Print SSH loop output Column wise
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I want to print output of below loop into columns, Can anybody please adivse me on this.
#!/bin/bash
DATE=`date "+%d-%m-%Y_%H-%M-%S"`
### Find User from Server with Expiry Date
for i in `cat /home/sandeepj/Project_user_count/serverlist2`;
do
echo -e "**********"
echo -e "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
done >> /tmp/user_count.txt
Current Output :
**********
10.25.59.3
root
bin
daemon
adm
lp
sync
**********
10.25.59.13
root
bin
daemon
adm
lp
sync
Expected Output:
********** **********
10.25.59.3 10.25.59.13
root root
bin bin
daemon daemon
adm adm
lp lp
sync sync
My Goal is to achieve above formatting.
bash shell-script awk sed text-formatting
add a comment |
I want to print output of below loop into columns, Can anybody please adivse me on this.
#!/bin/bash
DATE=`date "+%d-%m-%Y_%H-%M-%S"`
### Find User from Server with Expiry Date
for i in `cat /home/sandeepj/Project_user_count/serverlist2`;
do
echo -e "**********"
echo -e "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
done >> /tmp/user_count.txt
Current Output :
**********
10.25.59.3
root
bin
daemon
adm
lp
sync
**********
10.25.59.13
root
bin
daemon
adm
lp
sync
Expected Output:
********** **********
10.25.59.3 10.25.59.13
root root
bin bin
daemon daemon
adm adm
lp lp
sync sync
My Goal is to achieve above formatting.
bash shell-script awk sed text-formatting
how many columns do you expect to have ? is it fixed or is it ever growing ?
– RoVo
Mar 8 at 13:26
Hi Rovo, thanks for reply. It’s growing, depends on number of ip in loop list.
– Sandeep Singh
Mar 8 at 13:47
add a comment |
I want to print output of below loop into columns, Can anybody please adivse me on this.
#!/bin/bash
DATE=`date "+%d-%m-%Y_%H-%M-%S"`
### Find User from Server with Expiry Date
for i in `cat /home/sandeepj/Project_user_count/serverlist2`;
do
echo -e "**********"
echo -e "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
done >> /tmp/user_count.txt
Current Output :
**********
10.25.59.3
root
bin
daemon
adm
lp
sync
**********
10.25.59.13
root
bin
daemon
adm
lp
sync
Expected Output:
********** **********
10.25.59.3 10.25.59.13
root root
bin bin
daemon daemon
adm adm
lp lp
sync sync
My Goal is to achieve above formatting.
bash shell-script awk sed text-formatting
I want to print output of below loop into columns, Can anybody please adivse me on this.
#!/bin/bash
DATE=`date "+%d-%m-%Y_%H-%M-%S"`
### Find User from Server with Expiry Date
for i in `cat /home/sandeepj/Project_user_count/serverlist2`;
do
echo -e "**********"
echo -e "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
done >> /tmp/user_count.txt
Current Output :
**********
10.25.59.3
root
bin
daemon
adm
lp
sync
**********
10.25.59.13
root
bin
daemon
adm
lp
sync
Expected Output:
********** **********
10.25.59.3 10.25.59.13
root root
bin bin
daemon daemon
adm adm
lp lp
sync sync
My Goal is to achieve above formatting.
bash shell-script awk sed text-formatting
bash shell-script awk sed text-formatting
edited Mar 8 at 12:05
Jeff Schaller♦
44.7k1162145
44.7k1162145
asked Mar 8 at 11:49
Sandeep SinghSandeep Singh
85
85
how many columns do you expect to have ? is it fixed or is it ever growing ?
– RoVo
Mar 8 at 13:26
Hi Rovo, thanks for reply. It’s growing, depends on number of ip in loop list.
– Sandeep Singh
Mar 8 at 13:47
add a comment |
how many columns do you expect to have ? is it fixed or is it ever growing ?
– RoVo
Mar 8 at 13:26
Hi Rovo, thanks for reply. It’s growing, depends on number of ip in loop list.
– Sandeep Singh
Mar 8 at 13:47
how many columns do you expect to have ? is it fixed or is it ever growing ?
– RoVo
Mar 8 at 13:26
how many columns do you expect to have ? is it fixed or is it ever growing ?
