How to print an nth column in a file using awk?

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1















I have n files (call them input1, input2, and so on) with similar data and I wish to make a new file (call it out) that contains the 2nd column of these files. If I use



awk 'print $2' input1..n >> out


then I get a single column with all the entries from the 2nd column of the input files. What can I do to have different columns for different files, as in $1 in out = $2 of input1, $2 in out = $2 of input2, $3 in out = $2 of input3,....., $n in out = $2 of inputn?










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  • Are all files of the same length, i.e. do they all always have the same number of rows, and is this number known in advance?

    – Kusalananda
    Feb 19 at 14:23











  • @Kusalananda yes they're all of the same length and the #rows and #columns are known.

    – Hitanshu Sachania
    Feb 19 at 14:26















1















I have n files (call them input1, input2, and so on) with similar data and I wish to make a new file (call it out) that contains the 2nd column of these files. If I use



awk 'print $2' input1..n >> out


then I get a single column with all the entries from the 2nd column of the input files. What can I do to have different columns for different files, as in $1 in out = $2 of input1, $2 in out = $2 of input2, $3 in out = $2 of input3,....., $n in out = $2 of inputn?










share|improve this question
























  • Are all files of the same length, i.e. do they all always have the same number of rows, and is this number known in advance?

    – Kusalananda
    Feb 19 at 14:23











  • @Kusalananda yes they're all of the same length and the #rows and #columns are known.

    – Hitanshu Sachania
    Feb 19 at 14:26













1












1








1








I have n files (call them input1, input2, and so on) with similar data and I wish to make a new file (call it out) that contains the 2nd column of these files. If I use



awk 'print $2' input1..n >> out


then I get a single column with all the entries from the 2nd column of the input files. What can I do to have different columns for different files, as in $1 in out = $2 of input1, $2 in out = $2 of input2, $3 in out = $2 of input3,....., $n in out = $2 of inputn?










share|improve this question
















I have n files (call them input1, input2, and so on) with similar data and I wish to make a new file (call it out) that contains the 2nd column of these files. If I use



awk 'print $2' input1..n >> out


then I get a single column with all the entries from the 2nd column of the input files. What can I do to have different columns for different files, as in $1 in out = $2 of input1, $2 in out = $2 of input2, $3 in out = $2 of input3,....., $n in out = $2 of inputn?







text-processing awk






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share|improve this question













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share|improve this question








edited Feb 19 at 14:02







Hitanshu Sachania

















asked Feb 19 at 13:30









Hitanshu SachaniaHitanshu Sachania

425




425












  • Are all files of the same length, i.e. do they all always have the same number of rows, and is this number known in advance?

    – Kusalananda
    Feb 19 at 14:23











  • @Kusalananda yes they're all of the same length and the #rows and #columns are known.

    – Hitanshu Sachania
    Feb 19 at 14:26

















  • Are all files of the same length, i.e. do they all always have the same number of rows, and is this number known in advance?

    – Kusalananda
    Feb 19 at 14:23











  • @Kusalananda yes they're all of the same length and the #rows and #columns are known.

    – Hitanshu Sachania
    Feb 19 at 14:26
















Are all files of the same length, i.e. do they all always have the same number of rows, and is this number known in advance?

– Kusalananda
Feb 19 at 14:23





Are all files of the same length, i.e. do they all always have the same number of rows, and is this number known in advance?

– Kusalananda
Feb 19 at 14:23













@Kusalananda yes they're all of the same length and the #rows and #columns are known.

– Hitanshu Sachania
Feb 19 at 14:26





@Kusalananda yes they're all of the same length and the #rows and #columns are known.

– Hitanshu Sachania
Feb 19 at 14:26










4 Answers
4






active

oldest

votes


















1














You could do the whole thing in a BEGIN statement using getline



awk '
BEGIN
while(1)
line = sep = ""
for (i = 1; i < ARGC; i++)
if ((getline < ARGV[i]) <= 0) exit
line = line sep $2
sep = OFS

print line

' input1..n > out





share|improve this answer

























  • Is there any way we can use ORS? I was trying that but it doesn't work with multiple files.

    – Prvt_Yadv
    Feb 19 at 14:04











  • @PRY, there was a missing loop. It should be fixed now.

    – Stéphane Chazelas
    Feb 19 at 14:04











  • Sorry, I was asking in general manner, not related to your answer.

    – Prvt_Yadv
    Feb 19 at 14:05






  • 1





    @HitanshuSachania, getline retrieves one record from the given input file and return 0 upon end-of-file or a negative number upon error in which case we exit (so we stop as soon as we've reached the end of any of the input files so the number of records in the output file is that of the input file with fewest records).

