convert hexadecimal to binary

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3















I have a text file with lines (each of 631 characters) consisting of 16 hexadecimal numbers 0,1,2,...,9,A,B,...,F. I would like to replace each number with the corresponding 4 bits of 0 and 1, i.e. 0 with 0000, 1 with 0001, ..., F with 1111 and then save the file as .bin. How can I do so in Linux terminal?



Some lines of my text file are:



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
6321EB4F15D5F01D2A5F7474AC6FFCD1A8B52E680AC52CA9B500C956FD269DB8107EFCF6EC0B23B2C54B3A727CC53F6793019BF0D95A037485413576E4A0172A597027ED71D6E785430FA4748E164E5290214B01740736C0EC79D286692170B6EFBA21592EC485350F0DC6C635CD3FA7DAED258405C4247BFA68613B5F7CBEC903E16EA2E780D0934F0A2918F837CF0115B3D76AAFD3F37D905F9572D334D959DDD22C37EBA7707A76333A491F79B9C53A7912AEA38ED400949EB9AD9FCEE71765F4F4A2E21C481A509AB6807DDF5374D9A1A4D0C589E628CAA3C6DC9E4A5C1A7EF3C36A4D2231E2C1E856A19B6F7F4DE713D5BE8A4EFA750FB29A34F00754D875C22C2FC981FAECCC7113D1B0D6FF3BCC747852789A662D104DF1A8C90EB4DDFA48502A3BA9AAE70E7229E8A3D6FBBD00C19D99765BAFC9B09D547
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  • 1





    This question has an answer HERE

    – MelBurslan
    Apr 27 '16 at 14:24






  • 1





    for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc;done then you may need to do some padding for binary numbers shorter than 4 digits

    – MelBurslan
    Apr 27 '16 at 14:33












  • @MelBurslan +1 and you should write that as an answer.

    – dr01
    Apr 27 '16 at 14:34

















3















I have a text file with lines (each of 631 characters) consisting of 16 hexadecimal numbers 0,1,2,...,9,A,B,...,F. I would like to replace each number with the corresponding 4 bits of 0 and 1, i.e. 0 with 0000, 1 with 0001, ..., F with 1111 and then save the file as .bin. How can I do so in Linux terminal?



Some lines of my text file are:



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  • 1





    This question has an answer HERE

    – MelBurslan
    Apr 27 '16 at 14:24






  • 1





    for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc;done then you may need to do some padding for binary numbers shorter than 4 digits

    – MelBurslan
    Apr 27 '16 at 14:33












  • @MelBurslan +1 and you should write that as an answer.

    – dr01
    Apr 27 '16 at 14:34













3












3








3


1






I have a text file with lines (each of 631 characters) consisting of 16 hexadecimal numbers 0,1,2,...,9,A,B,...,F. I would like to replace each number with the corresponding 4 bits of 0 and 1, i.e. 0 with 0000, 1 with 0001, ..., F with 1111 and then save the file as .bin. How can I do so in Linux terminal?



Some lines of my text file are:



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I have a text file with lines (each of 631 characters) consisting of 16 hexadecimal numbers 0,1,2,...,9,A,B,...,F. I would like to replace each number with the corresponding 4 bits of 0 and 1, i.e. 0 with 0000, 1 with 0001, ..., F with 1111 and then save the file as .bin. How can I do so in Linux terminal?



Some lines of my text file are:



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






text-processing






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edited Apr 27 '16 at 17:21









MelBurslan

5,34611533




5,34611533










asked Apr 27 '16 at 14:20









user166316user166316

184




184







  • 1





    This question has an answer HERE

    – MelBurslan
    Apr 27 '16 at 14:24






  • 1





    for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc;done then you may need to do some padding for binary numbers shorter than 4 digits

    – MelBurslan
    Apr 27 '16 at 14:33












  • @MelBurslan +1 and you should write that as an answer.

