How can I typeset a formula or result like this one?

Clash Royale CLAN TAG#URR8PPP
up vote
5
down vote
favorite

I want to make a result like this one, but I have no clue. Please give me your suggest. Thank you a lot for your help.
P/s: Please tell me how to typeset equations in the same way like this... Sorry my bad English cannot give you all what I'm asking for.
For specific:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD. [
beginbcases
m = A \
m < -5
endbcases
] \
endtabular
enddocument

The final picture is what I expected for
math-mode
add a comment |Â
up vote
5
down vote
favorite

I want to make a result like this one, but I have no clue. Please give me your suggest. Thank you a lot for your help.
P/s: Please tell me how to typeset equations in the same way like this... Sorry my bad English cannot give you all what I'm asking for.
For specific:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD. [
beginbcases
m = A \
m < -5
endbcases
] \
endtabular
enddocument

The final picture is what I expected for
math-mode
You can use$beginbcases...endbcases$instead of[...],
â egreg
Sep 19 at 9:46
I added something based on your test case
â egreg
Sep 19 at 9:52
please tell us, what you expect from your code example? it works fine, but result is somehow unusual (to my taste)
â Zarko
Sep 19 at 9:54
add a comment |Â
up vote
5
down vote
favorite
up vote
5
down vote
favorite

I want to make a result like this one, but I have no clue. Please give me your suggest. Thank you a lot for your help.
P/s: Please tell me how to typeset equations in the same way like this... Sorry my bad English cannot give you all what I'm asking for.
For specific:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD. [
beginbcases
m = A \
m < -5
endbcases
] \
endtabular
enddocument

The final picture is what I expected for
math-mode

I want to make a result like this one, but I have no clue. Please give me your suggest. Thank you a lot for your help.
P/s: Please tell me how to typeset equations in the same way like this... Sorry my bad English cannot give you all what I'm asking for.
For specific:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD. [
beginbcases
m = A \
m < -5
endbcases
] \
endtabular
enddocument

The final picture is what I expected for
math-mode
math-mode
edited Sep 19 at 9:59
asked Sep 19 at 9:10
Hoà ng Duy Anh
434
434
You can use$beginbcases...endbcases$instead of[...],
â egreg
Sep 19 at 9:46
I added something based on your test case
â egreg
Sep 19 at 9:52
please tell us, what you expect from your code example? it works fine, but result is somehow unusual (to my taste)
â Zarko
Sep 19 at 9:54
add a comment |Â
You can use$beginbcases...endbcases$instead of[...],
â egreg
Sep 19 at 9:46
I added something based on your test case
â egreg
Sep 19 at 9:52
please tell us, what you expect from your code example? it works fine, but result is somehow unusual (to my taste)
â Zarko
Sep 19 at 9:54
You can use
$beginbcases...endbcases$ instead of [...],â egreg
Sep 19 at 9:46
You can use
$beginbcases...endbcases$ instead of [...],â egreg
Sep 19 at 9:46
I added something based on your test case
â egreg
Sep 19 at 9:52
I added something based on your test case
â egreg
Sep 19 at 9:52
please tell us, what you expect from your code example? it works fine, but result is somehow unusual (to my taste)
â Zarko
Sep 19 at 9:54
please tell us, what you expect from your code example? it works fine, but result is somehow unusual (to my taste)
â Zarko
Sep 19 at 9:54
add a comment |Â
3 Answers
3
active
oldest
votes
up vote
11
down vote
The newcases macro of mathtools ought to have an easier interface; with the current one you can still define a bcases environment (b for âÂÂbracketâÂÂ).
documentclassarticle
usepackagemathtools
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
[
beginbcases
m = A \
m < -5
endbcases
]
enddocument

You should also consider the more standard cases environment (it uses a brace).
Your test case can be improved:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$beginbcases
m = A \
m < -5
endbcases$
endtabular
enddocument
Note textcolor<color><text> instead of color<color><text>; the removal of useless \ tokens; the p column type instead of m; $...$ around bcases instead of [...].

add a comment |Â
up vote
4
down vote
I use an aligned stack here only to emphasize that if the left hand side of the two rows had different widths (here they do not), the aligned forms would be the most appropriate.
documentclassarticle
usepackagetabstackengine
stackMath
begindocument
[
left[alignCenterstackm=&4\m<&-5right.
]
enddocument

In terms of the OP's test case, I give two different vertical alignment options, in the form of "D" and "E".
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagetabstackengine
stackMath
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD.
$left[alignCenterstackm =& A \m <& -5right.$ \
colorredtextbfE.
belowbaseline[-htstrutbox]left[alignCenterstackm =& A \m <& -5right.
&
endtabular
enddocument

