How to unset range of array in Bash
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I'm trying to delete range of array element but it's fail..
My array
root@ubuntu:~/work# echo $a[@]
cocacola.com airtel.com pepsi.com
Print 0-1 array looks ok
root@ubuntu:~/work# echo $a[@]::2
cocacola.com airtel.com
Now I'm trying to delete only these element using :
root@ubuntu:~/work# unset a[@]::2
root@ubuntu:~/work# echo $a[@]
It's delete whole array..
What I'm doing wrong ?
I found other way of deleting range of array but why above things is not working ?
for ((i=0; i<2; i++)); do unset a[$i]; done
EDIT
I had also tried but no luck
unset -v 'a[@]::2'
bash array
add a comment |
I'm trying to delete range of array element but it's fail..
My array
root@ubuntu:~/work# echo $a[@]
cocacola.com airtel.com pepsi.com
Print 0-1 array looks ok
root@ubuntu:~/work# echo $a[@]::2
cocacola.com airtel.com
Now I'm trying to delete only these element using :
root@ubuntu:~/work# unset a[@]::2
root@ubuntu:~/work# echo $a[@]
It's delete whole array..
What I'm doing wrong ?
I found other way of deleting range of array but why above things is not working ?
for ((i=0; i<2; i++)); do unset a[$i]; done
EDIT
I had also tried but no luck
unset -v 'a[@]::2'
bash array
add a comment |
I'm trying to delete range of array element but it's fail..
My array
root@ubuntu:~/work# echo $a[@]
cocacola.com airtel.com pepsi.com
Print 0-1 array looks ok
root@ubuntu:~/work# echo $a[@]::2
cocacola.com airtel.com
Now I'm trying to delete only these element using :
root@ubuntu:~/work# unset a[@]::2
root@ubuntu:~/work# echo $a[@]
It's delete whole array..
What I'm doing wrong ?
I found other way of deleting range of array but why above things is not working ?
for ((i=0; i<2; i++)); do unset a[$i]; done
EDIT
I had also tried but no luck
unset -v 'a[@]::2'
bash array
I'm trying to delete range of array element but it's fail..
My array
root@ubuntu:~/work# echo $a[@]
cocacola.com airtel.com pepsi.com
Print 0-1 array looks ok
root@ubuntu:~/work# echo $a[@]::2
cocacola.com airtel.com
Now I'm trying to delete only these element using :
root@ubuntu:~/work# unset a[@]::2
root@ubuntu:~/work# echo $a[@]
It's delete whole array..
What I'm doing wrong ?
I found other way of deleting range of array but why above things is not working ?
for ((i=0; i<2; i++)); do unset a[$i]; done
EDIT
I had also tried but no luck
unset -v 'a[@]::2'
bash array
bash array
edited Jun 6 '13 at 23:16
Gilles
546k12911101624
546k12911101624
asked Apr 30 '13 at 16:02
Rahul PatilRahul Patil
15.2k186084
15.2k186084
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
One thing to bear in mind is that bash
implemented arrays like ksh
, that is as associative arrays where keys are limited to positive integers (contrary to other languages like perl
or zsh
for instance).
In:
a[123]=foo a[456]=bar a[789]=baz
In bash, you've got an associative array with 3 elements, while in perl
, you'd have an array with 790 elements (789 with zsh).
In ksh
or bash
, $a[@]:0:1
returns the first element of the array in the list of elements sorted numerically by key where the key is greater or equal to 0. So in that case, it returns $a[123]
, not $a[0]
.
unset 'a[123]'
(remember to quote it, otherwise it would fail if there was a file called a1 or a2 or a3 in the current directory) makes sense, as it removes a particular key in the array.
unset 'a[@]::2'
makes less sense though. bash
only understands unset a
, unset 'a[123]'
or unset 'a[*/@]'
, anything after is ignored, so unset 'a[@]::2'
and unset 'a[@]please'
do the same: unset the whole array.