    – dr01
    Apr 27 '16 at 14:34












  • 1





    This question has an answer HERE

    – MelBurslan
    Apr 27 '16 at 14:24






  • 1





    for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc;done then you may need to do some padding for binary numbers shorter than 4 digits

    – MelBurslan
    Apr 27 '16 at 14:33












  • @MelBurslan +1 and you should write that as an answer.

    – dr01
    Apr 27 '16 at 14:34







1




1





This question has an answer HERE

– MelBurslan
Apr 27 '16 at 14:24





This question has an answer HERE

– MelBurslan
Apr 27 '16 at 14:24




1




1





for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc;done then you may need to do some padding for binary numbers shorter than 4 digits

– MelBurslan
Apr 27 '16 at 14:33






for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc;done then you may need to do some padding for binary numbers shorter than 4 digits

– MelBurslan
Apr 27 '16 at 14:33














@MelBurslan +1 and you should write that as an answer.

– dr01
Apr 27 '16 at 14:34





@MelBurslan +1 and you should write that as an answer.

– dr01
Apr 27 '16 at 14:34










3 Answers
3






active

oldest

votes


















1














Posting my comment as an answer to be marked as "solved"



for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done



Okay, in the light of what you have said and what I understood, I have a couple of suggestions to you. The first one, converts each hex line into a new binary line and puts a line break at the end of each line. here is that solution:



cat myfile | while read line
do
len=$#line
binline=""
index=1
while [ $index -le $len ]
do
hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
bin=$(echo "obase=2; ibase=16; $hex"|bc)
padbin=$(printf "%04d" $bin)
binline="$binline$padbin"
(( index++ ))
done
echo $binline >> program.bin
done


And, if I am not mistaken, you are trying to use this binary file as a program to an embedded system or something similar. If that is the case the line breaks may present a problem. If this is the case, i.e., you want the whole file as one single humongous line, you can use the following snippet:



cat myfile | while read line
do
len=$#line
index=1
while [ $index -le $len ]
do
hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
bin=$(echo "obase=2; ibase=16; $hex"|bc)
printf "%04d" $bin >> p2.bin
(( index++ ))
done
done


Having said all of this, if your hexadecimal values file is in gigabytes size or even few hundred megabytes size, bash will complain and may throw a cryptic error. So, it is in your best interest to chop this input file to more manageable chunks and process them piece-by-piece.



Please note that, I wrote these scripts in the simplest for to understand. Hence it will have some performance penalties when you run them. 3 lines takes about 6 seconds of processing time. It is up to you to optimize it, if you find the wait intolerable.






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  • 1





    Thank you ! And how can I save my file in .bin format?

    – user166316
    Apr 27 '16 at 14:40











  • I am not sure what you mean by bin format but you can output these numbers to a files named as program.bin for instance using redirection at the end of the command, i.e., for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done >program.bin, but since you mentioned the word program, I am assuming there has to be some other heading or trailing blocks for your machine to understand, this is a program, not a random string of 1s and 0s. At this point you are on your own.

    – MelBurslan
    Apr 27 '16 at 14:46











  • OK, I got it ! Thanks ! But the terminal closes for my large file of 58 GB when I run the for loop. What can I do?

    – user166316
    Apr 27 '16 at 15:32












  • I tried for a small file, what I see in the output file is: 10000101100001101000110101101011000011111101010111110011000110000110 11011110100100101010011111111100000000100011110011001000010010000001 ... After every 68 zeros and ones there is a backslash, how can I remove it and have all 0s and 1s one after the other?

    – user166316
    Apr 27 '16 at 15:49











  • could you please post a few lines from your original file, so that I can see and test my code snippet against it ? Please update your original post and put the lines there, not here as a comment.

    – MelBurslan
    Apr 27 '16 at 15:59


















1














xxd -r -p



Example:



printf 12345678 | xxd -r -p | od -A n -t x1 -v


gives:



 12 34 56 78


od dumped the bytes, so xxd -r -p did what we wanted.






