Why are partitions and equivalence relations the same thing?

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My lecturer omitted the proof in the lecture notes. From what I can gather, it's because equivalence classes partition always partition a set (the class can contain only that element or more and the elements in that class can only be in that one class so it acts as a partition). However, this, firstly, doesn't tell me why equivalence relations are the same thing as partitions and not equivalence classes, and to me it sounds like partitions cannot be arbitrary. From what I understood all they have to be are a collection of subsets $A_i$ forming some set $A$ such that:



  1. $A_i ne emptyset$

  2. $A_i cap A_j = emptyset , textif $j ne i$$

  3. $cup _i A_i = A$

I don't see any of these rules demanding subtly there be an equivalence relation, and doing so sounds like it puts restrictions on the creation of a partition that I don't see in its definition. How are they equivalent?










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  • Do you mean $A_icap A_j=varnothing$ if $jne i$?
    – Frpzzd
    4 hours ago










  • @Frpzzd Good spot, thanks for pointing it out.
    – sangstar
    4 hours ago






  • 3




    Declare two things equivalent if they live in the same subset. That’s an equivalence relation.
    – Randall
    4 hours ago










  • @Randall Ah, that's a clever example. Can I use this to extend the general sameness of equivalence relations and partitions that I've been offered to accept however, or only if we consider the equivalence relation "if they live in the same subset"?
    – sangstar
    4 hours ago










  • They are equivalent: partitions and eq relations are the same concept via my remark. It’s a great learning exercise.
    – Randall
    4 hours ago














up vote
2
down vote

favorite












My lecturer omitted the proof in the lecture notes. From what I can gather, it's because equivalence classes partition always partition a set (the class can contain only that element or more and the elements in that class can only be in that one class so it acts as a partition). However, this, firstly, doesn't tell me why equivalence relations are the same thing as partitions and not equivalence classes, and to me it sounds like partitions cannot be arbitrary. From what I understood all they have to be are a collection of subsets $A_i$ forming some set $A$ such that:



  1. $A_i ne emptyset$

  2. $A_i cap A_j = emptyset , textif $j ne i$$

  3. $cup _i A_i = A$

I don't see any of these rules demanding subtly there be an equivalence relation, and doing so sounds like it puts restrictions on the creation of a partition that I don't see in its definition. How are they equivalent?










share|cite|improve this question























  • Do you mean $A_icap A_j=varnothing$ if $jne i$?
    – Frpzzd
    4 hours ago










  • @Frpzzd Good spot, thanks for pointing it out.
    – sangstar
    4 hours ago






  • 3




    Declare two things equivalent if they live in the same subset. That’s an equivalence relation.
    – Randall
    4 hours ago










  • @Randall Ah, that's a clever example. Can I use this to extend the general sameness of equivalence relations and partitions that I've been offered to accept however, or only if we consider the equivalence relation "if they live in the same subset"?
    – sangstar
    4 hours ago










  • They are equivalent: partitions and eq relations are the same concept via my remark. It’s a great learning exercise.
    – Randall
    4 hours ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











My lecturer omitted the proof in the lecture notes. From what I can gather, it's because equivalence classes partition always partition a set (the class can contain only that element or more and the elements in that class can only be in that one class so it acts as a partition). However, this, firstly, doesn't tell me why equivalence relations are the same thing as partitions and not equivalence classes, and to me it sounds like partitions cannot be arbitrary. From what I understood all they have to be are a collection of subsets $A_i$ forming some set $A$ such that:



  1. $A_i ne emptyset$

  2. $A_i cap A_j = emptyset , textif $j ne i$$

  3. $cup _i A_i = A$

I don't see any of these rules demanding subtly there be an equivalence relation, and doing so sounds like it puts restrictions on the creation of a partition that I don't see in its definition. How are they equivalent?










share|cite|improve this question















My lecturer omitted the proof in the lecture notes. From what I can gather, it's because equivalence classes partition always partition a set (the class can contain only that element or more and the elements in that class can only be in that one class so it acts as a partition). However, this, firstly, doesn't tell me why equivalence relations are the same thing as partitions and not equivalence classes, and to me it sounds like partitions cannot be arbitrary. From what I understood all they have to be are a collection of subsets $A_i$ forming some set $A$ such that:



  1. $A_i ne emptyset$

  2. $A_i cap A_j = emptyset , textif $j ne i$$

  3. $cup _i A_i = A$

I don't see any of these rules demanding subtly there be an equivalence relation, and doing so sounds like it puts restrictions on the creation of a partition that I don't see in its definition. How are they equivalent?







equivalence-relations set-partition






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edited 4 hours ago

























asked 4 hours ago









sangstar

786214




786214











  • Do you mean $A_icap A_j=varnothing$ if $jne i$?
    – Frpzzd
    4 hours ago










  • @Frpzzd Good spot, thanks for pointing it out.
    – sangstar
    4 hours ago






  • 3




    Declare two things equivalent if they live in the same subset. That’s an equivalence relation.
    – Randall
    4 hours ago










  • @Randall Ah, that's a clever example. Can I use this to extend the general sameness of equivalence relations and partitions that I've been offered to accept however, or only if we consider the equivalence relation "if they live in the same subset"?
    – sangstar
    4 hours ago










  • They are equivalent: partitions and eq relations are the same concept via my remark. It’s a great learning exercise.
    – Randall
    4 hours ago
















  • Do you mean $A_icap A_j=varnothing$ if $jne i$?
    – Frpzzd
    4 hours ago










  • @Frpzzd Good spot, thanks for pointing it out.
    – sangstar
    4 hours ago






  • 3




    Declare two things equivalent if they live in the same subset. That’s an equivalence relation.
    – Randall
    4 hours ago










  • @Randall Ah, that's a clever example. Can I use this to extend the general sameness of equivalence relations and partitions that I've been offered to accept however, or only if we consider the equivalence relation "if they live in the same subset"?
    – sangstar
    4 hours ago










  • They are equivalent: partitions and eq relations are the same concept via my remark. It’s a great learning exercise.
    – Randall
    4 hours ago















Do you mean $A_icap A_j=varnothing$ if $jne i$?
– Frpzzd
4 hours ago




Do you mean $A_icap A_j=varnothing$ if $jne i$?
– Frpzzd
4 hours ago












@Frpzzd Good spot, thanks for pointing it out.
– sangstar
4 hours ago




@Frpzzd Good spot, thanks for pointing it out.
– sangstar
4 hours ago




3




3




Declare two things equivalent if they live in the same subset. That’s an equivalence relation.
– Randall
4 hours ago




Declare two things equivalent if they live in the same subset. That’s an equivalence relation.
– Randall
4 hours ago












@Randall Ah, that's a clever example. Can I use this to extend the general sameness of equivalence relations and partitions that I've been offered to accept however, or only if we consider the equivalence relation "if they live in the same subset"?
– sangstar
4 hours ago




@Randall Ah, that's a clever example. Can I use this to extend the general sameness of equivalence relations and partitions that I've been offered to accept however, or only if we consider the equivalence relation "if they live in the same subset"?
– sangstar
4 hours ago












They are equivalent: partitions and eq relations are the same concept via my remark. It’s a great learning exercise.
– Randall
4 hours ago




They are equivalent: partitions and eq relations are the same concept via my remark. It’s a great learning exercise.
– Randall
4 hours ago










3 Answers
3






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oldest

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up vote
5
down vote



accepted










A partition and an equivalence relation are not the same thing; however, they can induce each other (as explained at the end of this answer). An equivalence relation $R$ on a set $A$ is a subset of $Atimes A$ satisfying the following properties:
$$(a,a)in Rspaceforall ain A$$
$$(a,b)in Rimplies (b,a)in Rspaceforall a,bin A$$
$$(a,b)in Rspacetextandspace (b,c)in Rimplies (a,c)in R spaceforall a,b,cin A$$
However, a partition $P$ of $A$ is a subset of $2^A$ satisfying the following two properties:
$$p_icap p_j=varnothingspaceforall p_i,p_jin 2^Aspacetextwithspace p_ine p_j$$
$$bigcup_i=1^p_i=A$$
We have that $Rsubset Atimes A$ and $Psubset 2^A$, so they're not even the same type of object. However, your professor probably meant that every equivalence relation on a set $A$ induces a partition of $A$, and vice versa.



