how to delete files with specific date pattern [duplicate]
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This question already has an answer here:
How to delete old backups based on a date in file name?
2 answers
Under the folder /var/log/roler_t
, we have the following files:
-rw-r--r-- 1 roler smike 37652 Jun 25 01:44 2018-06-23T02:KJU:00
-rw-r--r-- 1 roler smike 41742 Jun 25 01:45 2018-06-21T20:KJU:00
-rw-r--r-- 1 roler smike 36762 Jun 25 01:46 2018-06-22T08:KJU:00
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 42751 Jun 25 01:48 2018-06-21T16:KJU:00
-rw-r--r-- 1 roler smike 34627 Jun 25 01:49 2018-06-22T23:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 2018-06-23T05:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 2018-06-22T20:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
-rw-r--r-- 1 roler smike 36643 Jun 25 01:53 2018-06-22T01:KJU:00
How can we remove only the files that are older than ten days and have a specific date pattern, for example 2018-06-23
.
Expected results are as follows:
the following files will stay under /var/log/roler_t
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
linux shell-script find regular-expression
marked as duplicate by Jeff Schaller, Romeo Ninov, RalfFriedl, Thomas, Thomas Dickey Sep 13 at 20:03
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |Â
up vote
0
down vote
favorite
This question already has an answer here:
How to delete old backups based on a date in file name?
2 answers
Under the folder /var/log/roler_t
, we have the following files:
-rw-r--r-- 1 roler smike 37652 Jun 25 01:44 2018-06-23T02:KJU:00
-rw-r--r-- 1 roler smike 41742 Jun 25 01:45 2018-06-21T20:KJU:00
-rw-r--r-- 1 roler smike 36762 Jun 25 01:46 2018-06-22T08:KJU:00
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 42751 Jun 25 01:48 2018-06-21T16:KJU:00
-rw-r--r-- 1 roler smike 34627 Jun 25 01:49 2018-06-22T23:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 2018-06-23T05:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 2018-06-22T20:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
-rw-r--r-- 1 roler smike 36643 Jun 25 01:53 2018-06-22T01:KJU:00
How can we remove only the files that are older than ten days and have a specific date pattern, for example 2018-06-23
.
Expected results are as follows:
the following files will stay under /var/log/roler_t
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
linux shell-script find regular-expression
marked as duplicate by Jeff Schaller, Romeo Ninov, RalfFriedl, Thomas, Thomas Dickey Sep 13 at 20:03
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
This question already has an answer here:
How to delete old backups based on a date in file name?
2 answers
Under the folder /var/log/roler_t
, we have the following files:
-rw-r--r-- 1 roler smike 37652 Jun 25 01:44 2018-06-23T02:KJU:00
-rw-r--r-- 1 roler smike 41742 Jun 25 01:45 2018-06-21T20:KJU:00
-rw-r--r-- 1 roler smike 36762 Jun 25 01:46 2018-06-22T08:KJU:00
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 42751 Jun 25 01:48 2018-06-21T16:KJU:00
-rw-r--r-- 1 roler smike 34627 Jun 25 01:49 2018-06-22T23:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 2018-06-23T05:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 2018-06-22T20:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
-rw-r--r-- 1 roler smike 36643 Jun 25 01:53 2018-06-22T01:KJU:00
How can we remove only the files that are older than ten days and have a specific date pattern, for example 2018-06-23
.
Expected results are as follows:
the following files will stay under /var/log/roler_t
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
linux shell-script find regular-expression
This question already has an answer here:
How to delete old backups based on a date in file name?
2 answers
Under the folder /var/log/roler_t
, we have the following files:
-rw-r--r-- 1 roler smike 37652 Jun 25 01:44 2018-06-23T02:KJU:00
-rw-r--r-- 1 roler smike 41742 Jun 25 01:45 2018-06-21T20:KJU:00
-rw-r--r-- 1 roler smike 36762 Jun 25 01:46 2018-06-22T08:KJU:00
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 42751 Jun 25 01:48 2018-06-21T16:KJU:00
-rw-r--r-- 1 roler smike 34627 Jun 25 01:49 2018-06-22T23:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 2018-06-23T05:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 2018-06-22T20:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
-rw-r--r-- 1 roler smike 36643 Jun 25 01:53 2018-06-22T01:KJU:00
How can we remove only the files that are older than ten days and have a specific date pattern, for example 2018-06-23
.
