How to find out total memory resource usage with ps?
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With ps command I can find out how much memory each program uses:
ps -u mertnuhoglu -o pcpu,rss,pid,command
Is it possible to find out the sums of each type of resource usage as well, easily?
memory ps
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
add a comment |
With ps command I can find out how much memory each program uses:
ps -u mertnuhoglu -o pcpu,rss,pid,command
Is it possible to find out the sums of each type of resource usage as well, easily?
memory ps
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
1
Note that quantifying memory usage is tricky, because some memory is shared between processes. The sum of the figures you get this way will be an overestimate. RSS is only a rough estimate of how much memory an application uses anyway (it doesn't take into account swapped-out memory or file buffers).
– Gilles
Oct 1 '11 at 22:05
add a comment |
With ps command I can find out how much memory each program uses:
ps -u mertnuhoglu -o pcpu,rss,pid,command
Is it possible to find out the sums of each type of resource usage as well, easily?
memory ps
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
With ps command I can find out how much memory each program uses:
ps -u mertnuhoglu -o pcpu,rss,pid,command
Is it possible to find out the sums of each type of resource usage as well, easily?
memory ps
memory ps
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
edited Oct 1 '11 at 22:22
Stéphane Gimenez
19.5k25074
19.5k25074
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
asked Oct 1 '11 at 9:33
Mert NuhogluMert Nuhoglu
2762410
2762410
1
Note that quantifying memory usage is tricky, because some memory is shared between processes. The sum of the figures you get this way will be an overestimate. RSS is only a rough estimate of how much memory an application uses anyway (it doesn't take into account swapped-out memory or file buffers).
– Gilles
Oct 1 '11 at 22:05
add a comment |
1
Note that quantifying memory usage is tricky, because some memory is shared between processes. The sum of the figures you get this way will be an overestimate. RSS is only a rough estimate of how much memory an application uses anyway (it doesn't take into account swapped-out memory or file buffers).
– Gilles
Oct 1 '11 at 22:05
1
1
Note that quantifying memory usage is tricky, because some memory is shared between processes. The sum of the figures you get this way will be an overestimate. RSS is only a rough estimate of how much memory an application uses anyway (it doesn't take into account swapped-out memory or file buffers).
– Gilles
Oct 1 '11 at 22:05
Note that quantifying memory usage is tricky, because some memory is shared between processes. The sum of the figures you get this way will be an overestimate. RSS is only a rough estimate of how much memory an application uses anyway (it doesn't take into account swapped-out memory or file buffers).
– Gilles
Oct 1 '11 at 22:05
add a comment |
2 Answers
2
active
oldest
votes
You could sum the usage columns with awk:
ps --no-headers -u $USER -o pcpu,rss | awk 'cpu += $1; rss += $2 END print cpu, rss'
You might also be interested in the free command for memory usage:
$ free
total used free shared buffers cached
Mem: 2055480 1806596 248884 0 14016 346276
-/+ buffers/cache: 1446304 609176
Swap: 2097148 132980 1964168
The output is in kilobytes (use free --mega for megabytes or free -m for mebibytes). In particular, the used, +/- buffers/cache entry is something like the total physical memory used (by everyone).
edited Feb 16 at 13:05
Community♦
1
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
add a comment |
You can try:
$ ps -eo vsz,comm= | awk 'NR>1u[$2]+=$1ENDfor(i in u) print u[i]"="i'
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
2
Do not only paste command. please also mansion/explain how this command use to solve this question.
– Tejas
Dec 18 '14 at 9:54
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
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votes
active
oldest
votes
You could sum the usage columns with awk:
ps --no-headers -u $USER -o pcpu,rss | awk 'cpu += $1; rss += $2 END print cpu, rss'
You might also be interested in the free command for memory usage:
$ free
total used free shared buffers cached
Mem: 2055480 1806596 248884 0 14016 346276
-/+ buffers/cache: 1446304 609176
Swap: 2097148 132980 1964168
The output is in kilobytes (use free --mega for megabytes or free -m for mebibytes). In particular, the used, +/- buffers/cache entry is something like the total physical memory used (by everyone).
