How to get a count of variables passed to awk
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I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.
No. of variables passed to awk would be dynamic.
Below example
#!/bin/bash
NAME="Dell"
SERIAL="12345"
echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '
bash awk
asked 23 mins ago
Bharat
3699
add a comment |Â
up vote
0
down vote
favorite
I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.
No. of variables passed to awk would be dynamic.
Below example
#!/bin/bash
NAME="Dell"
SERIAL="12345"
echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '
bash awk
asked 23 mins ago
Bharat
3699
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.
No. of variables passed to awk would be dynamic.
Below example
#!/bin/bash
NAME="Dell"
SERIAL="12345"
echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '
bash awk
asked 23 mins ago
Bharat
3699
I am trying to invoke awk inside a bash script and passing some bash variables values to it. Is there any way to get a count of these variables and print all which are passed to it inside awk.
No. of variables passed to awk would be dynamic.
Below example
#!/bin/bash
NAME="Dell"
SERIAL="12345"
echo "Hello" | awk -v a=$NAME -v b=$SERIAL ' print a,b '
bash awk
bash awk
asked 23 mins ago
Bharat
3699
asked 23 mins ago
Bharat
3699
edited 3 mins ago
asked 23 mins ago
Bharat
3699
asked 23 mins ago
Bharat
3699
asked 23 mins ago
Bharat
3699
3699
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
One option I can think of is to reposition those variables so they feature in ARGV. ARGC will indicate how many of them there are. Beware this make the variables unavailable in BEGIN block. You also need to account for any file names that you may be passing as parameters to awk by subtracting the number of such files from ARGC
echo "Hello" | awk ' print a, b, ARGC - 1' a=$NAME b=$SERIAL
DELL 12345 2
answered 14 mins ago
iruvar
11.6k62959
ARGC should help, wondering why awk doesn't consider them as an input file
– Bharat
5 mins ago
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
One option I can think of is to reposition those variables so they feature in ARGV. ARGC will indicate how many of them there are. Beware this make the variables unavailable in BEGIN block. You also need to account for any file names that you may be passing as parameters to awk by subtracting the number of such files from ARGC
echo "Hello" | awk ' print a, b, ARGC - 1' a=$NAME b=$SERIAL
DELL 12345 2
answered 14 mins ago
iruvar
11.6k62959
ARGC should help, wondering why awk doesn't consider them as an input file
– Bharat
5 mins ago
add a comment |Â
up vote
1
down vote
accepted
One option I can think of is to reposition those variables so they feature in ARGV. ARGC will indicate how many of them there are. Beware this make the variables unavailable in BEGIN block. You also need to account for any file names that you may be passing as parameters to awk by subtracting the number of such files from ARGC
echo "Hello" | awk ' print a, b, ARGC - 1' a=$NAME b=$SERIAL
DELL 12345 2
answered 14 mins ago
iruvar
11.6k62959
ARGC should help, wondering why awk doesn't consider them as an input file
– Bharat
5 mins ago
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
One option I can think of is to reposition those variables so they feature in ARGV. ARGC will indicate how many of them there are. Beware this make the variables unavailable in BEGIN block. You also need to account for any file names that you may be passing as parameters to awk by subtracting the number of such files from ARGC
echo "Hello" | awk ' print a, b, ARGC - 1' a=$NAME b=$SERIAL
DELL 12345 2
answered 14 mins ago
iruvar
11.6k62959
One option I can think of is to reposition those variables so they feature in ARGV. ARGC will indicate how many of them there are. Beware this make the variables unavailable in BEGIN block. You also need to account for any file names that you may be passing as parameters to awk by subtracting the number of such files from ARGC
echo "Hello" | awk ' print a, b, ARGC - 1' a=$NAME b=$SERIAL
DELL 12345 2
answered 14 mins ago
iruvar
11.6k62959
edited 9 mins ago
answered 14 mins ago
iruvar
11.6k62959
answered 14 mins ago
iruvar
11.6k62959
answered 14 mins ago
iruvar
11.6k62959
11.6k62959
ARGC should help, wondering why awk doesn't consider them as an input file
– Bharat
5 mins ago
add a comment |Â
ARGC should help, wondering why awk doesn't consider them as an input file
– Bharat
5 mins ago
ARGC should help, wondering why awk doesn't consider them as an input file
– Bharat
5 mins ago
ARGC should help, wondering why awk doesn't consider them as an input file
– Bharat
5 mins ago
add a comment |Â
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