Expected results are as follows:
the following files will stay under /var/log/roler_t
-rw-r--r-- 1 roler smike 51764 Jun 25 01:47 PL-06-23T12:KJU:00
-rw-r--r-- 1 roler smike 59828 Jun 25 01:51 JFG:KJU:00
-rw-r--r-- 1 roler smike 33561 Jun 25 01:52 PL-22T20:KJU:00
This question already has an answer here:
How to delete old backups based on a date in file name?
2 answers
linux shell-script find regular-expression
linux shell-script find regular-expression
edited Sep 13 at 14:36
Patrick Mevzek
2,0581721
2,0581721
asked Sep 13 at 11:45
yael
2,0391345
2,0391345
marked as duplicate by Jeff Schaller, Romeo Ninov, RalfFriedl, Thomas, Thomas Dickey Sep 13 at 20:03
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Jeff Schaller, Romeo Ninov, RalfFriedl, Thomas, Thomas Dickey Sep 13 at 20:03
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |Â
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
0
down vote
You can filter your files by date with the find
command.
For example:
find /var/log/roler_t -mtime +10
returns all files with modification date > 10 days.
Similarly you can use flags like -atime
(access time), -ctime
(status change time), but I think -mtime
is what you're looking for.
If you want to remove them with a single command (but I suggest you always check before if the results of find
are what you're expecting):
find /var/log/roler_t -mtime +10 -exec rm ;
not as I ask , I mean to delete all files with name date syntax as xxxx-xx-xx , and that older then 10day
â yael
Sep 13 at 11:56
the syntax find /var/log/roler_t -mtime +10 -exec rm ; , will remove also the file as PL-22T20:KJU:00
â yael
Sep 13 at 12:01
@yael as @B.McCready answered, then just filter by filename, too adding-name "*XXXX-XX-XX*" to the
find` command.
â Mr Shunz
Sep 13 at 12:11
add a comment |Â
up vote
0
down vote
This is similar to your earlier question, you can achieve this by the following
$ find /var/log/roler_t -mtime +10 -name "XXXX-XX-XX*"
where XXXX-XX-XX is the datestamp you are looking for. If you know that the year month and day correspond to the modification time you are looking for you coul change the argument to the -name option to be something like this:
$find /var/log/roler_t -mtime +10 -name "`date -d'now - 10 days' +'%y-%m-%d'*"
to automatically generate the filename prefix, though you may need to play with the date command number of days you subtract to be sue the mtime and the datestamp match what you need.
If you just want to match the names of files that begin with a datestamp like string, e.g. '2018-09-13' then use the following:
/var/log/roler_t -mtime +10 -name "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*"
but XXXX-XX-XX can be 1998-02-34 or 2013-01-56 , etc , so the option "-name "XXXX-XX-XX*" must to fit to any date
â yael
Sep 13 at 12:16
@yael, are you saying there might be files of varying age and datestamps, but you only want to delete the ones whose names begin with a datestamp in the form of YYYY-MM-DD? then just change the -name option argument to "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*" or similar.
â B.McCready
Sep 13 at 12:20
yes thats I mean
â yael
Sep 13 at 12:30
@yael I think I get what you're saying; you want the filename to match a pattern? You can do that via âÂÂ-name '????-??-??â or âÂÂ-name "[0-9][0-9]0-9][0-9]-[0-9] (etc)â or also see the 'regexâ option stackoverflow.com/questions/19111067/â¦
â michael
Sep 13 at 12:31
so can you please update the answer , instead the remark so I will choose the right answer
â yael
Sep 13 at 12:33
 |Â
show 1 more comment
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You can filter your files by date with the find
command.
For example:
find /var/log/roler_t -mtime +10
returns all files with modification date > 10 days.
Similarly you can use flags like -atime
(access time), -ctime
(status change time), but I think -mtime
is what you're looking for.
If you want to remove them with a single command (but I suggest you always check before if the results of find
are what you're expecting):
find /var/log/roler_t -mtime +10 -exec rm ;
not as I ask , I mean to delete all files with name date syntax as xxxx-xx-xx , and that older then 10day
â yael
Sep 13 at 11:56
the syntax find /var/log/roler_t -mtime +10 -exec rm ; , will remove also the file as PL-22T20:KJU:00
â yael
Sep 13 at 12:01
@yael as @B.McCready answered, then just filter by filename, too adding-name "*XXXX-XX-XX*" to the
find` command.