More specifically, if $R$ is an equivalence relation on $A$, then the induced partition $P$ is
$$P=b:(a,b)in R:ain A$$
and if $P$ is a partition of $A$, then the induced equivalence relation $R$ is defined by
$$R=(a,b):exists p_iin Pspacetexts.t.space a,bin p_i$$
In plain words: If $R$ is a given equivalence relation, then the induced partition $P$ partitions $A$ into all sets of elements which are equivalent to each other under $R$. If $P$ is a given partition, then the induced equivalence relation $R$ is the relation for which $xsim y$ if and only if $x,y$ are in the same set of the partition P.






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  • A bit ashamed to admit the notation looks a bit daunting to read and it's presenting as difficult to me. Is there a more wordsy explanation to this? Mainly the end of your answer addressing the induced partition and induced equivalence relation bit?
    – sangstar
    4 hours ago











  • @sangstar Sure, thanks for asking! I edited my question for you.
    – Frpzzd
    4 hours ago










  • Thanks! I think I hopefully understand now. Does my example illustrate this understanding? Let $V$ be a vector space over a field $F$ and let $W$ be a subspace of that space. If we define an equivalence relation $R_W$ on $V$ by $u R_W v$ if $u-v in W$, then the set of elements which satisfy $u-v in W$ for arbitrary $u, v in V$ form a partition of $V$?
    – sangstar
    4 hours ago







  • 1




    @sangstar That's right! If you're familiar with a bit of elementary group theory, the sets in this induced partition are called the cosets of the subspace $W$.
    – Frpzzd
    4 hours ago










  • Ah, okay. Thank you!
    – sangstar
    4 hours ago

















up vote
4
down vote













They are "the same thing" in the sense that given an equivalence relation there is a natural way to construct a partition, and given a partition there is a natural way to construct an equivalence relation, and these two natural ways invert one another. That's useful because whenever you encounter one of these objects you are free to reason about the other if that makes your argument easier.



You are right when you say that it is the equivalence classes of an equivalence relation that form a partition (that is in fact the natural thing to look at), not the equivalence relation itself.



The natural way to construct an equivalence relation from a partition is to define two elements to be equivalent just when they are in the same block of the partition.






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  • I see. What if there is a defined equivalence relation $R$ that isn't defined as "is in the same partition as". Can we not then equate equivalence classes and partitions in this case? Just trying to make sure I understand you.
    – sangstar
    4 hours ago











  • @sangstar Every equivalent relation can be expressed as "is in the same partition as" for some partition; that is, every equivalence relation has an induced partition just as every partition has an induced equivalence relation.
    – Frpzzd
    4 hours ago











  • @Frpzzd I see. I'm afraid the notation in your answer is a bit difficult to read for my less experienced eyes. Is there a more wordy explanation for your answer?
    – sangstar
    4 hours ago











  • My answer says in words just what @Frpzzd 's answer says with notation.
    – Ethan Bolker
    3 hours ago

















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0
down vote













Here's a visual explanation.



enter image description here



Note that the nodes in the first three panels should have had edges to themselves as well (from reflexivity of equivalence relations).






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    3 Answers
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    active

    oldest

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    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    5
    down vote



    accepted










    A partition and an equivalence relation are not the same thing; however, they can induce each other (as explained at the end of this answer). An equivalence relation $R$ on a set $A$ is a subset of $Atimes A$ satisfying the following properties:
    $$(a,a)in Rspaceforall ain A$$
    $$(a,b)in Rimplies (b,a)in Rspaceforall a,bin A$$
    $$(a,b)in Rspacetextandspace (b,c)in Rimplies (a,c)in R spaceforall a,b,cin A$$
    However, a partition $P$ of $A$ is a subset of $2^A$ satisfying the following two properties:
    $$p_icap p_j=varnothingspaceforall p_i,p_jin 2^Aspacetextwithspace p_ine p_j$$
    $$bigcup_i=1^p_i=A$$
    We have that $Rsubset Atimes A$ and $Psubset 2^A$, so they're not even the same type of object. However, your professor probably meant that every equivalence relation on a set $A$ induces a partition of $A$, and vice versa.



