Using for loop in tikz to draw repeated shapes
Clash Royale CLAN TAG#URR8PPP
7
I am trying to create a lenticular pattern like the one in the picture.
I believe the repeated shape can be drawn using a for loop in tikz, but I wasn't able to get it done properly.
Appreciate any help on looping.
Edit: This is a part of a bigger diagram and below is the code.
begindocument
begintikzpicture[>=Stealth[inset=0pt,length=10pt,angle'=35,round]]
pgfmathsetmacrolensRadius6
pgfmathsetmacrolensHeight3
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (0,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Main\[-1ex]lens
arc[start angle=-startAngle,delta angle=2*startAngle,radius=lensRadius]
-- cycle;
draw [line width=1mm ] (-1.5,3) -- (-1.5,-3) node [below, align=center] \
[1em]Weak\[-1ex]diffuser;
draw (6,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Field\[-1ex]lens
-- cycle;
draw plot[only marks, mark=*,mark size=10pt,mark options=fill=Sepia]
coordinates(-6.5,0) node[below, align=center]\[1em]Object;
draw (-6,0) -- (0,3);
draw (-6,0) -- (0,-3);
draw (6.5,0) -- (0,3);
draw (6.5,0) -- (0,-3);
%lenticular pattern
pgfmathsetmacrolensRadius0.2
pgfmathsetmacrolensHeight0.2
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (8,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius];
draw [line width=0.25mm ] (8,3) -- (8,-3) -- (8.2,-3) -- (8.2,3) -- cycle;
endtikzpicture
enddocument
Output:
tikz-pgf foreach loops
asked Mar 13 at 7:20
SndnSndn
1775
add a comment |
7
I am trying to create a lenticular pattern like the one in the picture.
I believe the repeated shape can be drawn using a for loop in tikz, but I wasn't able to get it done properly.
Appreciate any help on looping.
Edit: This is a part of a bigger diagram and below is the code.
begindocument
begintikzpicture[>=Stealth[inset=0pt,length=10pt,angle'=35,round]]
pgfmathsetmacrolensRadius6
pgfmathsetmacrolensHeight3
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (0,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Main\[-1ex]lens
arc[start angle=-startAngle,delta angle=2*startAngle,radius=lensRadius]
-- cycle;
draw [line width=1mm ] (-1.5,3) -- (-1.5,-3) node [below, align=center] \
[1em]Weak\[-1ex]diffuser;
draw (6,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Field\[-1ex]lens
-- cycle;
draw plot[only marks, mark=*,mark size=10pt,mark options=fill=Sepia]
coordinates(-6.5,0) node[below, align=center]\[1em]Object;
draw (-6,0) -- (0,3);
draw (-6,0) -- (0,-3);
draw (6.5,0) -- (0,3);
draw (6.5,0) -- (0,-3);
%lenticular pattern
pgfmathsetmacrolensRadius0.2
pgfmathsetmacrolensHeight0.2
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (8,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius];
draw [line width=0.25mm ] (8,3) -- (8,-3) -- (8.2,-3) -- (8.2,3) -- cycle;
endtikzpicture
enddocument
Output:
tikz-pgf foreach loops
asked Mar 13 at 7:20
SndnSndn
1775
1
@Raaja sometimes one simply has no clue where to start :) I wouldn't close a question simply because one doesn't know how to do something: that's why they're here.
– Superuser27
Mar 13 at 7:38
2
@Superuser27 An OP doesnt always need a perfect MWE to start with. But atleast some commitment or motivation should be there behind a question, instead of knowing the way how to proceed and not trying it. Everyone of us makes mistakes (I am also learning things that way). In this case OP knows what to do, and has the recipies to do. It's just a matter of trial-and-error to atleast begin something. If you see this: tex.stackexchange.com/questions/472117/… then OP already has some knowledge on where to start with:).
– Raaja
Mar 13 at 7:45
1
@Raaja Thanks for pointing out. Added the code and the output I got so far.
– Sndn
Mar 13 at 8:22
@sndn good!! +1 since, this question already has an answer given by marmot. Consider accepting it, if you think that solves your issue.
– Raaja
Mar 13 at 8:30
add a comment |
7
7
7
I am trying to create a lenticular pattern like the one in the picture.
I believe the repeated shape can be drawn using a for loop in tikz, but I wasn't able to get it done properly.
Appreciate any help on looping.
Edit: This is a part of a bigger diagram and below is the code.
begindocument
begintikzpicture[>=Stealth[inset=0pt,length=10pt,angle'=35,round]]
pgfmathsetmacrolensRadius6
pgfmathsetmacrolensHeight3
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (0,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Main\[-1ex]lens
arc[start angle=-startAngle,delta angle=2*startAngle,radius=lensRadius]
-- cycle;
draw [line width=1mm ] (-1.5,3) -- (-1.5,-3) node [below, align=center] \
[1em]Weak\[-1ex]diffuser;
draw (6,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Field\[-1ex]lens
-- cycle;
draw plot[only marks, mark=*,mark size=10pt,mark options=fill=Sepia]
coordinates(-6.5,0) node[below, align=center]\[1em]Object;
draw (-6,0) -- (0,3);
draw (-6,0) -- (0,-3);
draw (6.5,0) -- (0,3);
draw (6.5,0) -- (0,-3);
%lenticular pattern
pgfmathsetmacrolensRadius0.2
pgfmathsetmacrolensHeight0.2
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (8,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius];
draw [line width=0.25mm ] (8,3) -- (8,-3) -- (8.2,-3) -- (8.2,3) -- cycle;
endtikzpicture
enddocument
Output:
tikz-pgf foreach loops
asked Mar 13 at 7:20
SndnSndn
1775
I am trying to create a lenticular pattern like the one in the picture.
