How to delete existing elements from an array and keep appending new elements afterwards

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite












Below is an example, where I am using two arrays which could be initiated with many elements, for now having "None" as the only element, is there any way to delete existing element/elements and then keep appending new elements when given condition matches otherwise leave the array unaltered.



Looking for a way with minimal coding.



array_a=(None)
array_b=(None)
declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
for index in $!DICT[@] ; do
[[ $index =~ 1 ]] && array_a+=("$DICT[$index]")
[[ $index =~ 50 ]] && array_b+=("$DICT[$index]")
done
echo $array_a[@]
echo $array_b[@]


Output:



None destination source 
None


Expected Output:



destination source
None


I am having a dumb solution for this



array_a=(None)
array_b=(None)
declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
a=0
b=0
for index in $!DICT[@] ; do
if [[ $index =~ 1 ]] ; then if [[ $a -eq 0 ]] ; then ((a++)) ; unset array_a ; fi ; array_a+=("$DICT[$index]") ; fi
if [[ $index =~ 50 ]]; then if [[ $b -eq 0 ]] ; then ((b++)) ; unset array_b ; fi ; array_b+=("$DICT[$index]") ; fi
done
echo $array_a[@]
echo $array_b[@]


Output:



destination source
None









share|improve this question



























    up vote
    1
    down vote

    favorite












    Below is an example, where I am using two arrays which could be initiated with many elements, for now having "None" as the only element, is there any way to delete existing element/elements and then keep appending new elements when given condition matches otherwise leave the array unaltered.



    Looking for a way with minimal coding.



    array_a=(None)
    array_b=(None)
    declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
    for index in $!DICT[@] ; do
    [[ $index =~ 1 ]] && array_a+=("$DICT[$index]")
    [[ $index =~ 50 ]] && array_b+=("$DICT[$index]")
    done
    echo $array_a[@]
    echo $array_b[@]


    Output:



    None destination source 
    None


    Expected Output:



    destination source
    None


    I am having a dumb solution for this



    array_a=(None)
    array_b=(None)
    declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
    a=0
    b=0
    for index in $!DICT[@] ; do
    if [[ $index =~ 1 ]] ; then if [[ $a -eq 0 ]] ; then ((a++)) ; unset array_a ; fi ; array_a+=("$DICT[$index]") ; fi
    if [[ $index =~ 50 ]]; then if [[ $b -eq 0 ]] ; then ((b++)) ; unset array_b ; fi ; array_b+=("$DICT[$index]") ; fi
    done
    echo $array_a[@]
    echo $array_b[@]


    Output:



    destination source
    None









    share|improve this question

























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      Below is an example, where I am using two arrays which could be initiated with many elements, for now having "None" as the only element, is there any way to delete existing element/elements and then keep appending new elements when given condition matches otherwise leave the array unaltered.



      Looking for a way with minimal coding.



      array_a=(None)
      array_b=(None)
      declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
      for index in $!DICT[@] ; do
      [[ $index =~ 1 ]] && array_a+=("$DICT[$index]")
      [[ $index =~ 50 ]] && array_b+=("$DICT[$index]")
      done
      echo $array_a[@]
      echo $array_b[@]


      Output:



      None destination source 
      None


      Expected Output:



      destination source
      None


      I am having a dumb solution for this



      array_a=(None)
      array_b=(None)
      declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
      a=0
      b=0
      for index in $!DICT[@] ; do
      if [[ $index =~ 1 ]] ; then if [[ $a -eq 0 ]] ; then ((a++)) ; unset array_a ; fi ; array_a+=("$DICT[$index]") ; fi
      if [[ $index =~ 50 ]]; then if [[ $b -eq 0 ]] ; then ((b++)) ; unset array_b ; fi ; array_b+=("$DICT[$index]") ; fi
      done
      echo $array_a[@]
      echo $array_b[@]


      Output:



      destination source
      None









      share|improve this question















      Below is an example, where I am using two arrays which could be initiated with many elements, for now having "None" as the only element, is there any way to delete existing element/elements and then keep appending new elements when given condition matches otherwise leave the array unaltered.