â Mr Shunz
Sep 13 at 12:11
add a comment |Â
up vote
0
down vote
You can filter your files by date with the find
command.
For example:
find /var/log/roler_t -mtime +10
returns all files with modification date > 10 days.
Similarly you can use flags like -atime
(access time), -ctime
(status change time), but I think -mtime
is what you're looking for.
If you want to remove them with a single command (but I suggest you always check before if the results of find
are what you're expecting):
find /var/log/roler_t -mtime +10 -exec rm ;
not as I ask , I mean to delete all files with name date syntax as xxxx-xx-xx , and that older then 10day
â yael
Sep 13 at 11:56
the syntax find /var/log/roler_t -mtime +10 -exec rm ; , will remove also the file as PL-22T20:KJU:00
â yael
Sep 13 at 12:01
@yael as @B.McCready answered, then just filter by filename, too adding-name "*XXXX-XX-XX*" to the
find` command.
â Mr Shunz
Sep 13 at 12:11
add a comment |Â
up vote
0
down vote
up vote
0
down vote
You can filter your files by date with the find
command.
For example:
find /var/log/roler_t -mtime +10
returns all files with modification date > 10 days.
Similarly you can use flags like -atime
(access time), -ctime
(status change time), but I think -mtime
is what you're looking for.
If you want to remove them with a single command (but I suggest you always check before if the results of find
are what you're expecting):
find /var/log/roler_t -mtime +10 -exec rm ;
You can filter your files by date with the find
command.
For example:
find /var/log/roler_t -mtime +10
returns all files with modification date > 10 days.
Similarly you can use flags like -atime
(access time), -ctime
(status change time), but I think -mtime
is what you're looking for.
If you want to remove them with a single command (but I suggest you always check before if the results of find
are what you're expecting):
find /var/log/roler_t -mtime +10 -exec rm ;
answered Sep 13 at 11:53
Mr Shunz
2,65811720
2,65811720
not as I ask , I mean to delete all files with name date syntax as xxxx-xx-xx , and that older then 10day
â yael
Sep 13 at 11:56
the syntax find /var/log/roler_t -mtime +10 -exec rm ; , will remove also the file as PL-22T20:KJU:00
â yael
Sep 13 at 12:01
@yael as @B.McCready answered, then just filter by filename, too adding-name "*XXXX-XX-XX*" to the
find` command.
â Mr Shunz
Sep 13 at 12:11
add a comment |Â
not as I ask , I mean to delete all files with name date syntax as xxxx-xx-xx , and that older then 10day
â yael
Sep 13 at 11:56
the syntax find /var/log/roler_t -mtime +10 -exec rm ; , will remove also the file as PL-22T20:KJU:00
â yael
Sep 13 at 12:01
@yael as @B.McCready answered, then just filter by filename, too adding-name "*XXXX-XX-XX*" to the
find` command.
â Mr Shunz
Sep 13 at 12:11
not as I ask , I mean to delete all files with name date syntax as xxxx-xx-xx , and that older then 10day
â yael
Sep 13 at 11:56
not as I ask , I mean to delete all files with name date syntax as xxxx-xx-xx , and that older then 10day
â yael
Sep 13 at 11:56
the syntax find /var/log/roler_t -mtime +10 -exec rm ; , will remove also the file as PL-22T20:KJU:00
â yael
Sep 13 at 12:01
the syntax find /var/log/roler_t -mtime +10 -exec rm ; , will remove also the file as PL-22T20:KJU:00
â yael
Sep 13 at 12:01
@yael as @B.McCready answered, then just filter by filename, too adding
-name "*XXXX-XX-XX*" to the
find` command.â Mr Shunz
Sep 13 at 12:11
@yael as @B.McCready answered, then just filter by filename, too adding
-name "*XXXX-XX-XX*" to the
find` command.â Mr Shunz
Sep 13 at 12:11
add a comment |Â
up vote
0
down vote
This is similar to your earlier question, you can achieve this by the following
$ find /var/log/roler_t -mtime +10 -name "XXXX-XX-XX*"
where XXXX-XX-XX is the datestamp you are looking for. If you know that the year month and day correspond to the modification time you are looking for you coul change the argument to the -name option to be something like this:
$find /var/log/roler_t -mtime +10 -name "`date -d'now - 10 days' +'%y-%m-%d'*"
to automatically generate the filename prefix, though you may need to play with the date command number of days you subtract to be sue the mtime and the datestamp match what you need.
