How to find files dynamically and copy them to a directory in linux
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up vote
0
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Trying to find these files and copy them to a directory (test_dir);
abc-1.0.zip
kncb-1.0.zip
jenk-1.1.zip
I would like to find all these files dynamically and copy them to a directory. I have tried the below command but it copies only last file(jenk*.zip) only, need a command which copies all the above files to a directory mentioned (test_dir);
find / -type f -name "*abc*.zip" -o -name "*kncb*.zip" -o -name "*jenk*.zip" ! -path '*/test_dir/*.jar' -exec cp -ar ./test_dir ;
linux find cp
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
asked Sep 25 at 1:40
itgeek
151
add a comment |Â
up vote
0
down vote
favorite
Trying to find these files and copy them to a directory (test_dir);
abc-1.0.zip
kncb-1.0.zip
jenk-1.1.zip
I would like to find all these files dynamically and copy them to a directory. I have tried the below command but it copies only last file(jenk*.zip) only, need a command which copies all the above files to a directory mentioned (test_dir);
find / -type f -name "*abc*.zip" -o -name "*kncb*.zip" -o -name "*jenk*.zip" ! -path '*/test_dir/*.jar' -exec cp -ar ./test_dir ;
linux find cp
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
asked Sep 25 at 1:40
itgeek
151
are you guaranteed that there'll only be one of each of those?
– Jeff Schaller
Sep 25 at 1:54
why are you recursively copying (-r) when you're looking (presumably) for single files?
– Jeff Schaller
Sep 25 at 1:55
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Trying to find these files and copy them to a directory (test_dir);
abc-1.0.zip
kncb-1.0.zip
jenk-1.1.zip
I would like to find all these files dynamically and copy them to a directory. I have tried the below command but it copies only last file(jenk*.zip) only, need a command which copies all the above files to a directory mentioned (test_dir);
find / -type f -name "*abc*.zip" -o -name "*kncb*.zip" -o -name "*jenk*.zip" ! -path '*/test_dir/*.jar' -exec cp -ar ./test_dir ;
linux find cp
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
asked Sep 25 at 1:40
itgeek
151
Trying to find these files and copy them to a directory (test_dir);
abc-1.0.zip
kncb-1.0.zip
jenk-1.1.zip
I would like to find all these files dynamically and copy them to a directory. I have tried the below command but it copies only last file(jenk*.zip) only, need a command which copies all the above files to a directory mentioned (test_dir);
find / -type f -name "*abc*.zip" -o -name "*kncb*.zip" -o -name "*jenk*.zip" ! -path '*/test_dir/*.jar' -exec cp -ar ./test_dir ;
linux find cp
linux find cp
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
asked Sep 25 at 1:40
itgeek
151
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
asked Sep 25 at 1:40
itgeek
151
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
edited Sep 25 at 1:55
Jeff Schaller
33.3k850112
33.3k850112
asked Sep 25 at 1:40
itgeek
151
asked Sep 25 at 1:40
itgeek
151
asked Sep 25 at 1:40
itgeek
151
151
are you guaranteed that there'll only be one of each of those?
– Jeff Schaller
Sep 25 at 1:54
why are you recursively copying (-r) when you're looking (presumably) for single files?
– Jeff Schaller
Sep 25 at 1:55
add a comment |Â
are you guaranteed that there'll only be one of each of those?
– Jeff Schaller
Sep 25 at 1:54
why are you recursively copying (-r) when you're looking (presumably) for single files?
– Jeff Schaller
Sep 25 at 1:55
are you guaranteed that there'll only be one of each of those?
– Jeff Schaller
Sep 25 at 1:54
are you guaranteed that there'll only be one of each of those?
– Jeff Schaller
Sep 25 at 1:54
why are you recursively copying (
-r) when you're looking (presumably) for single files?– Jeff Schaller
Sep 25 at 1:55
why are you recursively copying (
-r) when you're looking (presumably) for single files?– Jeff Schaller
Sep 25 at 1:55
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
2
down vote
You need to apply ( ) around your OR construct.
An explanation can be found in the man page:
Please note that -a, when specified implicitly (for example by two
tests appearing without an explicit operator between them) or
explicitly, has higher precedence than -o. This means that find . -name
afile -o -name bfile -print will never print afile.
Example:
touch afile bfile
Without ( ):
find . -name afile -o -name bfile -print
./bfile
which has an implicit -a between -name bfile and -print:
find . -name afile -o -name bfile -a -print
./bfile
With ( ) the result is as expected:
find . ( -name afile -o -name bfile ) -print
./afile
./bfile
Your implicit -a lies between -o -name "*jenk*.zip" and ! -path '*/test_dir/*.jar'.
answered Sep 25 at 4:59
nst0022
1062
Getting an error when I run this from jenkins; find / (-name "abc.zip" -o -name "kncb.zip" -o -name "jenk.zip" ) ! -path '/test_dir/.jar' -exec cp -ar ./test_dir ; find: invalid expression; you have used a binary operator '-o' with nothing before it.
– itgeek
Sep 25 at 13:57
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
You need to apply ( ) around your OR construct.
An explanation can be found in the man page:
Please note that -a, when specified implicitly (for example by two
tests appearing without an explicit operator between them) or
explicitly, has higher precedence than -o. This means that find . -name
afile -o -name bfile -print will never print afile.
