Kahler manifolds and algebraic varieties
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Let $X$ be a smooth complete algebraic variety over $mathbbC$. Can it happen that the underlying complex manifold is not Kahler? If yes, are there explicit examples? If not - how to prove this?
ag.algebraic-geometry complex-geometry
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up vote
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Let $X$ be a smooth complete algebraic variety over $mathbbC$. Can it happen that the underlying complex manifold is not Kahler? If yes, are there explicit examples? If not - how to prove this?
ag.algebraic-geometry complex-geometry
2
Yes, that can and does happen. Please see "Hironaka's example" in the appendices of Hartshorne's "Algebraic geometry".
â Jason Starr
2 hours ago
2
Relevant: mathoverflow.net/questions/108307/â¦
â M.G.
1 hour ago
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up vote
3
down vote
favorite
up vote
3
down vote
favorite
Let $X$ be a smooth complete algebraic variety over $mathbbC$. Can it happen that the underlying complex manifold is not Kahler? If yes, are there explicit examples? If not - how to prove this?
ag.algebraic-geometry complex-geometry
Let $X$ be a smooth complete algebraic variety over $mathbbC$. Can it happen that the underlying complex manifold is not Kahler? If yes, are there explicit examples? If not - how to prove this?
ag.algebraic-geometry complex-geometry
ag.algebraic-geometry complex-geometry
asked 2 hours ago
Alexander Braverman
3,8991239
3,8991239
2
Yes, that can and does happen. Please see "Hironaka's example" in the appendices of Hartshorne's "Algebraic geometry".
â Jason Starr
2 hours ago
2
Relevant: mathoverflow.net/questions/108307/â¦
â M.G.
1 hour ago
add a comment |Â
2
Yes, that can and does happen. Please see "Hironaka's example" in the appendices of Hartshorne's "Algebraic geometry".
â Jason Starr
2 hours ago
2
Relevant: mathoverflow.net/questions/108307/â¦
â M.G.
1 hour ago
2
2
Yes, that can and does happen. Please see "Hironaka's example" in the appendices of Hartshorne's "Algebraic geometry".
â Jason Starr
2 hours ago
Yes, that can and does happen. Please see "Hironaka's example" in the appendices of Hartshorne's "Algebraic geometry".
â Jason Starr
2 hours ago
2
2
Relevant: mathoverflow.net/questions/108307/â¦
â M.G.
1 hour ago
Relevant: mathoverflow.net/questions/108307/â¦
â M.G.
1 hour ago
add a comment |Â
1 Answer
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Nonprojective compact algebraic manifolds are never Kähler. Any compact algebraic manifold is Moishezon, and Moishezon's theorem says that a Moishezon manifold is Kähler if and only if it is a projective variety.
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1 Answer
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oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
Nonprojective compact algebraic manifolds are never Kähler. Any compact algebraic manifold is Moishezon, and Moishezon's theorem says that a Moishezon manifold is Kähler if and only if it is a projective variety.
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up vote
6
down vote
Nonprojective compact algebraic manifolds are never Kähler. Any compact algebraic manifold is Moishezon, and Moishezon's theorem says that a Moishezon manifold is Kähler if and only if it is a projective variety.
add a comment |Â
up vote
6
down vote
up vote
6
down vote
Nonprojective compact algebraic manifolds are never Kähler. Any compact algebraic manifold is Moishezon, and Moishezon's theorem says that a Moishezon manifold is Kähler if and only if it is a projective variety.
Nonprojective compact algebraic manifolds are never Kähler. Any compact algebraic manifold is Moishezon, and Moishezon's theorem says that a Moishezon manifold is Kähler if and only if it is a projective variety.
answered 2 hours ago
Dan Petersen
24.3k267130
24.3k267130
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2
Yes, that can and does happen. Please see "Hironaka's example" in the appendices of Hartshorne's "Algebraic geometry".
â Jason Starr
2 hours ago
2
Relevant: mathoverflow.net/questions/108307/â¦
â M.G.
1 hour ago