    More specifically, if $R$ is an equivalence relation on $A$, then the induced partition $P$ is
    $$P=b:(a,b)in R:ain A$$
    and if $P$ is a partition of $A$, then the induced equivalence relation $R$ is defined by
    $$R=(a,b):exists p_iin Pspacetexts.t.space a,bin p_i$$
    In plain words: If $R$ is a given equivalence relation, then the induced partition $P$ partitions $A$ into all sets of elements which are equivalent to each other under $R$. If $P$ is a given partition, then the induced equivalence relation $R$ is the relation for which $xsim y$ if and only if $x,y$ are in the same set of the partition P.






    share|cite|improve this answer






















    • A bit ashamed to admit the notation looks a bit daunting to read and it's presenting as difficult to me. Is there a more wordsy explanation to this? Mainly the end of your answer addressing the induced partition and induced equivalence relation bit?
      – sangstar
      4 hours ago











    • @sangstar Sure, thanks for asking! I edited my question for you.
      – Frpzzd
      4 hours ago










    • Thanks! I think I hopefully understand now. Does my example illustrate this understanding? Let $V$ be a vector space over a field $F$ and let $W$ be a subspace of that space. If we define an equivalence relation $R_W$ on $V$ by $u R_W v$ if $u-v in W$, then the set of elements which satisfy $u-v in W$ for arbitrary $u, v in V$ form a partition of $V$?
      – sangstar
      4 hours ago







    • 1




      @sangstar That's right! If you're familiar with a bit of elementary group theory, the sets in this induced partition are called the cosets of the subspace $W$.
      – Frpzzd
      4 hours ago










    • Ah, okay. Thank you!
      – sangstar
      4 hours ago














    up vote
    5
    down vote



    accepted










    A partition and an equivalence relation are not the same thing; however, they can induce each other (as explained at the end of this answer). An equivalence relation $R$ on a set $A$ is a subset of $Atimes A$ satisfying the following properties:
    $$(a,a)in Rspaceforall ain A$$
    $$(a,b)in Rimplies (b,a)in Rspaceforall a,bin A$$
    $$(a,b)in Rspacetextandspace (b,c)in Rimplies (a,c)in R spaceforall a,b,cin A$$
    However, a partition $P$ of $A$ is a subset of $2^A$ satisfying the following two properties:
    $$p_icap p_j=varnothingspaceforall p_i,p_jin 2^Aspacetextwithspace p_ine p_j$$
    $$bigcup_i=1^p_i=A$$
    We have that $Rsubset Atimes A$ and $Psubset 2^A$, so they're not even the same type of object. However, your professor probably meant that every equivalence relation on a set $A$ induces a partition of $A$, and vice versa.



    More specifically, if $R$ is an equivalence relation on $A$, then the induced partition $P$ is
    $$P=b:(a,b)in R:ain A$$
    and if $P$ is a partition of $A$, then the induced equivalence relation $R$ is defined by
    $$R=(a,b):exists p_iin Pspacetexts.t.space a,bin p_i$$
    In plain words: If $R$ is a given equivalence relation, then the induced partition $P$ partitions $A$ into all sets of elements which are equivalent to each other under $R$. If $P$ is a given partition, then the induced equivalence relation $R$ is the relation for which $xsim y$ if and only if $x,y$ are in the same set of the partition P.






    share|cite|improve this answer






















    • A bit ashamed to admit the notation looks a bit daunting to read and it's presenting as difficult to me. Is there a more wordsy explanation to this? Mainly the end of your answer addressing the induced partition and induced equivalence relation bit?
      – sangstar
      4 hours ago











