Min value of a trigonometric expression
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What is the value of $sin(x)$ for the maximum value of $(5+3sin(x))^2 (7-3sin(x))^3$.
calculus optimization
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up vote
1
down vote
favorite
What is the value of $sin(x)$ for the maximum value of $(5+3sin(x))^2 (7-3sin(x))^3$.
calculus optimization
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
What is the value of $sin(x)$ for the maximum value of $(5+3sin(x))^2 (7-3sin(x))^3$.
calculus optimization
What is the value of $sin(x)$ for the maximum value of $(5+3sin(x))^2 (7-3sin(x))^3$.
calculus optimization
calculus optimization
edited 1 hour ago
gt6989b
31.5k22349
31.5k22349
asked 1 hour ago
Hik Aubergine
185
185
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add a comment |Â
3 Answers
3
active
oldest
votes
up vote
4
down vote
accepted
Hint:
AM GM inequality
$$dfrac2cdot3(5+3sin x)+3cdot2(7-3sin x)2+3gesqrt[5]3^2(5+3sin x)^22^3(7-3sin x)^3$$
The equality occurs if $3(5+3sin x)=2(7-3sin x)$
Thanks a lot sir, thats what im looking for
â Hik Aubergine
1 hour ago
add a comment |Â
up vote
1
down vote
AM-GM inequality is the neat approach, but if you can't figure it out algebra also helps...
let $z=sin(x)$, $f(z)=g(z)^2h(z)^3$
$$
f' = 2gg'h^3 + 3gh^2h' = gh^2(2g'h+3hh')
$$
since $-1 le z le 1$, $g$ and $h$ do not have zeros in this region. Therefore $2g'h=-3hh'$, which will give you the same equation to solve for $z$.
add a comment |Â
up vote
0
down vote
HINT
Let $z = sin x$. You are asking for what value of $z$ does the function $$f(z) = (5+3z)^2 (7-3z)^3$$ attains its maximum. Taking a derivative would likely help.
UPDATE
As mentioned in the comments below, you are only optimizing over $-1 le z le 1$.
1
Worth mentioning that $x$ is probably meant to be real, so $z$ has to be between $-1$ and $1$.
â SmileyCraft
1 hour ago
add a comment |Â
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
Hint:
AM GM inequality
$$dfrac2cdot3(5+3sin x)+3cdot2(7-3sin x)2+3gesqrt[5]3^2(5+3sin x)^22^3(7-3sin x)^3$$
The equality occurs if $3(5+3sin x)=2(7-3sin x)$
Thanks a lot sir, thats what im looking for
â Hik Aubergine
1 hour ago
add a comment |Â
up vote
4
down vote
accepted
Hint:
AM GM inequality
$$dfrac2cdot3(5+3sin x)+3cdot2(7-3sin x)2+3gesqrt[5]3^2(5+3sin x)^22^3(7-3sin x)^3$$
The equality occurs if $3(5+3sin x)=2(7-3sin x)$
Thanks a lot sir, thats what im looking for
â Hik Aubergine
1 hour ago
add a comment |Â
up vote
4
down vote
accepted
up vote
4
down vote
accepted
Hint:
AM GM inequality
$$dfrac2cdot3(5+3sin x)+3cdot2(7-3sin x)2+3gesqrt[5]3^2(5+3sin x)^22^3(7-3sin x)^3$$
The equality occurs if $3(5+3sin x)=2(7-3sin x)$
Hint:
AM GM inequality
$$dfrac2cdot3(5+3sin x)+3cdot2(7-3sin x)2+3gesqrt[5]3^2(5+3sin x)^22^3(7-3sin x)^3$$
The equality occurs if $3(5+3sin x)=2(7-3sin x)$
answered 1 hour ago
lab bhattacharjee
217k14153267
217k14153267
Thanks a lot sir, thats what im looking for
â Hik Aubergine
1 hour ago
add a comment |Â
Thanks a lot sir, thats what im looking for
â Hik Aubergine
1 hour ago
Thanks a lot sir, thats what im looking for
â Hik Aubergine
1 hour ago
Thanks a lot sir, thats what im looking for
â Hik Aubergine
1 hour ago
add a comment |Â
up vote
1
down vote
AM-GM inequality is the neat approach, but if you can't figure it out algebra also helps...
