Filling In Region of 3D Plot
Clash Royale CLAN TAG#URR8PPP
2
I am trying to fill in the area under this 3D graph, using the idea from this post. Here is a MWE for the function I want to plot under:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endaxis
endtikzpicture
enddocument
Here is the result:
Now, here is the MWE with the code that should shade in the sides:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And this is the result:
Can anyone make any suggestions as to what is going on? It seems when I add multiple functions to the same plot via addplot3, everything gets messed up.
Sorry if this seems like a "just fix this for me," but I have no idea what I'm doing wrong.
EDIT
I now see that for some reason, when adding the new plots to shade in the side, the domain was changed from (0,2) to (-4,4), so setting the domain as you add the plots helps:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And here is the result:
My question now is, why is the original function shifted up?
ANOTHER EDIT
I have figured out a way to get what I want (not including the excellent answers below), but I still have some more concerns. Here is a MWE with a good result:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
beginaxis[
zmax=1.25,
zmin=0,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
%shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
Which give this result:
Now, the issue is the %shader=interp, line. When I uncomment this out, this happens:
So does this command force the graph to shift upwards for some reason? Why does this happen?
tikz-pgf pgfplots 3d
edited Feb 19 at 11:58
Raaja
4,98421442
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
add a comment |
2
I am trying to fill in the area under this 3D graph, using the idea from this post. Here is a MWE for the function I want to plot under:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endaxis
endtikzpicture
enddocument
Here is the result:
Now, here is the MWE with the code that should shade in the sides:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And this is the result:
Can anyone make any suggestions as to what is going on? It seems when I add multiple functions to the same plot via addplot3, everything gets messed up.
Sorry if this seems like a "just fix this for me," but I have no idea what I'm doing wrong.
EDIT
I now see that for some reason, when adding the new plots to shade in the side, the domain was changed from (0,2) to (-4,4), so setting the domain as you add the plots helps:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And here is the result:
My question now is, why is the original function shifted up?
ANOTHER EDIT
I have figured out a way to get what I want (not including the excellent answers below), but I still have some more concerns. Here is a MWE with a good result:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
beginaxis[
zmax=1.25,
zmin=0,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
%shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
Which give this result:
Now, the issue is the %shader=interp, line. When I uncomment this out, this happens:
So does this command force the graph to shift upwards for some reason? Why does this happen?
tikz-pgf pgfplots 3d
edited Feb 19 at 11:58
Raaja
4,98421442
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
I cannot find a picture of exactly what I need, but I just added another picture which is a closer resemblance to what I need. Pretty much I want to fill in the sides of the graph with the same color as the function.
– Aiden Kenny
Feb 19 at 10:47
add a comment |
2
2
2
I am trying to fill in the area under this 3D graph, using the idea from this post. Here is a MWE for the function I want to plot under:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endaxis
endtikzpicture
enddocument
Here is the result:
Now, here is the MWE with the code that should shade in the sides:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And this is the result:
Can anyone make any suggestions as to what is going on? It seems when I add multiple functions to the same plot via addplot3, everything gets messed up.
Sorry if this seems like a "just fix this for me," but I have no idea what I'm doing wrong.
EDIT
I now see that for some reason, when adding the new plots to shade in the side, the domain was changed from (0,2) to (-4,4), so setting the domain as you add the plots helps:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And here is the result:
My question now is, why is the original function shifted up?
ANOTHER EDIT
I have figured out a way to get what I want (not including the excellent answers below), but I still have some more concerns. Here is a MWE with a good result:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
beginaxis[
zmax=1.25,
zmin=0,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
%shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
Which give this result:
Now, the issue is the %shader=interp, line. When I uncomment this out, this happens:
So does this command force the graph to shift upwards for some reason? Why does this happen?
tikz-pgf pgfplots 3d
edited Feb 19 at 11:58
Raaja
4,98421442
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
I am trying to fill in the area under this 3D graph, using the idea from this post. Here is a MWE for the function I want to plot under:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endaxis
endtikzpicture
enddocument
Here is the result:
Now, here is the MWE with the code that should shade in the sides:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And this is the result:
Can anyone make any suggestions as to what is going on? It seems when I add multiple functions to the same plot via addplot3, everything gets messed up.
Sorry if this seems like a "just fix this for me," but I have no idea what I'm doing wrong.
EDIT
I now see that for some reason, when adding the new plots to shade in the side, the domain was changed from (0,2) to (-4,4), so setting the domain as you add the plots helps:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
beginpgfonlayerpre main
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
endpgfonlayer
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
And here is the result:
My question now is, why is the original function shifted up?