I believe the repeated shape can be drawn using a for loop in tikz, but I wasn't able to get it done properly.
Appreciate any help on looping.
Edit: This is a part of a bigger diagram and below is the code.
begindocument
begintikzpicture[>=Stealth[inset=0pt,length=10pt,angle'=35,round]]
pgfmathsetmacrolensRadius6
pgfmathsetmacrolensHeight3
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (0,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Main\[-1ex]lens
arc[start angle=-startAngle,delta angle=2*startAngle,radius=lensRadius]
-- cycle;
draw [line width=1mm ] (-1.5,3) -- (-1.5,-3) node [below, align=center] \
[1em]Weak\[-1ex]diffuser;
draw (6,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius]node [below, align=center] \
[1em]Field\[-1ex]lens
-- cycle;
draw plot[only marks, mark=*,mark size=10pt,mark options=fill=Sepia]
coordinates(-6.5,0) node[below, align=center]\[1em]Object;
draw (-6,0) -- (0,3);
draw (-6,0) -- (0,-3);
draw (6.5,0) -- (0,3);
draw (6.5,0) -- (0,-3);
%lenticular pattern
pgfmathsetmacrolensRadius0.2
pgfmathsetmacrolensHeight0.2
pgfmathsetmacrostartAngleasin(lensHeight/lensRadius)
draw (8,lensHeight)
arc[start angle=180-startAngle,delta
angle=2*startAngle,radius=lensRadius];
draw [line width=0.25mm ] (8,3) -- (8,-3) -- (8.2,-3) -- (8.2,3) -- cycle;
endtikzpicture
enddocument
Output:
tikz-pgf foreach loops
tikz-pgf foreach loops
asked Mar 13 at 7:20
SndnSndn
1775
asked Mar 13 at 7:20
SndnSndn
1775
edited Mar 13 at 8:20
Sndn
asked Mar 13 at 7:20
SndnSndn
1775
asked Mar 13 at 7:20
SndnSndn
1775
asked Mar 13 at 7:20
SndnSndn
1775
1775
1
@Raaja sometimes one simply has no clue where to start :) I wouldn't close a question simply because one doesn't know how to do something: that's why they're here.
– Superuser27
Mar 13 at 7:38
2
@Superuser27 An OP doesnt always need a perfect MWE to start with. But atleast some commitment or motivation should be there behind a question, instead of knowing the way how to proceed and not trying it. Everyone of us makes mistakes (I am also learning things that way). In this case OP knows what to do, and has the recipies to do. It's just a matter of trial-and-error to atleast begin something. If you see this: tex.stackexchange.com/questions/472117/… then OP already has some knowledge on where to start with:).
– Raaja
Mar 13 at 7:45
1
@Raaja Thanks for pointing out. Added the code and the output I got so far.
– Sndn
Mar 13 at 8:22
@sndn good!! +1 since, this question already has an answer given by marmot. Consider accepting it, if you think that solves your issue.
– Raaja
Mar 13 at 8:30
add a comment |
1
@Raaja sometimes one simply has no clue where to start :) I wouldn't close a question simply because one doesn't know how to do something: that's why they're here.
– Superuser27
Mar 13 at 7:38
2
@Superuser27 An OP doesnt always need a perfect MWE to start with. But atleast some commitment or motivation should be there behind a question, instead of knowing the way how to proceed and not trying it. Everyone of us makes mistakes (I am also learning things that way). In this case OP knows what to do, and has the recipies to do. It's just a matter of trial-and-error to atleast begin something. If you see this: tex.stackexchange.com/questions/472117/… then OP already has some knowledge on where to start with:).
– Raaja
Mar 13 at 7:45
1
@Raaja Thanks for pointing out. Added the code and the output I got so far.
– Sndn
Mar 13 at 8:22
@sndn good!! +1 since, this question already has an answer given by marmot. Consider accepting it, if you think that solves your issue.
– Raaja
Mar 13 at 8:30
1
1
@Raaja sometimes one simply has no clue where to start :) I wouldn't close a question simply because one doesn't know how to do something: that's why they're here.
– Superuser27
Mar 13 at 7:38
@Raaja sometimes one simply has no clue where to start :) I wouldn't close a question simply because one doesn't know how to do something: that's why they're here.