– RoVo
Mar 8 at 13:26
Hi Rovo, thanks for reply. It’s growing, depends on number of ip in loop list.
– Sandeep Singh
Mar 8 at 13:47
Hi Rovo, thanks for reply. It’s growing, depends on number of ip in loop list.
– Sandeep Singh
Mar 8 at 13:47
add a comment |
3 Answers
3
active
oldest
votes
If you instead of
>> /tmp/user_count.txt
would write in a new file for each server:
do
(
printf '%sn%sn' '**********' "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
) > "/tmp/user_count_$i.txt"
done
it would be very easy:
paste user_count_*.txt | column -tn
add a comment |
The difficult bit with this question is actually to format the output in columns.
Suppose that you have an existing file with|
-delimited columns, and you want to append a new column to that. If you use paste
as
paste -d '|' file newdata
and your file is not of the same length as the existing file, then the number of columns in the output will vary, and adding further columns would potentially make it even worse. Reading the final result would be difficult to do correctly.
Instead, here's an awk
program that reads an existing file, and adds the data read from standard input to a new column in that file. The output will have a fixed number of columns, all the way from the first line to the last, regardless of whether the new column data has fewer or more lines than the existing data.
BEGIN OFS = FS
FNR == 1
# We assume that all lines have the same number of columns.
nf = NF
# Read new column from stdin (clear col if failing).
if ((getline col <"/dev/stdin") != 1)
col = ""
# Add new column (possibly empty) and print.
$(nf + 1) = col
print
END
# We only need to do something here if the new column
# data is longer than the existing data.
$0 = "" # Clear current line.
# Add data from stdin until there is no more to read.
while ((getline col <"/dev/stdin") == 1)
$(nf + 1) = col
print
Ok, let us then use this to create a small shell script that will SSH over to a number of servers, whose names are listed in a file, and extract the users from the /etc/passwd
file on each:
#!/bin/sh
outfile=/tmp/outfile
serverlist=servers.list
tmpfile=$( mktemp )
while read -r server; do
ssh -n "$server" cat /etc/passwd |
cut -d : -f 1 |
echo '****************'
printf '%snn' "$server"
cat
|
awk -F '|' -f append_column.awk "$tmpfile" >"$outfile"
cp "$outfile" "$tmpfile"
done <"$serverlist"
awk -F '|' ' for (i=1; i<=NF; ++i) $i = sprintf("%-20s", $i); print ' "$tmpfile" >"$outfile"
rm -f "$tmpfile"
Here, append_column.awk
is a file consisting of the awk
program at the top of this answer.
The script reads the $serverlist
file in a loop and calls ssh -n
to get the /etc/passwd
file. The -n
option is needed with ssh
as ssh
would otherwise read from the same $serverlist
file as the loop is iterating over.
The usernames are extracted using cut
.
The ...
bit outputs a short header, and then passes on the usernames unmodified through a call to cat
.
The awk
program is used to add columns to the output file by reading from a temporary file (which will contain the result collected so far), and the resulting data is copied back to the temporary file.
After the end of the loop, the file in $tmpfile
(as well as $output
actually) will contain the data that you want as |
-delimited fields. To clean this up, we call another short in-line awk
script that formats the columns of the output file as left-justified, 20 character long, text fields.
add a comment |
You can try by below method
for i in `cat serverlist`
do
echo " "| sed "s/.*/====================================/g"
echo $i
ssh -o 'StrictHostKeyChecking no' $i -A "cat /etc/passwd| awk -F ':' 'print $1'">$i_host_username_details.txt
done
paste *_host_username_details.txt
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you instead of
>> /tmp/user_count.txt
would write in a new file for each server:
do
(
printf '%sn%sn' '**********' "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
) > "/tmp/user_count_$i.txt"
done
it would be very easy:
paste user_count_*.txt | column -tn
add a comment |
If you instead of
>> /tmp/user_count.txt
would write in a new file for each server:
do
(
printf '%sn%sn' '**********' "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
) > "/tmp/user_count_$i.txt"
done
it would be very easy:
paste user_count_*.txt | column -tn
add a comment |
If you instead of
>> /tmp/user_count.txt
would write in a new file for each server:
do
(
printf '%sn%sn' '**********' "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
) > "/tmp/user_count_$i.txt"
done
it would be very easy:
paste user_count_*.txt | column -tn
If you instead of
>> /tmp/user_count.txt
would write in a new file for each server:
do
(
printf '%sn%sn' '**********' "$i"
ssh sandeepj@$i "awk -F: 'print $1' /etc/passwd"
) > "/tmp/user_count_$i.txt"
done
it would be very easy:
paste user_count_*.txt | column -tn
edited Mar 8 at 14:58
answered Mar 8 at 14:46
RoVoRoVo
3,477317
3,477317
add a comment |
add a comment |
The difficult bit with this question is actually to format the output in columns.