It doesn't work much in my test question :( Check the code of my test question please.
â Hoà ng Duy Anh
Sep 19 at 9:51
@Hoà ngDuyAnh Yes it does. Please see my edit.
â Steven B. Segletes
Sep 19 at 9:59
Oh I see, that's exactly what I'm trying to text out! Thank you alot
â Hoà ng Duy Anh
Sep 19 at 10:00
add a comment |Â
up vote
3
down vote

a simple way which cross my mind :-) :
documentclassarticle
begindocument
[
left[
beginarrayl
m=4 \
m<-5
endarray
right.
]
enddocument
edit:
considering your mwe, with my above proposition you will obtain:

documentclass[a4paper , 12pt]article
% usepackagecolor % it is loaded by xcolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgfplots%pgf,tikz
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$left[beginarrayc
m = A \
m < -5
endarrayright.$
endtabular
enddocument
documentclass[t]beamer
setbeamertemplatenavigation symbols
setbeamertemplatefootline
setbeamertemplateheadline
usepackage[edges]forest
Oh thank you a lots, That's help a lot but there is some struggle when I put it in the answers of my test:
â Hoà ng Duy Anh
Sep 19 at 9:15
2
@Hoà ngDuyAnh - Please be more specific about the "struggle when I put in my answers" consists of.
â Mico
Sep 19 at 9:40
@Hoà ngDuyAnh, you not provide any code (as small complete document which we can copy and test), so we haven't any idea about your document. anyway, the proposed solution is so elementary that it should work in any document.
â Zarko
Sep 19 at 9:40
Let me add my code into the question
â Hoà ng Duy Anh
Sep 19 at 9:40
add a comment |Â
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
11
down vote
The newcases macro of mathtools ought to have an easier interface; with the current one you can still define a bcases environment (b for âÂÂbracketâÂÂ).
documentclassarticle
usepackagemathtools
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
[
beginbcases
m = A \
m < -5
endbcases
]
enddocument

You should also consider the more standard cases environment (it uses a brace).
Your test case can be improved:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$beginbcases
m = A \
m < -5
endbcases$
endtabular
enddocument
Note textcolor<color><text> instead of color<color><text>; the removal of useless \ tokens; the p column type instead of m; $...$ around bcases instead of [...].

add a comment |Â
up vote
11
down vote
The newcases macro of mathtools ought to have an easier interface; with the current one you can still define a bcases environment (b for âÂÂbracketâÂÂ).
documentclassarticle
usepackagemathtools
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
[
beginbcases
m = A \
m < -5
endbcases
]
enddocument

You should also consider the more standard cases environment (it uses a brace).
Your test case can be improved:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$beginbcases
m = A \
m < -5
endbcases$
endtabular
enddocument
Note textcolor<color><text> instead of color<color><text>; the removal of useless \ tokens; the p column type instead of m; $...$ around bcases instead of [...].

add a comment |Â
up vote
11
down vote
up vote
11
down vote
The newcases macro of mathtools ought to have an easier interface; with the current one you can still define a bcases environment (b for âÂÂbracketâÂÂ).
documentclassarticle
usepackagemathtools
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
[
beginbcases
m = A \
m < -5
endbcases
]
enddocument

You should also consider the more standard cases environment (it uses a brace).
Your test case can be improved:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$beginbcases
m = A \
m < -5
endbcases$
endtabular
enddocument
Note textcolor<color><text> instead of color<color><text>; the removal of useless \ tokens; the p column type instead of m; $...$ around bcases instead of [...].

The newcases macro of mathtools ought to have an easier interface; with the current one you can still define a bcases environment (b for âÂÂbracketâÂÂ).
documentclassarticle
usepackagemathtools
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
[
beginbcases
m = A \
m < -5
endbcases
]
enddocument

You should also consider the more standard cases environment (it uses a brace).
Your test case can be improved:
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
makeatletter
newcasesbcases
quad
$m@th##$hfil
$m@th##$hfil
lbrack
.
makeatother
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$beginbcases
m = A \
m < -5
endbcases$
endtabular
enddocument
Note textcolor<color><text> instead of color<color><text>; the removal of useless \ tokens; the p column type instead of m; $...$ around bcases instead of [...].