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    0














    You can use printf:





    $ printf '%04dn' 0
    0000

    $ printf '%04dn' 1
    0001


    Or the POSIX Awk stdlib library:



    $ awklib 'BEGIN print base_conv("F", 16, 2)'
    1111





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      3 Answers
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      1














      Posting my comment as an answer to be marked as "solved"



      for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done



      Okay, in the light of what you have said and what I understood, I have a couple of suggestions to you. The first one, converts each hex line into a new binary line and puts a line break at the end of each line. here is that solution:



      cat myfile | while read line
      do
      len=$#line
      binline=""
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      padbin=$(printf "%04d" $bin)
      binline="$binline$padbin"
      (( index++ ))
      done
      echo $binline >> program.bin
      done


      And, if I am not mistaken, you are trying to use this binary file as a program to an embedded system or something similar. If that is the case the line breaks may present a problem. If this is the case, i.e., you want the whole file as one single humongous line, you can use the following snippet:



      cat myfile | while read line
      do
      len=$#line
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      printf "%04d" $bin >> p2.bin
      (( index++ ))
      done
      done


      Having said all of this, if your hexadecimal values file is in gigabytes size or even few hundred megabytes size, bash will complain and may throw a cryptic error. So, it is in your best interest to chop this input file to more manageable chunks and process them piece-by-piece.



      Please note that, I wrote these scripts in the simplest for to understand. Hence it will have some performance penalties when you run them. 3 lines takes about 6 seconds of processing time. It is up to you to optimize it, if you find the wait intolerable.






      share|improve this answer




















      • 1





        Thank you ! And how can I save my file in .bin format?

        – user166316
        Apr 27 '16 at 14:40











      • I am not sure what you mean by bin format but you can output these numbers to a files named as program.bin for instance using redirection at the end of the command, i.e., for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done >program.bin, but since you mentioned the word program, I am assuming there has to be some other heading or trailing blocks for your machine to understand, this is a program, not a random string of 1s and 0s. At this point you are on your own.

        – MelBurslan
        Apr 27 '16 at 14:46











      • OK, I got it ! Thanks ! But the terminal closes for my large file of 58 GB when I run the for loop. What can I do?

        – user166316
        Apr 27 '16 at 15:32












      • I tried for a small file, what I see in the output file is: 10000101100001101000110101101011000011111101010111110011000110000110 11011110100100101010011111111100000000100011110011001000010010000001 ... After every 68 zeros and ones there is a backslash, how can I remove it and have all 0s and 1s one after the other?

        – user166316
        Apr 27 '16 at 15:49











      • could you please post a few lines from your original file, so that I can see and test my code snippet against it ? Please update your original post and put the lines there, not here as a comment.

        – MelBurslan
        Apr 27 '16 at 15:59















      1














      Posting my comment as an answer to be marked as "solved"



      for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done



      Okay, in the light of what you have said and what I understood, I have a couple of suggestions to you. The first one, converts each hex line into a new binary line and puts a line break at the end of each line. here is that solution:



      cat myfile | while read line
      do
      len=$#line
      binline=""
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      padbin=$(printf "%04d" $bin)
      binline="$binline$padbin"
      (( index++ ))
      done
      echo $binline >> program.bin
      done


      And, if I am not mistaken, you are trying to use this binary file as a program to an embedded system or something similar. If that is the case the line breaks may present a problem. If this is the case, i.e., you want the whole file as one single humongous line, you can use the following snippet:



      cat myfile | while read line
      do
      len=$#line
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      printf "%04d" $bin >> p2.bin
      (( index++ ))
      done
      done


      Having said all of this, if your hexadecimal values file is in gigabytes size or even few hundred megabytes size, bash will complain and may throw a cryptic error. So, it is in your best interest to chop this input file to more manageable chunks and process them piece-by-piece.