    • @sangstar Sure, thanks for asking! I edited my question for you.
      – Frpzzd
      4 hours ago










    • Thanks! I think I hopefully understand now. Does my example illustrate this understanding? Let $V$ be a vector space over a field $F$ and let $W$ be a subspace of that space. If we define an equivalence relation $R_W$ on $V$ by $u R_W v$ if $u-v in W$, then the set of elements which satisfy $u-v in W$ for arbitrary $u, v in V$ form a partition of $V$?
      – sangstar
      4 hours ago







    • 1




      @sangstar That's right! If you're familiar with a bit of elementary group theory, the sets in this induced partition are called the cosets of the subspace $W$.
      – Frpzzd
      4 hours ago










    • Ah, okay. Thank you!
      – sangstar
      4 hours ago












    up vote
    5
    down vote



    accepted







    up vote
    5
    down vote



    accepted






    A partition and an equivalence relation are not the same thing; however, they can induce each other (as explained at the end of this answer). An equivalence relation $R$ on a set $A$ is a subset of $Atimes A$ satisfying the following properties:
    $$(a,a)in Rspaceforall ain A$$
    $$(a,b)in Rimplies (b,a)in Rspaceforall a,bin A$$
    $$(a,b)in Rspacetextandspace (b,c)in Rimplies (a,c)in R spaceforall a,b,cin A$$
    However, a partition $P$ of $A$ is a subset of $2^A$ satisfying the following two properties:
    $$p_icap p_j=varnothingspaceforall p_i,p_jin 2^Aspacetextwithspace p_ine p_j$$
    $$bigcup_i=1^p_i=A$$
    We have that $Rsubset Atimes A$ and $Psubset 2^A$, so they're not even the same type of object. However, your professor probably meant that every equivalence relation on a set $A$ induces a partition of $A$, and vice versa.



    More specifically, if $R$ is an equivalence relation on $A$, then the induced partition $P$ is
    $$P=b:(a,b)in R:ain A$$
    and if $P$ is a partition of $A$, then the induced equivalence relation $R$ is defined by
    $$R=(a,b):exists p_iin Pspacetexts.t.space a,bin p_i$$
    In plain words: If $R$ is a given equivalence relation, then the induced partition $P$ partitions $A$ into all sets of elements which are equivalent to each other under $R$. If $P$ is a given partition, then the induced equivalence relation $R$ is the relation for which $xsim y$ if and only if $x,y$ are in the same set of the partition P.






    share|cite|improve this answer














    A partition and an equivalence relation are not the same thing; however, they can induce each other (as explained at the end of this answer). An equivalence relation $R$ on a set $A$ is a subset of $Atimes A$ satisfying the following properties:
    $$(a,a)in Rspaceforall ain A$$
    $$(a,b)in Rimplies (b,a)in Rspaceforall a,bin A$$
    $$(a,b)in Rspacetextandspace (b,c)in Rimplies (a,c)in R spaceforall a,b,cin A$$
    However, a partition $P$ of $A$ is a subset of $2^A$ satisfying the following two properties:
    $$p_icap p_j=varnothingspaceforall p_i,p_jin 2^Aspacetextwithspace p_ine p_j$$
    $$bigcup_i=1^p_i=A$$
    We have that $Rsubset Atimes A$ and $Psubset 2^A$, so they're not even the same type of object. However, your professor probably meant that every equivalence relation on a set $A$ induces a partition of $A$, and vice versa.



