If all permutations of word “FATIMAH” are written in lexicographic order. What would be the 1444th word?

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Following is my question:




If all permutations of word "FATIMAH" are written in lexicographic order. What would be the 1444th word you write?




Here is my solution:



Firstly arrange them in alphabetic order: $A,F,H,I,M,T$



Now all the permutations when first letter is A $= 6! = 720$



All the permutations when first letter is F $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is H $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is I $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is M $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is T $= dfrac6!2! = 360$ (since
A is repeated twice)



Total words up to H $= 1440$



$1441$st word = IAAFHMT



$1442$nd word = IAAFHTM



$1443$rd word = IAAFTHM



$1444$th word = IAATFHM



Please tell whether this is correct or not.










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    I think 1443 will be $IAAFMHT$ and 1444 will be $IAAFMTH$
    – Vasya
    Sep 13 at 11:20














up vote
3
down vote

favorite












Following is my question:




If all permutations of word "FATIMAH" are written in lexicographic order. What would be the 1444th word you write?




Here is my solution:



Firstly arrange them in alphabetic order: $A,F,H,I,M,T$



Now all the permutations when first letter is A $= 6! = 720$



All the permutations when first letter is F $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is H $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is I $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is M $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is T $= dfrac6!2! = 360$ (since
A is repeated twice)



Total words up to H $= 1440$



$1441$st word = IAAFHMT



$1442$nd word = IAAFHTM



$1443$rd word = IAAFTHM



$1444$th word = IAATFHM



Please tell whether this is correct or not.










share|cite|improve this question























  • Welcome to MathSE. Please read this tutorial, which explains how to typeset mathematics on this site using MathJax.
    – N. F. Taussig
    Sep 13 at 11:15






  • 1




    I think 1443 will be $IAAFMHT$ and 1444 will be $IAAFMTH$
    – Vasya
    Sep 13 at 11:20












up vote
3
down vote

favorite









up vote
3
down vote

favorite











Following is my question:




If all permutations of word "FATIMAH" are written in lexicographic order. What would be the 1444th word you write?




Here is my solution:



Firstly arrange them in alphabetic order: $A,F,H,I,M,T$



Now all the permutations when first letter is A $= 6! = 720$



All the permutations when first letter is F $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is H $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is I $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is M $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is T $= dfrac6!2! = 360$ (since
A is repeated twice)



Total words up to H $= 1440$



$1441$st word = IAAFHMT



$1442$nd word = IAAFHTM



$1443$rd word = IAAFTHM



$1444$th word = IAATFHM



Please tell whether this is correct or not.










share|cite|improve this question















Following is my question:




If all permutations of word "FATIMAH" are written in lexicographic order. What would be the 1444th word you write?




Here is my solution:



Firstly arrange them in alphabetic order: $A,F,H,I,M,T$



Now all the permutations when first letter is A $= 6! = 720$



All the permutations when first letter is F $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is H $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is I $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is M $= dfrac6!2! = 360$ (since A is repeated twice)



All the permutations when first letter is T $= dfrac6!2! = 360$ (since
A is repeated twice)



Total words up to H $= 1440$



$1441$st word = IAAFHMT



$1442$nd word = IAAFHTM



$1443$rd word = IAAFTHM



$1444$th word = IAATFHM



Please tell whether this is correct or not.







combinatorics permutations






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edited Sep 13 at 11:14









N. F. Taussig

40.4k93253




40.4k93253










asked Sep 13 at 11:06









puffles

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  • Welcome to MathSE. Please read this tutorial, which explains how to typeset mathematics on this site using MathJax.
    – N. F. Taussig
    Sep 13 at 11:15






  • 1




    I think 1443 will be $IAAFMHT$ and 1444 will be $IAAFMTH$
    – Vasya
    Sep 13 at 11:20
















  • Welcome to MathSE. Please read this tutorial, which explains how to typeset mathematics on this site using MathJax.
    – N. F. Taussig
    Sep 13 at 11:15






  • 1




    I think 1443 will be $IAAFMHT$ and 1444 will be $IAAFMTH$
    – Vasya
    Sep 13 at 11:20















Welcome to MathSE. Please read this tutorial, which explains how to typeset mathematics on this site using MathJax.
– N. F. Taussig
Sep 13 at 11:15




Welcome to MathSE. Please read this tutorial, which explains how to typeset mathematics on this site using MathJax.
– N. F. Taussig
Sep 13 at 11:15




1




1




I think 1443 will be $IAAFMHT$ and 1444 will be $IAAFMTH$
– Vasya
Sep 13 at 11:20




I think 1443 will be $IAAFMHT$ and 1444 will be $IAAFMTH$
– Vasya
Sep 13 at 11:20










3 Answers
3






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up vote
2
down vote



accepted










Your answer is correct until the 1443rd word.



