How to count number of variables passed to awk

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I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.



No. of variables passed to awk would be dynamic.



Below example



#!/bin/bash
NAME="Dell"
SERIAL="12345"
echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '





bash awk






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    0
    down vote

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    I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.



    No. of variables passed to awk would be dynamic.



    Below example



    #!/bin/bash
    NAME="Dell"
    SERIAL="12345"
    echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '





    bash awk






    share























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.



      No. of variables passed to awk would be dynamic.



      Below example



      #!/bin/bash
      NAME="Dell"
      SERIAL="12345"
      echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '





      bash awk






      share













      I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.



      No. of variables passed to awk would be dynamic.



      Below example



      #!/bin/bash
      NAME="Dell"
      SERIAL="12345"
      echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '





      bash awk




      bash awk





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      asked 5 mins ago









      Bharat

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