    More specifically, if $R$ is an equivalence relation on $A$, then the induced partition $P$ is
    $$P=b:(a,b)in R:ain A$$
    and if $P$ is a partition of $A$, then the induced equivalence relation $R$ is defined by
    $$R=(a,b):exists p_iin Pspacetexts.t.space a,bin p_i$$
    In plain words: If $R$ is a given equivalence relation, then the induced partition $P$ partitions $A$ into all sets of elements which are equivalent to each other under $R$. If $P$ is a given partition, then the induced equivalence relation $R$ is the relation for which $xsim y$ if and only if $x,y$ are in the same set of the partition P.







    share|cite|improve this answer














    share|cite|improve this answer



    share|cite|improve this answer








    edited 4 hours ago

























    answered 4 hours ago









    Frpzzd

    19k63798




    19k63798











    • A bit ashamed to admit the notation looks a bit daunting to read and it's presenting as difficult to me. Is there a more wordsy explanation to this? Mainly the end of your answer addressing the induced partition and induced equivalence relation bit?
      – sangstar
      4 hours ago











    • @sangstar Sure, thanks for asking! I edited my question for you.
      – Frpzzd
      4 hours ago










    • Thanks! I think I hopefully understand now. Does my example illustrate this understanding? Let $V$ be a vector space over a field $F$ and let $W$ be a subspace of that space. If we define an equivalence relation $R_W$ on $V$ by $u R_W v$ if $u-v in W$, then the set of elements which satisfy $u-v in W$ for arbitrary $u, v in V$ form a partition of $V$?
      – sangstar
      4 hours ago







    • 1




      @sangstar That's right! If you're familiar with a bit of elementary group theory, the sets in this induced partition are called the cosets of the subspace $W$.
      – Frpzzd
      4 hours ago










    • Ah, okay. Thank you!
      – sangstar
      4 hours ago
















    • A bit ashamed to admit the notation looks a bit daunting to read and it's presenting as difficult to me. Is there a more wordsy explanation to this? Mainly the end of your answer addressing the induced partition and induced equivalence relation bit?
      – sangstar
      4 hours ago











    • @sangstar Sure, thanks for asking! I edited my question for you.
      – Frpzzd
      4 hours ago










    • Thanks! I think I hopefully understand now. Does my example illustrate this understanding? Let $V$ be a vector space over a field $F$ and let $W$ be a subspace of that space. If we define an equivalence relation $R_W$ on $V$ by $u R_W v$ if $u-v in W$, then the set of elements which satisfy $u-v in W$ for arbitrary $u, v in V$ form a partition of $V$?
      – sangstar
      4 hours ago







    • 1




      @sangstar That's right! If you're familiar with a bit of elementary group theory, the sets in this induced partition are called the cosets of the subspace $W$.
      – Frpzzd
      4 hours ago










    • Ah, okay. Thank you!
      – sangstar
      4 hours ago















    A bit ashamed to admit the notation looks a bit daunting to read and it's presenting as difficult to me. Is there a more wordsy explanation to this? Mainly the end of your answer addressing the induced partition and induced equivalence relation bit?
    – sangstar
    4 hours ago





    A bit ashamed to admit the notation looks a bit daunting to read and it's presenting as difficult to me. Is there a more wordsy explanation to this? Mainly the end of your answer addressing the induced partition and induced equivalence relation bit?
    – sangstar
    4 hours ago













    @sangstar Sure, thanks for asking! I edited my question for you.
    – Frpzzd
    4 hours ago




    @sangstar Sure, thanks for asking! I edited my question for you.
    – Frpzzd
    4 hours ago












    Thanks! I think I hopefully understand now. Does my example illustrate this understanding? Let $V$ be a vector space over a field $F$ and let $W$ be a subspace of that space. If we define an equivalence relation $R_W$ on $V$ by $u R_W v$ if $u-v in W$, then the set of elements which satisfy $u-v in W$ for arbitrary $u, v in V$ form a partition of $V$?
    – sangstar
    4 hours ago





    Thanks! I think I hopefully understand now. Does my example illustrate this understanding? Let $V$ be a vector space over a field $F$ and let $W$ be a subspace of that space. If we define an equivalence relation $R_W$ on $V$ by $u R_W v$ if $u-v in W$, then the set of elements which satisfy $u-v in W$ for arbitrary $u, v in V$ form a partition of $V$?
    – sangstar
    4 hours ago





    1




    1




    @sangstar That's right! If you're familiar with a bit of elementary group theory, the sets in this induced partition are called the cosets of the subspace $W$.
    – Frpzzd
    4 hours ago




