Commenting an equation with a vertical bar
Clash Royale CLAN TAG#URR8PPP
8
I want to use a vertical bar to comment on solving a simple equation.
Do you know a way to do that with LaTeX ?
equations line vertical bar
asked Dec 17 at 21:36
gilhoo
485
add a comment |
8
I want to use a vertical bar to comment on solving a simple equation.
Do you know a way to do that with LaTeX ?
equations line vertical bar
asked Dec 17 at 21:36
gilhoo
485
Welcome to TeX.SE!
– Sebastiano
Dec 17 at 21:40
add a comment |
8
8
8
2
I want to use a vertical bar to comment on solving a simple equation.
Do you know a way to do that with LaTeX ?
equations line vertical bar
asked Dec 17 at 21:36
gilhoo
485
I want to use a vertical bar to comment on solving a simple equation.
Do you know a way to do that with LaTeX ?
equations line vertical bar
equations line vertical bar
asked Dec 17 at 21:36
gilhoo
485
asked Dec 17 at 21:36
gilhoo
485
edited Dec 17 at 22:26
asked Dec 17 at 21:36
gilhoo
485
asked Dec 17 at 21:36
gilhoo
485
asked Dec 17 at 21:36
gilhoo
485
485
Welcome to TeX.SE!
– Sebastiano
Dec 17 at 21:40
add a comment |
Welcome to TeX.SE!
– Sebastiano
Dec 17 at 21:40
Welcome to TeX.SE!
– Sebastiano
Dec 17 at 21:40
Welcome to TeX.SE!
– Sebastiano
Dec 17 at 21:40
add a comment |
3 Answers
3
active
oldest
votes
11
Yes, it's possible:
documentclassarticle
usepackageamsmath,array
begindocument
beginequation*
renewcommandarraystretch1.2
setlengtharraycolsep0pt
beginarray
>displaystyler % right aligned
>displaystylel % left aligned
@hspace4em % spacing
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endarray
endequation*
enddocument
If you're satisfied by the spacing, you can make this into an environment:
documentclassarticle
usepackageamsmath,array
newenvironmentsolve
%
renewcommandarraystretch1.2%
setlengtharraycolsep0pt%
beginarray % vertical rule
@hspace2em % spacing
>displaystyler % comments
%
%
endarray
begindocument
beginequation*
beginsolve
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endsolve
endequation*
enddocument
answered Dec 17 at 21:52
egreg
708k8618813163
add a comment |
3
It almost seems better to use a different format, which allows you easier control of numbering elements within a sequence if needed.
documentclassarticle
usepackageamsmath
newcommandeqcomment[1]& triangleright~ & #1
begindocument
beginalign*
2x + 2 &= 7x + 3 eqcomment-2 \
2x &= 7x + 1 eqcomment-7x \
-5x &= 1 eqcommentdiv(-5) \
x &= boxed-frac15
endalign*
enddocument
One can play around with the alignment and notation.
answered Dec 17 at 22:14
Werner
437k649581648
add a comment |
3
Two other possibilities:
documentclassarticle
usepackageshowframe
renewcommandShowFrameLinethickness0.3pt
usepackageeqparbox
usepackageamsmath,array
begindocument
beginflalign*
qquad & & 2x+2 &= 7x+3 &smashrule[-4.5baselineskip]0.5pt5.5baselineskip quadeqmakebox[B][r]$ -2 $ & \
& & 2x &= 7x+1 &eqmakebox[B][r]$ -7x $& \
& & -5x &= 1 & eqmakebox[B][r]$ div(-5) $ & \
& & x &= boxed-frac15 & &
endflalign*
beginalignat*2
qquad2x+2 &= 7x+3 &hspace6emsmashrule[-5baselineskip]0.5pt6baselineskip qquad-2 & \
2x &= 7x+1 & -7 x & \
-5x &= 1 &div(-5) & \
x &= boxed-frac15 & &
endalignat*
enddocument
answered Dec 17 at 22:27
Bernard
165k769193
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
11
Yes, it's possible:
documentclassarticle
usepackageamsmath,array
begindocument
beginequation*
renewcommandarraystretch1.2
setlengtharraycolsep0pt
beginarray
>displaystyler % right aligned
>displaystylel % left aligned
@hspace4em % spacing
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endarray
endequation*
enddocument
If you're satisfied by the spacing, you can make this into an environment:
documentclassarticle
usepackageamsmath,array
newenvironmentsolve
%
renewcommandarraystretch1.2%
setlengtharraycolsep0pt%
beginarray % vertical rule
@hspace2em % spacing
>displaystyler % comments
%
%
endarray
begindocument
beginequation*
beginsolve
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endsolve
endequation*
enddocument
answered Dec 17 at 21:52
egreg
708k8618813163
add a comment |
11
Yes, it's possible:
documentclassarticle