If you just want to match the names of files that begin with a datestamp like string, e.g. '2018-09-13' then use the following:
/var/log/roler_t -mtime +10 -name "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*"
but XXXX-XX-XX can be 1998-02-34 or 2013-01-56 , etc , so the option "-name "XXXX-XX-XX*" must to fit to any date
â yael
Sep 13 at 12:16
@yael, are you saying there might be files of varying age and datestamps, but you only want to delete the ones whose names begin with a datestamp in the form of YYYY-MM-DD? then just change the -name option argument to "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*" or similar.
â B.McCready
Sep 13 at 12:20
yes thats I mean
â yael
Sep 13 at 12:30
@yael I think I get what you're saying; you want the filename to match a pattern? You can do that via âÂÂ-name '????-??-??â or âÂÂ-name "[0-9][0-9]0-9][0-9]-[0-9] (etc)â or also see the 'regexâ option stackoverflow.com/questions/19111067/â¦
â michael
Sep 13 at 12:31
so can you please update the answer , instead the remark so I will choose the right answer
â yael
Sep 13 at 12:33
 |Â
show 1 more comment
up vote
0
down vote
This is similar to your earlier question, you can achieve this by the following
$ find /var/log/roler_t -mtime +10 -name "XXXX-XX-XX*"
where XXXX-XX-XX is the datestamp you are looking for. If you know that the year month and day correspond to the modification time you are looking for you coul change the argument to the -name option to be something like this:
$find /var/log/roler_t -mtime +10 -name "`date -d'now - 10 days' +'%y-%m-%d'*"
to automatically generate the filename prefix, though you may need to play with the date command number of days you subtract to be sue the mtime and the datestamp match what you need.
If you just want to match the names of files that begin with a datestamp like string, e.g. '2018-09-13' then use the following:
/var/log/roler_t -mtime +10 -name "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*"
but XXXX-XX-XX can be 1998-02-34 or 2013-01-56 , etc , so the option "-name "XXXX-XX-XX*" must to fit to any date
â yael
Sep 13 at 12:16
@yael, are you saying there might be files of varying age and datestamps, but you only want to delete the ones whose names begin with a datestamp in the form of YYYY-MM-DD? then just change the -name option argument to "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*" or similar.
â B.McCready
Sep 13 at 12:20
yes thats I mean
â yael
Sep 13 at 12:30
@yael I think I get what you're saying; you want the filename to match a pattern? You can do that via âÂÂ-name '????-??-??â or âÂÂ-name "[0-9][0-9]0-9][0-9]-[0-9] (etc)â or also see the 'regexâ option stackoverflow.com/questions/19111067/â¦
â michael
Sep 13 at 12:31
so can you please update the answer , instead the remark so I will choose the right answer
â yael
Sep 13 at 12:33
 |Â
show 1 more comment
up vote
0
down vote
up vote
0
down vote
This is similar to your earlier question, you can achieve this by the following
$ find /var/log/roler_t -mtime +10 -name "XXXX-XX-XX*"
where XXXX-XX-XX is the datestamp you are looking for. If you know that the year month and day correspond to the modification time you are looking for you coul change the argument to the -name option to be something like this:
$find /var/log/roler_t -mtime +10 -name "`date -d'now - 10 days' +'%y-%m-%d'*"
to automatically generate the filename prefix, though you may need to play with the date command number of days you subtract to be sue the mtime and the datestamp match what you need.
If you just want to match the names of files that begin with a datestamp like string, e.g. '2018-09-13' then use the following:
/var/log/roler_t -mtime +10 -name "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*"
This is similar to your earlier question, you can achieve this by the following
$ find /var/log/roler_t -mtime +10 -name "XXXX-XX-XX*"
where XXXX-XX-XX is the datestamp you are looking for. If you know that the year month and day correspond to the modification time you are looking for you coul change the argument to the -name option to be something like this:
$find /var/log/roler_t -mtime +10 -name "`date -d'now - 10 days' +'%y-%m-%d'*"
to automatically generate the filename prefix, though you may need to play with the date command number of days you subtract to be sue the mtime and the datestamp match what you need.
