Elements Replacement

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$begingroup$


Please I need help on how to replace elements in a matrix with another elements. For example, I have a (5,5) matrix, and I like to replace elements from All rows and column 3 to 5, with zero. such that (All, 3;;5) replace with zero.



m = MatrixForm[Partition[Range[25]^2, 5]]



Sample Matrix



I like to replace all the elements in the specified area with zero:
enter image description here










share|improve this question









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    2












    $begingroup$


    Please I need help on how to replace elements in a matrix with another elements. For example, I have a (5,5) matrix, and I like to replace elements from All rows and column 3 to 5, with zero. such that (All, 3;;5) replace with zero.



    m = MatrixForm[Partition[Range[25]^2, 5]]



    Sample Matrix



    I like to replace all the elements in the specified area with zero:
    enter image description here










    share|improve this question









    $endgroup$














      2












      2








      2





      $begingroup$


      Please I need help on how to replace elements in a matrix with another elements. For example, I have a (5,5) matrix, and I like to replace elements from All rows and column 3 to 5, with zero. such that (All, 3;;5) replace with zero.



      m = MatrixForm[Partition[Range[25]^2, 5]]



      Sample Matrix



      I like to replace all the elements in the specified area with zero:
      enter image description here










      share|improve this question









      $endgroup$




      Please I need help on how to replace elements in a matrix with another elements. For example, I have a (5,5) matrix, and I like to replace elements from All rows and column 3 to 5, with zero. such that (All, 3;;5) replace with zero.



      m = MatrixForm[Partition[Range[25]^2, 5]]



      Sample Matrix



      I like to replace all the elements in the specified area with zero:
      enter image description here







      list-manipulation matrix replacement






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Feb 16 at 10:24









      GeopGeop

      473




      473




















          2 Answers
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          4












          $begingroup$

          Don't use MatrixForm when defining the matrix. It's only a display wrapper, as explained here.



          m = Partition[Range[25]^2, 5]



          1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625




          Replacement:



          m[[All, 3 ;; 5]] = 0;
          m



          1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289, 0, 0, 0, 441, 484, 0, 0, 0







          share|improve this answer











          $endgroup$




















            2












            $begingroup$

            m = Partition[Range[25]^2, 5]


            A few more alternatives:



            SparseArray[m[[All, ;; 2]], Dimensions[m]]
            PadRight[m[[All, ;; 2]], Dimensions@m]
            MapAt[0 &, m , All, 3 ;; ]


            all give




            1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289,
            0, 0, 0, 441, 484, 0, 0, 0







            share|improve this answer









            $endgroup$












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              2 Answers
              2






              active

              oldest

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              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              4












              $begingroup$

              Don't use MatrixForm when defining the matrix. It's only a display wrapper, as explained here.



              m = Partition[Range[25]^2, 5]



              1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625




              Replacement:



              m[[All, 3 ;; 5]] = 0;
              m



              1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289, 0, 0, 0, 441, 484, 0, 0, 0







              share|improve this answer











              $endgroup$

















                4












                $begingroup$

                Don't use MatrixForm when defining the matrix. It's only a display wrapper, as explained here.



                m = Partition[Range[25]^2, 5]



                1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625




                Replacement:



                m[[All, 3 ;; 5]] = 0;
                m



                1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289, 0, 0, 0, 441, 484, 0, 0, 0







                share|improve this answer











                $endgroup$















                  4












                  4








                  4





                  $begingroup$

                  Don't use MatrixForm when defining the matrix. It's only a display wrapper, as explained here.



                  m = Partition[Range[25]^2, 5]



                  1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625




                  Replacement:



                  m[[All, 3 ;; 5]] = 0;
                  m



                  1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289, 0, 0, 0, 441, 484, 0, 0, 0







                  share|improve this answer











                  $endgroup$



                  Don't use MatrixForm when defining the matrix. It's only a display wrapper, as explained here.



                  m = Partition[Range[25]^2, 5]



                  1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625




                  Replacement:



                  m[[All, 3 ;; 5]] = 0;
                  m



                  1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289, 0, 0, 0, 441, 484, 0, 0, 0








                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Feb 17 at 4:36

























                  answered Feb 16 at 10:33









                  RomanRoman

                  3,030718




                  3,030718





















                      2












                      $begingroup$

                      m = Partition[Range[25]^2, 5]


                      A few more alternatives:



                      SparseArray[m[[All, ;; 2]], Dimensions[m]]
                      PadRight[m[[All, ;; 2]], Dimensions@m]
                      MapAt[0 &, m , All, 3 ;; ]


                      all give




                      1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289,
                      0, 0, 0, 441, 484, 0, 0, 0







                      share|improve this answer









                      $endgroup$

















                        2












                        $begingroup$

                        m = Partition[Range[25]^2, 5]


                        A few more alternatives:



                        SparseArray[m[[All, ;; 2]], Dimensions[m]]
                        PadRight[m[[All, ;; 2]], Dimensions@m]
                        MapAt[0 &, m , All, 3 ;; ]


                        all give




                        1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289,
                        0, 0, 0, 441, 484, 0, 0, 0







                        share|improve this answer









                        $endgroup$















                          2












                          2








                          2





                          $begingroup$

                          m = Partition[Range[25]^2, 5]


                          A few more alternatives:



                          SparseArray[m[[All, ;; 2]], Dimensions[m]]
                          PadRight[m[[All, ;; 2]], Dimensions@m]
                          MapAt[0 &, m , All, 3 ;; ]


                          all give




                          1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289,
                          0, 0, 0, 441, 484, 0, 0, 0







                          share|improve this answer









                          $endgroup$



                          m = Partition[Range[25]^2, 5]


                          A few more alternatives:



                          SparseArray[m[[All, ;; 2]], Dimensions[m]]
                          PadRight[m[[All, ;; 2]], Dimensions@m]
                          MapAt[0 &, m , All, 3 ;; ]


                          all give




                          1, 4, 0, 0, 0, 36, 49, 0, 0, 0, 121, 144, 0, 0, 0, 256, 289,
                          0, 0, 0, 441, 484, 0, 0, 0








                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Feb 16 at 11:42









                          kglrkglr

                          188k10204422




                          188k10204422



























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