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Belated 20th Happy Birthday to Google (600613)!

Challenge: Use 6, 0, 0, 6, 1, 3 to make the number 20.

Rules:

• Use all numbers, in that exact order.




• Allowed operations: +, -, x, /, sqrt, (); no factorials, nth roots or powers




• No concatenation of final result (e.g. 2 || 0) but concatenation allowed for original numbers




• All numbers in base 10.

How about

$frac600+6-1times3$

another one

$60times(0times6+frac13)$

last one

$sqrtfrac6006times(1+3)$

Here is a solution:

$frac60 + (0 × 6 × 1)3 = 20$

How about:

-(60-0)/6*(1-3)

I rolled back the MathJax edit as, although it looks prettier, I feel that the in-line solution is required to precisely meet the "in that exact order." requirement.

Not quite an answer, but a kind of lateral (or literal) thinking one

$6times0+fracxx+0+6+13$ (assuming $x$ non-zero)

It's because

Allowed operations: +, -, x, /, sqrt, (); so, x is allowed (despite it's used as a variable, not operation; there is definitely a lowercase x, not a multiplication sign in the question text)

How about:

$6-0^0+(6-1)times3$.

Without a power:

$frac60+06times(-1+3)$