Zsh: test newline in case

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0
down vote

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# user input a here
vared -p "input something" -c a
case $a 'n']) echo something;;

won't work, can someone give an insight?

I'm trying to test against user input that if contain y or an enter - newline, echo something.

EDIT:

set | grep IFS
IFS=$' tnC-@'

edited Sep 13 at 12:16

JdeBP

29.7k461136

asked Sep 13 at 9:35

Tuyen Pham

30510

add a commentÂ |Â

up vote
0
down vote

favorite

# user input a here
vared -p "input something" -c a
case $a 'n']) echo something;;

won't work, can someone give an insight?

I'm trying to test against user input that if contain y or an enter - newline, echo something.

EDIT:

set | grep IFS
IFS=$' tnC-@'

edited Sep 13 at 12:16

JdeBP

29.7k461136

asked Sep 13 at 9:35

Tuyen Pham

30510

add a commentÂ |Â

up vote
0
down vote

favorite

# user input a here
vared -p "input something" -c a
case $a 'n']) echo something;;

won't work, can someone give an insight?

I'm trying to test against user input that if contain y or an enter - newline, echo something.

EDIT:

set | grep IFS
IFS=$' tnC-@'

edited Sep 13 at 12:16

JdeBP

29.7k461136

asked Sep 13 at 9:35

Tuyen Pham

30510

# user input a here
vared -p "input something" -c a
case $a 'n']) echo something;;

won't work, can someone give an insight?

I'm trying to test against user input that if contain y or an enter - newline, echo something.

EDIT:

set | grep IFS
IFS=$' tnC-@'

zsh

edited Sep 13 at 12:16

JdeBP

29.7k461136

asked Sep 13 at 9:35

Tuyen Pham

30510

edited Sep 13 at 12:16

JdeBP

29.7k461136

asked Sep 13 at 9:35

Tuyen Pham

30510

edited Sep 13 at 12:16

JdeBP

29.7k461136

edited Sep 13 at 12:16

JdeBP

29.7k461136

edited Sep 13 at 12:16

JdeBP

29.7k461136

asked Sep 13 at 9:35

Tuyen Pham

30510

asked Sep 13 at 9:35

Tuyen Pham

30510

asked Sep 13 at 9:35

Tuyen Pham

30510

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
1
down vote

accepted

You're not saying how you're getting user input.

With read:

read -k 'answer?Are you OK? '
case $answer in
 (y | Y | $'n') echo 1;;
 # or ([$'yYn']) echo 1;;
 (*) echo 2;;
esac

But if you're using read without -k or vared and want to detect when the user presses Enter without entering any answer, that's when you would want to test for an empty value:

answer=; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y | "") echo 1;;
 # or ([yY] | "") echo 1;;
 (*) echo 2;;
esac

Or seed the answer with y (though the user would have to do BackspaceN to say no):

answer=y; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y) echo 1;;
 (*) echo 2;;
esac

edited Sep 13 at 15:42

answered Sep 13 at 9:45

StÃ©phane Chazelas

286k53528867

I used vared -p "input something" -c a to get input, I don't think your answer works for me. Did I miss something?
â€“Â Tuyen Pham
Sep 13 at 9:54

@TuyenPham, vared is to edit the content of a variable. To get a newline character into that variable, the user would have to type Ctrl+V Ctrl+J, or Alt+Enter, is that really what you want? Or do you want to check whether the user has entered an empty input (like when they press Enter when the editing buffer is empty)?
â€“Â StÃ©phane Chazelas
Sep 13 at 11:40

Yes, with vared that I mentioned above I'd like to capture that user input is enter or not? if enter echo something. Because -c I believe the variable is create if not exist. I only check for enter not an empty input like space.
â€“Â Tuyen Pham
Sep 13 at 11:45

@TuyenPham, it's still unclear what you want. "Enter" in vared is for accepting the current value. You also need to press "Enter" after having edited the variable value so as to contain "y" or "n" (for instance by pressing "y" or "n" if the variable was initially empty). Pressing space adds a space character to the content of the variable, it makes it non-empty. Do you want to check that the user didn't modify the value of the variable?
â€“Â StÃ©phane Chazelas
Sep 13 at 12:38

1

@TuenPham, sounds like you want a=y; vared -p "input something: " a
â€“Â StÃ©phane Chazelas
Sep 13 at 15:07

Â |Â
show 2 more comments

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
1
down vote

accepted

You're not saying how you're getting user input.