usepackageamsmath,array
begindocument
beginequation*
renewcommandarraystretch1.2
setlengtharraycolsep0pt
beginarray
>displaystyler % right aligned
>displaystylel % left aligned
@hspace4em % spacing
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endarray
endequation*
enddocument
If you're satisfied by the spacing, you can make this into an environment:
documentclassarticle
usepackageamsmath,array
newenvironmentsolve
%
renewcommandarraystretch1.2%
setlengtharraycolsep0pt%
beginarray % vertical rule
@hspace2em % spacing
>displaystyler % comments
%
%
endarray
begindocument
beginequation*
beginsolve
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endsolve
endequation*
enddocument
answered Dec 17 at 21:52
egreg
708k8618813163
add a comment |
11
11
11
Yes, it's possible:
documentclassarticle
usepackageamsmath,array
begindocument
beginequation*
renewcommandarraystretch1.2
setlengtharraycolsep0pt
beginarray
>displaystyler % right aligned
>displaystylel % left aligned
@hspace4em % spacing
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endarray
endequation*
enddocument
If you're satisfied by the spacing, you can make this into an environment:
documentclassarticle
usepackageamsmath,array
newenvironmentsolve
%
renewcommandarraystretch1.2%
setlengtharraycolsep0pt%
beginarray % vertical rule
@hspace2em % spacing
>displaystyler % comments
%
%
endarray
begindocument
beginequation*
beginsolve
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endsolve
endequation*
enddocument
answered Dec 17 at 21:52
egreg
708k8618813163
Yes, it's possible:
documentclassarticle
usepackageamsmath,array
begindocument
beginequation*
renewcommandarraystretch1.2
setlengtharraycolsep0pt
beginarray
>displaystyler % right aligned
>displaystylel % left aligned
@hspace4em % spacing
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endarray
endequation*
enddocument
If you're satisfied by the spacing, you can make this into an environment:
documentclassarticle
usepackageamsmath,array
newenvironmentsolve
%
renewcommandarraystretch1.2%
setlengtharraycolsep0pt%
beginarray % vertical rule
@hspace2em % spacing
>displaystyler % comments
%
%
endarray
begindocument
beginequation*
beginsolve
2x+2 &= 7x+3 & -2 \
2x &= 7x+1 & -7x \
-5x &= 1 & div(-5) \
x &= boxed-frac15 & \
endsolve
endequation*
enddocument
answered Dec 17 at 21:52
egreg
708k8618813163
answered Dec 17 at 21:52
egreg
708k8618813163
answered Dec 17 at 21:52
egreg
708k8618813163
answered Dec 17 at 21:52
egreg
708k8618813163
708k8618813163
add a comment |
add a comment |
3
It almost seems better to use a different format, which allows you easier control of numbering elements within a sequence if needed.
documentclassarticle
usepackageamsmath
newcommandeqcomment[1]& triangleright~ & #1
begindocument
beginalign*
2x + 2 &= 7x + 3 eqcomment-2 \
2x &= 7x + 1 eqcomment-7x \
-5x &= 1 eqcommentdiv(-5) \
x &= boxed-frac15
endalign*
enddocument
One can play around with the alignment and notation.
answered Dec 17 at 22:14
Werner
437k649581648
add a comment |
3
It almost seems better to use a different format, which allows you easier control of numbering elements within a sequence if needed.
documentclassarticle
usepackageamsmath
newcommandeqcomment[1]& triangleright~ & #1
begindocument
beginalign*
2x + 2 &= 7x + 3 eqcomment-2 \
2x &= 7x + 1 eqcomment-7x \
-5x &= 1 eqcommentdiv(-5) \
x &= boxed-frac15
endalign*
enddocument
One can play around with the alignment and notation.
answered Dec 17 at 22:14
Werner
437k649581648
add a comment |
3
3
3
It almost seems better to use a different format, which allows you easier control of numbering elements within a sequence if needed.
documentclassarticle
usepackageamsmath
newcommandeqcomment[1]& triangleright~ & #1
begindocument
beginalign*
2x + 2 &= 7x + 3 eqcomment-2 \
2x &= 7x + 1 eqcomment-7x \
-5x &= 1 eqcommentdiv(-5) \
x &= boxed-frac15
endalign*
enddocument
One can play around with the alignment and notation.
answered Dec 17 at 22:14
Werner
437k649581648
It almost seems better to use a different format, which allows you easier control of numbering elements within a sequence if needed.