edited Feb 16 at 13:05
Community♦
1
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
add a comment |
You could sum the usage columns with awk:
ps --no-headers -u $USER -o pcpu,rss | awk 'cpu += $1; rss += $2 END print cpu, rss'
You might also be interested in the free command for memory usage:
$ free
total used free shared buffers cached
Mem: 2055480 1806596 248884 0 14016 346276
-/+ buffers/cache: 1446304 609176
Swap: 2097148 132980 1964168
The output is in kilobytes (use free --mega for megabytes or free -m for mebibytes). In particular, the used, +/- buffers/cache entry is something like the total physical memory used (by everyone).
edited Feb 16 at 13:05
Community♦
1
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
add a comment |
You could sum the usage columns with awk:
ps --no-headers -u $USER -o pcpu,rss | awk 'cpu += $1; rss += $2 END print cpu, rss'
You might also be interested in the free command for memory usage:
$ free
total used free shared buffers cached
Mem: 2055480 1806596 248884 0 14016 346276
-/+ buffers/cache: 1446304 609176
Swap: 2097148 132980 1964168
The output is in kilobytes (use free --mega for megabytes or free -m for mebibytes). In particular, the used, +/- buffers/cache entry is something like the total physical memory used (by everyone).
edited Feb 16 at 13:05
Community♦
1
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
You could sum the usage columns with awk:
ps --no-headers -u $USER -o pcpu,rss | awk 'cpu += $1; rss += $2 END print cpu, rss'
You might also be interested in the free command for memory usage:
$ free
total used free shared buffers cached
Mem: 2055480 1806596 248884 0 14016 346276
-/+ buffers/cache: 1446304 609176
Swap: 2097148 132980 1964168
The output is in kilobytes (use free --mega for megabytes or free -m for mebibytes). In particular, the used, +/- buffers/cache entry is something like the total physical memory used (by everyone).
edited Feb 16 at 13:05
Community♦
1
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
edited Feb 16 at 13:05
Community♦
1
edited Feb 16 at 13:05
Community♦
1
edited Feb 16 at 13:05
Community♦
1
1
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
answered Oct 1 '11 at 20:36
Doctor JDoctor J
38137
38137
add a comment |
add a comment |
You can try:
$ ps -eo vsz,comm= | awk 'NR>1u[$2]+=$1ENDfor(i in u) print u[i]"="i'
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
2
Do not only paste command. please also mansion/explain how this command use to solve this question.
– Tejas
Dec 18 '14 at 9:54
add a comment |
You can try:
$ ps -eo vsz,comm= | awk 'NR>1u[$2]+=$1ENDfor(i in u) print u[i]"="i'
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
2
Do not only paste command. please also mansion/explain how this command use to solve this question.
– Tejas
Dec 18 '14 at 9:54
add a comment |
You can try:
$ ps -eo vsz,comm= | awk 'NR>1u[$2]+=$1ENDfor(i in u) print u[i]"="i'
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
You can try:
$ ps -eo vsz,comm= | awk 'NR>1u[$2]+=$1ENDfor(i in u) print u[i]"="i'
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
edited Dec 18 '14 at 10:09
a CVn
17.3k851106
17.3k851106
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
answered Dec 18 '14 at 9:48
Daniel LerchDaniel Lerch
1091
1091
2
Do not only paste command. please also mansion/explain how this command use to solve this question.
– Tejas
Dec 18 '14 at 9:54
add a comment |
2
Do not only paste command. please also mansion/explain how this command use to solve this question.
– Tejas
Dec 18 '14 at 9:54
2
2
Do not only paste command. please also mansion/explain how this command use to solve this question.
– Tejas
Dec 18 '14 at 9:54
Do not only paste command. please also mansion/explain how this command use to solve this question.
– Tejas
Dec 18 '14 at 9:54
add a comment |
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1
Note that quantifying memory usage is tricky, because some memory is shared between processes. The sum of the figures you get this way will be an overestimate. RSS is only a rough estimate of how much memory an application uses anyway (it doesn't take into account swapped-out memory or file buffers).
– Gilles
Oct 1 '11 at 22:05