Process a list of filenames to split directory and basename

up vote
0
down vote

favorite

I have a file containing a bunch of filenames:

$ cat test_as1
/var/incoming/foo.txt
/var/incoming/bar.txt
/var/incoming/baz.txt

For each filename, I want to print the directory name and the base filename, comma-separated. For example:

/var/incoming,foo.txt
/var/incoming,bar.txt
/var/incoming,baz.txt

How can I do that?

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

asked Aug 31 at 14:41

user210912

2

You might want to check out the basename and dirname commands
â€“Â hhoke1
Aug 31 at 14:50

add a commentÂ |Â

up vote
0
down vote

favorite

I have a file containing a bunch of filenames:

$ cat test_as1
/var/incoming/foo.txt
/var/incoming/bar.txt
/var/incoming/baz.txt

For each filename, I want to print the directory name and the base filename, comma-separated. For example:

/var/incoming,foo.txt
/var/incoming,bar.txt
/var/incoming,baz.txt

How can I do that?

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

asked Aug 31 at 14:41

user210912

2

You might want to check out the basename and dirname commands
â€“Â hhoke1
Aug 31 at 14:50

add a commentÂ |Â

up vote
0
down vote

favorite

I have a file containing a bunch of filenames:

$ cat test_as1
/var/incoming/foo.txt
/var/incoming/bar.txt
/var/incoming/baz.txt

For each filename, I want to print the directory name and the base filename, comma-separated. For example:

/var/incoming,foo.txt
/var/incoming,bar.txt
/var/incoming,baz.txt

How can I do that?

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

asked Aug 31 at 14:41

user210912

I have a file containing a bunch of filenames:

$ cat test_as1
/var/incoming/foo.txt
/var/incoming/bar.txt
/var/incoming/baz.txt

For each filename, I want to print the directory name and the base filename, comma-separated. For example:

/var/incoming,foo.txt
/var/incoming,bar.txt
/var/incoming,baz.txt

How can I do that?

centos text-processing filenames

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

asked Aug 31 at 14:41

user210912

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

asked Aug 31 at 14:41

user210912

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

edited Aug 31 at 16:54

Michael Mrozekâ™¦

58.7k27184207

asked Aug 31 at 14:41

user210912

asked Aug 31 at 14:41

user210912

asked Aug 31 at 14:41

user210912

2

You might want to check out the basename and dirname commands
â€“Â hhoke1
Aug 31 at 14:50

add a commentÂ |Â

2

You might want to check out the basename and dirname commands
â€“Â hhoke1
Aug 31 at 14:50

You might want to check out the basename and dirname commands
â€“Â hhoke1
Aug 31 at 14:50

add a commentÂ |Â

3 Answers
3

active

oldest

votes

up vote
1
down vote

Like @hhoke1 mentioned in a comment above, you can use the basename and dirname commands:

$ basename /var/incoming/new_items.txt
new_items.txt

$ dirname /var/incoming/new_items.txt
/var/incoming

answered Aug 31 at 14:54

Andy Dalton

4,8391520

Thanks Andy basename /var/incoming/new_items.txt and dirname /var/incoming/new_items.txt seem to do the trick. Do you know how I can do it for about 150 similar items
â€“Â user210912
Aug 31 at 15:00

2

@user210912 Can you tell us what you're trying to do?
â€“Â Andy Dalton
Aug 31 at 15:05

1

Edited the question with what I believe user210912 is looking for based on a comment thread
â€“Â Michael Mrozekâ™¦
Aug 31 at 16:56

add a commentÂ |Â

up vote
1
down vote

Do you mean something like this ?

sed -e 's/(.*)//1,/' -i /var/incoming/new_item.txt

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

answered Aug 31 at 14:48

Alexander

80413

add a commentÂ |Â

up vote
1
down vote

You could loop over the file and then print the parts before and after the last slash with parameter expansion:

while IFS= read -r line; do
 printf '%s,%sn' "$line%/*" "$line##*/"
done < test_as1

"$line%/*" removes the shortest match of /* from the end of the line, and "$line##*/" removes the longest match of */ from the beginning of the line.

answered Aug 31 at 18:17

Benjamin W.

413211

add a commentÂ |Â

Your Answer

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);

);

draft saved

draft discarded

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f466057%2fprocess-a-list-of-filenames-to-split-directory-and-basename%23new-answer', 'question_page');

);

Post as a guest

Name

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
1
down vote

Like @hhoke1 mentioned in a comment above, you can use the basename and dirname commands:

$ basename /var/incoming/new_items.txt
new_items.txt

$ dirname /var/incoming/new_items.txt
/var/incoming

answered Aug 31 at 14:54

Andy Dalton

4,8391520

Thanks Andy basename /var/incoming/new_items.txt and dirname /var/incoming/new_items.txt seem to do the trick. Do you know how I can do it for about 150 similar items
â€“Â user210912
Aug 31 at 15:00

2

@user210912 Can you tell us what you're trying to do?
â€“Â Andy Dalton
Aug 31 at 15:05

1

Edited the question with what I believe user210912 is looking for based on a comment thread
â€“Â Michael Mrozekâ™¦
Aug 31 at 16:56

add a commentÂ |Â

up vote
1
down vote

Like @hhoke1 mentioned in a comment above, you can use the basename and dirname commands:

$ basename /var/incoming/new_items.txt
new_items.txt

$ dirname /var/incoming/new_items.txt
/var/incoming

answered Aug 31 at 14:54

Andy Dalton

4,8391520

Thanks Andy basename /var/incoming/new_items.txt and dirname /var/incoming/new_items.txt seem to do the trick. Do you know how I can do it for about 150 similar items
â€“Â user210912
Aug 31 at 15:00