    – Stéphane Chazelas
    Feb 19 at 14:51







  • 1





    @HitanshuSachania, not it builds one line of output (in line) at a time, as opposed to storing all the lines of output in an array and printing it at the end. We could skip storing the line in line and print the fields as they come, but that would cause problem for the last record if not all input files have the same number of records.

    – Stéphane Chazelas
    Feb 19 at 15:48



















1














You could construct a paste command to put all the second columns together:



cmd="paste"
for x in input1..n; do
cmd="$cmd <(awk 'print $2;' $x)"
done
echo $cmd
eval $cmd





share|improve this answer






























    1














    using this post as reference



    awk 'a[FNR] = a[FNR]" " $2ENDfor(i=1;i<=FNR;i++) print a[i]' input1..n


    an array holds each line from different files



    FNR number of records read in current input file, set to zero at begining of each file.



    ENDfor(i=1;i<FNR;i++) print a[i] 


    prints the content of array a on END of file






    share|improve this answer

























    • What is the purpose of the double quotes before $2 and how does the array a store just the 2nd column?

      – Hitanshu Sachania
      Feb 19 at 14:14












    • Note that it stores the whole output in memory before starting to print it.

      – Stéphane Chazelas
      Feb 19 at 14:16











    • I changed the lstaro of the loop froom 0 to 1

      – Emilio Galarraga
      Feb 19 at 14:23






    • 1





      the double quotes before $2 defile the delimiter between columns in the output file and the script is passing the value in $2 to a[FNR] element of the array

      – Emilio Galarraga
      Feb 19 at 14:27











    • Use a[FNR]=!a[FNR]?$2:a[FNR]" "$2 to eleminate white space in front of each line...

      – RoVo
      Feb 19 at 14:35


















    1














    I would use the pr tool, which is designed to columnize data:



    awk 'print $2' input1..n | pr -t --columns=n > out


    This assumes each file has the same number of lines.






    share|improve this answer























    • The best answer for this scenario.

      – Rakesh Sharma
      Feb 20 at 1:00










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    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    You could do the whole thing in a BEGIN statement using getline



    awk '
    BEGIN
    while(1)
    line = sep = ""
    for (i = 1; i < ARGC; i++)
    if ((getline < ARGV[i]) <= 0) exit
    line = line sep $2
    sep = OFS

    print line

    ' input1..n > out





    share|improve this answer

























    • Is there any way we can use ORS? I was trying that but it doesn't work with multiple files.

      – Prvt_Yadv
      Feb 19 at 14:04











    • @PRY, there was a missing loop. It should be fixed now.

      – Stéphane Chazelas
      Feb 19 at 14:04











    • Sorry, I was asking in general manner, not related to your answer.

      – Prvt_Yadv
      Feb 19 at 14:05






    • 1





      @HitanshuSachania, getline retrieves one record from the given input file and return 0 upon end-of-file or a negative number upon error in which case we exit (so we stop as soon as we've reached the end of any of the input files so the number of records in the output file is that of the input file with fewest records).

      – Stéphane Chazelas
      Feb 19 at 14:51







    • 1





      @HitanshuSachania, not it builds one line of output (in line) at a time, as opposed to storing all the lines of output in an array and printing it at the end. We could skip storing the line in line and print the fields as they come, but that would cause problem for the last record if not all input files have the same number of records.

      – Stéphane Chazelas
      Feb 19 at 15:48
















    1














    You could do the whole thing in a BEGIN statement using getline



    awk '
    BEGIN
    while(1)
    line = sep = ""
    for (i = 1; i < ARGC; i++)
    if ((getline < ARGV[i]) <= 0) exit
    line = line sep $2
    sep = OFS

    print line

    ' input1..n > out





    share|improve this answer

























    • Is there any way we can use ORS? I was trying that but it doesn't work with multiple files.

      – Prvt_Yadv
      Feb 19 at 14:04











    • @PRY, there was a missing loop. It should be fixed now.

      – Stéphane Chazelas
      Feb 19 at 14:04











    • Sorry, I was asking in general manner, not related to your answer.

      – Prvt_Yadv
      Feb 19 at 14:05






    • 1





      @HitanshuSachania, getline retrieves one record from the given input file and return 0 upon end-of-file or a negative number upon error in which case we exit (so we stop as soon as we've reached the end of any of the input files so the number of records in the output file is that of the input file with fewest records).

