Create alphabetic index with letters repeating

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I am running Debian 9. In Bash I can echo a..z for the alphabet, or echo a..za..z to print letter combinations. However, I would like to generate an index with: a b c d etc. then aa bb cc dd etc. then aaa bbb ccc ddd etc. until it is aaaaa bbbbb (until zzzzz). How could this be done with brace expansion or another similar method? Thanks









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    I am running Debian 9. In Bash I can echo a..z for the alphabet, or echo a..za..z to print letter combinations. However, I would like to generate an index with: a b c d etc. then aa bb cc dd etc. then aaa bbb ccc ddd etc. until it is aaaaa bbbbb (until zzzzz). How could this be done with brace expansion or another similar method? Thanks









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      up vote
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      down vote

      favorite









      up vote
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      down vote

      favorite











      I am running Debian 9. In Bash I can echo a..z for the alphabet, or echo a..za..z to print letter combinations. However, I would like to generate an index with: a b c d etc. then aa bb cc dd etc. then aaa bbb ccc ddd etc. until it is aaaaa bbbbb (until zzzzz). How could this be done with brace expansion or another similar method? Thanks









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      I am running Debian 9. In Bash I can echo a..z for the alphabet, or echo a..za..z to print letter combinations. However, I would like to generate an index with: a b c d etc. then aa bb cc dd etc. then aaa bbb ccc ddd etc. until it is aaaaa bbbbb (until zzzzz). How could this be done with brace expansion or another similar method? Thanks







      bash brace-expansion





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      asked 5 mins ago









      jbrock

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