If you want to unset a range of keys, you'd need to loop through the keys:
To get the list of keys of the array, the syntax is "$!a[@]"
. Unfortunately, applying a range to that doesn't work with bash
nor ksh
, so you'd need a temporary array:
keys=("$!a[@]")
for i in "$keys[@]::2"; do unset "a[$i]"; done
Now if you want to consider those arrays like in other languages, you don't want to use unset
. Like, if the array is not sparse in the first place and you want to keep it so (that is shift all the elements by 2 instead of unsetting the first two), you can do things like:
a=("$a[@]:2")
That is reassign the array with the list of elements you want to keep.
For comparison, with zsh
.
a=(1..20)
unset 'a[12,16]'
would set an empty value to elements 12 to 16. while unset 'a[16,20]'
would shrink the array to 15 elements.
a=(1..20)
a[12,16]=()
(still with zsh
) would shift elements 17 to 20 by 5 positions so a[12]
would contain 17
.
Thanks.. you are my master... with help of this , I have solve one problem.. so please have look at this and let me if any improvement in that Bash Code .. unix.stackexchange.com/questions/74001/…
– Rahul Patil
May 1 '13 at 6:46
add a comment |
If your array is continuous/not sparse (all elements from 0..N-1 set)
You can remove the 2nd element of the array with
unset 'a[1]'
To remove the 2nd, 3rd and 4th element, you can use e.g.
for ((i=1; i<=3; i++)); do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for ((i=2; i<$#a[@]; i++)); do unset "a[$i]"; done
General solution (works also for sparse arrays):
You can remove the 2nd element of the array withunset "a[$(echo $!a[@] | cut -d" " -f 2)]"
To remove the 2nd, 3rd and 4th element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-4) ; do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-) ; do unset "a[$i]"; done
I already did this n had updated in question.. but question remain aboutunset a[@]::2
– Rahul Patil
Apr 30 '13 at 16:32
That's wrong in the general case because$#a[@]
is the number of elements in the array, not the greatest indice in the array (bash
arrays, likeksh
arrays are sparse, contrary to zsh ones).
– Stéphane Chazelas
Apr 30 '13 at 16:43
@StephaneChazelas after deleting element why not reset index ?
– Rahul Patil
Apr 30 '13 at 16:54
@StephaneChazelas after doing some RnD I Found this way to reset arraya=( $(echo $a[@]) )
is this fine ?
– Rahul Patil
Apr 30 '13 at 17:05
2
@RahulPatil, if you want to unsparse the array, just write it:a=("$a[@]")
, usingecho
and command substitution would only work in limited corner cases (like when none of the elements are empty or contain spc, tab, NL, backslash, *, ?, [ or start with -).
– Stéphane Chazelas
Apr 30 '13 at 19:40
|
show 1 more comment
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2 Answers
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active
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2 Answers
2
active
oldest
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oldest
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active
oldest
votes
One thing to bear in mind is that bash
implemented arrays like ksh
, that is as associative arrays where keys are limited to positive integers (contrary to other languages like perl
or zsh
for instance).
In:
a[123]=foo a[456]=bar a[789]=baz
In bash, you've got an associative array with 3 elements, while in perl
, you'd have an array with 790 elements (789 with zsh).
In ksh
or bash
, $a[@]:0:1
returns the first element of the array in the list of elements sorted numerically by key where the key is greater or equal to 0. So in that case, it returns $a[123]
, not $a[0]
.
unset 'a[123]'
(remember to quote it, otherwise it would fail if there was a file called a1 or a2 or a3 in the current directory) makes sense, as it removes a particular key in the array.
unset 'a[@]::2'
makes less sense though. bash
only understands unset a
, unset 'a[123]'
or unset 'a[*/@]'
, anything after is ignored, so unset 'a[@]::2'
and unset 'a[@]please'
do the same: unset the whole array.
If you want to unset a range of keys, you'd need to loop through the keys:
To get the list of keys of the array, the syntax is "$!a[@]"
. Unfortunately, applying a range to that doesn't work with bash
nor ksh
, so you'd need a temporary array:
keys=("$!a[@]")
for i in "$keys[@]::2"; do unset "a[$i]"; done
Now if you want to consider those arrays like in other languages, you don't want to use unset
. Like, if the array is not sparse in the first place and you want to keep it so (that is shift all the elements by 2 instead of unsetting the first two), you can do things like:
a=("$a[@]:2")
That is reassign the array with the list of elements you want to keep.
