Automatically rotate frame ticks labels
Clash Royale CLAN TAG#URR8PPP
$begingroup$
Say in
ListPlot[Range[0, 1, 0.1], Frame -> True]
I want the tick marks on the vertical axis to be rotated 90 degrees. How to do it automatically, preserving the sub-ticks?
It's of course doable with explicitly given FrameTicks
, but then the sub-ticks need to be specified and it gets cumbersome. I'm looking for something like FrameTicks(Labels) -> Rotated,Automatic,Automatic,Automatic
, or something similar to RotateLabel
.
$Version
"10.4.1 for Linux x86 (64-bit) (April 11, 2016)"
plotting ticks
$endgroup$
add a comment |
$begingroup$
Say in
ListPlot[Range[0, 1, 0.1], Frame -> True]
I want the tick marks on the vertical axis to be rotated 90 degrees. How to do it automatically, preserving the sub-ticks?
It's of course doable with explicitly given FrameTicks
, but then the sub-ticks need to be specified and it gets cumbersome. I'm looking for something like FrameTicks(Labels) -> Rotated,Automatic,Automatic,Automatic
, or something similar to RotateLabel
.
$Version
"10.4.1 for Linux x86 (64-bit) (April 11, 2016)"
plotting ticks
$endgroup$
add a comment |
$begingroup$
Say in
ListPlot[Range[0, 1, 0.1], Frame -> True]
I want the tick marks on the vertical axis to be rotated 90 degrees. How to do it automatically, preserving the sub-ticks?
It's of course doable with explicitly given FrameTicks
, but then the sub-ticks need to be specified and it gets cumbersome. I'm looking for something like FrameTicks(Labels) -> Rotated,Automatic,Automatic,Automatic
, or something similar to RotateLabel
.
$Version
"10.4.1 for Linux x86 (64-bit) (April 11, 2016)"
plotting ticks
$endgroup$
Say in
ListPlot[Range[0, 1, 0.1], Frame -> True]
I want the tick marks on the vertical axis to be rotated 90 degrees. How to do it automatically, preserving the sub-ticks?
It's of course doable with explicitly given FrameTicks
, but then the sub-ticks need to be specified and it gets cumbersome. I'm looking for something like FrameTicks(Labels) -> Rotated,Automatic,Automatic,Automatic
, or something similar to RotateLabel
.
$Version
"10.4.1 for Linux x86 (64-bit) (April 11, 2016)"
plotting ticks
plotting ticks
edited Feb 16 at 12:37
corey979
asked Feb 16 at 12:32
corey979corey979
20.9k64282
20.9k64282
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> Charting`ScaledTicks["Linear"][##] /.
a_?NumericQ, b_, c___ :> a, Rotate[b, 90 Degree], c &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
Also
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> MapAt[Rotate[#, 90 Degree] &,
Charting`FindTicks[0, 1, 0, 1][##], All, 2] &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
same picture
This works in
$Version
"11.3.0 for Microsoft Windows (64-bit) (March 7, 2018)"
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> Charting`ScaledTicks["Linear"][##] /.
a_?NumericQ, b_, c___ :> a, Rotate[b, 90 Degree], c &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
Also
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> MapAt[Rotate[#, 90 Degree] &,
Charting`FindTicks[0, 1, 0, 1][##], All, 2] &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
same picture
This works in
$Version
"11.3.0 for Microsoft Windows (64-bit) (March 7, 2018)"
$endgroup$
add a comment |
$begingroup$
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> Charting`ScaledTicks["Linear"][##] /.
a_?NumericQ, b_, c___ :> a, Rotate[b, 90 Degree], c &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
Also
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> MapAt[Rotate[#, 90 Degree] &,
Charting`FindTicks[0, 1, 0, 1][##], All, 2] &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
same picture
This works in
$Version
"11.3.0 for Microsoft Windows (64-bit) (March 7, 2018)"
$endgroup$
add a comment |
$begingroup$
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> Charting`ScaledTicks["Linear"][##] /.
a_?NumericQ, b_, c___ :> a, Rotate[b, 90 Degree], c &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
Also
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> MapAt[Rotate[#, 90 Degree] &,
Charting`FindTicks[0, 1, 0, 1][##], All, 2] &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
same picture
This works in
$Version
"11.3.0 for Microsoft Windows (64-bit) (March 7, 2018)"
$endgroup$
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> Charting`ScaledTicks["Linear"][##] /.
a_?NumericQ, b_, c___ :> a, Rotate[b, 90 Degree], c &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
Also
ListPlot[Range[0, 1, 0.1], Frame -> True,
FrameTicks -> MapAt[Rotate[#, 90 Degree] &,
Charting`FindTicks[0, 1, 0, 1][##], All, 2] &, Automatic,
Automatic, Automatic,
ImagePadding -> Scaled[.02]]
same picture
This works in
$Version
"11.3.0 for Microsoft Windows (64-bit) (March 7, 2018)"
edited Feb 16 at 22:43
answered Feb 16 at 12:44
kglrkglr
188k10204422
188k10204422
add a comment |
add a comment |
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