edited Sep 19 at 9:52
answered Sep 19 at 9:36
egreg
686k8418283078
686k8418283078
add a comment |Â
add a comment |Â
up vote
4
down vote
I use an aligned stack here only to emphasize that if the left hand side of the two rows had different widths (here they do not), the aligned forms would be the most appropriate.
documentclassarticle
usepackagetabstackengine
stackMath
begindocument
[
left[alignCenterstackm=&4\m<&-5right.
]
enddocument

In terms of the OP's test case, I give two different vertical alignment options, in the form of "D" and "E".
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagetabstackengine
stackMath
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD.
$left[alignCenterstackm =& A \m <& -5right.$ \
colorredtextbfE.
belowbaseline[-htstrutbox]left[alignCenterstackm =& A \m <& -5right.
&
endtabular
enddocument

It doesn't work much in my test question :( Check the code of my test question please.
â Hoà ng Duy Anh
Sep 19 at 9:51
@Hoà ngDuyAnh Yes it does. Please see my edit.
â Steven B. Segletes
Sep 19 at 9:59
Oh I see, that's exactly what I'm trying to text out! Thank you alot
â Hoà ng Duy Anh
Sep 19 at 10:00
add a comment |Â
up vote
4
down vote
I use an aligned stack here only to emphasize that if the left hand side of the two rows had different widths (here they do not), the aligned forms would be the most appropriate.
documentclassarticle
usepackagetabstackengine
stackMath
begindocument
[
left[alignCenterstackm=&4\m<&-5right.
]
enddocument

In terms of the OP's test case, I give two different vertical alignment options, in the form of "D" and "E".
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagetabstackengine
stackMath
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD.
$left[alignCenterstackm =& A \m <& -5right.$ \
colorredtextbfE.
belowbaseline[-htstrutbox]left[alignCenterstackm =& A \m <& -5right.
&
endtabular
enddocument

It doesn't work much in my test question :( Check the code of my test question please.
â Hoà ng Duy Anh
Sep 19 at 9:51
@Hoà ngDuyAnh Yes it does. Please see my edit.
â Steven B. Segletes
Sep 19 at 9:59
Oh I see, that's exactly what I'm trying to text out! Thank you alot
â Hoà ng Duy Anh
Sep 19 at 10:00
add a comment |Â
up vote
4
down vote
up vote
4
down vote
I use an aligned stack here only to emphasize that if the left hand side of the two rows had different widths (here they do not), the aligned forms would be the most appropriate.
documentclassarticle
usepackagetabstackengine
stackMath
begindocument
[
left[alignCenterstackm=&4\m<&-5right.
]
enddocument

In terms of the OP's test case, I give two different vertical alignment options, in the form of "D" and "E".
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagetabstackengine
stackMath
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD.
$left[alignCenterstackm =& A \m <& -5right.$ \
colorredtextbfE.
belowbaseline[-htstrutbox]left[alignCenterstackm =& A \m <& -5right.
&
endtabular
enddocument

I use an aligned stack here only to emphasize that if the left hand side of the two rows had different widths (here they do not), the aligned forms would be the most appropriate.
documentclassarticle
usepackagetabstackengine
stackMath
begindocument
[
left[alignCenterstackm=&4\m<&-5right.
]
enddocument

In terms of the OP's test case, I give two different vertical alignment options, in the form of "D" and "E".
documentclass[a4paper , 12pt]article
usepackagecolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgf,tikz,pgfplots
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
usepackagetabstackengine
stackMath
begindocument
colorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá» $y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng. \
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularm6cmm6cm
colorbluetextbfA. $m=4 v m<-5$ & colorbluetextbfB. $m=4$ \
colorbluetextbfC. $m<-5$ & colorredtextbfD.
$left[alignCenterstackm =& A \m <& -5right.$ \
colorredtextbfE.
belowbaseline[-htstrutbox]left[alignCenterstackm =& A \m <& -5right.
&
endtabular
enddocument