With read:

read -k 'answer?Are you OK? '
case $answer in
 (y | Y | $'n') echo 1;;
 # or ([$'yYn']) echo 1;;
 (*) echo 2;;
esac

But if you're using read without -k or vared and want to detect when the user presses Enter without entering any answer, that's when you would want to test for an empty value:

answer=; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y | "") echo 1;;
 # or ([yY] | "") echo 1;;
 (*) echo 2;;
esac

Or seed the answer with y (though the user would have to do BackspaceN to say no):

answer=y; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y) echo 1;;
 (*) echo 2;;
esac

edited Sep 13 at 15:42

answered Sep 13 at 9:45

StÃ©phane Chazelas

286k53528867

I used vared -p "input something" -c a to get input, I don't think your answer works for me. Did I miss something?
â€“Â Tuyen Pham
Sep 13 at 9:54

@TuyenPham, vared is to edit the content of a variable. To get a newline character into that variable, the user would have to type Ctrl+V Ctrl+J, or Alt+Enter, is that really what you want? Or do you want to check whether the user has entered an empty input (like when they press Enter when the editing buffer is empty)?
â€“Â StÃ©phane Chazelas
Sep 13 at 11:40

Yes, with vared that I mentioned above I'd like to capture that user input is enter or not? if enter echo something. Because -c I believe the variable is create if not exist. I only check for enter not an empty input like space.
â€“Â Tuyen Pham
Sep 13 at 11:45

@TuyenPham, it's still unclear what you want. "Enter" in vared is for accepting the current value. You also need to press "Enter" after having edited the variable value so as to contain "y" or "n" (for instance by pressing "y" or "n" if the variable was initially empty). Pressing space adds a space character to the content of the variable, it makes it non-empty. Do you want to check that the user didn't modify the value of the variable?
â€“Â StÃ©phane Chazelas
Sep 13 at 12:38

1

@TuenPham, sounds like you want a=y; vared -p "input something: " a
â€“Â StÃ©phane Chazelas
Sep 13 at 15:07

Â |Â
show 2 more comments

up vote
1
down vote

accepted

You're not saying how you're getting user input.

With read:

read -k 'answer?Are you OK? '
case $answer in
 (y | Y | $'n') echo 1;;
 # or ([$'yYn']) echo 1;;
 (*) echo 2;;
esac

But if you're using read without -k or vared and want to detect when the user presses Enter without entering any answer, that's when you would want to test for an empty value:

answer=; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y | "") echo 1;;
 # or ([yY] | "") echo 1;;
 (*) echo 2;;
esac

Or seed the answer with y (though the user would have to do BackspaceN to say no):

answer=y; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y) echo 1;;
 (*) echo 2;;
esac

edited Sep 13 at 15:42

answered Sep 13 at 9:45

StÃ©phane Chazelas

286k53528867

I used vared -p "input something" -c a to get input, I don't think your answer works for me. Did I miss something?
â€“Â Tuyen Pham
Sep 13 at 9:54

@TuyenPham, vared is to edit the content of a variable. To get a newline character into that variable, the user would have to type Ctrl+V Ctrl+J, or Alt+Enter, is that really what you want? Or do you want to check whether the user has entered an empty input (like when they press Enter when the editing buffer is empty)?
â€“Â StÃ©phane Chazelas
Sep 13 at 11:40

Yes, with vared that I mentioned above I'd like to capture that user input is enter or not? if enter echo something. Because -c I believe the variable is create if not exist. I only check for enter not an empty input like space.
â€“Â Tuyen Pham
Sep 13 at 11:45

@TuyenPham, it's still unclear what you want. "Enter" in vared is for accepting the current value. You also need to press "Enter" after having edited the variable value so as to contain "y" or "n" (for instance by pressing "y" or "n" if the variable was initially empty). Pressing space adds a space character to the content of the variable, it makes it non-empty. Do you want to check that the user didn't modify the value of the variable?
â€“Â StÃ©phane Chazelas
Sep 13 at 12:38

Â |Â
show 2 more comments

up vote
1
down vote

accepted

You're not saying how you're getting user input.

With read:

read -k 'answer?Are you OK? '
case $answer in
 (y | Y | $'n') echo 1;;
 # or ([$'yYn']) echo 1;;
 (*) echo 2;;
esac

But if you're using read without -k or vared and want to detect when the user presses Enter without entering any answer, that's when you would want to test for an empty value:

answer=; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y | "") echo 1;;
 # or ([yY] | "") echo 1;;
 (*) echo 2;;
esac

Or seed the answer with y (though the user would have to do BackspaceN to say no):

answer=y; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y) echo 1;;
 (*) echo 2;;
esac

edited Sep 13 at 15:42

answered Sep 13 at 9:45

286k53528867

You're not saying how you're getting user input.

