What does 'driving force of the engine' mean?
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I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?
homework-and-exercises newtonian-mechanics forces acceleration
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up vote
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I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?
homework-and-exercises newtonian-mechanics forces acceleration
edited 1 hour ago
Chair
3,23151933
asked 2 hours ago
Tfue
61
New contributor
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?
homework-and-exercises newtonian-mechanics forces acceleration
edited 1 hour ago
Chair
3,23151933
asked 2 hours ago
Tfue
61
New contributor
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?
homework-and-exercises newtonian-mechanics forces acceleration
homework-and-exercises newtonian-mechanics forces acceleration
edited 1 hour ago
Chair
3,23151933
asked 2 hours ago
Tfue
61
New contributor
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Chair
3,23151933
asked 2 hours ago
Tfue
61
New contributor
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Chair
3,23151933
edited 1 hour ago
Chair
3,23151933
edited 1 hour ago
Chair
3,23151933
3,23151933
asked 2 hours ago
Tfue
61
New contributor
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Tfue
61
asked 2 hours ago
Tfue
61
61
New contributor
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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1 Answer
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You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.
answered 1 hour ago
Buzz
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.
answered 1 hour ago
Buzz
2,80821321
add a comment |Â
up vote
2
down vote
You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.
answered 1 hour ago
Buzz
2,80821321
add a comment |Â
up vote
2
down vote
up vote
2
down vote
You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.
answered 1 hour ago
Buzz
2,80821321
You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.
answered 1 hour ago
Buzz
2,80821321
answered 1 hour ago
Buzz
2,80821321
answered 1 hour ago
Buzz
2,80821321
answered 1 hour ago
Buzz
2,80821321
2,80821321
add a comment |Â
add a comment |Â
Tfue is a new contributor. Be nice, and check out our Code of Conduct.
Tfue is a new contributor. Be nice, and check out our Code of Conduct.
Tfue is a new contributor. Be nice, and check out our Code of Conduct.
Tfue is a new contributor. Be nice, and check out our Code of Conduct.
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