You can think of it this way:



We know that the 1443rd word will be (obviously) $IAA****$. Now we can label $F=1, H=2, M=3, T=4$



And now the question simplifies into arranging 4-digit numbers made by $1,2,3,4$ in ascending order and taking the 4th one.



1: $1234$



2: $1243$



3: $1324$



4: $1342$



Now we can change the numbers back to the corresponding letters, and we will get $IAAFMTH$. $ _square$






share|cite|improve this answer



























    up vote
    2
    down vote













    There are $1440$ words with first letter $A$, $F$ or $H$, as you've correctly found out.



    Using the same tactic you used to count words beginning with a single letter, count the number of words beginning with $IAAF$. You will see that there are actually six. You only wrote down three of them before moving on to $IAAT$ (which is also wrong, because $IAAH$ and $IAAM$ both come before $IAAT$ lexicographically).






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      up vote
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      Almost. Your argument is correct until you reach the $1443$rd word. Since F precedes H, H precedes M, and M precedes T in the alphabet, All the words beginning with IAAF must precede the first word beginning with IAAH, all the words beginning with IAAH must precede the first word beginning with IAAM, and all the words beginning with IAAM must precede the first word beginning with IAAT. The words beginning with IAAF are, in lexicographical order, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH, IAAFTHM, IAAAFTMH. Thus, the $1441$st word, $1442$nd word, $1443$rd word, and $1444$th word are, respectively, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH.






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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes








        up vote
        2
        down vote



        accepted










        Your answer is correct until the 1443rd word.



        You can think of it this way:



        We know that the 1443rd word will be (obviously) $IAA****$. Now we can label $F=1, H=2, M=3, T=4$



        And now the question simplifies into arranging 4-digit numbers made by $1,2,3,4$ in ascending order and taking the 4th one.



        1: $1234$



        2: $1243$



        3: $1324$



        4: $1342$



        Now we can change the numbers back to the corresponding letters, and we will get $IAAFMTH$. $ _square$






        share|cite|improve this answer
























          up vote
          2
          down vote



          accepted










          Your answer is correct until the 1443rd word.



          You can think of it this way:



          We know that the 1443rd word will be (obviously) $IAA****$. Now we can label $F=1, H=2, M=3, T=4$



          And now the question simplifies into arranging 4-digit numbers made by $1,2,3,4$ in ascending order and taking the 4th one.



          1: $1234$



          2: $1243$



          3: $1324$



          4: $1342$



          Now we can change the numbers back to the corresponding letters, and we will get $IAAFMTH$. $ _square$






          share|cite|improve this answer






















            up vote
            2
            down vote



            accepted







            up vote
            2
            down vote



            accepted






            Your answer is correct until the 1443rd word.



            You can think of it this way:



            We know that the 1443rd word will be (obviously) $IAA****$. Now we can label $F=1, H=2, M=3, T=4$



            And now the question simplifies into arranging 4-digit numbers made by $1,2,3,4$ in ascending order and taking the 4th one.



            1: $1234$



            2: $1243$



            3: $1324$



            4: $1342$



            Now we can change the numbers back to the corresponding letters, and we will get $IAAFMTH$. $ _square$






            share|cite|improve this answer












            Your answer is correct until the 1443rd word.



            You can think of it this way:



            We know that the 1443rd word will be (obviously) $IAA****$. Now we can label $F=1, H=2, M=3, T=4$



            And now the question simplifies into arranging 4-digit numbers made by $1,2,3,4$ in ascending order and taking the 4th one.



            1: $1234$



            2: $1243$



            3: $1324$



            4: $1342$



            Now we can change the numbers back to the corresponding letters, and we will get $IAAFMTH$. $ _square$







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Sep 13 at 11:54









            Vee Hua Zhi

            76419




            76419




















                up vote
                2
                down vote













                There are $1440$ words with first letter $A$, $F$ or $H$, as you've correctly found out.