ANOTHER EDIT
I have figured out a way to get what I want (not including the excellent answers below), but I still have some more concerns. Here is a MWE with a good result:
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture
beginaxis[
zmax=1.25,
zmin=0,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
%shader=interp,
opacity=0.5,
]
exp(-(x^2+y^2));
addplot3 [name path = xline, draw = none, domain=0:2] (x,0,0);
% x is the variable
% second 0 is the y coordinate of the leftmost part of the graph
% third 0 is height
addplot3 [name path = yline, draw = none, domain=0:2] (2,y,0);
% y is the variable
% first 2 is the x coordinate of the rightmost part of the graph
% third 0 is height
addplot3 [name path = xcurve, domain=0:2, y domain = 0:0, draw = none]
(x, 0, exp(-x^2));
% now instead of height being 0, it is height of function
addplot3 [name path = ycurve, domain=0:2, y domain = 0:0, draw = none]
(2, x, exp(-(x^2 + 4)));
% same idea
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = xcurve and xline];
% fills in x axis
addplot [color = SteelBlue3, opacity = 0.5, draw = none]
fill between[of = yline and ycurve, reverse = true];
endaxis
endtikzpicture
enddocument
Which give this result:
Now, the issue is the %shader=interp, line. When I uncomment this out, this happens:
So does this command force the graph to shift upwards for some reason? Why does this happen?
tikz-pgf pgfplots 3d
tikz-pgf pgfplots 3d
edited Feb 19 at 11:58
Raaja
4,98421442
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
edited Feb 19 at 11:58
Raaja
4,98421442
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
edited Feb 19 at 11:58
Raaja
4,98421442
edited Feb 19 at 11:58
Raaja
4,98421442
edited Feb 19 at 11:58
Raaja
4,98421442
4,98421442
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
asked Feb 19 at 10:33
Aiden KennyAiden Kenny
4437
4437
I cannot find a picture of exactly what I need, but I just added another picture which is a closer resemblance to what I need. Pretty much I want to fill in the sides of the graph with the same color as the function.
– Aiden Kenny
Feb 19 at 10:47
add a comment |
I cannot find a picture of exactly what I need, but I just added another picture which is a closer resemblance to what I need. Pretty much I want to fill in the sides of the graph with the same color as the function.
– Aiden Kenny
Feb 19 at 10:47
I cannot find a picture of exactly what I need, but I just added another picture which is a closer resemblance to what I need. Pretty much I want to fill in the sides of the graph with the same color as the function.
– Aiden Kenny
Feb 19 at 10:47
I cannot find a picture of exactly what I need, but I just added another picture which is a closer resemblance to what I need. Pretty much I want to fill in the sides of the graph with the same color as the function.
– Aiden Kenny
Feb 19 at 10:47
add a comment |
1 Answer
1
active
oldest
votes
5
Something like this?
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.16
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture[declare function=f(x,y)=exp(-(x*x+y*y));]
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
f(x,y);
fill[blue] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[blue!80] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
endaxis
endtikzpicture
enddocument
Or, if you do the fills with
fill[SteelBlue3] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[SteelBlue3] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
you get
Notice that I added pgfplotssetcompat=1.16. If you do not want that, you need to prepend the coordinates with axis cs:
fill[SteelBlue3] (axis cs:0,0,-1) -- plot[variable=x,domain=0:2] (axis cs:x,0,f(x,0)) -- (axis cs:2,0,-1) --
cycle;
fill[SteelBlue3] (axis cs:2,0,-1) -- plot[variable=y,domain=0:2] (axis cs:2,y,f(2,y))
-- (axis cs:2,2,-1) --cycle;
answered Feb 19 at 10:50
marmotmarmot
108k5133251
Exactly! I would like the sides to be the same color, but that can obviously be changed very easily.
– Aiden Kenny
Feb 19 at 10:55
@AidenKenny Yes, that's simple, I added something. (In principle one could do it then in one stretch but that does not make the code substantially simpler).
– marmot
Feb 19 at 11:04
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
Something like this?
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.16
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture[declare function=f(x,y)=exp(-(x*x+y*y));]
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
f(x,y);
fill[blue] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[blue!80] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
endaxis
endtikzpicture
enddocument
Or, if you do the fills with
fill[SteelBlue3] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[SteelBlue3] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
you get
Notice that I added pgfplotssetcompat=1.16. If you do not want that, you need to prepend the coordinates with axis cs:
fill[SteelBlue3] (axis cs:0,0,-1) -- plot[variable=x,domain=0:2] (axis cs:x,0,f(x,0)) -- (axis cs:2,0,-1) --
cycle;
fill[SteelBlue3] (axis cs:2,0,-1) -- plot[variable=y,domain=0:2] (axis cs:2,y,f(2,y))
-- (axis cs:2,2,-1) --cycle;
answered Feb 19 at 10:50
marmotmarmot
108k5133251
Exactly! I would like the sides to be the same color, but that can obviously be changed very easily.
– Aiden Kenny
Feb 19 at 10:55
@AidenKenny Yes, that's simple, I added something. (In principle one could do it then in one stretch but that does not make the code substantially simpler).
– marmot
Feb 19 at 11:04
add a comment |
5
Something like this?