      Looking for a way with minimal coding.



      array_a=(None)
      array_b=(None)
      declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
      for index in $!DICT[@] ; do
      [[ $index =~ 1 ]] && array_a+=("$DICT[$index]")
      [[ $index =~ 50 ]] && array_b+=("$DICT[$index]")
      done
      echo $array_a[@]
      echo $array_b[@]


      Output:



      None destination source 
      None


      Expected Output:



      destination source
      None


      I am having a dumb solution for this



      array_a=(None)
      array_b=(None)
      declare -A DICT=([1]="source" [11]="destination" [2]="nowhere")
      a=0
      b=0
      for index in $!DICT[@] ; do
      if [[ $index =~ 1 ]] ; then if [[ $a -eq 0 ]] ; then ((a++)) ; unset array_a ; fi ; array_a+=("$DICT[$index]") ; fi
      if [[ $index =~ 50 ]]; then if [[ $b -eq 0 ]] ; then ((b++)) ; unset array_b ; fi ; array_b+=("$DICT[$index]") ; fi
      done
      echo $array_a[@]
      echo $array_b[@]


      Output:



      destination source
      None






      bash shell-script array






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Aug 31 at 9:31

























      asked Aug 31 at 6:55









      Bharat

      3619




      3619




















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          1
          down vote













          Use this:



          ini_array_a=(None xyz)
          ini_array_b=()
          array_a=()
          array_b=()
          [...]
          array_a=($array_a[@]:-$ini_array_a[@])
          array_b=($array_b[@]:-$ini_array_b[@])
          echo $array_a[@]:-None
          echo $array_b[@]:-None



          Where $ini_array_a and $ini_array_b are the already initialized arrays. We define two new arrays with no value inside. Then do your processing. For echoing the arrays, use Parameter Expansion. The arrays $array_a and array_b are those to print in the end (this is to address your comment).



          $parameter:-word

          If parameter is unset or null, the expansion of word is substituted.
          Otherwise, the value of parameter is substituted.





          share|improve this answer






















          • Alternately, after the loop, "$array_a[0]:=None" to assign a default value.
            – muru
            Aug 31 at 7:45










          • It would require to have a new loop through all the arrays, can it be adjusted in the same loop, however question is assuming there are some existing elements in arrays.
            – Bharat
            Aug 31 at 7:50










          • @Bharat "some existing elements"? More than one? Please clarify the question with what you actually have and what parts of the code you can modify.
            – muru
            Aug 31 at 7:58










          • @muru Yes, I mean right now I am only considering None as the only element in array, but there could be many in it, eg. ( None xyz ...) so what I want if condition matches unset the array and append the elements, if it doesn't match just leave all the elements which were there initially i.e None xyz ...
            – Bharat
            Aug 31 at 8:01










          • @chaos Assumption is to have initialized arrays in the question.
            – Bharat
            Aug 31 at 8:17










          Your Answer







          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "106"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          convertImagesToLinks: false,
          noModals: false,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













           

          draft saved


          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f465938%2fhow-to-delete-existing-elements-from-an-array-and-keep-appending-new-elements-af%23new-answer', 'question_page');

          );

          Post as a guest






























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote













          Use this:



          ini_array_a=(None xyz)
          ini_array_b=()
          array_a=()
          array_b=()
          [...]
          array_a=($array_a[@]:-$ini_array_a[@])
          array_b=($array_b[@]:-$ini_array_b[@])
          echo $array_a[@]:-None
          echo $array_b[@]:-None



          Where $ini_array_a and $ini_array_b are the already initialized arrays. We define two new arrays with no value inside. Then do your processing. For echoing the arrays, use Parameter Expansion. The arrays $array_a and array_b are those to print in the end (this is to address your comment).



