Show circle with points coloured red and blue must have monochromatic red equilateral triangle
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Colour each point on a circle of radius $frac12$ red or blue, such that the region of blue points has length $1$. Prove that we can inscribe an equilateral triangle in the circle such that all three vertices are red.
I think the Pigeonhole Principle will be involved, but don't quite see how to apply it. The length condition also seems a bit hard to work with, so any hints or suggestions would be much appreciated.
combinatorics discrete-mathematics
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up vote
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down vote
favorite
Colour each point on a circle of radius $frac12$ red or blue, such that the region of blue points has length $1$. Prove that we can inscribe an equilateral triangle in the circle such that all three vertices are red.
I think the Pigeonhole Principle will be involved, but don't quite see how to apply it. The length condition also seems a bit hard to work with, so any hints or suggestions would be much appreciated.
combinatorics discrete-mathematics
1
What does "region of blue points has length 1" mean? Is one of the assumptions that the blue set is measurable?
– John Hughes
Dec 9 at 21:41
Yes, we are essentially assuming that you can get all the blue points together in a line and measure its length.
– Prasiortle
Dec 9 at 21:53
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
Colour each point on a circle of radius $frac12$ red or blue, such that the region of blue points has length $1$. Prove that we can inscribe an equilateral triangle in the circle such that all three vertices are red.
I think the Pigeonhole Principle will be involved, but don't quite see how to apply it. The length condition also seems a bit hard to work with, so any hints or suggestions would be much appreciated.
combinatorics discrete-mathematics
Colour each point on a circle of radius $frac12$ red or blue, such that the region of blue points has length $1$. Prove that we can inscribe an equilateral triangle in the circle such that all three vertices are red.
I think the Pigeonhole Principle will be involved, but don't quite see how to apply it. The length condition also seems a bit hard to work with, so any hints or suggestions would be much appreciated.
combinatorics discrete-mathematics
combinatorics discrete-mathematics
edited Dec 9 at 22:16
Jean Marie
28.7k41849
28.7k41849
asked Dec 9 at 21:31
Prasiortle
1075
1075
1
What does "region of blue points has length 1" mean? Is one of the assumptions that the blue set is measurable?
– John Hughes
Dec 9 at 21:41
Yes, we are essentially assuming that you can get all the blue points together in a line and measure its length.
– Prasiortle
Dec 9 at 21:53
add a comment |
1
What does "region of blue points has length 1" mean? Is one of the assumptions that the blue set is measurable?
– John Hughes
Dec 9 at 21:41
Yes, we are essentially assuming that you can get all the blue points together in a line and measure its length.
– Prasiortle
Dec 9 at 21:53
1
1
What does "region of blue points has length 1" mean? Is one of the assumptions that the blue set is measurable?
– John Hughes
Dec 9 at 21:41
What does "region of blue points has length 1" mean? Is one of the assumptions that the blue set is measurable?
– John Hughes
Dec 9 at 21:41
Yes, we are essentially assuming that you can get all the blue points together in a line and measure its length.
– Prasiortle
Dec 9 at 21:53
Yes, we are essentially assuming that you can get all the blue points together in a line and measure its length.
– Prasiortle
Dec 9 at 21:53
add a comment |
1 Answer
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Make all the red points that are a distance exactly $frac 2pi3$ away from a blue point blue. The measure of the blue points is now no more than $3$, but the circumference of the circle is $pi$. There is at least $pi-3$ of the circle still colored red and any of the red points is on an all red equilateral triangle.
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
10
down vote
Make all the red points that are a distance exactly $frac 2pi3$ away from a blue point blue. The measure of the blue points is now no more than $3$, but the circumference of the circle is $pi$. There is at least $pi-3$ of the circle still colored red and any of the red points is on an all red equilateral triangle.
add a comment |
up vote
10
down vote
Make all the red points that are a distance exactly $frac 2pi3$ away from a blue point blue. The measure of the blue points is now no more than $3$, but the circumference of the circle is $pi$. There is at least $pi-3$ of the circle still colored red and any of the red points is on an all red equilateral triangle.
add a comment |
up vote
10
down vote
up vote
10
down vote
Make all the red points that are a distance exactly $frac 2pi3$ away from a blue point blue. The measure of the blue points is now no more than $3$, but the circumference of the circle is $pi$. There is at least $pi-3$ of the circle still colored red and any of the red points is on an all red equilateral triangle.
Make all the red points that are a distance exactly $frac 2pi3$ away from a blue point blue. The measure of the blue points is now no more than $3$, but the circumference of the circle is $pi$. There is at least $pi-3$ of the circle still colored red and any of the red points is on an all red equilateral triangle.
edited Dec 10 at 5:22
Acccumulation
6,6512616
6,6512616
answered Dec 9 at 21:41
Ross Millikan
290k23196369
290k23196369
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1
What does "region of blue points has length 1" mean? Is one of the assumptions that the blue set is measurable?
– John Hughes
Dec 9 at 21:41
Yes, we are essentially assuming that you can get all the blue points together in a line and measure its length.
– Prasiortle
Dec 9 at 21:53