What will happen if I use a nonparametric test with normally distributed data?

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I was asked if a type I error in the Shapiro-Wilk test would impact the main analysis and if the wrong test was used if it would matter or not if my data was normally distributed...










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  • That makes sense thank you!
    – DaisyRiver
    3 hours ago










  • @a_statistician - might want to expand that a little and post it as an answer, since it is!
    – jbowman
    3 hours ago










  • @jbowman Thank you for your editing.
    – a_statistician
    3 hours ago
















up vote
2
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I was asked if a type I error in the Shapiro-Wilk test would impact the main analysis and if the wrong test was used if it would matter or not if my data was normally distributed...










share|cite|improve this question







New contributor




DaisyRiver is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • That makes sense thank you!
    – DaisyRiver
    3 hours ago










  • @a_statistician - might want to expand that a little and post it as an answer, since it is!
    – jbowman
    3 hours ago










  • @jbowman Thank you for your editing.
    – a_statistician
    3 hours ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











I was asked if a type I error in the Shapiro-Wilk test would impact the main analysis and if the wrong test was used if it would matter or not if my data was normally distributed...










share|cite|improve this question







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DaisyRiver is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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I was asked if a type I error in the Shapiro-Wilk test would impact the main analysis and if the wrong test was used if it would matter or not if my data was normally distributed...







nonparametric






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  • That makes sense thank you!
    – DaisyRiver
    3 hours ago










  • @a_statistician - might want to expand that a little and post it as an answer, since it is!
    – jbowman
    3 hours ago










  • @jbowman Thank you for your editing.
    – a_statistician
    3 hours ago
















  • That makes sense thank you!
    – DaisyRiver
    3 hours ago










  • @a_statistician - might want to expand that a little and post it as an answer, since it is!
    – jbowman
    3 hours ago










  • @jbowman Thank you for your editing.
    – a_statistician
    3 hours ago















That makes sense thank you!
– DaisyRiver
3 hours ago




That makes sense thank you!
– DaisyRiver
3 hours ago












@a_statistician - might want to expand that a little and post it as an answer, since it is!
– jbowman
3 hours ago




@a_statistician - might want to expand that a little and post it as an answer, since it is!
– jbowman
3 hours ago












@jbowman Thank you for your editing.
– a_statistician
3 hours ago




@jbowman Thank you for your editing.
– a_statistician
3 hours ago










2 Answers
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In statistical analysis, if your data follow a parametric distribution, you should utilize the benefit of knowing the distribution, and employ the statistical methods based on that distribution.



But sometimes we do not know the distribution of the random variable, so the nonparametric statistical methods were developed to embrace the wide range of the distributions while scarifying the efficiency.



Given you know the distribution of random variable and use the nonparametric statistical method, instead of parametric statistical methods based on knowing the distribution, it will be inefficient, i.e., the power of test will decrease, standard error will increase, and the confidence intervals will be wider than with the parametric method.






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    up vote
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    If your data happened to be drawn from a normal population, the test works as it should (it's non-parametric, it's supposed to work). There's no drama on that score.



    If you know enough that you're confident in assuming normality you may want to take advantage of that knowledge, but for many tests it doesn't help you a lot.



    If you're doing one of the common location-tests (Wilcoxon signed rank test, Wilcoxon-Mann-Whitney test) you lose almost nothing (power-wise) in a test for a location shift by ignoring the normality. [You need one extra observation for every 21 observations to match the power of the most powerful test when all its assumptions hold.]



    If you're dealing with some other tests is may matter a bit more (though some may matter even less). One example where it makes a somewhat bigger difference is using a Friedman test compared to the corresponding ANOVA test in a randomized blocks design.






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      2 Answers
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      2 Answers
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      up vote
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      down vote













      In statistical analysis, if your data follow a parametric distribution, you should utilize the benefit of knowing the distribution, and employ the statistical methods based on that distribution.



      But sometimes we do not know the distribution of the random variable, so the nonparametric statistical methods were developed to embrace the wide range of the distributions while scarifying the efficiency.



      Given you know the distribution of random variable and use the nonparametric statistical method, instead of parametric statistical methods based on knowing the distribution, it will be inefficient, i.e., the power of test will decrease, standard error will increase, and the confidence intervals will be wider than with the parametric method.






      share|cite|improve this answer


























        up vote
        3
        down vote













        In statistical analysis, if your data follow a parametric distribution, you should utilize the benefit of knowing the distribution, and employ the statistical methods based on that distribution.



        But sometimes we do not know the distribution of the random variable, so the nonparametric statistical methods were developed to embrace the wide range of the distributions while scarifying the efficiency.



