Remove “n” string from end of certain lines

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How do I remove the string "n" (not the newline character) from the end of only lines that begin with the string "///"? Thanks.



Example Input:



Some textn

/// Some commentn


Desired Output:



Some textn

/// Some comment


I've tried to use



sed -i 's/\n*$//' $1


But, it removes all of the trailing "n" strings.







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    up vote
    2
    down vote

    favorite
    1












    How do I remove the string "n" (not the newline character) from the end of only lines that begin with the string "///"? Thanks.



    Example Input:



    Some textn

    /// Some commentn


    Desired Output:



    Some textn

    /// Some comment


    I've tried to use



    sed -i 's/\n*$//' $1


    But, it removes all of the trailing "n" strings.







    share|improve this question





















      up vote
      2
      down vote

      favorite
      1









      up vote
      2
      down vote

      favorite
      1






      1





      How do I remove the string "n" (not the newline character) from the end of only lines that begin with the string "///"? Thanks.



      Example Input:



      Some textn

      /// Some commentn


      Desired Output:



      Some textn

      /// Some comment


      I've tried to use



      sed -i 's/\n*$//' $1


      But, it removes all of the trailing "n" strings.







      share|improve this question











      How do I remove the string "n" (not the newline character) from the end of only lines that begin with the string "///"? Thanks.



      Example Input:



      Some textn

      /// Some commentn


      Desired Output:



      Some textn

      /// Some comment


      I've tried to use



      sed -i 's/\n*$//' $1


      But, it removes all of the trailing "n" strings.









      share|improve this question










      share|improve this question




      share|improve this question









      asked Jul 11 at 23:30









      caleb_hendrix

      133




      133




















          1 Answer
          1






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          up vote
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          accepted










          Add a regex address specifier at the front - since your pattern has forward slashes, it's clearer if you use a different expression separator:



          sed -i '%^///% s/\n$//' Input


          Testing:



          $ sed '%^///% s/\n$//' Input 
          Some textn

          /// Some comment


          If you prefer "leaning toothpicks"



          sed -i '/^//// s/\n$//' Input





          share|improve this answer





















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            1 Answer
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            active

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            1 Answer
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            active

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            active

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            active

            oldest

            votes








            up vote
            2
            down vote



            accepted










            Add a regex address specifier at the front - since your pattern has forward slashes, it's clearer if you use a different expression separator:



            sed -i '%^///% s/\n$//' Input


            Testing:



            $ sed '%^///% s/\n$//' Input 
            Some textn

            /// Some comment


            If you prefer "leaning toothpicks"



            sed -i '/^//// s/\n$//' Input





            share|improve this answer

























              up vote
              2
              down vote



              accepted










              Add a regex address specifier at the front - since your pattern has forward slashes, it's clearer if you use a different expression separator:



              sed -i '%^///% s/\n$//' Input


              Testing:



              $ sed '%^///% s/\n$//' Input 
              Some textn

              /// Some comment


              If you prefer "leaning toothpicks"



              sed -i '/^//// s/\n$//' Input





              share|improve this answer























                up vote
                2
                down vote



                accepted







                up vote
                2
                down vote



                accepted






                Add a regex address specifier at the front - since your pattern has forward slashes, it's clearer if you use a different expression separator:



                sed -i '%^///% s/\n$//' Input


                Testing:



                $ sed '%^///% s/\n$//' Input 
                Some textn

                /// Some comment


                If you prefer "leaning toothpicks"



                sed -i '/^//// s/\n$//' Input





                share|improve this answer













                Add a regex address specifier at the front - since your pattern has forward slashes, it's clearer if you use a different expression separator:



                sed -i '%^///% s/\n$//' Input


                Testing:



                $ sed '%^///% s/\n$//' Input 
                Some textn

                /// Some comment


                If you prefer "leaning toothpicks"



                sed -i '/^//// s/\n$//' Input






                share|improve this answer













                share|improve this answer



                share|improve this answer











                answered Jul 11 at 23:35









                steeldriver

                30.9k34877




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