Suppose that you have an existing file with|
-delimited columns, and you want to append a new column to that. If you use paste
as
paste -d '|' file newdata
and your file is not of the same length as the existing file, then the number of columns in the output will vary, and adding further columns would potentially make it even worse. Reading the final result would be difficult to do correctly.
Instead, here's an awk
program that reads an existing file, and adds the data read from standard input to a new column in that file. The output will have a fixed number of columns, all the way from the first line to the last, regardless of whether the new column data has fewer or more lines than the existing data.
BEGIN OFS = FS
FNR == 1
# We assume that all lines have the same number of columns.
nf = NF
# Read new column from stdin (clear col if failing).
if ((getline col <"/dev/stdin") != 1)
col = ""
# Add new column (possibly empty) and print.
$(nf + 1) = col
print
END
# We only need to do something here if the new column
# data is longer than the existing data.
$0 = "" # Clear current line.
# Add data from stdin until there is no more to read.
while ((getline col <"/dev/stdin") == 1)
$(nf + 1) = col
print
Ok, let us then use this to create a small shell script that will SSH over to a number of servers, whose names are listed in a file, and extract the users from the /etc/passwd
file on each:
#!/bin/sh
outfile=/tmp/outfile
serverlist=servers.list
tmpfile=$( mktemp )
while read -r server; do
ssh -n "$server" cat /etc/passwd |
cut -d : -f 1 |
echo '****************'
printf '%snn' "$server"
cat
|
awk -F '|' -f append_column.awk "$tmpfile" >"$outfile"
cp "$outfile" "$tmpfile"
done <"$serverlist"
awk -F '|' ' for (i=1; i<=NF; ++i) $i = sprintf("%-20s", $i); print ' "$tmpfile" >"$outfile"
rm -f "$tmpfile"
Here, append_column.awk
is a file consisting of the awk
program at the top of this answer.
The script reads the $serverlist
file in a loop and calls ssh -n
to get the /etc/passwd
file. The -n
option is needed with ssh
as ssh
would otherwise read from the same $serverlist
file as the loop is iterating over.
The usernames are extracted using cut
.
The ...
bit outputs a short header, and then passes on the usernames unmodified through a call to cat
.
The awk
program is used to add columns to the output file by reading from a temporary file (which will contain the result collected so far), and the resulting data is copied back to the temporary file.
After the end of the loop, the file in $tmpfile
(as well as $output
actually) will contain the data that you want as |
-delimited fields. To clean this up, we call another short in-line awk
script that formats the columns of the output file as left-justified, 20 character long, text fields.
add a comment |
The difficult bit with this question is actually to format the output in columns.
Suppose that you have an existing file with|
-delimited columns, and you want to append a new column to that. If you use paste
as
paste -d '|' file newdata
and your file is not of the same length as the existing file, then the number of columns in the output will vary, and adding further columns would potentially make it even worse. Reading the final result would be difficult to do correctly.
Instead, here's an awk
program that reads an existing file, and adds the data read from standard input to a new column in that file. The output will have a fixed number of columns, all the way from the first line to the last, regardless of whether the new column data has fewer or more lines than the existing data.
BEGIN OFS = FS
FNR == 1
# We assume that all lines have the same number of columns.
nf = NF
# Read new column from stdin (clear col if failing).
if ((getline col <"/dev/stdin") != 1)
col = ""
# Add new column (possibly empty) and print.
$(nf + 1) = col
print
END
# We only need to do something here if the new column
# data is longer than the existing data.
$0 = "" # Clear current line.