        Given you know the distribution of random variable and use the nonparametric statistical method, instead of parametric statistical methods based on knowing the distribution, it will be inefficient, i.e., the power of test will decrease, standard error will increase, and the confidence intervals will be wider than with the parametric method.






        share|cite|improve this answer
























          up vote
          3
          down vote










          up vote
          3
          down vote









          In statistical analysis, if your data follow a parametric distribution, you should utilize the benefit of knowing the distribution, and employ the statistical methods based on that distribution.



          But sometimes we do not know the distribution of the random variable, so the nonparametric statistical methods were developed to embrace the wide range of the distributions while scarifying the efficiency.



          Given you know the distribution of random variable and use the nonparametric statistical method, instead of parametric statistical methods based on knowing the distribution, it will be inefficient, i.e., the power of test will decrease, standard error will increase, and the confidence intervals will be wider than with the parametric method.






          share|cite|improve this answer














          In statistical analysis, if your data follow a parametric distribution, you should utilize the benefit of knowing the distribution, and employ the statistical methods based on that distribution.



          But sometimes we do not know the distribution of the random variable, so the nonparametric statistical methods were developed to embrace the wide range of the distributions while scarifying the efficiency.



          Given you know the distribution of random variable and use the nonparametric statistical method, instead of parametric statistical methods based on knowing the distribution, it will be inefficient, i.e., the power of test will decrease, standard error will increase, and the confidence intervals will be wider than with the parametric method.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited 3 hours ago









          jbowman

          23.1k24178




          23.1k24178










          answered 3 hours ago









          a_statistician

          3,335139




          3,335139






















              up vote
              1
              down vote













              If your data happened to be drawn from a normal population, the test works as it should (it's non-parametric, it's supposed to work). There's no drama on that score.



              If you know enough that you're confident in assuming normality you may want to take advantage of that knowledge, but for many tests it doesn't help you a lot.



              If you're doing one of the common location-tests (Wilcoxon signed rank test, Wilcoxon-Mann-Whitney test) you lose almost nothing (power-wise) in a test for a location shift by ignoring the normality. [You need one extra observation for every 21 observations to match the power of the most powerful test when all its assumptions hold.]



              If you're dealing with some other tests is may matter a bit more (though some may matter even less). One example where it makes a somewhat bigger difference is using a Friedman test compared to the corresponding ANOVA test in a randomized blocks design.






              share|cite|improve this answer
























                up vote
                1
                down vote













                If your data happened to be drawn from a normal population, the test works as it should (it's non-parametric, it's supposed to work). There's no drama on that score.



                If you know enough that you're confident in assuming normality you may want to take advantage of that knowledge, but for many tests it doesn't help you a lot.



                If you're doing one of the common location-tests (Wilcoxon signed rank test, Wilcoxon-Mann-Whitney test) you lose almost nothing (power-wise) in a test for a location shift by ignoring the normality. [You need one extra observation for every 21 observations to match the power of the most powerful test when all its assumptions hold.]



                If you're dealing with some other tests is may matter a bit more (though some may matter even less). One example where it makes a somewhat bigger difference is using a Friedman test compared to the corresponding ANOVA test in a randomized blocks design.






                share|cite|improve this answer






















                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  If your data happened to be drawn from a normal population, the test works as it should (it's non-parametric, it's supposed to work). There's no drama on that score.



                  If you know enough that you're confident in assuming normality you may want to take advantage of that knowledge, but for many tests it doesn't help you a lot.



                  If you're doing one of the common location-tests (Wilcoxon signed rank test, Wilcoxon-Mann-Whitney test) you lose almost nothing (power-wise) in a test for a location shift by ignoring the normality. [You need one extra observation for every 21 observations to match the power of the most powerful test when all its assumptions hold.]



                  If you're dealing with some other tests is may matter a bit more (though some may matter even less). One example where it makes a somewhat bigger difference is using a Friedman test compared to the corresponding ANOVA test in a randomized blocks design.






                  share|cite|improve this answer












                  If your data happened to be drawn from a normal population, the test works as it should (it's non-parametric, it's supposed to work). There's no drama on that score.



                  If you know enough that you're confident in assuming normality you may want to take advantage of that knowledge, but for many tests it doesn't help you a lot.



                  If you're doing one of the common location-tests (Wilcoxon signed rank test, Wilcoxon-Mann-Whitney test) you lose almost nothing (power-wise) in a test for a location shift by ignoring the normality. [You need one extra observation for every 21 observations to match the power of the most powerful test when all its assumptions hold.]



                  If you're dealing with some other tests is may matter a bit more (though some may matter even less). One example where it makes a somewhat bigger difference is using a Friedman test compared to the corresponding ANOVA test in a randomized blocks design.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 21 mins ago









                  Glen_b

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