Example:
touch afile bfile
Without ( ):
find . -name afile -o -name bfile -print
./bfile
which has an implicit -a between -name bfile and -print:
find . -name afile -o -name bfile -a -print
./bfile
With ( ) the result is as expected:
find . ( -name afile -o -name bfile ) -print
./afile
./bfile
Your implicit -a lies between -o -name "*jenk*.zip" and ! -path '*/test_dir/*.jar'.
answered Sep 25 at 4:59
nst0022
1062
Getting an error when I run this from jenkins; find / (-name "abc.zip" -o -name "kncb.zip" -o -name "jenk.zip" ) ! -path '/test_dir/.jar' -exec cp -ar ./test_dir ; find: invalid expression; you have used a binary operator '-o' with nothing before it.
– itgeek
Sep 25 at 13:57
add a comment |Â
up vote
2
down vote
You need to apply ( ) around your OR construct.
An explanation can be found in the man page:
Please note that -a, when specified implicitly (for example by two
tests appearing without an explicit operator between them) or
explicitly, has higher precedence than -o. This means that find . -name
afile -o -name bfile -print will never print afile.
Example:
touch afile bfile
Without ( ):
find . -name afile -o -name bfile -print
./bfile
which has an implicit -a between -name bfile and -print:
find . -name afile -o -name bfile -a -print
./bfile
With ( ) the result is as expected:
find . ( -name afile -o -name bfile ) -print
./afile
./bfile
Your implicit -a lies between -o -name "*jenk*.zip" and ! -path '*/test_dir/*.jar'.
answered Sep 25 at 4:59
nst0022
1062
Getting an error when I run this from jenkins; find / (-name "abc.zip" -o -name "kncb.zip" -o -name "jenk.zip" ) ! -path '/test_dir/.jar' -exec cp -ar ./test_dir ; find: invalid expression; you have used a binary operator '-o' with nothing before it.
– itgeek
Sep 25 at 13:57
add a comment |Â
up vote
2
down vote
up vote
2
down vote
You need to apply ( ) around your OR construct.
An explanation can be found in the man page:
Please note that -a, when specified implicitly (for example by two
tests appearing without an explicit operator between them) or
explicitly, has higher precedence than -o. This means that find . -name
afile -o -name bfile -print will never print afile.
Example:
touch afile bfile
Without ( ):
find . -name afile -o -name bfile -print
./bfile
which has an implicit -a between -name bfile and -print:
find . -name afile -o -name bfile -a -print
./bfile
With ( ) the result is as expected:
find . ( -name afile -o -name bfile ) -print
./afile
./bfile
Your implicit -a lies between -o -name "*jenk*.zip" and ! -path '*/test_dir/*.jar'.
answered Sep 25 at 4:59
nst0022
1062
You need to apply ( ) around your OR construct.
An explanation can be found in the man page:
Please note that -a, when specified implicitly (for example by two
tests appearing without an explicit operator between them) or
explicitly, has higher precedence than -o. This means that find . -name
afile -o -name bfile -print will never print afile.
Example:
touch afile bfile
Without ( ):
find . -name afile -o -name bfile -print
./bfile
which has an implicit -a between -name bfile and -print:
find . -name afile -o -name bfile -a -print
./bfile
With ( ) the result is as expected:
find . ( -name afile -o -name bfile ) -print
./afile
./bfile
Your implicit -a lies between -o -name "*jenk*.zip" and ! -path '*/test_dir/*.jar'.
answered Sep 25 at 4:59
nst0022
1062
answered Sep 25 at 4:59
nst0022
1062
answered Sep 25 at 4:59
nst0022
1062
answered Sep 25 at 4:59
nst0022
1062
1062
Getting an error when I run this from jenkins; find / (-name "abc.zip" -o -name "kncb.zip" -o -name "jenk.zip" ) ! -path '/test_dir/.jar' -exec cp -ar ./test_dir ; find: invalid expression; you have used a binary operator '-o' with nothing before it.
– itgeek
Sep 25 at 13:57
add a comment |Â
Getting an error when I run this from jenkins; find / (-name "abc.zip" -o -name "kncb.zip" -o -name "jenk.zip" ) ! -path '/test_dir/.jar' -exec cp -ar ./test_dir ; find: invalid expression; you have used a binary operator '-o' with nothing before it.
– itgeek
Sep 25 at 13:57
Getting an error when I run this from jenkins; find / (-name "abc.zip" -o -name "kncb.zip" -o -name "jenk.zip" ) ! -path '/test_dir/.jar' -exec cp -ar ./test_dir ; find: invalid expression; you have used a binary operator '-o' with nothing before it.
– itgeek
Sep 25 at 13:57
Getting an error when I run this from jenkins; find / (-name "abc.zip" -o -name "kncb.zip" -o -name "jenk.zip" ) ! -path '/test_dir/.jar' -exec cp -ar ./test_dir ; find: invalid expression; you have used a binary operator '-o' with nothing before it.
– itgeek
Sep 25 at 13:57
add a comment |Â
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are you guaranteed that there'll only be one of each of those?
– Jeff Schaller
Sep 25 at 1:54
why are you recursively copying (
-r) when you're looking (presumably) for single files?– Jeff Schaller
Sep 25 at 1:55