# Add data from stdin until there is no more to read.
while ((getline col <"/dev/stdin") == 1)
$(nf + 1) = col
print
Ok, let us then use this to create a small shell script that will SSH over to a number of servers, whose names are listed in a file, and extract the users from the /etc/passwd
file on each:
#!/bin/sh
outfile=/tmp/outfile
serverlist=servers.list
tmpfile=$( mktemp )
while read -r server; do
ssh -n "$server" cat /etc/passwd |
cut -d : -f 1 |
echo '****************'
printf '%snn' "$server"
cat
|
awk -F '|' -f append_column.awk "$tmpfile" >"$outfile"
cp "$outfile" "$tmpfile"
done <"$serverlist"
awk -F '|' ' for (i=1; i<=NF; ++i) $i = sprintf("%-20s", $i); print ' "$tmpfile" >"$outfile"
rm -f "$tmpfile"
Here, append_column.awk
is a file consisting of the awk
program at the top of this answer.
The script reads the $serverlist
file in a loop and calls ssh -n
to get the /etc/passwd
file. The -n
option is needed with ssh
as ssh
would otherwise read from the same $serverlist
file as the loop is iterating over.
The usernames are extracted using cut
.
The ...
bit outputs a short header, and then passes on the usernames unmodified through a call to cat
.
The awk
program is used to add columns to the output file by reading from a temporary file (which will contain the result collected so far), and the resulting data is copied back to the temporary file.
After the end of the loop, the file in $tmpfile
(as well as $output
actually) will contain the data that you want as |
-delimited fields. To clean this up, we call another short in-line awk
script that formats the columns of the output file as left-justified, 20 character long, text fields.
add a comment |
The difficult bit with this question is actually to format the output in columns.
Suppose that you have an existing file with|
-delimited columns, and you want to append a new column to that. If you use paste
as
paste -d '|' file newdata
and your file is not of the same length as the existing file, then the number of columns in the output will vary, and adding further columns would potentially make it even worse. Reading the final result would be difficult to do correctly.
Instead, here's an awk
program that reads an existing file, and adds the data read from standard input to a new column in that file. The output will have a fixed number of columns, all the way from the first line to the last, regardless of whether the new column data has fewer or more lines than the existing data.
BEGIN OFS = FS
FNR == 1
# We assume that all lines have the same number of columns.
nf = NF
# Read new column from stdin (clear col if failing).
if ((getline col <"/dev/stdin") != 1)
col = ""
# Add new column (possibly empty) and print.
$(nf + 1) = col
print
END
# We only need to do something here if the new column
# data is longer than the existing data.
$0 = "" # Clear current line.
# Add data from stdin until there is no more to read.
while ((getline col <"/dev/stdin") == 1)
$(nf + 1) = col
print
Ok, let us then use this to create a small shell script that will SSH over to a number of servers, whose names are listed in a file, and extract the users from the /etc/passwd
file on each:
#!/bin/sh
outfile=/tmp/outfile
serverlist=servers.list
tmpfile=$( mktemp )
while read -r server; do
ssh -n "$server" cat /etc/passwd |
cut -d : -f 1 |
echo '****************'
printf '%snn' "$server"
cat
|
awk -F '|' -f append_column.awk "$tmpfile" >"$outfile"
cp "$outfile" "$tmpfile"
done <"$serverlist"
awk -F '|' ' for (i=1; i<=NF; ++i) $i = sprintf("%-20s", $i); print ' "$tmpfile" >"$outfile"
rm -f "$tmpfile"
Here, append_column.awk
is a file consisting of the awk
program at the top of this answer.
The script reads the $serverlist
file in a loop and calls ssh -n
to get the /etc/passwd
file. The -n
option is needed with ssh
as ssh
would otherwise read from the same $serverlist
file as the loop is iterating over.
The usernames are extracted using cut
.
The ...
bit outputs a short header, and then passes on the usernames unmodified through a call to cat
.
The awk
program is used to add columns to the output file by reading from a temporary file (which will contain the result collected so far), and the resulting data is copied back to the temporary file.
After the end of the loop, the file in $tmpfile
(as well as $output
actually) will contain the data that you want as |
-delimited fields. To clean this up, we call another short in-line awk
script that formats the columns of the output file as left-justified, 20 character long, text fields.
The difficult bit with this question is actually to format the output in columns.