      Please note that, I wrote these scripts in the simplest for to understand. Hence it will have some performance penalties when you run them. 3 lines takes about 6 seconds of processing time. It is up to you to optimize it, if you find the wait intolerable.






      share|improve this answer




















      • 1





        Thank you ! And how can I save my file in .bin format?

        – user166316
        Apr 27 '16 at 14:40











      • I am not sure what you mean by bin format but you can output these numbers to a files named as program.bin for instance using redirection at the end of the command, i.e., for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done >program.bin, but since you mentioned the word program, I am assuming there has to be some other heading or trailing blocks for your machine to understand, this is a program, not a random string of 1s and 0s. At this point you are on your own.

        – MelBurslan
        Apr 27 '16 at 14:46











      • OK, I got it ! Thanks ! But the terminal closes for my large file of 58 GB when I run the for loop. What can I do?

        – user166316
        Apr 27 '16 at 15:32












      • I tried for a small file, what I see in the output file is: 10000101100001101000110101101011000011111101010111110011000110000110 11011110100100101010011111111100000000100011110011001000010010000001 ... After every 68 zeros and ones there is a backslash, how can I remove it and have all 0s and 1s one after the other?

        – user166316
        Apr 27 '16 at 15:49











      • could you please post a few lines from your original file, so that I can see and test my code snippet against it ? Please update your original post and put the lines there, not here as a comment.

        – MelBurslan
        Apr 27 '16 at 15:59













      1












      1








      1







      Posting my comment as an answer to be marked as "solved"



      for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done



      Okay, in the light of what you have said and what I understood, I have a couple of suggestions to you. The first one, converts each hex line into a new binary line and puts a line break at the end of each line. here is that solution:



      cat myfile | while read line
      do
      len=$#line
      binline=""
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      padbin=$(printf "%04d" $bin)
      binline="$binline$padbin"
      (( index++ ))
      done
      echo $binline >> program.bin
      done


      And, if I am not mistaken, you are trying to use this binary file as a program to an embedded system or something similar. If that is the case the line breaks may present a problem. If this is the case, i.e., you want the whole file as one single humongous line, you can use the following snippet:



      cat myfile | while read line
      do
      len=$#line
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      printf "%04d" $bin >> p2.bin
      (( index++ ))
      done
      done


      Having said all of this, if your hexadecimal values file is in gigabytes size or even few hundred megabytes size, bash will complain and may throw a cryptic error. So, it is in your best interest to chop this input file to more manageable chunks and process them piece-by-piece.



      Please note that, I wrote these scripts in the simplest for to understand. Hence it will have some performance penalties when you run them. 3 lines takes about 6 seconds of processing time. It is up to you to optimize it, if you find the wait intolerable.






      share|improve this answer















      Posting my comment as an answer to be marked as "solved"



      for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done



      Okay, in the light of what you have said and what I understood, I have a couple of suggestions to you. The first one, converts each hex line into a new binary line and puts a line break at the end of each line. here is that solution:



      cat myfile | while read line
      do
      len=$#line
      binline=""
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      padbin=$(printf "%04d" $bin)
      binline="$binline$padbin"
      (( index++ ))
      done
      echo $binline >> program.bin
      done


      And, if I am not mistaken, you are trying to use this binary file as a program to an embedded system or something similar. If that is the case the line breaks may present a problem. If this is the case, i.e., you want the whole file as one single humongous line, you can use the following snippet:



      cat myfile | while read line
      do
      len=$#line
      index=1
      while [ $index -le $len ]
      do
      hex=$(echo $line | cut -c $index | tr 'a-f' 'A-F')
      bin=$(echo "obase=2; ibase=16; $hex"|bc)
      printf "%04d" $bin >> p2.bin
      (( index++ ))
      done
      done


      Having said all of this, if your hexadecimal values file is in gigabytes size or even few hundred megabytes size, bash will complain and may throw a cryptic error. So, it is in your best interest to chop this input file to more manageable chunks and process them piece-by-piece.