          $parameter:-word

          If parameter is unset or null, the expansion of word is substituted.
          Otherwise, the value of parameter is substituted.





          share|improve this answer






















          • Alternately, after the loop, "$array_a[0]:=None" to assign a default value.
            – muru
            Aug 31 at 7:45










          • It would require to have a new loop through all the arrays, can it be adjusted in the same loop, however question is assuming there are some existing elements in arrays.
            – Bharat
            Aug 31 at 7:50










          • @Bharat "some existing elements"? More than one? Please clarify the question with what you actually have and what parts of the code you can modify.
            – muru
            Aug 31 at 7:58










          • @muru Yes, I mean right now I am only considering None as the only element in array, but there could be many in it, eg. ( None xyz ...) so what I want if condition matches unset the array and append the elements, if it doesn't match just leave all the elements which were there initially i.e None xyz ...
            – Bharat
            Aug 31 at 8:01










          • @chaos Assumption is to have initialized arrays in the question.
            – Bharat
            Aug 31 at 8:17














          up vote
          1
          down vote













          Use this:



          ini_array_a=(None xyz)
          ini_array_b=()
          array_a=()
          array_b=()
          [...]
          array_a=($array_a[@]:-$ini_array_a[@])
          array_b=($array_b[@]:-$ini_array_b[@])
          echo $array_a[@]:-None
          echo $array_b[@]:-None



          Where $ini_array_a and $ini_array_b are the already initialized arrays. We define two new arrays with no value inside. Then do your processing. For echoing the arrays, use Parameter Expansion. The arrays $array_a and array_b are those to print in the end (this is to address your comment).



          $parameter:-word

          If parameter is unset or null, the expansion of word is substituted.
          Otherwise, the value of parameter is substituted.





          share|improve this answer






















          • Alternately, after the loop, "$array_a[0]:=None" to assign a default value.
            – muru
            Aug 31 at 7:45










          • It would require to have a new loop through all the arrays, can it be adjusted in the same loop, however question is assuming there are some existing elements in arrays.
            – Bharat
            Aug 31 at 7:50










          • @Bharat "some existing elements"? More than one? Please clarify the question with what you actually have and what parts of the code you can modify.
            – muru
            Aug 31 at 7:58










          • @muru Yes, I mean right now I am only considering None as the only element in array, but there could be many in it, eg. ( None xyz ...) so what I want if condition matches unset the array and append the elements, if it doesn't match just leave all the elements which were there initially i.e None xyz ...
            – Bharat
            Aug 31 at 8:01










          • @chaos Assumption is to have initialized arrays in the question.
            – Bharat
            Aug 31 at 8:17












          up vote
          1
          down vote










          up vote
          1
          down vote









          Use this:



          ini_array_a=(None xyz)
          ini_array_b=()
          array_a=()
          array_b=()
          [...]
          array_a=($array_a[@]:-$ini_array_a[@])
          array_b=($array_b[@]:-$ini_array_b[@])
          echo $array_a[@]:-None
          echo $array_b[@]:-None



          Where $ini_array_a and $ini_array_b are the already initialized arrays. We define two new arrays with no value inside. Then do your processing. For echoing the arrays, use Parameter Expansion. The arrays $array_a and array_b are those to print in the end (this is to address your comment).



          $parameter:-word

          If parameter is unset or null, the expansion of word is substituted.
          Otherwise, the value of parameter is substituted.





          share|improve this answer














          Use this:



          ini_array_a=(None xyz)
          ini_array_b=()
          array_a=()
          array_b=()
          [...]
          array_a=($array_a[@]:-$ini_array_a[@])
          array_b=($array_b[@]:-$ini_array_b[@])
          echo $array_a[@]:-None
          echo $array_b[@]:-None



          Where $ini_array_a and $ini_array_b are the already initialized arrays. We define two new arrays with no value inside. Then do your processing. For echoing the arrays, use Parameter Expansion. The arrays $array_a and array_b are those to print in the end (this is to address your comment).



          $parameter:-word

          If parameter is unset or null, the expansion of word is substituted.
          Otherwise, the value of parameter is substituted.