let $z=sin(x)$, $f(z)=g(z)^2h(z)^3$
$$
f' = 2gg'h^3 + 3gh^2h' = gh^2(2g'h+3hh')
$$
since $-1 le z le 1$, $g$ and $h$ do not have zeros in this region. Therefore $2g'h=-3hh'$, which will give you the same equation to solve for $z$.
add a comment |Â
up vote
1
down vote
AM-GM inequality is the neat approach, but if you can't figure it out algebra also helps...
let $z=sin(x)$, $f(z)=g(z)^2h(z)^3$
$$
f' = 2gg'h^3 + 3gh^2h' = gh^2(2g'h+3hh')
$$
since $-1 le z le 1$, $g$ and $h$ do not have zeros in this region. Therefore $2g'h=-3hh'$, which will give you the same equation to solve for $z$.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
AM-GM inequality is the neat approach, but if you can't figure it out algebra also helps...
let $z=sin(x)$, $f(z)=g(z)^2h(z)^3$
$$
f' = 2gg'h^3 + 3gh^2h' = gh^2(2g'h+3hh')
$$
since $-1 le z le 1$, $g$ and $h$ do not have zeros in this region. Therefore $2g'h=-3hh'$, which will give you the same equation to solve for $z$.
AM-GM inequality is the neat approach, but if you can't figure it out algebra also helps...
let $z=sin(x)$, $f(z)=g(z)^2h(z)^3$
$$
f' = 2gg'h^3 + 3gh^2h' = gh^2(2g'h+3hh')
$$
since $-1 le z le 1$, $g$ and $h$ do not have zeros in this region. Therefore $2g'h=-3hh'$, which will give you the same equation to solve for $z$.
answered 1 hour ago
karakfa
1,813811
1,813811
add a comment |Â
add a comment |Â
up vote
0
down vote
HINT
Let $z = sin x$. You are asking for what value of $z$ does the function $$f(z) = (5+3z)^2 (7-3z)^3$$ attains its maximum. Taking a derivative would likely help.
UPDATE
As mentioned in the comments below, you are only optimizing over $-1 le z le 1$.
1
Worth mentioning that $x$ is probably meant to be real, so $z$ has to be between $-1$ and $1$.
â SmileyCraft
1 hour ago
add a comment |Â
up vote
0
down vote
HINT
Let $z = sin x$. You are asking for what value of $z$ does the function $$f(z) = (5+3z)^2 (7-3z)^3$$ attains its maximum. Taking a derivative would likely help.
UPDATE
As mentioned in the comments below, you are only optimizing over $-1 le z le 1$.
1
Worth mentioning that $x$ is probably meant to be real, so $z$ has to be between $-1$ and $1$.
â SmileyCraft
1 hour ago
add a comment |Â
up vote
0
down vote
up vote
0
down vote
HINT
Let $z = sin x$. You are asking for what value of $z$ does the function $$f(z) = (5+3z)^2 (7-3z)^3$$ attains its maximum. Taking a derivative would likely help.
UPDATE
As mentioned in the comments below, you are only optimizing over $-1 le z le 1$.
HINT
Let $z = sin x$. You are asking for what value of $z$ does the function $$f(z) = (5+3z)^2 (7-3z)^3$$ attains its maximum. Taking a derivative would likely help.
UPDATE
As mentioned in the comments below, you are only optimizing over $-1 le z le 1$.
edited 44 mins ago
answered 1 hour ago
gt6989b
31.5k22349
31.5k22349
1
Worth mentioning that $x$ is probably meant to be real, so $z$ has to be between $-1$ and $1$.
â SmileyCraft
1 hour ago
add a comment |Â
1
Worth mentioning that $x$ is probably meant to be real, so $z$ has to be between $-1$ and $1$.
â SmileyCraft
1 hour ago
1
1
Worth mentioning that $x$ is probably meant to be real, so $z$ has to be between $-1$ and $1$.
â SmileyCraft
1 hour ago
Worth mentioning that $x$ is probably meant to be real, so $z$ has to be between $-1$ and $1$.
â SmileyCraft
1 hour ago
add a comment |Â
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