      Please note that, I wrote these scripts in the simplest for to understand. Hence it will have some performance penalties when you run them. 3 lines takes about 6 seconds of processing time. It is up to you to optimize it, if you find the wait intolerable.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Apr 27 '16 at 18:23

























      answered Apr 27 '16 at 14:38









      MelBurslanMelBurslan

      5,34611533




      5,34611533







      • 1





        Thank you ! And how can I save my file in .bin format?

        – user166316
        Apr 27 '16 at 14:40











      • I am not sure what you mean by bin format but you can output these numbers to a files named as program.bin for instance using redirection at the end of the command, i.e., for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done >program.bin, but since you mentioned the word program, I am assuming there has to be some other heading or trailing blocks for your machine to understand, this is a program, not a random string of 1s and 0s. At this point you are on your own.

        – MelBurslan
        Apr 27 '16 at 14:46











      • OK, I got it ! Thanks ! But the terminal closes for my large file of 58 GB when I run the for loop. What can I do?

        – user166316
        Apr 27 '16 at 15:32












      • I tried for a small file, what I see in the output file is: 10000101100001101000110101101011000011111101010111110011000110000110 11011110100100101010011111111100000000100011110011001000010010000001 ... After every 68 zeros and ones there is a backslash, how can I remove it and have all 0s and 1s one after the other?

        – user166316
        Apr 27 '16 at 15:49











      • could you please post a few lines from your original file, so that I can see and test my code snippet against it ? Please update your original post and put the lines there, not here as a comment.

        – MelBurslan
        Apr 27 '16 at 15:59












      • 1





        Thank you ! And how can I save my file in .bin format?

        – user166316
        Apr 27 '16 at 14:40











      • I am not sure what you mean by bin format but you can output these numbers to a files named as program.bin for instance using redirection at the end of the command, i.e., for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done >program.bin, but since you mentioned the word program, I am assuming there has to be some other heading or trailing blocks for your machine to understand, this is a program, not a random string of 1s and 0s. At this point you are on your own.

        – MelBurslan
        Apr 27 '16 at 14:46











      • OK, I got it ! Thanks ! But the terminal closes for my large file of 58 GB when I run the for loop. What can I do?

        – user166316
        Apr 27 '16 at 15:32












      • I tried for a small file, what I see in the output file is: 10000101100001101000110101101011000011111101010111110011000110000110 11011110100100101010011111111100000000100011110011001000010010000001 ... After every 68 zeros and ones there is a backslash, how can I remove it and have all 0s and 1s one after the other?

        – user166316
        Apr 27 '16 at 15:49











      • could you please post a few lines from your original file, so that I can see and test my code snippet against it ? Please update your original post and put the lines there, not here as a comment.

        – MelBurslan
        Apr 27 '16 at 15:59







      1




      1





      Thank you ! And how can I save my file in .bin format?

      – user166316
      Apr 27 '16 at 14:40





      Thank you ! And how can I save my file in .bin format?

      – user166316
      Apr 27 '16 at 14:40













      I am not sure what you mean by bin format but you can output these numbers to a files named as program.bin for instance using redirection at the end of the command, i.e., for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done >program.bin, but since you mentioned the word program, I am assuming there has to be some other heading or trailing blocks for your machine to understand, this is a program, not a random string of 1s and 0s. At this point you are on your own.

      – MelBurslan
      Apr 27 '16 at 14:46





      I am not sure what you mean by bin format but you can output these numbers to a files named as program.bin for instance using redirection at the end of the command, i.e., for n in $(cat myfile | tr 'a-f' 'A-F');do echo "obase=2; ibase=16; $n" | bc ;done >program.bin, but since you mentioned the word program, I am assuming there has to be some other heading or trailing blocks for your machine to understand, this is a program, not a random string of 1s and 0s. At this point you are on your own.