    @sangstar That's right! If you're familiar with a bit of elementary group theory, the sets in this induced partition are called the cosets of the subspace $W$.
    – Frpzzd
    4 hours ago












    Ah, okay. Thank you!
    – sangstar
    4 hours ago




    Ah, okay. Thank you!
    – sangstar
    4 hours ago










    up vote
    4
    down vote













    They are "the same thing" in the sense that given an equivalence relation there is a natural way to construct a partition, and given a partition there is a natural way to construct an equivalence relation, and these two natural ways invert one another. That's useful because whenever you encounter one of these objects you are free to reason about the other if that makes your argument easier.



    You are right when you say that it is the equivalence classes of an equivalence relation that form a partition (that is in fact the natural thing to look at), not the equivalence relation itself.



    The natural way to construct an equivalence relation from a partition is to define two elements to be equivalent just when they are in the same block of the partition.






    share|cite|improve this answer




















    • I see. What if there is a defined equivalence relation $R$ that isn't defined as "is in the same partition as". Can we not then equate equivalence classes and partitions in this case? Just trying to make sure I understand you.
      – sangstar
      4 hours ago











    • @sangstar Every equivalent relation can be expressed as "is in the same partition as" for some partition; that is, every equivalence relation has an induced partition just as every partition has an induced equivalence relation.
      – Frpzzd
      4 hours ago











    • @Frpzzd I see. I'm afraid the notation in your answer is a bit difficult to read for my less experienced eyes. Is there a more wordy explanation for your answer?
      – sangstar
      4 hours ago











    • My answer says in words just what @Frpzzd 's answer says with notation.
      – Ethan Bolker
      3 hours ago














    up vote
    4
    down vote













    They are "the same thing" in the sense that given an equivalence relation there is a natural way to construct a partition, and given a partition there is a natural way to construct an equivalence relation, and these two natural ways invert one another. That's useful because whenever you encounter one of these objects you are free to reason about the other if that makes your argument easier.



    You are right when you say that it is the equivalence classes of an equivalence relation that form a partition (that is in fact the natural thing to look at), not the equivalence relation itself.



    The natural way to construct an equivalence relation from a partition is to define two elements to be equivalent just when they are in the same block of the partition.






    share|cite|improve this answer




















    • I see. What if there is a defined equivalence relation $R$ that isn't defined as "is in the same partition as". Can we not then equate equivalence classes and partitions in this case? Just trying to make sure I understand you.
      – sangstar
      4 hours ago











    • @sangstar Every equivalent relation can be expressed as "is in the same partition as" for some partition; that is, every equivalence relation has an induced partition just as every partition has an induced equivalence relation.
      – Frpzzd
      4 hours ago











    • @Frpzzd I see. I'm afraid the notation in your answer is a bit difficult to read for my less experienced eyes. Is there a more wordy explanation for your answer?
      – sangstar
      4 hours ago











    • My answer says in words just what @Frpzzd 's answer says with notation.
      – Ethan Bolker
      3 hours ago












    up vote
    4
    down vote










    up vote
    4
    down vote









    They are "the same thing" in the sense that given an equivalence relation there is a natural way to construct a partition, and given a partition there is a natural way to construct an equivalence relation, and these two natural ways invert one another. That's useful because whenever you encounter one of these objects you are free to reason about the other if that makes your argument easier.



    You are right when you say that it is the equivalence classes of an equivalence relation that form a partition (that is in fact the natural thing to look at), not the equivalence relation itself.



    The natural way to construct an equivalence relation from a partition is to define two elements to be equivalent just when they are in the same block of the partition.






    share|cite|improve this answer












    They are "the same thing" in the sense that given an equivalence relation there is a natural way to construct a partition, and given a partition there is a natural way to construct an equivalence relation, and these two natural ways invert one another. That's useful because whenever you encounter one of these objects you are free to reason about the other if that makes your argument easier.



    You are right when you say that it is the equivalence classes of an equivalence relation that form a partition (that is in fact the natural thing to look at), not the equivalence relation itself.



