior of the number of length $n$ self-avoiding walks (or self-avoiding polygons) is denoted $c_n$ ($p_n$ resp.) and depends on the structure of one's graph namely on the connective constant $mu=limlimits_nin mathbbN c_n^frac1n=limlimits_nin 2mathbbN p_n^frac1n$.
    According to Madras' paper here an upper bound for $mathbbZ^2$ is given by $p_n leq Cn^−1/2mu^n$ with a better estimate anticipated (see @Kostya_I's answer).



    Edit: @Kostya_I's comments on conformal mappings supercedes most of the information here. The best estimate that was found after looking through a few papers improves Madras' $p_n leq Cn^−1/2mu^n$ mentioned above to $p_n ≤ n^−3/2+o(1)mu^n$ by A. Hammond here (for a set of even $n$ of full density).






    share|cite|improve this answer


























      up vote
      2
      down vote













      The problem you are interested in is related to enumerating self-avoiding walks in a graph (one can consider self-avoiding polygons, which are closed SAWs, also) and is a difficult problem computationally.



      For an infinite graph, the asymptotic behavior of the number of length $n$ self-avoiding walks (or self-avoiding polygons) is denoted $c_n$ ($p_n$ resp.) and depends on the structure of one's graph namely on the connective constant $mu=limlimits_nin mathbbN c_n^frac1n=limlimits_nin 2mathbbN p_n^frac1n$.
      According to Madras' paper here an upper bound for $mathbbZ^2$ is given by $p_n leq Cn^−1/2mu^n$ with a better estimate anticipated (see @Kostya_I's answer).



      Edit: @Kostya_I's comments on conformal mappings supercedes most of the information here. The best estimate that was found after looking through a few papers improves Madras' $p_n leq Cn^−1/2mu^n$ mentioned above to $p_n ≤ n^−3/2+o(1)mu^n$ by A. Hammond here (for a set of even $n$ of full density).






      share|cite|improve this answer
























        up vote
        2
        down vote










        up vote
        2
        down vote









        The problem you are interested in is related to enumerating self-avoiding walks in a graph (one can consider self-avoiding polygons, which are closed SAWs, also) and is a difficult problem computationally.



        For an infinite graph, the asymptotic behavior of the number of length $n$ self-avoiding walks (or self-avoiding polygons) is denoted $c_n$ ($p_n$ resp.) and depends on the structure of one's graph namely on the connective constant $mu=limlimits_nin mathbbN c_n^frac1n=limlimits_nin 2mathbbN p_n^frac1n$.
        According to Madras' paper here an upper bound for $mathbbZ^2$ is given by $p_n leq Cn^−1/2mu^n$ with a better estimate anticipated (see @Kostya_I's answer).



        Edit: @Kostya_I's comments on conformal mappings supercedes most of the information here. The best estimate that was found after looking through a few papers improves Madras' $p_n leq Cn^−1/2mu^n$ mentioned above to $p_n ≤ n^−3/2+o(1)mu^n$ by A. Hammond here (for a set of even $n$ of full density).






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        The problem you are interested in is related to enumerating self-avoiding walks in a graph (one can consider self-avoiding polygons, which are closed SAWs, also) and is a difficult problem computationally.



        For an infinite graph, the asymptotic behavior of the number of length $n$ self-avoiding walks (or self-avoiding polygons) is denoted $c_n$ ($p_n$ resp.) and depends on the structure of one's graph namely on the connective constant $mu=limlimits_nin mathbbN c_n^frac1n=limlimits_nin 2mathbbN p_n^frac1n$.
        According to Madras' paper here an upper bound for $mathbbZ^2$ is given by $p_n leq Cn^−1/2mu^n$ with a better estimate anticipated (see @Kostya_I's answer).



        Edit: @Kostya_I's comments on conformal mappings supercedes most of the information here. The best estimate that was found after looking through a few papers improves Madras' $p_n leq Cn^−1/2mu^n$ mentioned above to $p_n ≤ n^−3/2+o(1)mu^n$ by A. Hammond here (for a set of even $n$ of full density).







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 1 hour ago

























        answered 3 hours ago









        Josiah Park

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