– Superuser27
Mar 13 at 7:38
2
2
@Superuser27 An OP doesnt always need a perfect MWE to start with. But atleast some commitment or motivation should be there behind a question, instead of knowing the way how to proceed and not trying it. Everyone of us makes mistakes (I am also learning things that way). In this case OP knows what to do, and has the recipies to do. It's just a matter of trial-and-error to atleast begin something. If you see this: tex.stackexchange.com/questions/472117/… then OP already has some knowledge on where to start with
:).– Raaja
Mar 13 at 7:45
@Superuser27 An OP doesnt always need a perfect MWE to start with. But atleast some commitment or motivation should be there behind a question, instead of knowing the way how to proceed and not trying it. Everyone of us makes mistakes (I am also learning things that way). In this case OP knows what to do, and has the recipies to do. It's just a matter of trial-and-error to atleast begin something. If you see this: tex.stackexchange.com/questions/472117/… then OP already has some knowledge on where to start with
:).– Raaja
Mar 13 at 7:45
1
1
@Raaja Thanks for pointing out. Added the code and the output I got so far.
– Sndn
Mar 13 at 8:22
@Raaja Thanks for pointing out. Added the code and the output I got so far.
– Sndn
Mar 13 at 8:22
@sndn good!! +1 since, this question already has an answer given by marmot. Consider accepting it, if you think that solves your issue.
– Raaja
Mar 13 at 8:30
@sndn good!! +1 since, this question already has an answer given by marmot. Consider accepting it, if you think that solves your issue.
– Raaja
Mar 13 at 8:30
add a comment |
1 Answer
1
active
oldest
votes
13
There are many possibilities to draw something like is, here is one of them.
documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture[pics/rr/.style=code=- ++(-0.4,0.4)
to[out=180,in=180] ++ (0,-0.4) -- cycle;]
path foreach X in 0,1,...,10
(0,0.4*X) picrr;
draw (0.2,-0.2) rectangle (0.4,10*0.4+0.2);
endtikzpicture
enddocument
answered Mar 13 at 7:30
marmotmarmot
117k5150283
add a comment |
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There are many possibilities to draw something like is, here is one of them.
documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture[pics/rr/.style=code=- ++(-0.4,0.4)
to[out=180,in=180] ++ (0,-0.4) -- cycle;]
path foreach X in 0,1,...,10
(0,0.4*X) picrr;
draw (0.2,-0.2) rectangle (0.4,10*0.4+0.2);
endtikzpicture
enddocument
answered Mar 13 at 7:30
marmotmarmot
117k5150283
add a comment |
13
There are many possibilities to draw something like is, here is one of them.
documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture[pics/rr/.style=code=- ++(-0.4,0.4)
to[out=180,in=180] ++ (0,-0.4) -- cycle;]
path foreach X in 0,1,...,10
(0,0.4*X) picrr;
draw (0.2,-0.2) rectangle (0.4,10*0.4+0.2);
endtikzpicture
enddocument
answered Mar 13 at 7:30
marmotmarmot
117k5150283
add a comment |
13
13
13
There are many possibilities to draw something like is, here is one of them.
documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture[pics/rr/.style=code=- ++(-0.4,0.4)
to[out=180,in=180] ++ (0,-0.4) -- cycle;]
path foreach X in 0,1,...,10
(0,0.4*X) picrr;
draw (0.2,-0.2) rectangle (0.4,10*0.4+0.2);
endtikzpicture
enddocument
answered Mar 13 at 7:30
marmotmarmot
117k5150283
There are many possibilities to draw something like is, here is one of them.
documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture[pics/rr/.style=code=- ++(-0.4,0.4)
to[out=180,in=180] ++ (0,-0.4) -- cycle;]
path foreach X in 0,1,...,10
(0,0.4*X) picrr;
draw (0.2,-0.2) rectangle (0.4,10*0.4+0.2);
endtikzpicture
enddocument
answered Mar 13 at 7:30
marmotmarmot
117k5150283
answered Mar 13 at 7:30
marmotmarmot
117k5150283
answered Mar 13 at 7:30
marmotmarmot
117k5150283
answered Mar 13 at 7:30
marmotmarmot
117k5150283
117k5150283
add a comment |
add a comment |
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1
@Raaja sometimes one simply has no clue where to start :) I wouldn't close a question simply because one doesn't know how to do something: that's why they're here.
– Superuser27
Mar 13 at 7:38
2
@Superuser27 An OP doesnt always need a perfect MWE to start with. But atleast some commitment or motivation should be there behind a question, instead of knowing the way how to proceed and not trying it. Everyone of us makes mistakes (I am also learning things that way). In this case OP knows what to do, and has the recipies to do. It's just a matter of trial-and-error to atleast begin something. If you see this: tex.stackexchange.com/questions/472117/… then OP already has some knowledge on where to start with
:).– Raaja
Mar 13 at 7:45
1
@Raaja Thanks for pointing out. Added the code and the output I got so far.
– Sndn
Mar 13 at 8:22
@sndn good!! +1 since, this question already has an answer given by marmot. Consider accepting it, if you think that solves your issue.
– Raaja
Mar 13 at 8:30