For comparison, with zsh
.
a=(1..20)
unset 'a[12,16]'
would set an empty value to elements 12 to 16. while unset 'a[16,20]'
would shrink the array to 15 elements.
a=(1..20)
a[12,16]=()
(still with zsh
) would shift elements 17 to 20 by 5 positions so a[12]
would contain 17
.
Thanks.. you are my master... with help of this , I have solve one problem.. so please have look at this and let me if any improvement in that Bash Code .. unix.stackexchange.com/questions/74001/…
– Rahul Patil
May 1 '13 at 6:46
add a comment |
One thing to bear in mind is that bash
implemented arrays like ksh
, that is as associative arrays where keys are limited to positive integers (contrary to other languages like perl
or zsh
for instance).
In:
a[123]=foo a[456]=bar a[789]=baz
In bash, you've got an associative array with 3 elements, while in perl
, you'd have an array with 790 elements (789 with zsh).
In ksh
or bash
, $a[@]:0:1
returns the first element of the array in the list of elements sorted numerically by key where the key is greater or equal to 0. So in that case, it returns $a[123]
, not $a[0]
.
unset 'a[123]'
(remember to quote it, otherwise it would fail if there was a file called a1 or a2 or a3 in the current directory) makes sense, as it removes a particular key in the array.
unset 'a[@]::2'
makes less sense though. bash
only understands unset a
, unset 'a[123]'
or unset 'a[*/@]'
, anything after is ignored, so unset 'a[@]::2'
and unset 'a[@]please'
do the same: unset the whole array.
If you want to unset a range of keys, you'd need to loop through the keys:
To get the list of keys of the array, the syntax is "$!a[@]"
. Unfortunately, applying a range to that doesn't work with bash
nor ksh
, so you'd need a temporary array:
keys=("$!a[@]")
for i in "$keys[@]::2"; do unset "a[$i]"; done
Now if you want to consider those arrays like in other languages, you don't want to use unset
. Like, if the array is not sparse in the first place and you want to keep it so (that is shift all the elements by 2 instead of unsetting the first two), you can do things like:
a=("$a[@]:2")
That is reassign the array with the list of elements you want to keep.
For comparison, with zsh
.
a=(1..20)
unset 'a[12,16]'
would set an empty value to elements 12 to 16. while unset 'a[16,20]'
would shrink the array to 15 elements.
a=(1..20)
a[12,16]=()
(still with zsh
) would shift elements 17 to 20 by 5 positions so a[12]
would contain 17
.
Thanks.. you are my master... with help of this , I have solve one problem.. so please have look at this and let me if any improvement in that Bash Code .. unix.stackexchange.com/questions/74001/…
– Rahul Patil
May 1 '13 at 6:46
add a comment |
One thing to bear in mind is that bash
implemented arrays like ksh
, that is as associative arrays where keys are limited to positive integers (contrary to other languages like perl
or zsh
for instance).
In:
a[123]=foo a[456]=bar a[789]=baz
In bash, you've got an associative array with 3 elements, while in perl
, you'd have an array with 790 elements (789 with zsh).
In ksh
or bash
, $a[@]:0:1
returns the first element of the array in the list of elements sorted numerically by key where the key is greater or equal to 0. So in that case, it returns $a[123]
, not $a[0]
.
unset 'a[123]'
(remember to quote it, otherwise it would fail if there was a file called a1 or a2 or a3 in the current directory) makes sense, as it removes a particular key in the array.
unset 'a[@]::2'
makes less sense though. bash
only understands unset a
, unset 'a[123]'
or unset 'a[*/@]'
, anything after is ignored, so unset 'a[@]::2'
and unset 'a[@]please'
do the same: unset the whole array.