edited Sep 19 at 10:04
answered Sep 19 at 9:45
Steven B. Segletes
148k9186390
148k9186390
It doesn't work much in my test question :( Check the code of my test question please.
â Hoà ng Duy Anh
Sep 19 at 9:51
@Hoà ngDuyAnh Yes it does. Please see my edit.
â Steven B. Segletes
Sep 19 at 9:59
Oh I see, that's exactly what I'm trying to text out! Thank you alot
â Hoà ng Duy Anh
Sep 19 at 10:00
add a comment |Â
It doesn't work much in my test question :( Check the code of my test question please.
â Hoà ng Duy Anh
Sep 19 at 9:51
@Hoà ngDuyAnh Yes it does. Please see my edit.
â Steven B. Segletes
Sep 19 at 9:59
Oh I see, that's exactly what I'm trying to text out! Thank you alot
â Hoà ng Duy Anh
Sep 19 at 10:00
It doesn't work much in my test question :( Check the code of my test question please.
â Hoà ng Duy Anh
Sep 19 at 9:51
It doesn't work much in my test question :( Check the code of my test question please.
â Hoà ng Duy Anh
Sep 19 at 9:51
@Hoà ngDuyAnh Yes it does. Please see my edit.
â Steven B. Segletes
Sep 19 at 9:59
@Hoà ngDuyAnh Yes it does. Please see my edit.
â Steven B. Segletes
Sep 19 at 9:59
Oh I see, that's exactly what I'm trying to text out! Thank you alot
â Hoà ng Duy Anh
Sep 19 at 10:00
Oh I see, that's exactly what I'm trying to text out! Thank you alot
â Hoà ng Duy Anh
Sep 19 at 10:00
add a comment |Â
up vote
3
down vote

a simple way which cross my mind :-) :
documentclassarticle
begindocument
[
left[
beginarrayl
m=4 \
m<-5
endarray
right.
]
enddocument
edit:
considering your mwe, with my above proposition you will obtain:

documentclass[a4paper , 12pt]article
% usepackagecolor % it is loaded by xcolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgfplots%pgf,tikz
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$left[beginarrayc
m = A \
m < -5
endarrayright.$
endtabular
enddocument
documentclass[t]beamer
setbeamertemplatenavigation symbols
setbeamertemplatefootline
setbeamertemplateheadline
usepackage[edges]forest
Oh thank you a lots, That's help a lot but there is some struggle when I put it in the answers of my test:
â Hoà ng Duy Anh
Sep 19 at 9:15
2
@Hoà ngDuyAnh - Please be more specific about the "struggle when I put in my answers" consists of.
â Mico
Sep 19 at 9:40
@Hoà ngDuyAnh, you not provide any code (as small complete document which we can copy and test), so we haven't any idea about your document. anyway, the proposed solution is so elementary that it should work in any document.
â Zarko
Sep 19 at 9:40
Let me add my code into the question
â Hoà ng Duy Anh
Sep 19 at 9:40
add a comment |Â
up vote
3
down vote

a simple way which cross my mind :-) :
documentclassarticle
begindocument
[
left[
beginarrayl
m=4 \
m<-5
endarray
right.
]
enddocument
edit:
considering your mwe, with my above proposition you will obtain:

documentclass[a4paper , 12pt]article
% usepackagecolor % it is loaded by xcolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgfplots%pgf,tikz
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$left[beginarrayc
m = A \
m < -5
endarrayright.$
endtabular
enddocument
documentclass[t]beamer
setbeamertemplatenavigation symbols
setbeamertemplatefootline
setbeamertemplateheadline
usepackage[edges]forest
Oh thank you a lots, That's help a lot but there is some struggle when I put it in the answers of my test:
â Hoà ng Duy Anh
Sep 19 at 9:15
2
@Hoà ngDuyAnh - Please be more specific about the "struggle when I put in my answers" consists of.
â Mico
Sep 19 at 9:40
@Hoà ngDuyAnh, you not provide any code (as small complete document which we can copy and test), so we haven't any idea about your document. anyway, the proposed solution is so elementary that it should work in any document.
â Zarko
Sep 19 at 9:40
Let me add my code into the question
â Hoà ng Duy Anh
Sep 19 at 9:40
add a comment |Â
up vote
3
down vote
up vote
3
down vote

a simple way which cross my mind :-) :
documentclassarticle
begindocument
[
left[
beginarrayl
m=4 \
m<-5
endarray
right.
]
enddocument
edit:
considering your mwe, with my above proposition you will obtain:

documentclass[a4paper , 12pt]article
% usepackagecolor % it is loaded by xcolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgfplots%pgf,tikz
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$left[beginarrayc
m = A \
m < -5
endarrayright.$
endtabular
enddocument
documentclass[t]beamer
setbeamertemplatenavigation symbols
setbeamertemplatefootline
setbeamertemplateheadline
usepackage[edges]forest

a simple way which cross my mind :-) :
documentclassarticle
begindocument
[
left[
beginarrayl
m=4 \
m<-5
endarray
right.
]
enddocument
edit:
considering your mwe, with my above proposition you will obtain:

documentclass[a4paper , 12pt]article
% usepackagecolor % it is loaded by xcolor
usepackage[dvipsnames]xcolor
usepackagearray
usepackagefloatrow
usepackagegraphicx
usepackage[utf8]inputenc
usepackage[utf8]vietnam
usepackagetikz,tkz-tab
usepackageamssymb
usepackagedsfont
usepackagepgfplots%pgf,tikz
pgfplotssetcompat=1.15
usepackagemathrsfs
usepackagemathtools
usetikzlibraryarrows
renewcommandbaselinestretch1.5 %Chá»Ânh dãn dòng
usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]geometry
begindocument
textcolorbluetextbfCâu 18: Cho hàm sá» $y=f(x)$ có bảng biến thiên
nhð hình phÃÂa dðá»Âi. Tìm tất cả $min mathdsR$ ÃÂá» hàm sá»Â
$y=dfrac1f(x)-m$ có 2 ÃÂðá»Âng tiá»Âm cáºÂn ÃÂứng.
begincenter
begintikzpicture
tkzTabInit$x$ /1, $f'(x)$ /1, $f(x)$ /2.5
$-infty$,-1,1,2, $+infty$
tkzTabLine,+,0,-,0,+,0,-
tkzTabVar-/$-infty$, +/$4$ , -/$-5$, +/$4$, -/$infty$
endtikzpicture
endcenter
begintabularp6cmp6cm
textcolorbluetextbfA. $m=4 vee m<-5$ &
textcolorbluetextbfB. $m=4$ \
textcolorbluetextbfC. $m<-5$ & textcolorredtextbfD.
$left[beginarrayc
m = A \
m < -5
endarrayright.$
endtabular
enddocument
documentclass[t]beamer
setbeamertemplatenavigation symbols
setbeamertemplatefootline
setbeamertemplateheadline
usepackage[edges]forest
edited Sep 19 at 10:08
answered Sep 19 at 9:14
Zarko
114k863152
114k863152
Oh thank you a lots, That's help a lot but there is some struggle when I put it in the answers of my test:
â Hoà ng Duy Anh
Sep 19 at 9:15
2
@Hoà ngDuyAnh - Please be more specific about the "struggle when I put in my answers" consists of.
â Mico
Sep 19 at 9:40
@Hoà ngDuyAnh, you not provide any code (as small complete document which we can copy and test), so we haven't any idea about your document. anyway, the proposed solution is so elementary that it should work in any document.
â Zarko
Sep 19 at 9:40
Let me add my code into the question
â Hoà ng Duy Anh
Sep 19 at 9:40
add a comment |Â
Oh thank you a lots, That's help a lot but there is some struggle when I put it in the answers of my test:
â Hoà ng Duy Anh
Sep 19 at 9:15
2
@Hoà ngDuyAnh - Please be more specific about the "struggle when I put in my answers" consists of.
â Mico
Sep 19 at 9:40
@Hoà ngDuyAnh, you not provide any code (as small complete document which we can copy and test), so we haven't any idea about your document. anyway, the proposed solution is so elementary that it should work in any document.
â Zarko
Sep 19 at 9:40
Let me add my code into the question
â Hoà ng Duy Anh
Sep 19 at 9:40
Oh thank you a lots, That's help a lot but there is some struggle when I put it in the answers of my test:
â Hoà ng Duy Anh
Sep 19 at 9:15
Oh thank you a lots, That's help a lot but there is some struggle when I put it in the answers of my test:
â Hoà ng Duy Anh
Sep 19 at 9:15
2
2
@Hoà ngDuyAnh - Please be more specific about the "struggle when I put in my answers" consists of.
â Mico
Sep 19 at 9:40
@Hoà ngDuyAnh - Please be more specific about the "struggle when I put in my answers" consists of.
â Mico
Sep 19 at 9:40
@Hoà ngDuyAnh, you not provide any code (as small complete document which we can copy and test), so we haven't any idea about your document. anyway, the proposed solution is so elementary that it should work in any document.
â Zarko
Sep 19 at 9:40
@Hoà ngDuyAnh, you not provide any code (as small complete document which we can copy and test), so we haven't any idea about your document. anyway, the proposed solution is so elementary that it should work in any document.
â Zarko
Sep 19 at 9:40
Let me add my code into the question
â Hoà ng Duy Anh
Sep 19 at 9:40
Let me add my code into the question
â Hoà ng Duy Anh
Sep 19 at 9:40
add a comment |Â
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You can use
$beginbcases...endbcases$instead of[...],â egreg
Sep 19 at 9:46
I added something based on your test case
â egreg
Sep 19 at 9:52
please tell us, what you expect from your code example? it works fine, but result is somehow unusual (to my taste)
â Zarko
Sep 19 at 9:54