Array Test: Looping through an array

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1
down vote

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Why isn't this simple test returning any values for array index [1] and onwards?

#!/bin/bash

SessionName=(
'SessionName_1'
'SessionName_2'
)

srcds_run=(
'/path/to/srcds_run'
'/path/to/srcds_run_2'
)

array=(
SessionName
srcds_run
)

clear
echo

for element in "$array[@]"
do
 echo "$element[0] = $!element[0]"
 echo "$element[1] = $!element[1]"
done

echo
echo "literal printout test:"
echo "SessionName[0] = $SessionName[0]"
echo "SessionName[1] = $SessionName[1]"

The script outputs this:

SessionName[0] = SessionName_1
SessionName[1] =
srcds_run[0] = /path/to/srcds_run
srcds_run[1] =

literal printout test:
SessionName[0] = SessionName_1
SessionName[1] = SessionName_2

Thanks

edited 3 mins ago

don_crissti

47.9k15126155

asked 6 mins ago

johndoe

111

New contributor

Possible duplicate of How to access further members of an array when using bash variable indirection?
â€“Â don_crissti
3 mins ago

add a commentÂ |Â

up vote
1
down vote

favorite

Why isn't this simple test returning any values for array index [1] and onwards?

#!/bin/bash

SessionName=(
'SessionName_1'
'SessionName_2'
)

srcds_run=(
'/path/to/srcds_run'
'/path/to/srcds_run_2'
)

array=(
SessionName
srcds_run
)

clear
echo

for element in "$array[@]"
do
 echo "$element[0] = $!element[0]"
 echo "$element[1] = $!element[1]"
done

echo
echo "literal printout test:"
echo "SessionName[0] = $SessionName[0]"
echo "SessionName[1] = $SessionName[1]"

The script outputs this:

SessionName[0] = SessionName_1
SessionName[1] =
srcds_run[0] = /path/to/srcds_run
srcds_run[1] =

literal printout test:
SessionName[0] = SessionName_1
SessionName[1] = SessionName_2

Thanks

edited 3 mins ago

don_crissti

47.9k15126155

asked 6 mins ago

johndoe

111

New contributor

Possible duplicate of How to access further members of an array when using bash variable indirection?
â€“Â don_crissti
3 mins ago

add a commentÂ |Â

up vote
1
down vote

favorite

Why isn't this simple test returning any values for array index [1] and onwards?

#!/bin/bash

SessionName=(
'SessionName_1'
'SessionName_2'
)

srcds_run=(
'/path/to/srcds_run'
'/path/to/srcds_run_2'
)

array=(
SessionName
srcds_run
)

clear
echo

for element in "$array[@]"
do
 echo "$element[0] = $!element[0]"
 echo "$element[1] = $!element[1]"
done

echo
echo "literal printout test:"
echo "SessionName[0] = $SessionName[0]"
echo "SessionName[1] = $SessionName[1]"

The script outputs this:

SessionName[0] = SessionName_1
SessionName[1] =
srcds_run[0] = /path/to/srcds_run
srcds_run[1] =

literal printout test:
SessionName[0] = SessionName_1
SessionName[1] = SessionName_2

Thanks

edited 3 mins ago

don_crissti

47.9k15126155

asked 6 mins ago

johndoe

111

New contributor

Why isn't this simple test returning any values for array index [1] and onwards?

#!/bin/bash

SessionName=(
'SessionName_1'
'SessionName_2'
)

srcds_run=(
'/path/to/srcds_run'
'/path/to/srcds_run_2'
)

array=(
SessionName
srcds_run
)

clear
echo

for element in "$array[@]"
do
 echo "$element[0] = $!element[0]"
 echo "$element[1] = $!element[1]"
done

echo
echo "literal printout test:"
echo "SessionName[0] = $SessionName[0]"
echo "SessionName[1] = $SessionName[1]"

The script outputs this:

SessionName[0] = SessionName_1
SessionName[1] =
srcds_run[0] = /path/to/srcds_run
srcds_run[1] =

literal printout test:
SessionName[0] = SessionName_1
SessionName[1] = SessionName_2

Thanks

bash array

edited 3 mins ago

don_crissti

47.9k15126155

asked 6 mins ago

johndoe

111

New contributor

edited 3 mins ago

don_crissti

47.9k15126155

asked 6 mins ago

johndoe

111

New contributor

edited 3 mins ago

don_crissti

47.9k15126155

edited 3 mins ago

don_crissti

47.9k15126155

edited 3 mins ago

don_crissti

47.9k15126155

asked 6 mins ago

johndoe

111

New contributor

asked 6 mins ago

johndoe

111

asked 6 mins ago

johndoe

111

New contributor

johndoe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Possible duplicate of How to access further members of an array when using bash variable indirection?
â€“Â don_crissti
3 mins ago

add a commentÂ |Â

Possible duplicate of How to access further members of an array when using bash variable indirection?
â€“Â don_crissti
3 mins ago

Possible duplicate of How to access further members of an array when using bash variable indirection?
â€“Â don_crissti
3 mins ago

add a commentÂ |Â

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