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Aug 31 at 9:33

























          answered Aug 31 at 7:41









          chaos

          34.1k770113




          34.1k770113











          • Alternately, after the loop, "$array_a[0]:=None" to assign a default value.
            – muru
            Aug 31 at 7:45










          • It would require to have a new loop through all the arrays, can it be adjusted in the same loop, however question is assuming there are some existing elements in arrays.
            – Bharat
            Aug 31 at 7:50










          • @Bharat "some existing elements"? More than one? Please clarify the question with what you actually have and what parts of the code you can modify.
            – muru
            Aug 31 at 7:58










          • @muru Yes, I mean right now I am only considering None as the only element in array, but there could be many in it, eg. ( None xyz ...) so what I want if condition matches unset the array and append the elements, if it doesn't match just leave all the elements which were there initially i.e None xyz ...
            – Bharat
            Aug 31 at 8:01










          • @chaos Assumption is to have initialized arrays in the question.
            – Bharat
            Aug 31 at 8:17
















          • Alternately, after the loop, "$array_a[0]:=None" to assign a default value.
            – muru
            Aug 31 at 7:45










          • It would require to have a new loop through all the arrays, can it be adjusted in the same loop, however question is assuming there are some existing elements in arrays.
            – Bharat
            Aug 31 at 7:50










          • @Bharat "some existing elements"? More than one? Please clarify the question with what you actually have and what parts of the code you can modify.
            – muru
            Aug 31 at 7:58










          • @muru Yes, I mean right now I am only considering None as the only element in array, but there could be many in it, eg. ( None xyz ...) so what I want if condition matches unset the array and append the elements, if it doesn't match just leave all the elements which were there initially i.e None xyz ...
            – Bharat
            Aug 31 at 8:01










          • @chaos Assumption is to have initialized arrays in the question.
            – Bharat
            Aug 31 at 8:17















          Alternately, after the loop, "$array_a[0]:=None" to assign a default value.
          – muru
          Aug 31 at 7:45




          Alternately, after the loop, "$array_a[0]:=None" to assign a default value.
          – muru
          Aug 31 at 7:45












          It would require to have a new loop through all the arrays, can it be adjusted in the same loop, however question is assuming there are some existing elements in arrays.
          – Bharat
          Aug 31 at 7:50




          It would require to have a new loop through all the arrays, can it be adjusted in the same loop, however question is assuming there are some existing elements in arrays.
          – Bharat
          Aug 31 at 7:50












          @Bharat "some existing elements"? More than one? Please clarify the question with what you actually have and what parts of the code you can modify.
          – muru
          Aug 31 at 7:58




          @Bharat "some existing elements"? More than one? Please clarify the question with what you actually have and what parts of the code you can modify.
          – muru
          Aug 31 at 7:58












          @muru Yes, I mean right now I am only considering None as the only element in array, but there could be many in it, eg. ( None xyz ...) so what I want if condition matches unset the array and append the elements, if it doesn't match just leave all the elements which were there initially i.e None xyz ...
          – Bharat
          Aug 31 at 8:01




          @muru Yes, I mean right now I am only considering None as the only element in array, but there could be many in it, eg. ( None xyz ...) so what I want if condition matches unset the array and append the elements, if it doesn't match just leave all the elements which were there initially i.e None xyz ...
          – Bharat
          Aug 31 at 8:01












          @chaos Assumption is to have initialized arrays in the question.
          – Bharat
          Aug 31 at 8:17




          @chaos Assumption is to have initialized arrays in the question.
          – Bharat
          Aug 31 at 8:17

















           

          draft saved


          draft discarded















































           


          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f465938%2fhow-to-delete-existing-elements-from-an-array-and-keep-appending-new-elements-af%23new-answer', 'question_page');

          );

          Post as a guest













































































          Popular posts from this blog

          How to check contact read email or not when send email to Individual?

          Displaying single band from multi-band raster using QGIS

          How many registers does an x86_64 CPU actually have?