      – Stéphane Chazelas
      Feb 19 at 14:51







    • 1





      @HitanshuSachania, not it builds one line of output (in line) at a time, as opposed to storing all the lines of output in an array and printing it at the end. We could skip storing the line in line and print the fields as they come, but that would cause problem for the last record if not all input files have the same number of records.

      – Stéphane Chazelas
      Feb 19 at 15:48














    1












    1








    1







    You could do the whole thing in a BEGIN statement using getline



    awk '
    BEGIN
    while(1)
    line = sep = ""
    for (i = 1; i < ARGC; i++)
    if ((getline < ARGV[i]) <= 0) exit
    line = line sep $2
    sep = OFS

    print line

    ' input1..n > out





    share|improve this answer















    You could do the whole thing in a BEGIN statement using getline



    awk '
    BEGIN
    while(1)
    line = sep = ""
    for (i = 1; i < ARGC; i++)
    if ((getline < ARGV[i]) <= 0) exit
    line = line sep $2
    sep = OFS

    print line

    ' input1..n > out






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Feb 19 at 14:17

























    answered Feb 19 at 13:39









    Stéphane ChazelasStéphane Chazelas

    310k57584945




    310k57584945












    • Is there any way we can use ORS? I was trying that but it doesn't work with multiple files.

      – Prvt_Yadv
      Feb 19 at 14:04











    • @PRY, there was a missing loop. It should be fixed now.

      – Stéphane Chazelas
      Feb 19 at 14:04











    • Sorry, I was asking in general manner, not related to your answer.

      – Prvt_Yadv
      Feb 19 at 14:05






    • 1





      @HitanshuSachania, getline retrieves one record from the given input file and return 0 upon end-of-file or a negative number upon error in which case we exit (so we stop as soon as we've reached the end of any of the input files so the number of records in the output file is that of the input file with fewest records).

      – Stéphane Chazelas
      Feb 19 at 14:51







    • 1





      @HitanshuSachania, not it builds one line of output (in line) at a time, as opposed to storing all the lines of output in an array and printing it at the end. We could skip storing the line in line and print the fields as they come, but that would cause problem for the last record if not all input files have the same number of records.

      – Stéphane Chazelas
      Feb 19 at 15:48


















    • Is there any way we can use ORS? I was trying that but it doesn't work with multiple files.

      – Prvt_Yadv
      Feb 19 at 14:04











    • @PRY, there was a missing loop. It should be fixed now.

      – Stéphane Chazelas
      Feb 19 at 14:04











    • Sorry, I was asking in general manner, not related to your answer.

      – Prvt_Yadv
      Feb 19 at 14:05






    • 1





      @HitanshuSachania, getline retrieves one record from the given input file and return 0 upon end-of-file or a negative number upon error in which case we exit (so we stop as soon as we've reached the end of any of the input files so the number of records in the output file is that of the input file with fewest records).

      – Stéphane Chazelas
      Feb 19 at 14:51







    • 1





      @HitanshuSachania, not it builds one line of output (in line) at a time, as opposed to storing all the lines of output in an array and printing it at the end. We could skip storing the line in line and print the fields as they come, but that would cause problem for the last record if not all input files have the same number of records.

      – Stéphane Chazelas
      Feb 19 at 15:48

















    Is there any way we can use ORS? I was trying that but it doesn't work with multiple files.

    – Prvt_Yadv
    Feb 19 at 14:04





    Is there any way we can use ORS? I was trying that but it doesn't work with multiple files.

    – Prvt_Yadv
    Feb 19 at 14:04













    @PRY, there was a missing loop. It should be fixed now.

    – Stéphane Chazelas
    Feb 19 at 14:04





    @PRY, there was a missing loop. It should be fixed now.

    – Stéphane Chazelas
    Feb 19 at 14:04













    Sorry, I was asking in general manner, not related to your answer.

    – Prvt_Yadv
    Feb 19 at 14:05





    Sorry, I was asking in general manner, not related to your answer.

    – Prvt_Yadv
    Feb 19 at 14:05




    1




    1





    @HitanshuSachania, getline retrieves one record from the given input file and return 0 upon end-of-file or a negative number upon error in which case we exit (so we stop as soon as we've reached the end of any of the input files so the number of records in the output file is that of the input file with fewest records).

    – Stéphane Chazelas
    Feb 19 at 14:51






    @HitanshuSachania, getline retrieves one record from the given input file and return 0 upon end-of-file or a negative number upon error in which case we exit (so we stop as soon as we've reached the end of any of the input files so the number of records in the output file is that of the input file with fewest records).