    The natural way to construct an equivalence relation from a partition is to define two elements to be equivalent just when they are in the same block of the partition.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 4 hours ago









    Ethan Bolker

    38.7k543102




    38.7k543102











    • I see. What if there is a defined equivalence relation $R$ that isn't defined as "is in the same partition as". Can we not then equate equivalence classes and partitions in this case? Just trying to make sure I understand you.
      – sangstar
      4 hours ago











    • @sangstar Every equivalent relation can be expressed as "is in the same partition as" for some partition; that is, every equivalence relation has an induced partition just as every partition has an induced equivalence relation.
      – Frpzzd
      4 hours ago











    • @Frpzzd I see. I'm afraid the notation in your answer is a bit difficult to read for my less experienced eyes. Is there a more wordy explanation for your answer?
      – sangstar
      4 hours ago











    • My answer says in words just what @Frpzzd 's answer says with notation.
      – Ethan Bolker
      3 hours ago
















    • I see. What if there is a defined equivalence relation $R$ that isn't defined as "is in the same partition as". Can we not then equate equivalence classes and partitions in this case? Just trying to make sure I understand you.
      – sangstar
      4 hours ago











    • @sangstar Every equivalent relation can be expressed as "is in the same partition as" for some partition; that is, every equivalence relation has an induced partition just as every partition has an induced equivalence relation.
      – Frpzzd
      4 hours ago











    • @Frpzzd I see. I'm afraid the notation in your answer is a bit difficult to read for my less experienced eyes. Is there a more wordy explanation for your answer?
      – sangstar
      4 hours ago











    • My answer says in words just what @Frpzzd 's answer says with notation.
      – Ethan Bolker
      3 hours ago















    I see. What if there is a defined equivalence relation $R$ that isn't defined as "is in the same partition as". Can we not then equate equivalence classes and partitions in this case? Just trying to make sure I understand you.
    – sangstar
    4 hours ago





    I see. What if there is a defined equivalence relation $R$ that isn't defined as "is in the same partition as". Can we not then equate equivalence classes and partitions in this case? Just trying to make sure I understand you.
    – sangstar
    4 hours ago













    @sangstar Every equivalent relation can be expressed as "is in the same partition as" for some partition; that is, every equivalence relation has an induced partition just as every partition has an induced equivalence relation.
    – Frpzzd
    4 hours ago





    @sangstar Every equivalent relation can be expressed as "is in the same partition as" for some partition; that is, every equivalence relation has an induced partition just as every partition has an induced equivalence relation.
    – Frpzzd
    4 hours ago













    @Frpzzd I see. I'm afraid the notation in your answer is a bit difficult to read for my less experienced eyes. Is there a more wordy explanation for your answer?
    – sangstar
    4 hours ago





    @Frpzzd I see. I'm afraid the notation in your answer is a bit difficult to read for my less experienced eyes. Is there a more wordy explanation for your answer?
    – sangstar
    4 hours ago













    My answer says in words just what @Frpzzd 's answer says with notation.
    – Ethan Bolker
    3 hours ago




    My answer says in words just what @Frpzzd 's answer says with notation.
    – Ethan Bolker
    3 hours ago










    up vote
    0
    down vote













    Here's a visual explanation.



    enter image description here



    Note that the nodes in the first three panels should have had edges to themselves as well (from reflexivity of equivalence relations).






    share|cite|improve this answer
























      up vote
      0
      down vote













      Here's a visual explanation.



      enter image description here



      Note that the nodes in the first three panels should have had edges to themselves as well (from reflexivity of equivalence relations).






      share|cite|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        Here's a visual explanation.



        enter image description here



        Note that the nodes in the first three panels should have had edges to themselves as well (from reflexivity of equivalence relations).






        share|cite|improve this answer












        Here's a visual explanation.



        enter image description here



        Note that the nodes in the first three panels should have had edges to themselves as well (from reflexivity of equivalence relations).







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 24 mins ago









        rlms

        2591317




        2591317



























             

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