With read:

read -k 'answer?Are you OK? '
case $answer in
 (y | Y | $'n') echo 1;;
 # or ([$'yYn']) echo 1;;
 (*) echo 2;;
esac

But if you're using read without -k or vared and want to detect when the user presses Enter without entering any answer, that's when you would want to test for an empty value:

answer=; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y | "") echo 1;;
 # or ([yY] | "") echo 1;;
 (*) echo 2;;
esac

Or seed the answer with y (though the user would have to do BackspaceN to say no):

answer=y; vared -p 'Are you OK? ' answer
case $answer in
 (y | Y) echo 1;;
 (*) echo 2;;
esac

edited Sep 13 at 15:42

answered Sep 13 at 9:45

286k53528867

edited Sep 13 at 15:42

answered Sep 13 at 9:45

286k53528867

answered Sep 13 at 9:45

286k53528867

answered Sep 13 at 9:45

286k53528867

I used vared -p "input something" -c a to get input, I don't think your answer works for me. Did I miss something?
â€“Â Tuyen Pham
Sep 13 at 9:54

@TuyenPham, vared is to edit the content of a variable. To get a newline character into that variable, the user would have to type Ctrl+V Ctrl+J, or Alt+Enter, is that really what you want? Or do you want to check whether the user has entered an empty input (like when they press Enter when the editing buffer is empty)?
â€“Â StÃ©phane Chazelas
Sep 13 at 11:40

Yes, with vared that I mentioned above I'd like to capture that user input is enter or not? if enter echo something. Because -c I believe the variable is create if not exist. I only check for enter not an empty input like space.
â€“Â Tuyen Pham
Sep 13 at 11:45

@TuyenPham, it's still unclear what you want. "Enter" in vared is for accepting the current value. You also need to press "Enter" after having edited the variable value so as to contain "y" or "n" (for instance by pressing "y" or "n" if the variable was initially empty). Pressing space adds a space character to the content of the variable, it makes it non-empty. Do you want to check that the user didn't modify the value of the variable?
â€“Â StÃ©phane Chazelas
Sep 13 at 12:38

Â |Â
show 2 more comments

I used vared -p "input something" -c a to get input, I don't think your answer works for me. Did I miss something?
â€“Â Tuyen Pham
Sep 13 at 9:54

@TuyenPham, vared is to edit the content of a variable. To get a newline character into that variable, the user would have to type Ctrl+V Ctrl+J, or Alt+Enter, is that really what you want? Or do you want to check whether the user has entered an empty input (like when they press Enter when the editing buffer is empty)?
â€“Â StÃ©phane Chazelas
Sep 13 at 11:40

Yes, with vared that I mentioned above I'd like to capture that user input is enter or not? if enter echo something. Because -c I believe the variable is create if not exist. I only check for enter not an empty input like space.
â€“Â Tuyen Pham
Sep 13 at 11:45

@TuyenPham, it's still unclear what you want. "Enter" in vared is for accepting the current value. You also need to press "Enter" after having edited the variable value so as to contain "y" or "n" (for instance by pressing "y" or "n" if the variable was initially empty). Pressing space adds a space character to the content of the variable, it makes it non-empty. Do you want to check that the user didn't modify the value of the variable?
â€“Â StÃ©phane Chazelas
Sep 13 at 12:38

I used vared -p "input something" -c a to get input, I don't think your answer works for me. Did I miss something?
â€“Â Tuyen Pham
Sep 13 at 9:54

@TuyenPham, vared is to edit the content of a variable. To get a newline character into that variable, the user would have to type Ctrl+V Ctrl+J, or Alt+Enter, is that really what you want? Or do you want to check whether the user has entered an empty input (like when they press Enter when the editing buffer is empty)?
â€“Â StÃ©phane Chazelas
Sep 13 at 11:40

Yes, with vared that I mentioned above I'd like to capture that user input is enter or not? if enter echo something. Because -c I believe the variable is create if not exist. I only check for enter not an empty input like space.
â€“Â Tuyen Pham
Sep 13 at 11:45

@TuyenPham, it's still unclear what you want. "Enter" in vared is for accepting the current value. You also need to press "Enter" after having edited the variable value so as to contain "y" or "n" (for instance by pressing "y" or "n" if the variable was initially empty). Pressing space adds a space character to the content of the variable, it makes it non-empty. Do you want to check that the user didn't modify the value of the variable?
â€“Â StÃ©phane Chazelas
Sep 13 at 12:38

Â |Â
show 2 more comments

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