If you want to unset a range of keys, you'd need to loop through the keys:
To get the list of keys of the array, the syntax is "$!a[@]"
. Unfortunately, applying a range to that doesn't work with bash
nor ksh
, so you'd need a temporary array:
keys=("$!a[@]")
for i in "$keys[@]::2"; do unset "a[$i]"; done
Now if you want to consider those arrays like in other languages, you don't want to use unset
. Like, if the array is not sparse in the first place and you want to keep it so (that is shift all the elements by 2 instead of unsetting the first two), you can do things like:
a=("$a[@]:2")
That is reassign the array with the list of elements you want to keep.
For comparison, with zsh
.
a=(1..20)
unset 'a[12,16]'
would set an empty value to elements 12 to 16. while unset 'a[16,20]'
would shrink the array to 15 elements.
a=(1..20)
a[12,16]=()
(still with zsh
) would shift elements 17 to 20 by 5 positions so a[12]
would contain 17
.
One thing to bear in mind is that bash
implemented arrays like ksh
, that is as associative arrays where keys are limited to positive integers (contrary to other languages like perl
or zsh
for instance).
In:
a[123]=foo a[456]=bar a[789]=baz
In bash, you've got an associative array with 3 elements, while in perl
, you'd have an array with 790 elements (789 with zsh).
In ksh
or bash
, $a[@]:0:1
returns the first element of the array in the list of elements sorted numerically by key where the key is greater or equal to 0. So in that case, it returns $a[123]
, not $a[0]
.
unset 'a[123]'
(remember to quote it, otherwise it would fail if there was a file called a1 or a2 or a3 in the current directory) makes sense, as it removes a particular key in the array.
unset 'a[@]::2'
makes less sense though. bash
only understands unset a
, unset 'a[123]'
or unset 'a[*/@]'
, anything after is ignored, so unset 'a[@]::2'
and unset 'a[@]please'
do the same: unset the whole array.
If you want to unset a range of keys, you'd need to loop through the keys:
To get the list of keys of the array, the syntax is "$!a[@]"
. Unfortunately, applying a range to that doesn't work with bash
nor ksh
, so you'd need a temporary array:
keys=("$!a[@]")
for i in "$keys[@]::2"; do unset "a[$i]"; done
Now if you want to consider those arrays like in other languages, you don't want to use unset
. Like, if the array is not sparse in the first place and you want to keep it so (that is shift all the elements by 2 instead of unsetting the first two), you can do things like:
a=("$a[@]:2")
That is reassign the array with the list of elements you want to keep.
For comparison, with zsh
.
a=(1..20)
unset 'a[12,16]'
would set an empty value to elements 12 to 16. while unset 'a[16,20]'
would shrink the array to 15 elements.
a=(1..20)
a[12,16]=()
(still with zsh
) would shift elements 17 to 20 by 5 positions so a[12]
would contain 17
.
edited Mar 8 at 12:38
answered Apr 30 '13 at 17:04
Stéphane ChazelasStéphane Chazelas
313k57592948
313k57592948
Thanks.. you are my master... with help of this , I have solve one problem.. so please have look at this and let me if any improvement in that Bash Code .. unix.stackexchange.com/questions/74001/…
– Rahul Patil
May 1 '13 at 6:46
add a comment |
Thanks.. you are my master... with help of this , I have solve one problem.. so please have look at this and let me if any improvement in that Bash Code .. unix.stackexchange.com/questions/74001/…
– Rahul Patil
May 1 '13 at 6:46
Thanks.. you are my master... with help of this , I have solve one problem.. so please have look at this and let me if any improvement in that Bash Code .. unix.stackexchange.com/questions/74001/…
– Rahul Patil
May 1 '13 at 6:46
Thanks.. you are my master... with help of this , I have solve one problem.. so please have look at this and let me if any improvement in that Bash Code .. unix.stackexchange.com/questions/74001/…
– Rahul Patil
May 1 '13 at 6:46
add a comment |
If your array is continuous/not sparse (all elements from 0..N-1 set)
You can remove the 2nd element of the array with
unset 'a[1]'
To remove the 2nd, 3rd and 4th element, you can use e.g.
for ((i=1; i<=3; i++)); do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for ((i=2; i<$#a[@]; i++)); do unset "a[$i]"; done
General solution (works also for sparse arrays):
You can remove the 2nd element of the array withunset "a[$(echo $!a[@] | cut -d" " -f 2)]"
To remove the 2nd, 3rd and 4th element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-4) ; do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-) ; do unset "a[$i]"; done
I already did this n had updated in question.. but question remain aboutunset a[@]::2
– Rahul Patil
Apr 30 '13 at 16:32
That's wrong in the general case because$#a[@]
is the number of elements in the array, not the greatest indice in the array (bash
arrays, likeksh
arrays are sparse, contrary to zsh ones).