                Using the same tactic you used to count words beginning with a single letter, count the number of words beginning with $IAAF$. You will see that there are actually six. You only wrote down three of them before moving on to $IAAT$ (which is also wrong, because $IAAH$ and $IAAM$ both come before $IAAT$ lexicographically).






                share|cite|improve this answer
























                  up vote
                  2
                  down vote













                  There are $1440$ words with first letter $A$, $F$ or $H$, as you've correctly found out.



                  Using the same tactic you used to count words beginning with a single letter, count the number of words beginning with $IAAF$. You will see that there are actually six. You only wrote down three of them before moving on to $IAAT$ (which is also wrong, because $IAAH$ and $IAAM$ both come before $IAAT$ lexicographically).






                  share|cite|improve this answer






















                    up vote
                    2
                    down vote










                    up vote
                    2
                    down vote









                    There are $1440$ words with first letter $A$, $F$ or $H$, as you've correctly found out.



                    Using the same tactic you used to count words beginning with a single letter, count the number of words beginning with $IAAF$. You will see that there are actually six. You only wrote down three of them before moving on to $IAAT$ (which is also wrong, because $IAAH$ and $IAAM$ both come before $IAAT$ lexicographically).






                    share|cite|improve this answer












                    There are $1440$ words with first letter $A$, $F$ or $H$, as you've correctly found out.



                    Using the same tactic you used to count words beginning with a single letter, count the number of words beginning with $IAAF$. You will see that there are actually six. You only wrote down three of them before moving on to $IAAT$ (which is also wrong, because $IAAH$ and $IAAM$ both come before $IAAT$ lexicographically).







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Sep 13 at 11:20









                    Arthur

                    103k797179




                    103k797179




















                        up vote
                        1
                        down vote













                        Almost. Your argument is correct until you reach the $1443$rd word. Since F precedes H, H precedes M, and M precedes T in the alphabet, All the words beginning with IAAF must precede the first word beginning with IAAH, all the words beginning with IAAH must precede the first word beginning with IAAM, and all the words beginning with IAAM must precede the first word beginning with IAAT. The words beginning with IAAF are, in lexicographical order, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH, IAAFTHM, IAAAFTMH. Thus, the $1441$st word, $1442$nd word, $1443$rd word, and $1444$th word are, respectively, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH.






                        share|cite|improve this answer


























                          up vote
                          1
                          down vote













                          Almost. Your argument is correct until you reach the $1443$rd word. Since F precedes H, H precedes M, and M precedes T in the alphabet, All the words beginning with IAAF must precede the first word beginning with IAAH, all the words beginning with IAAH must precede the first word beginning with IAAM, and all the words beginning with IAAM must precede the first word beginning with IAAT. The words beginning with IAAF are, in lexicographical order, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH, IAAFTHM, IAAAFTMH. Thus, the $1441$st word, $1442$nd word, $1443$rd word, and $1444$th word are, respectively, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH.






                          share|cite|improve this answer
























                            up vote
                            1
                            down vote










                            up vote
                            1
                            down vote









                            Almost. Your argument is correct until you reach the $1443$rd word. Since F precedes H, H precedes M, and M precedes T in the alphabet, All the words beginning with IAAF must precede the first word beginning with IAAH, all the words beginning with IAAH must precede the first word beginning with IAAM, and all the words beginning with IAAM must precede the first word beginning with IAAT. The words beginning with IAAF are, in lexicographical order, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH, IAAFTHM, IAAAFTMH. Thus, the $1441$st word, $1442$nd word, $1443$rd word, and $1444$th word are, respectively, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH.






                            share|cite|improve this answer














                            Almost. Your argument is correct until you reach the $1443$rd word. Since F precedes H, H precedes M, and M precedes T in the alphabet, All the words beginning with IAAF must precede the first word beginning with IAAH, all the words beginning with IAAH must precede the first word beginning with IAAM, and all the words beginning with IAAM must precede the first word beginning with IAAT. The words beginning with IAAF are, in lexicographical order, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH, IAAFTHM, IAAAFTMH. Thus, the $1441$st word, $1442$nd word, $1443$rd word, and $1444$th word are, respectively, IAAFHMT, IAAFHTM, IAAFMHT, IAAFMTH.







                            share|cite|improve this answer














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                            edited Sep 13 at 11:36

























                            answered Sep 13 at 11:20









                            N. F. Taussig

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