If you just want to match the names of files that begin with a datestamp like string, e.g. '2018-09-13' then use the following:
/var/log/roler_t -mtime +10 -name "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*"
edited Sep 13 at 16:04
answered Sep 13 at 12:09
B.McCready
663
663
but XXXX-XX-XX can be 1998-02-34 or 2013-01-56 , etc , so the option "-name "XXXX-XX-XX*" must to fit to any date
â yael
Sep 13 at 12:16
@yael, are you saying there might be files of varying age and datestamps, but you only want to delete the ones whose names begin with a datestamp in the form of YYYY-MM-DD? then just change the -name option argument to "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*" or similar.
â B.McCready
Sep 13 at 12:20
yes thats I mean
â yael
Sep 13 at 12:30
@yael I think I get what you're saying; you want the filename to match a pattern? You can do that via âÂÂ-name '????-??-??â or âÂÂ-name "[0-9][0-9]0-9][0-9]-[0-9] (etc)â or also see the 'regexâ option stackoverflow.com/questions/19111067/â¦
â michael
Sep 13 at 12:31
so can you please update the answer , instead the remark so I will choose the right answer
â yael
Sep 13 at 12:33
 |Â
show 1 more comment
but XXXX-XX-XX can be 1998-02-34 or 2013-01-56 , etc , so the option "-name "XXXX-XX-XX*" must to fit to any date
â yael
Sep 13 at 12:16
@yael, are you saying there might be files of varying age and datestamps, but you only want to delete the ones whose names begin with a datestamp in the form of YYYY-MM-DD? then just change the -name option argument to "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*" or similar.
â B.McCready
Sep 13 at 12:20
yes thats I mean
â yael
Sep 13 at 12:30
@yael I think I get what you're saying; you want the filename to match a pattern? You can do that via âÂÂ-name '????-??-??â or âÂÂ-name "[0-9][0-9]0-9][0-9]-[0-9] (etc)â or also see the 'regexâ option stackoverflow.com/questions/19111067/â¦
â michael
Sep 13 at 12:31
so can you please update the answer , instead the remark so I will choose the right answer
â yael
Sep 13 at 12:33
but XXXX-XX-XX can be 1998-02-34 or 2013-01-56 , etc , so the option "-name "XXXX-XX-XX*" must to fit to any date
â yael
Sep 13 at 12:16
but XXXX-XX-XX can be 1998-02-34 or 2013-01-56 , etc , so the option "-name "XXXX-XX-XX*" must to fit to any date
â yael
Sep 13 at 12:16
@yael, are you saying there might be files of varying age and datestamps, but you only want to delete the ones whose names begin with a datestamp in the form of YYYY-MM-DD? then just change the -name option argument to "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*" or similar.
â B.McCready
Sep 13 at 12:20
@yael, are you saying there might be files of varying age and datestamps, but you only want to delete the ones whose names begin with a datestamp in the form of YYYY-MM-DD? then just change the -name option argument to "[12][0-9][0-9][0-9]-[01][0-9]-[0-3][0-9]*" or similar.
â B.McCready
Sep 13 at 12:20
yes thats I mean
â yael
Sep 13 at 12:30
yes thats I mean
â yael
Sep 13 at 12:30
@yael I think I get what you're saying; you want the filename to match a pattern? You can do that via âÂÂ-name '????-??-??â or âÂÂ-name "[0-9][0-9]0-9][0-9]-[0-9] (etc)â or also see the 'regexâ option stackoverflow.com/questions/19111067/â¦
â michael
Sep 13 at 12:31
@yael I think I get what you're saying; you want the filename to match a pattern? You can do that via âÂÂ-name '????-??-??â or âÂÂ-name "[0-9][0-9]0-9][0-9]-[0-9] (etc)â or also see the 'regexâ option stackoverflow.com/questions/19111067/â¦
â michael
Sep 13 at 12:31
so can you please update the answer , instead the remark so I will choose the right answer
â yael
Sep 13 at 12:33
so can you please update the answer , instead the remark so I will choose the right answer
â yael
Sep 13 at 12:33
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