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.16
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture[declare function=f(x,y)=exp(-(x*x+y*y));]
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
f(x,y);
fill[blue] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[blue!80] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
endaxis
endtikzpicture
enddocument
Or, if you do the fills with
fill[SteelBlue3] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[SteelBlue3] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
you get
Notice that I added pgfplotssetcompat=1.16. If you do not want that, you need to prepend the coordinates with axis cs:
fill[SteelBlue3] (axis cs:0,0,-1) -- plot[variable=x,domain=0:2] (axis cs:x,0,f(x,0)) -- (axis cs:2,0,-1) --
cycle;
fill[SteelBlue3] (axis cs:2,0,-1) -- plot[variable=y,domain=0:2] (axis cs:2,y,f(2,y))
-- (axis cs:2,2,-1) --cycle;
answered Feb 19 at 10:50
marmotmarmot
108k5133251
Exactly! I would like the sides to be the same color, but that can obviously be changed very easily.
– Aiden Kenny
Feb 19 at 10:55
@AidenKenny Yes, that's simple, I added something. (In principle one could do it then in one stretch but that does not make the code substantially simpler).
– marmot
Feb 19 at 11:04
add a comment |
5
5
5
Something like this?
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.16
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture[declare function=f(x,y)=exp(-(x*x+y*y));]
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
f(x,y);
fill[blue] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[blue!80] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
endaxis
endtikzpicture
enddocument
Or, if you do the fills with
fill[SteelBlue3] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[SteelBlue3] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
you get
Notice that I added pgfplotssetcompat=1.16. If you do not want that, you need to prepend the coordinates with axis cs:
fill[SteelBlue3] (axis cs:0,0,-1) -- plot[variable=x,domain=0:2] (axis cs:x,0,f(x,0)) -- (axis cs:2,0,-1) --
cycle;
fill[SteelBlue3] (axis cs:2,0,-1) -- plot[variable=y,domain=0:2] (axis cs:2,y,f(2,y))
-- (axis cs:2,2,-1) --cycle;
answered Feb 19 at 10:50
marmotmarmot
108k5133251
Something like this?
PassOptionsToPackageusenames,dvipsnames,table,x11namesxcolor
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.16
usepgfplotslibrarycolormaps,fillbetween
begindocument
begintikzpicture[declare function=f(x,y)=exp(-(x*x+y*y));]
pgfdeclarelayerpre main
pgfsetlayerspre main,main
beginaxis[
zmax=1.25,
view = 4545,
grid=minor,
colormap=mycolcolor=(SteelBlue3), color=(SteelBlue3),
xlabel = $x$,
ylabel = $y$,
zlabel = $f(x,y)$,
]
addplot3[
surf,
samples=30,
domain=0:2,
shader=interp,
opacity=0.5,
]
f(x,y);
fill[blue] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[blue!80] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
endaxis
endtikzpicture
enddocument
Or, if you do the fills with
fill[SteelBlue3] (0,0,-1) -- plot[variable=x,domain=0:2] (x,0,f(x,0)) -- (2,0,-1) --
cycle;
fill[SteelBlue3] (2,0,-1) -- plot[variable=y,domain=0:2] (2,y,f(2,y))
-- (2,2,-1) --cycle;
you get
Notice that I added pgfplotssetcompat=1.16. If you do not want that, you need to prepend the coordinates with axis cs:
fill[SteelBlue3] (axis cs:0,0,-1) -- plot[variable=x,domain=0:2] (axis cs:x,0,f(x,0)) -- (axis cs:2,0,-1) --
cycle;
fill[SteelBlue3] (axis cs:2,0,-1) -- plot[variable=y,domain=0:2] (axis cs:2,y,f(2,y))
-- (axis cs:2,2,-1) --cycle;
answered Feb 19 at 10:50
marmotmarmot
108k5133251
edited Feb 19 at 11:24
answered Feb 19 at 10:50
marmotmarmot
108k5133251
answered Feb 19 at 10:50
marmotmarmot
108k5133251
answered Feb 19 at 10:50
marmotmarmot
108k5133251
108k5133251
Exactly! I would like the sides to be the same color, but that can obviously be changed very easily.
– Aiden Kenny
Feb 19 at 10:55
@AidenKenny Yes, that's simple, I added something. (In principle one could do it then in one stretch but that does not make the code substantially simpler).
– marmot
Feb 19 at 11:04
add a comment |
Exactly! I would like the sides to be the same color, but that can obviously be changed very easily.
– Aiden Kenny
Feb 19 at 10:55
@AidenKenny Yes, that's simple, I added something. (In principle one could do it then in one stretch but that does not make the code substantially simpler).
– marmot
Feb 19 at 11:04
Exactly! I would like the sides to be the same color, but that can obviously be changed very easily.
– Aiden Kenny
Feb 19 at 10:55
Exactly! I would like the sides to be the same color, but that can obviously be changed very easily.
– Aiden Kenny
Feb 19 at 10:55
@AidenKenny Yes, that's simple, I added something. (In principle one could do it then in one stretch but that does not make the code substantially simpler).
– marmot
Feb 19 at 11:04
@AidenKenny Yes, that's simple, I added something. (In principle one could do it then in one stretch but that does not make the code substantially simpler).
– marmot
Feb 19 at 11:04
add a comment |
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I cannot find a picture of exactly what I need, but I just added another picture which is a closer resemblance to what I need. Pretty much I want to fill in the sides of the graph with the same color as the function.
– Aiden Kenny
Feb 19 at 10:47