    – Stéphane Chazelas
    Feb 19 at 14:51





    1




    1





    @HitanshuSachania, not it builds one line of output (in line) at a time, as opposed to storing all the lines of output in an array and printing it at the end. We could skip storing the line in line and print the fields as they come, but that would cause problem for the last record if not all input files have the same number of records.

    – Stéphane Chazelas
    Feb 19 at 15:48






    @HitanshuSachania, not it builds one line of output (in line) at a time, as opposed to storing all the lines of output in an array and printing it at the end. We could skip storing the line in line and print the fields as they come, but that would cause problem for the last record if not all input files have the same number of records.

    – Stéphane Chazelas
    Feb 19 at 15:48














    1














    You could construct a paste command to put all the second columns together:



    cmd="paste"
    for x in input1..n; do
    cmd="$cmd <(awk 'print $2;' $x)"
    done
    echo $cmd
    eval $cmd





    share|improve this answer



























      1














      You could construct a paste command to put all the second columns together:



      cmd="paste"
      for x in input1..n; do
      cmd="$cmd <(awk 'print $2;' $x)"
      done
      echo $cmd
      eval $cmd





      share|improve this answer

























        1












        1








        1







        You could construct a paste command to put all the second columns together:



        cmd="paste"
        for x in input1..n; do
        cmd="$cmd <(awk 'print $2;' $x)"
        done
        echo $cmd
        eval $cmd





        share|improve this answer













        You could construct a paste command to put all the second columns together:



        cmd="paste"
        for x in input1..n; do
        cmd="$cmd <(awk 'print $2;' $x)"
        done
        echo $cmd
        eval $cmd






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Feb 19 at 14:05









        NickDNickD

        1,7181314




        1,7181314





















            1














            using this post as reference



            awk 'a[FNR] = a[FNR]" " $2ENDfor(i=1;i<=FNR;i++) print a[i]' input1..n


            an array holds each line from different files



            FNR number of records read in current input file, set to zero at begining of each file.



            ENDfor(i=1;i<FNR;i++) print a[i] 


            prints the content of array a on END of file






            share|improve this answer

























            • What is the purpose of the double quotes before $2 and how does the array a store just the 2nd column?

              – Hitanshu Sachania
              Feb 19 at 14:14












            • Note that it stores the whole output in memory before starting to print it.

              – Stéphane Chazelas
              Feb 19 at 14:16











            • I changed the lstaro of the loop froom 0 to 1

              – Emilio Galarraga
              Feb 19 at 14:23






            • 1





              the double quotes before $2 defile the delimiter between columns in the output file and the script is passing the value in $2 to a[FNR] element of the array

              – Emilio Galarraga
              Feb 19 at 14:27











            • Use a[FNR]=!a[FNR]?$2:a[FNR]" "$2 to eleminate white space in front of each line...

              – RoVo
              Feb 19 at 14:35















            1














            using this post as reference



            awk 'a[FNR] = a[FNR]" " $2ENDfor(i=1;i<=FNR;i++) print a[i]' input1..n


            an array holds each line from different files



            FNR number of records read in current input file, set to zero at begining of each file.



            ENDfor(i=1;i<FNR;i++) print a[i] 


            prints the content of array a on END of file






            share|improve this answer

























            • What is the purpose of the double quotes before $2 and how does the array a store just the 2nd column?

              – Hitanshu Sachania
              Feb 19 at 14:14












            • Note that it stores the whole output in memory before starting to print it.

              – Stéphane Chazelas
              Feb 19 at 14:16











            • I changed the lstaro of the loop froom 0 to 1

              – Emilio Galarraga
              Feb 19 at 14:23






            • 1





              the double quotes before $2 defile the delimiter between columns in the output file and the script is passing the value in $2 to a[FNR] element of the array

              – Emilio Galarraga
              Feb 19 at 14:27











            • Use a[FNR]=!a[FNR]?$2:a[FNR]" "$2 to eleminate white space in front of each line...

              – RoVo
              Feb 19 at 14:35













            1












            1








            1







            using this post as reference



            awk 'a[FNR] = a[FNR]" " $2ENDfor(i=1;i<=FNR;i++) print a[i]' input1..n


            an array holds each line from different files



            FNR number of records read in current input file, set to zero at begining of each file.



            ENDfor(i=1;i<FNR;i++) print a[i] 


            prints the content of array a on END of file






            share|improve this answer















            using this post as reference



            awk 'a[FNR] = a[FNR]" " $2ENDfor(i=1;i<=FNR;i++) print a[i]' input1..n


            an array holds each line from different files



            FNR number of records read in current input file, set to zero at begining of each file.