Suppose that you have an existing file with|
-delimited columns, and you want to append a new column to that. If you use paste
as
paste -d '|' file newdata
and your file is not of the same length as the existing file, then the number of columns in the output will vary, and adding further columns would potentially make it even worse. Reading the final result would be difficult to do correctly.
Instead, here's an awk
program that reads an existing file, and adds the data read from standard input to a new column in that file. The output will have a fixed number of columns, all the way from the first line to the last, regardless of whether the new column data has fewer or more lines than the existing data.
BEGIN OFS = FS
FNR == 1
# We assume that all lines have the same number of columns.
nf = NF
# Read new column from stdin (clear col if failing).
if ((getline col <"/dev/stdin") != 1)
col = ""
# Add new column (possibly empty) and print.
$(nf + 1) = col
print
END
# We only need to do something here if the new column
# data is longer than the existing data.
$0 = "" # Clear current line.
# Add data from stdin until there is no more to read.
while ((getline col <"/dev/stdin") == 1)
$(nf + 1) = col
print
Ok, let us then use this to create a small shell script that will SSH over to a number of servers, whose names are listed in a file, and extract the users from the /etc/passwd
file on each:
#!/bin/sh
outfile=/tmp/outfile
serverlist=servers.list
tmpfile=$( mktemp )
while read -r server; do
ssh -n "$server" cat /etc/passwd |
cut -d : -f 1 |
echo '****************'
printf '%snn' "$server"
cat
|
awk -F '|' -f append_column.awk "$tmpfile" >"$outfile"
cp "$outfile" "$tmpfile"
done <"$serverlist"
awk -F '|' ' for (i=1; i<=NF; ++i) $i = sprintf("%-20s", $i); print ' "$tmpfile" >"$outfile"
rm -f "$tmpfile"
Here, append_column.awk
is a file consisting of the awk
program at the top of this answer.
The script reads the $serverlist
file in a loop and calls ssh -n
to get the /etc/passwd
file. The -n
option is needed with ssh
as ssh
would otherwise read from the same $serverlist
file as the loop is iterating over.
The usernames are extracted using cut
.
The ...
bit outputs a short header, and then passes on the usernames unmodified through a call to cat
.
The awk
program is used to add columns to the output file by reading from a temporary file (which will contain the result collected so far), and the resulting data is copied back to the temporary file.
After the end of the loop, the file in $tmpfile
(as well as $output
actually) will contain the data that you want as |
-delimited fields. To clean this up, we call another short in-line awk
script that formats the columns of the output file as left-justified, 20 character long, text fields.
edited Mar 21 at 14:12
answered Mar 16 at 18:44
Kusalananda♦Kusalananda
140k17261434
140k17261434
add a comment |
add a comment |
You can try by below method
for i in `cat serverlist`
do
echo " "| sed "s/.*/====================================/g"
echo $i
ssh -o 'StrictHostKeyChecking no' $i -A "cat /etc/passwd| awk -F ':' 'print $1'">$i_host_username_details.txt
done
paste *_host_username_details.txt
add a comment |
You can try by below method
for i in `cat serverlist`
do
echo " "| sed "s/.*/====================================/g"
echo $i
ssh -o 'StrictHostKeyChecking no' $i -A "cat /etc/passwd| awk -F ':' 'print $1'">$i_host_username_details.txt
done
paste *_host_username_details.txt
add a comment |
You can try by below method
for i in `cat serverlist`
do
echo " "| sed "s/.*/====================================/g"
echo $i
ssh -o 'StrictHostKeyChecking no' $i -A "cat /etc/passwd| awk -F ':' 'print $1'">$i_host_username_details.txt
done
paste *_host_username_details.txt
You can try by below method
for i in `cat serverlist`
do
echo " "| sed "s/.*/====================================/g"
echo $i
ssh -o 'StrictHostKeyChecking no' $i -A "cat /etc/passwd| awk -F ':' 'print $1'">$i_host_username_details.txt
done
paste *_host_username_details.txt
answered Mar 10 at 12:45
Praveen Kumar BSPraveen Kumar BS
1,7391311
1,7391311
add a comment |
add a comment |
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how many columns do you expect to have ? is it fixed or is it ever growing ?
– RoVo
Mar 8 at 13:26
Hi Rovo, thanks for reply. It’s growing, depends on number of ip in loop list.
– Sandeep Singh
Mar 8 at 13:47