      – MelBurslan
      Apr 27 '16 at 14:46













      OK, I got it ! Thanks ! But the terminal closes for my large file of 58 GB when I run the for loop. What can I do?

      – user166316
      Apr 27 '16 at 15:32






      OK, I got it ! Thanks ! But the terminal closes for my large file of 58 GB when I run the for loop. What can I do?

      – user166316
      Apr 27 '16 at 15:32














      I tried for a small file, what I see in the output file is: 10000101100001101000110101101011000011111101010111110011000110000110 11011110100100101010011111111100000000100011110011001000010010000001 ... After every 68 zeros and ones there is a backslash, how can I remove it and have all 0s and 1s one after the other?

      – user166316
      Apr 27 '16 at 15:49





      I tried for a small file, what I see in the output file is: 10000101100001101000110101101011000011111101010111110011000110000110 11011110100100101010011111111100000000100011110011001000010010000001 ... After every 68 zeros and ones there is a backslash, how can I remove it and have all 0s and 1s one after the other?

      – user166316
      Apr 27 '16 at 15:49













      could you please post a few lines from your original file, so that I can see and test my code snippet against it ? Please update your original post and put the lines there, not here as a comment.

      – MelBurslan
      Apr 27 '16 at 15:59





      could you please post a few lines from your original file, so that I can see and test my code snippet against it ? Please update your original post and put the lines there, not here as a comment.

      – MelBurslan
      Apr 27 '16 at 15:59













      1














      xxd -r -p



      Example:



      printf 12345678 | xxd -r -p | od -A n -t x1 -v


      gives:



       12 34 56 78


      od dumped the bytes, so xxd -r -p did what we wanted.






      share|improve this answer



























        1














        xxd -r -p



        Example:



        printf 12345678 | xxd -r -p | od -A n -t x1 -v


        gives:



         12 34 56 78


        od dumped the bytes, so xxd -r -p did what we wanted.






        share|improve this answer

























          1












          1








          1







          xxd -r -p



          Example:



          printf 12345678 | xxd -r -p | od -A n -t x1 -v


          gives:



           12 34 56 78


          od dumped the bytes, so xxd -r -p did what we wanted.






          share|improve this answer













          xxd -r -p



          Example:



          printf 12345678 | xxd -r -p | od -A n -t x1 -v


          gives:



           12 34 56 78


          od dumped the bytes, so xxd -r -p did what we wanted.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 8 at 13:59









          Ciro Santilli 新疆改造中心 六四事件 法轮功Ciro Santilli 新疆改造中心 六四事件 法轮功

          5,41024644




          5,41024644





















              0














              You can use printf:





              $ printf '%04dn' 0
              0000

              $ printf '%04dn' 1
              0001


              Or the POSIX Awk stdlib library:



              $ awklib 'BEGIN print base_conv("F", 16, 2)'
              1111





              share|improve this answer



























                0














                You can use printf:





                $ printf '%04dn' 0
                0000

                $ printf '%04dn' 1
                0001


                Or the POSIX Awk stdlib library:



                $ awklib 'BEGIN print base_conv("F", 16, 2)'
                1111





                share|improve this answer

























                  0












                  0








                  0







                  You can use printf:





                  $ printf '%04dn' 0
                  0000

                  $ printf '%04dn' 1
                  0001


                  Or the POSIX Awk stdlib library:



                  $ awklib 'BEGIN print base_conv("F", 16, 2)'
                  1111





                  share|improve this answer













                  You can use printf:





                  $ printf '%04dn' 0
                  0000

                  $ printf '%04dn' 1
                  0001


                  Or the POSIX Awk stdlib library:



                  $ awklib 'BEGIN print base_conv("F", 16, 2)'
                  1111






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Apr 9 '17 at 3:11









                  Steven PennySteven Penny

                  1




                  1



























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