– Stéphane Chazelas
Apr 30 '13 at 16:43
@StephaneChazelas after deleting element why not reset index ?
– Rahul Patil
Apr 30 '13 at 16:54
@StephaneChazelas after doing some RnD I Found this way to reset arraya=( $(echo $a[@]) )
is this fine ?
– Rahul Patil
Apr 30 '13 at 17:05
2
@RahulPatil, if you want to unsparse the array, just write it:a=("$a[@]")
, usingecho
and command substitution would only work in limited corner cases (like when none of the elements are empty or contain spc, tab, NL, backslash, *, ?, [ or start with -).
– Stéphane Chazelas
Apr 30 '13 at 19:40
|
show 1 more comment
If your array is continuous/not sparse (all elements from 0..N-1 set)
You can remove the 2nd element of the array with
unset 'a[1]'
To remove the 2nd, 3rd and 4th element, you can use e.g.
for ((i=1; i<=3; i++)); do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for ((i=2; i<$#a[@]; i++)); do unset "a[$i]"; done
General solution (works also for sparse arrays):
You can remove the 2nd element of the array withunset "a[$(echo $!a[@] | cut -d" " -f 2)]"
To remove the 2nd, 3rd and 4th element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-4) ; do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-) ; do unset "a[$i]"; done
I already did this n had updated in question.. but question remain aboutunset a[@]::2
– Rahul Patil
Apr 30 '13 at 16:32
That's wrong in the general case because$#a[@]
is the number of elements in the array, not the greatest indice in the array (bash
arrays, likeksh
arrays are sparse, contrary to zsh ones).
– Stéphane Chazelas
Apr 30 '13 at 16:43
@StephaneChazelas after deleting element why not reset index ?
– Rahul Patil
Apr 30 '13 at 16:54
@StephaneChazelas after doing some RnD I Found this way to reset arraya=( $(echo $a[@]) )
is this fine ?
– Rahul Patil
Apr 30 '13 at 17:05
2
@RahulPatil, if you want to unsparse the array, just write it:a=("$a[@]")
, usingecho
and command substitution would only work in limited corner cases (like when none of the elements are empty or contain spc, tab, NL, backslash, *, ?, [ or start with -).
– Stéphane Chazelas
Apr 30 '13 at 19:40
|
show 1 more comment
If your array is continuous/not sparse (all elements from 0..N-1 set)
You can remove the 2nd element of the array with
unset 'a[1]'
To remove the 2nd, 3rd and 4th element, you can use e.g.
for ((i=1; i<=3; i++)); do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for ((i=2; i<$#a[@]; i++)); do unset "a[$i]"; done
General solution (works also for sparse arrays):
You can remove the 2nd element of the array withunset "a[$(echo $!a[@] | cut -d" " -f 2)]"
To remove the 2nd, 3rd and 4th element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-4) ; do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-) ; do unset "a[$i]"; done
If your array is continuous/not sparse (all elements from 0..N-1 set)
You can remove the 2nd element of the array with
unset 'a[1]'
To remove the 2nd, 3rd and 4th element, you can use e.g.
for ((i=1; i<=3; i++)); do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for ((i=2; i<$#a[@]; i++)); do unset "a[$i]"; done
General solution (works also for sparse arrays):
You can remove the 2nd element of the array withunset "a[$(echo $!a[@] | cut -d" " -f 2)]"
To remove the 2nd, 3rd and 4th element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-4) ; do unset "a[$i]"; done
To delete all but the 1st and 2nd element, you can use e.g.
for $(echo $!a[@] | cut -d" " -f 2-) ; do unset "a[$i]"; done
edited Apr 30 '13 at 17:05
answered Apr 30 '13 at 16:20
jofeljofel
20.8k34980
20.8k34980
I already did this n had updated in question.. but question remain aboutunset a[@]::2
– Rahul Patil
Apr 30 '13 at 16:32
That's wrong in the general case because$#a[@]
is the number of elements in the array, not the greatest indice in the array (bash
arrays, likeksh
arrays are sparse, contrary to zsh ones).
