Displaying and updating a counter in bash

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
3
down vote

favorite
1












I think it's something like this: (Fedora14/bash)



#!/bin/bash

for i in 0..10..1; do echo -e "$i"'c'
echo -e "nr"
sleep 1
done


But it doesn't work.
Purpose: like this, but without the "clear": 



#!/bin/bash

for i in 0..10..1; do echo -e "$i"
sleep 1
clear
done


So a counting script that doesn't deletes the whole screen to output +1 number, instead it only deletes the line, where the counting is, so that there could be ex.: a beatifull "progress bar"..






bash shell terminal control-flow







share|improve this question



























    up vote
    3
    down vote

    favorite
    1












    I think it's something like this: (Fedora14/bash)



    #!/bin/bash

    for i in 0..10..1; do echo -e "$i"'c'
    echo -e "nr"
    sleep 1
    done


    But it doesn't work.
    Purpose: like this, but without the "clear": 



    #!/bin/bash

    for i in 0..10..1; do echo -e "$i"
    sleep 1
    clear
    done


    So a counting script that doesn't deletes the whole screen to output +1 number, instead it only deletes the line, where the counting is, so that there could be ex.: a beatifull "progress bar"..






    bash shell terminal control-flow







    share|improve this question

























      up vote
      3
      down vote

      favorite
      1









      up vote
      3
      down vote

      favorite
      1






      1





      I think it's something like this: (Fedora14/bash)



      #!/bin/bash

      for i in 0..10..1; do echo -e "$i"'c'
      echo -e "nr"
      sleep 1
      done


      But it doesn't work.
      Purpose: like this, but without the "clear": 



      #!/bin/bash

      for i in 0..10..1; do echo -e "$i"
      sleep 1
      clear
      done


      So a counting script that doesn't deletes the whole screen to output +1 number, instead it only deletes the line, where the counting is, so that there could be ex.: a beatifull "progress bar"..






      bash shell terminal control-flow







      share|improve this question















      I think it's something like this: (Fedora14/bash)



      #!/bin/bash

      for i in 0..10..1; do echo -e "$i"'c'
      echo -e "nr"
      sleep 1
      done


      But it doesn't work.
      Purpose: like this, but without the "clear": 



      #!/bin/bash

      for i in 0..10..1; do echo -e "$i"
      sleep 1
      clear
      done


      So a counting script that doesn't deletes the whole screen to output +1 number, instead it only deletes the line, where the counting is, so that there could be ex.: a beatifull "progress bar"..






      bash shell terminal control-flow




      bash shell terminal control-flow






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Sep 17 '11 at 17:04









      Michael Mrozek♦

      59.5k27187208




      59.5k27187208










      asked Aug 30 '11 at 13:57









      LanceBaynes

      9,96675190321




      9,96675190321




















          3 Answers
          3






          active

          oldest

          votes

















          up vote
          7
          down vote



          accepted










          for i in 0..15; do echo -ne "$i"'r'; sleep 1; done; echo


          You don't need ..1 for stepwidth 1 which is default. 



          echo -n


          prevents newlines.



          r is returning to begin of line (without newline - n), and better than my formerly used 'b' for backstepping a single character, unhandy, if you have more than one digit-numbers. Thanks to rozcietrzewiacz.






          share|improve this answer






















          • You can also just use one r instead of all the b's.
            – rozcietrzewiacz
            Aug 30 '11 at 15:06











          • Yes, thanks, I changed my post accordingly.
            – user unknown
            Aug 30 '11 at 21:17

















          up vote
          1
          down vote













          Are you looking for something like this?



          for i in 1..10; do 
           printf 'r%2d' $i
           sleep 1
          done
          printf 'n'





          share|improve this answer






















          • Why the first printf?
            – rozcietrzewiacz
            Aug 30 '11 at 14:40










          • It would make sense if you were counting backwards from 10 to 1
            – glenn jackman
            Aug 30 '11 at 14:44










          • @rozcietrzewiacz and glenn jackman: I think i put it, without thinking too much, remembering a case where the numbers had different lengths, so that something old could be leaved on screen.
            – enzotib
            Aug 30 '11 at 14:56










          • @glen Really? How exactly?
            – rozcietrzewiacz
            Aug 30 '11 at 15:02










          • I missed the '%2d' in the next printf. If it had just been for i in 10..1..-1; do printf "r%d" $i; sleep 1; done then you would have seen 10, 90, 80, 70, etc
            – glenn jackman
            Aug 30 '11 at 15:34

















          up vote
          0
          down vote













          https://github.com/extensionsapp/progre.sh



          Create 48 percent progress: progreSh 48



          enter image description here






          share|improve this answer








          New contributor




          Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.

















