Create alphabetic index with letters repeating
Clash Royale CLAN TAG#URR8PPP
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I am running Debian 9. In Bash I can echo a..z
for the alphabet, or echo a..za..z
to print letter combinations. However, I would like to generate an index with: a b c d
etc. then aa bb cc dd
etc. then aaa bbb ccc ddd
etc. until it is aaaaa bbbbb
(until zzzzz
). How could this be done with brace expansion or another similar method? Thanks
bash brace-expansion
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up vote
0
down vote
favorite
I am running Debian 9. In Bash I can echo a..z
for the alphabet, or echo a..za..z
to print letter combinations. However, I would like to generate an index with: a b c d
etc. then aa bb cc dd
etc. then aaa bbb ccc ddd
etc. until it is aaaaa bbbbb
(until zzzzz
). How could this be done with brace expansion or another similar method? Thanks
bash brace-expansion
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am running Debian 9. In Bash I can echo a..z
for the alphabet, or echo a..za..z
to print letter combinations. However, I would like to generate an index with: a b c d
etc. then aa bb cc dd
etc. then aaa bbb ccc ddd
etc. until it is aaaaa bbbbb
(until zzzzz
). How could this be done with brace expansion or another similar method? Thanks
bash brace-expansion
I am running Debian 9. In Bash I can echo a..z
for the alphabet, or echo a..za..z
to print letter combinations. However, I would like to generate an index with: a b c d
etc. then aa bb cc dd
etc. then aaa bbb ccc ddd
etc. until it is aaaaa bbbbb
(until zzzzz
). How could this be done with brace expansion or another similar method? Thanks
bash brace-expansion
bash brace-expansion
asked 5 mins ago
jbrock
265313
265313
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add a comment |Â
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