– Stéphane Chazelas
Apr 30 '13 at 16:43
@StephaneChazelas after deleting element why not reset index ?
– Rahul Patil
Apr 30 '13 at 16:54
@StephaneChazelas after doing some RnD I Found this way to reset arraya=( $(echo $a[@]) )
is this fine ?
– Rahul Patil
Apr 30 '13 at 17:05
2
@RahulPatil, if you want to unsparse the array, just write it:a=("$a[@]")
, usingecho
and command substitution would only work in limited corner cases (like when none of the elements are empty or contain spc, tab, NL, backslash, *, ?, [ or start with -).
– Stéphane Chazelas
Apr 30 '13 at 19:40
|
show 1 more comment
I already did this n had updated in question.. but question remain aboutunset a[@]::2
– Rahul Patil
Apr 30 '13 at 16:32
That's wrong in the general case because$#a[@]
is the number of elements in the array, not the greatest indice in the array (bash
arrays, likeksh
arrays are sparse, contrary to zsh ones).
– Stéphane Chazelas
Apr 30 '13 at 16:43
@StephaneChazelas after deleting element why not reset index ?
– Rahul Patil
Apr 30 '13 at 16:54
@StephaneChazelas after doing some RnD I Found this way to reset arraya=( $(echo $a[@]) )
is this fine ?
– Rahul Patil
Apr 30 '13 at 17:05
2
@RahulPatil, if you want to unsparse the array, just write it:a=("$a[@]")
, usingecho
and command substitution would only work in limited corner cases (like when none of the elements are empty or contain spc, tab, NL, backslash, *, ?, [ or start with -).
– Stéphane Chazelas
Apr 30 '13 at 19:40
I already did this n had updated in question.. but question remain about
unset a[@]::2
– Rahul Patil
Apr 30 '13 at 16:32
I already did this n had updated in question.. but question remain about
unset a[@]::2
– Rahul Patil
Apr 30 '13 at 16:32
That's wrong in the general case because
$#a[@]
is the number of elements in the array, not the greatest indice in the array (bash
arrays, like ksh
arrays are sparse, contrary to zsh ones).– Stéphane Chazelas
Apr 30 '13 at 16:43
That's wrong in the general case because
$#a[@]
is the number of elements in the array, not the greatest indice in the array (bash
arrays, like ksh
arrays are sparse, contrary to zsh ones).– Stéphane Chazelas
Apr 30 '13 at 16:43
@StephaneChazelas after deleting element why not reset index ?
– Rahul Patil
Apr 30 '13 at 16:54
@StephaneChazelas after deleting element why not reset index ?
– Rahul Patil
Apr 30 '13 at 16:54
@StephaneChazelas after doing some RnD I Found this way to reset array
a=( $(echo $a[@]) )
is this fine ?– Rahul Patil
Apr 30 '13 at 17:05
@StephaneChazelas after doing some RnD I Found this way to reset array
a=( $(echo $a[@]) )
is this fine ?– Rahul Patil
Apr 30 '13 at 17:05
2
2
@RahulPatil, if you want to unsparse the array, just write it:
a=("$a[@]")
, using echo
and command substitution would only work in limited corner cases (like when none of the elements are empty or contain spc, tab, NL, backslash, *, ?, [ or start with -).– Stéphane Chazelas
Apr 30 '13 at 19:40
@RahulPatil, if you want to unsparse the array, just write it:
a=("$a[@]")
, using echo
and command substitution would only work in limited corner cases (like when none of the elements are empty or contain spc, tab, NL, backslash, *, ?, [ or start with -).– Stéphane Chazelas
Apr 30 '13 at 19:40
|
show 1 more comment
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