2

@user210912 Can you tell us what you're trying to do?
â€“Â Andy Dalton
Aug 31 at 15:05

1

Edited the question with what I believe user210912 is looking for based on a comment thread
â€“Â Michael Mrozekâ™¦
Aug 31 at 16:56

add a commentÂ |Â

up vote
1
down vote

Like @hhoke1 mentioned in a comment above, you can use the basename and dirname commands:

$ basename /var/incoming/new_items.txt
new_items.txt

$ dirname /var/incoming/new_items.txt
/var/incoming

answered Aug 31 at 14:54

Andy Dalton

4,8391520

Like @hhoke1 mentioned in a comment above, you can use the basename and dirname commands:

$ basename /var/incoming/new_items.txt
new_items.txt

$ dirname /var/incoming/new_items.txt
/var/incoming

answered Aug 31 at 14:54

Andy Dalton

4,8391520

answered Aug 31 at 14:54

Andy Dalton

4,8391520

answered Aug 31 at 14:54

Andy Dalton

4,8391520

answered Aug 31 at 14:54

Andy Dalton

4,8391520

Thanks Andy basename /var/incoming/new_items.txt and dirname /var/incoming/new_items.txt seem to do the trick. Do you know how I can do it for about 150 similar items
â€“Â user210912
Aug 31 at 15:00

2

@user210912 Can you tell us what you're trying to do?
â€“Â Andy Dalton
Aug 31 at 15:05

1

Edited the question with what I believe user210912 is looking for based on a comment thread
â€“Â Michael Mrozekâ™¦
Aug 31 at 16:56

add a commentÂ |Â

Thanks Andy basename /var/incoming/new_items.txt and dirname /var/incoming/new_items.txt seem to do the trick. Do you know how I can do it for about 150 similar items
â€“Â user210912
Aug 31 at 15:00

2

@user210912 Can you tell us what you're trying to do?
â€“Â Andy Dalton
Aug 31 at 15:05

1

Edited the question with what I believe user210912 is looking for based on a comment thread
â€“Â Michael Mrozekâ™¦
Aug 31 at 16:56

Thanks Andy basename /var/incoming/new_items.txt and dirname /var/incoming/new_items.txt seem to do the trick. Do you know how I can do it for about 150 similar items
â€“Â user210912
Aug 31 at 15:00

@user210912 Can you tell us what you're trying to do?
â€“Â Andy Dalton
Aug 31 at 15:05

Edited the question with what I believe user210912 is looking for based on a comment thread
â€“Â Michael Mrozekâ™¦
Aug 31 at 16:56

add a commentÂ |Â

up vote
1
down vote

Do you mean something like this ?

sed -e 's/(.*)//1,/' -i /var/incoming/new_item.txt

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

answered Aug 31 at 14:48

Alexander

80413

add a commentÂ |Â

up vote
1
down vote

Do you mean something like this ?

sed -e 's/(.*)//1,/' -i /var/incoming/new_item.txt

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

answered Aug 31 at 14:48

Alexander

80413

add a commentÂ |Â

up vote
1
down vote

Do you mean something like this ?

sed -e 's/(.*)//1,/' -i /var/incoming/new_item.txt

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

answered Aug 31 at 14:48

Alexander

80413

Do you mean something like this ?

sed -e 's/(.*)//1,/' -i /var/incoming/new_item.txt

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

answered Aug 31 at 14:48

Alexander

80413

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

edited Aug 31 at 17:14

ÃŽÂ±Ã’Â“sÃÂ½ÃŽÂ¹ÃŽÂ·

16k92563

answered Aug 31 at 14:48

Alexander

80413

answered Aug 31 at 14:48

Alexander

80413

answered Aug 31 at 14:48

Alexander

80413

add a commentÂ |Â

up vote
1
down vote

You could loop over the file and then print the parts before and after the last slash with parameter expansion:

while IFS= read -r line; do
 printf '%s,%sn' "$line%/*" "$line##*/"
done < test_as1

"$line%/*" removes the shortest match of /* from the end of the line, and "$line##*/" removes the longest match of */ from the beginning of the line.

answered Aug 31 at 18:17

Benjamin W.

413211

add a commentÂ |Â

up vote
1
down vote

You could loop over the file and then print the parts before and after the last slash with parameter expansion:

while IFS= read -r line; do
 printf '%s,%sn' "$line%/*" "$line##*/"
done < test_as1

"$line%/*" removes the shortest match of /* from the end of the line, and "$line##*/" removes the longest match of */ from the beginning of the line.

answered Aug 31 at 18:17

Benjamin W.

413211

add a commentÂ |Â

up vote
1
down vote

You could loop over the file and then print the parts before and after the last slash with parameter expansion:

while IFS= read -r line; do
 printf '%s,%sn' "$line%/*" "$line##*/"
done < test_as1

"$line%/*" removes the shortest match of /* from the end of the line, and "$line##*/" removes the longest match of */ from the beginning of the line.

answered Aug 31 at 18:17

Benjamin W.

413211

You could loop over the file and then print the parts before and after the last slash with parameter expansion:

while IFS= read -r line; do
 printf '%s,%sn' "$line%/*" "$line##*/"
done < test_as1

"$line%/*" removes the shortest match of /* from the end of the line, and "$line##*/" removes the longest match of */ from the beginning of the line.

answered Aug 31 at 18:17

Benjamin W.

413211

answered Aug 31 at 18:17

Benjamin W.

413211

answered Aug 31 at 18:17

Benjamin W.

413211

answered Aug 31 at 18:17

Benjamin W.

413211

add a commentÂ |Â

draft saved

draft discarded

draft saved

draft discarded

Post as a guest

Name

搜尋此網誌

mjhjmtu