documentclassarticle
usepackageamsmath
newcommandeqcomment[1]& triangleright~ & #1
begindocument
beginalign*
2x + 2 &= 7x + 3 eqcomment-2 \
2x &= 7x + 1 eqcomment-7x \
-5x &= 1 eqcommentdiv(-5) \
x &= boxed-frac15
endalign*
enddocument
One can play around with the alignment and notation.
answered Dec 17 at 22:14
Werner
437k649581648
answered Dec 17 at 22:14
Werner
437k649581648
answered Dec 17 at 22:14
Werner
437k649581648
answered Dec 17 at 22:14
Werner
437k649581648
437k649581648
add a comment |
add a comment |
3
Two other possibilities:
documentclassarticle
usepackageshowframe
renewcommandShowFrameLinethickness0.3pt
usepackageeqparbox
usepackageamsmath,array
begindocument
beginflalign*
qquad & & 2x+2 &= 7x+3 &smashrule[-4.5baselineskip]0.5pt5.5baselineskip quadeqmakebox[B][r]$ -2 $ & \
& & 2x &= 7x+1 &eqmakebox[B][r]$ -7x $& \
& & -5x &= 1 & eqmakebox[B][r]$ div(-5) $ & \
& & x &= boxed-frac15 & &
endflalign*
beginalignat*2
qquad2x+2 &= 7x+3 &hspace6emsmashrule[-5baselineskip]0.5pt6baselineskip qquad-2 & \
2x &= 7x+1 & -7 x & \
-5x &= 1 &div(-5) & \
x &= boxed-frac15 & &
endalignat*
enddocument
answered Dec 17 at 22:27
Bernard
165k769193
add a comment |
3
Two other possibilities:
documentclassarticle
usepackageshowframe
renewcommandShowFrameLinethickness0.3pt
usepackageeqparbox
usepackageamsmath,array
begindocument
beginflalign*
qquad & & 2x+2 &= 7x+3 &smashrule[-4.5baselineskip]0.5pt5.5baselineskip quadeqmakebox[B][r]$ -2 $ & \
& & 2x &= 7x+1 &eqmakebox[B][r]$ -7x $& \
& & -5x &= 1 & eqmakebox[B][r]$ div(-5) $ & \
& & x &= boxed-frac15 & &
endflalign*
beginalignat*2
qquad2x+2 &= 7x+3 &hspace6emsmashrule[-5baselineskip]0.5pt6baselineskip qquad-2 & \
2x &= 7x+1 & -7 x & \
-5x &= 1 &div(-5) & \
x &= boxed-frac15 & &
endalignat*
enddocument
answered Dec 17 at 22:27
Bernard
165k769193
add a comment |
3
3
3
Two other possibilities:
documentclassarticle
usepackageshowframe
renewcommandShowFrameLinethickness0.3pt
usepackageeqparbox
usepackageamsmath,array
begindocument
beginflalign*
qquad & & 2x+2 &= 7x+3 &smashrule[-4.5baselineskip]0.5pt5.5baselineskip quadeqmakebox[B][r]$ -2 $ & \
& & 2x &= 7x+1 &eqmakebox[B][r]$ -7x $& \
& & -5x &= 1 & eqmakebox[B][r]$ div(-5) $ & \
& & x &= boxed-frac15 & &
endflalign*
beginalignat*2
qquad2x+2 &= 7x+3 &hspace6emsmashrule[-5baselineskip]0.5pt6baselineskip qquad-2 & \
2x &= 7x+1 & -7 x & \
-5x &= 1 &div(-5) & \
x &= boxed-frac15 & &
endalignat*
enddocument
answered Dec 17 at 22:27
Bernard
165k769193
Two other possibilities:
documentclassarticle
usepackageshowframe
renewcommandShowFrameLinethickness0.3pt
usepackageeqparbox
usepackageamsmath,array
begindocument
beginflalign*
qquad & & 2x+2 &= 7x+3 &smashrule[-4.5baselineskip]0.5pt5.5baselineskip quadeqmakebox[B][r]$ -2 $ & \
& & 2x &= 7x+1 &eqmakebox[B][r]$ -7x $& \
& & -5x &= 1 & eqmakebox[B][r]$ div(-5) $ & \
& & x &= boxed-frac15 & &
endflalign*
beginalignat*2
qquad2x+2 &= 7x+3 &hspace6emsmashrule[-5baselineskip]0.5pt6baselineskip qquad-2 & \
2x &= 7x+1 & -7 x & \
-5x &= 1 &div(-5) & \
x &= boxed-frac15 & &
endalignat*
enddocument
answered Dec 17 at 22:27
Bernard
165k769193
answered Dec 17 at 22:27
Bernard
165k769193
answered Dec 17 at 22:27
Bernard
165k769193
answered Dec 17 at 22:27
Bernard
165k769193
165k769193
add a comment |
add a comment |
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Dec 17 at 21:40