How to exclude a circle from a rectangle when drawing a contour figure?

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I need to draw a contour figure defined by coordinate x and y. The domain is a rectangle (-100<=x<=100,-100<=y<=100) excluding a circle (center at the origin, and radius of 5). The object function is 'z=x+y'.



What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?










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    up vote
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    I need to draw a contour figure defined by coordinate x and y. The domain is a rectangle (-100<=x<=100,-100<=y<=100) excluding a circle (center at the origin, and radius of 5). The object function is 'z=x+y'.



    What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?










    share|improve this question























      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      I need to draw a contour figure defined by coordinate x and y. The domain is a rectangle (-100<=x<=100,-100<=y<=100) excluding a circle (center at the origin, and radius of 5). The object function is 'z=x+y'.



      What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?










      share|improve this question













      I need to draw a contour figure defined by coordinate x and y. The domain is a rectangle (-100<=x<=100,-100<=y<=100) excluding a circle (center at the origin, and radius of 5). The object function is 'z=x+y'.



      What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?







      plotting






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      share|improve this question











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      share|improve this question










      asked 2 days ago









      Robin_Lyn

      836




      836




















          2 Answers
          2






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          up vote
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          You can also use ConditionalExpression as the first argument of ContourPlot:



          ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],
          x, -100, 100, y, -100, 100, PlotLegends -> Automatic]


          enter image description here






          share|improve this answer



























            up vote
            6
            down vote













            How about this?



            ContourPlot[x + y, x, -100, 100, y, -100, 100, 
            RegionFunction -> Function[x, y, z, x^2 + y^2 >= 5^2],
            PlotPoints -> 100, PerformanceGoal -> "Quality",
            PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]


            enter image description here



            If the smoothness of disk bothers you (it bothers me), you can cheat it like so:



            Show[ContourPlot[x + y, x, -100, 100, y, -100, 100, 
            PlotPoints -> 100, PerformanceGoal -> "Quality",
            PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"],
            Graphics[White, Disk[0, 0, 5]]]


            enter image description here






            share|improve this answer






















            • Nice quality of the figure! Got it~ Thank you!
              – Robin_Lyn
              yesterday










            Your Answer





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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            2
            down vote



            accepted










            You can also use ConditionalExpression as the first argument of ContourPlot:



            ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],
            x, -100, 100, y, -100, 100, PlotLegends -> Automatic]


            enter image description here






            share|improve this answer
























              up vote
              2
              down vote



              accepted










              You can also use ConditionalExpression as the first argument of ContourPlot:



              ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],
              x, -100, 100, y, -100, 100, PlotLegends -> Automatic]


              enter image description here






              share|improve this answer






















                up vote
                2
                down vote



                accepted







                up vote
                2
                down vote



                accepted






                You can also use ConditionalExpression as the first argument of ContourPlot:



                ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],
                x, -100, 100, y, -100, 100, PlotLegends -> Automatic]


                enter image description here






                share|improve this answer












                You can also use ConditionalExpression as the first argument of ContourPlot:



                ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],
                x, -100, 100, y, -100, 100, PlotLegends -> Automatic]


                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered yesterday









                kglr

                171k8194399




                171k8194399




















                    up vote
                    6
                    down vote













                    How about this?



                    ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    RegionFunction -> Function[x, y, z, x^2 + y^2 >= 5^2],
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]


                    enter image description here



                    If the smoothness of disk bothers you (it bothers me), you can cheat it like so:



                    Show[ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"],
                    Graphics[White, Disk[0, 0, 5]]]


                    enter image description here






                    share|improve this answer






















                    • Nice quality of the figure! Got it~ Thank you!
                      – Robin_Lyn
                      yesterday














                    up vote
                    6
                    down vote













                    How about this?



                    ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    RegionFunction -> Function[x, y, z, x^2 + y^2 >= 5^2],
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]


                    enter image description here



                    If the smoothness of disk bothers you (it bothers me), you can cheat it like so:



                    Show[ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"],
                    Graphics[White, Disk[0, 0, 5]]]


                    enter image description here






                    share|improve this answer






















                    • Nice quality of the figure! Got it~ Thank you!
                      – Robin_Lyn
                      yesterday












                    up vote
                    6
                    down vote










                    up vote
                    6
                    down vote









                    How about this?



                    ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    RegionFunction -> Function[x, y, z, x^2 + y^2 >= 5^2],
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]


                    enter image description here



                    If the smoothness of disk bothers you (it bothers me), you can cheat it like so:



                    Show[ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"],
                    Graphics[White, Disk[0, 0, 5]]]


                    enter image description here






                    share|improve this answer














                    How about this?



                    ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    RegionFunction -> Function[x, y, z, x^2 + y^2 >= 5^2],
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]


                    enter image description here



                    If the smoothness of disk bothers you (it bothers me), you can cheat it like so:



                    Show[ContourPlot[x + y, x, -100, 100, y, -100, 100, 
                    PlotPoints -> 100, PerformanceGoal -> "Quality",
                    PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"],
                    Graphics[White, Disk[0, 0, 5]]]


                    enter image description here







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited yesterday

























                    answered 2 days ago









                    Okkes Dulgerci

                    3,5481716




                    3,5481716











                    • Nice quality of the figure! Got it~ Thank you!
                      – Robin_Lyn
                      yesterday
















                    • Nice quality of the figure! Got it~ Thank you!
                      – Robin_Lyn
                      yesterday















                    Nice quality of the figure! Got it~ Thank you!
                    – Robin_Lyn
                    yesterday




                    Nice quality of the figure! Got it~ Thank you!
                    – Robin_Lyn
                    yesterday

















                     

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