While I was writing numbers I noticed after a while that my keyboard had the Shift key pressed and blocked and all I wrote was $%&-like characters. And even worse, I had been switching between the English and Spanish keyboard layouts so I don't know which one I used for each number.

Challenge

Given a string containing symbol characters, try to guess which number I wrote. My keyboard produces the following characters for the numbers when the Shift is pressed:

1234567890
----------
!"·$%&/()= Spanish layout
!@#$%^&*() English layout

• The input will be a non-null, non-empty string composed of the symbols above.


• The output will be a single number if the keyboard layout can be inferred from the string (i.e. if the string contains a @ an English layout was used, and if the string contains a " a Spanish layout was used) or if the number is the same for both layouts (i.e. the input is !$ which translates as 14 for both layouts); otherwise the output will be the two possible numbers for both layouts if it cannot be inferred and the resulting numbers are different.


• The input string will always be written in a single layout. So you don't need to expect "@ as input.

Examples

Input --> Output
------------------
/() 789 (Spanish layout detected by the use of /)
$%& 456,457 (Layout cannot be inferred)
!@# 123 (English layout detected by the use of @ and #)
()&! 8961,9071 (Layout cannot be inferred)
((·)) 88399 (Spanish layout detected by the use of ·)
!$ 14 (Layout cannot be inferred but the result is the same for both)
!!$$%% 114455 (Layout cannot be inferred but the result is the same for both)
==$" 0042/42 (Spanish layout, if a number starts with 0 you can choose to
 omit them in the result or not)

Single character translations:
------------------------------
! 1 
" 2
· 3
$ 4
% 5
& 6,7
/ 7
( 8,9
) 9,0
= 0
@ 2
# 3
^ 6
* 8

This is code-golf, so may the shortest code for each language win!

Python 3, 76 bytes

lambda s:(*map(k.find,s),)for k in['=!"·$%&/()',')!@#$%^&*(']if*s<=*k

Try it online!

Java (JDK), 173 bytes

Golfed

c->String s="",e=s;var m="21#3457#908###6##12#456389###0#7".split("");for(int l:c)e+=m[l=l%16];s+=m[l+16];return s.equals(e)

Try it online!

c-> // Lamdba taking char array as input
 String s="",e=s; // Initialise Spanish and English strings
 var m="21#3457#908###6##12#456389###0#7".split(""); // Create magic hashing lookup array (see below)
 for(int l:c) // Loops through all chars in input
 e+=m[l=l%16]; // Get english number from array and append
 s+=m[l+16]; // Get Spanish number from array and append
 
 return s.equals(e)

After some experimenting with values I realised that each of the ASCII values of the characters !"·$%&/()=@#^* modulo 16 returns a unique number. The 'magic hashing lookup array' stores the English numbers associated with each character at this unique index, and each of the Spanish numbers at this index offset by 16, making fetching the required number from the array trivial for each language. A hash is stored for values that are invalid for either language.

Jelly, 38 bytes

183Ọ“=!"“$%&/()”j,“)!@#$%^&*(”iⱮ€⁸ẠƇ’Q

Try it online!