            ENDfor(i=1;i<FNR;i++) print a[i] 


            prints the content of array a on END of file







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Feb 19 at 14:22

























            answered Feb 19 at 14:04









            Emilio GalarragaEmilio Galarraga

            55439




            55439












            • What is the purpose of the double quotes before $2 and how does the array a store just the 2nd column?

              – Hitanshu Sachania
              Feb 19 at 14:14












            • Note that it stores the whole output in memory before starting to print it.

              – Stéphane Chazelas
              Feb 19 at 14:16











            • I changed the lstaro of the loop froom 0 to 1

              – Emilio Galarraga
              Feb 19 at 14:23






            • 1





              the double quotes before $2 defile the delimiter between columns in the output file and the script is passing the value in $2 to a[FNR] element of the array

              – Emilio Galarraga
              Feb 19 at 14:27











            • Use a[FNR]=!a[FNR]?$2:a[FNR]" "$2 to eleminate white space in front of each line...

              – RoVo
              Feb 19 at 14:35

















            • What is the purpose of the double quotes before $2 and how does the array a store just the 2nd column?

              – Hitanshu Sachania
              Feb 19 at 14:14












            • Note that it stores the whole output in memory before starting to print it.

              – Stéphane Chazelas
              Feb 19 at 14:16











            • I changed the lstaro of the loop froom 0 to 1

              – Emilio Galarraga
              Feb 19 at 14:23






            • 1





              the double quotes before $2 defile the delimiter between columns in the output file and the script is passing the value in $2 to a[FNR] element of the array

              – Emilio Galarraga
              Feb 19 at 14:27











            • Use a[FNR]=!a[FNR]?$2:a[FNR]" "$2 to eleminate white space in front of each line...

              – RoVo
              Feb 19 at 14:35
















            What is the purpose of the double quotes before $2 and how does the array a store just the 2nd column?

            – Hitanshu Sachania
            Feb 19 at 14:14






            What is the purpose of the double quotes before $2 and how does the array a store just the 2nd column?

            – Hitanshu Sachania
            Feb 19 at 14:14














            Note that it stores the whole output in memory before starting to print it.

            – Stéphane Chazelas
            Feb 19 at 14:16





            Note that it stores the whole output in memory before starting to print it.

            – Stéphane Chazelas
            Feb 19 at 14:16













            I changed the lstaro of the loop froom 0 to 1

            – Emilio Galarraga
            Feb 19 at 14:23





            I changed the lstaro of the loop froom 0 to 1

            – Emilio Galarraga
            Feb 19 at 14:23




            1




            1





            the double quotes before $2 defile the delimiter between columns in the output file and the script is passing the value in $2 to a[FNR] element of the array

            – Emilio Galarraga
            Feb 19 at 14:27





            the double quotes before $2 defile the delimiter between columns in the output file and the script is passing the value in $2 to a[FNR] element of the array

            – Emilio Galarraga
            Feb 19 at 14:27













            Use a[FNR]=!a[FNR]?$2:a[FNR]" "$2 to eleminate white space in front of each line...

            – RoVo
            Feb 19 at 14:35





            Use a[FNR]=!a[FNR]?$2:a[FNR]" "$2 to eleminate white space in front of each line...

            – RoVo
            Feb 19 at 14:35











            1














            I would use the pr tool, which is designed to columnize data:



            awk 'print $2' input1..n | pr -t --columns=n > out


            This assumes each file has the same number of lines.






            share|improve this answer























            • The best answer for this scenario.

              – Rakesh Sharma
              Feb 20 at 1:00















            1














            I would use the pr tool, which is designed to columnize data:



            awk 'print $2' input1..n | pr -t --columns=n > out


            This assumes each file has the same number of lines.






            share|improve this answer























            • The best answer for this scenario.

              – Rakesh Sharma
              Feb 20 at 1:00













            1












            1








            1







            I would use the pr tool, which is designed to columnize data:



            awk 'print $2' input1..n | pr -t --columns=n > out


            This assumes each file has the same number of lines.






            share|improve this answer













            I would use the pr tool, which is designed to columnize data:



            awk 'print $2' input1..n | pr -t --columns=n > out


            This assumes each file has the same number of lines.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Feb 19 at 14:48









            glenn jackmanglenn jackman

            52.3k572113




            52.3k572113












            • The best answer for this scenario.

              – Rakesh Sharma
              Feb 20 at 1:00

















            • The best answer for this scenario.

              – Rakesh Sharma
              Feb 20 at 1:00
















            The best answer for this scenario.

            – Rakesh Sharma
            Feb 20 at 1:00





            The best answer for this scenario.

            – Rakesh Sharma
            Feb 20 at 1:00

















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