mjhjmtu

I have 3 files which will come everyday with date in file name.
I need to check all 3 files date if matching with today's date.
and need to wait for 3 files, because all files may not come at same time.
if all file arrives then only need to copy all 3 files to target directory.

below sample code is working for all files if available. but i need to make some while loop or something sleep command where my script can wait/look for all 3 files in src dir then move all together.

#!/bin/ksh
src_dir=/data/SIN/src;
tgt_dir=/data/SIN/tmp;
cd $src_dir;
RUN_DATE=`date +%Y%m%d`;

file1=file1_$RUN_DATE.txt
file2=file2_$RUN_DATE.txt
file3=file3_$RUN_DATE.txt

file_count=`ls -lrt $src_dir/*.txt | grep $RUN_DATE | wc -l` ;

if [ "$file_count" == 3 ]
then
 echo "all 3 files are available";
 cp $src_dir/$file1 $tgt_dir;
 cp $src_dir/$file2 $tgt_dir;
 cp $src_dir/$file3 $tgt_dir;
 echo "files copied";
else
 echo "file missing";
fi

You're so close, just switching your if statement with a while loop, or just adding a while loop as you suggest should do the trick for you.

#!/bin/ksh
src_dir=/data/SIN/src;
tgt_dir=/data/SIN/tmp;
cd $src_dir;
RUN_DATE=`date +%Y%m%d`;

file1=file1_$RUN_DATE.txt
file2=file2_$RUN_DATE.txt
file3=file3_$RUN_DATE.txt

file_count=`ls -lrt $src_dir/*.txt | grep $RUN_DATE | wc -l` ;

# check every 5 seconds if the files are all there
while [ "$file_count" -ne 3 ]; do
 sleep 5
 file_count=`ls -lrt $src_dir/*.txt | grep $RUN_DATE | wc -l`
done

if [ "$file_count" == 3 ]
then
 echo "all 3 files are available";
 cp $src_dir/$file1 $tgt_dir;
 cp $src_dir/$file2 $tgt_dir;
 cp $src_dir/$file3 $tgt_dir;
 echo "files copied";
else
 echo "file missing";
fi

This would work, though it would hang should there ever be more than 3 files in that dir, or if one or more of the files never turn up. So I'd recommend adding a break to the while loop:

# check every 5 seconds if the files are all there, up to 10 times
count=0
while [ "$file_count" -ne 3 ]; do
 sleep 5
 file_count=`ls -lrt $src_dir/*.txt | grep $RUN_DATE | wc -l`
 found_files=$(ls -lrt $src_dir/*.txt | grep $RUN_DATE)
 echo -e "files found:nt$found_files" # print the files that have been found so you know which are missing
 ((count++))
 if [ "$count" = 10 ]; then
 break
 fi
done

try

file_count=$(ls -lrt $src_dir/*.txt | grep -c $RUN_DATE)

while [ "$file_count" != 3 ]
do
 echo "file missing";
 sleep 60
 file_count=$(ls -lrt $src_dir/*.txt | grep -c $RUN_DATE)
else
 echo "all 3 files are available";
 cp $src_dir/$file1 $tgt_dir;
 cp $src_dir/$file2 $tgt_dir;
 cp $src_dir/$file3 $tgt_dir;
 echo "files copied";
 return

done

note that

• it is a bad idea to parse ls's output, unless you sure you don't hava any funny char (space, new line ...)


• I replaced grep | wc -l by grep -c which do the same


• In same way I replaced back quote by $( )

Edit : which file is missing ?

replace

echo "file missing";

by

test -f $src_dir/$file1 || echo $file1 missing
test -f $src_dir/$file2 || echo $file2 missing
test -f $src_dir/$file3 || echo $file3 missing