            Your Answer








            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "106"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













             

            draft saved


            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f19756%2fdisplaying-and-updating-a-counter-in-bash%23new-answer', 'question_page');

            );

            Post as a guest

















            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            7
            down vote



            accepted










            for i in 0..15; do echo -ne "$i"'r'; sleep 1; done; echo


            You don't need ..1 for stepwidth 1 which is default. 



            echo -n


            prevents newlines.



            r is returning to begin of line (without newline - n), and better than my formerly used 'b' for backstepping a single character, unhandy, if you have more than one digit-numbers. Thanks to rozcietrzewiacz.






            share|improve this answer






















            • You can also just use one r instead of all the b's.
              – rozcietrzewiacz
              Aug 30 '11 at 15:06











            • Yes, thanks, I changed my post accordingly.
              – user unknown
              Aug 30 '11 at 21:17














            up vote
            7
            down vote



            accepted










            for i in 0..15; do echo -ne "$i"'r'; sleep 1; done; echo


            You don't need ..1 for stepwidth 1 which is default. 



            echo -n


            prevents newlines.



            r is returning to begin of line (without newline - n), and better than my formerly used 'b' for backstepping a single character, unhandy, if you have more than one digit-numbers. Thanks to rozcietrzewiacz.






            share|improve this answer






















            • You can also just use one r instead of all the b's.
              – rozcietrzewiacz
              Aug 30 '11 at 15:06











            • Yes, thanks, I changed my post accordingly.
              – user unknown
              Aug 30 '11 at 21:17












            up vote
            7
            down vote



            accepted







            up vote
            7
            down vote



            accepted






            for i in 0..15; do echo -ne "$i"'r'; sleep 1; done; echo


            You don't need ..1 for stepwidth 1 which is default. 



            echo -n


            prevents newlines.



            r is returning to begin of line (without newline - n), and better than my formerly used 'b' for backstepping a single character, unhandy, if you have more than one digit-numbers. Thanks to rozcietrzewiacz.






            share|improve this answer














            for i in 0..15; do echo -ne "$i"'r'; sleep 1; done; echo


            You don't need ..1 for stepwidth 1 which is default. 



            echo -n


            prevents newlines.



            r is returning to begin of line (without newline - n), and better than my formerly used 'b' for backstepping a single character, unhandy, if you have more than one digit-numbers. Thanks to rozcietrzewiacz.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Aug 30 '11 at 21:00

























            answered Aug 30 '11 at 14:09









            user unknown

            7,11412148




            7,11412148











            • You can also just use one r instead of all the b's.
              – rozcietrzewiacz
              Aug 30 '11 at 15:06











            • Yes, thanks, I changed my post accordingly.
              – user unknown
              Aug 30 '11 at 21:17
















            • You can also just use one r instead of all the b's.
              – rozcietrzewiacz
              Aug 30 '11 at 15:06











            • Yes, thanks, I changed my post accordingly.
              – user unknown
              Aug 30 '11 at 21:17















            You can also just use one r instead of all the b's.
            – rozcietrzewiacz
            Aug 30 '11 at 15:06





            You can also just use one r instead of all the b's.
            – rozcietrzewiacz
            Aug 30 '11 at 15:06













            Yes, thanks, I changed my post accordingly.
            – user unknown
            Aug 30 '11 at 21:17




            Yes, thanks, I changed my post accordingly.
            – user unknown
            Aug 30 '11 at 21:17












            up vote
            1
            down vote













            Are you looking for something like this?



            for i in 1..10; do 
             printf 'r%2d' $i
             sleep 1
            done
            printf 'n'





            share|improve this answer






















            • Why the first printf?
              – rozcietrzewiacz
              Aug 30 '11 at 14:40










            • It would make sense if you were counting backwards from 10 to 1
              – glenn jackman
              Aug 30 '11 at 14:44










            • @rozcietrzewiacz and glenn jackman: I think i put it, without thinking too much, remembering a case where the numbers had different lengths, so that something old could be leaved on screen.
              – enzotib
              Aug 30 '11 at 14:56










            • @glen Really? How exactly?
              – rozcietrzewiacz
              Aug 30 '11 at 15:02










            • I missed the '%2d' in the next printf. If it had just been for i in 10..1..-1; do printf "r%d" $i; sleep 1; done then you would have seen 10, 90, 80, 70, etc
              – glenn jackman
              Aug 30 '11 at 15:34














            up vote
            1
            down vote













            Are you looking for something like this?



            for i in 1..10; do 
             printf 'r%2d' $i
             sleep 1
            done
            printf 'n'





            share|improve this answer






















            • Why the first printf?
              – rozcietrzewiacz
              Aug 30 '11 at 14:40










            • It would make sense if you were counting backwards from 10 to 1
              – glenn jackman
              Aug 30 '11 at 14:44










            • @rozcietrzewiacz and glenn jackman: I think i put it, without thinking too much, remembering a case where the numbers had different lengths, so that something old could be leaved on screen.
              – enzotib
              Aug 30 '11 at 14:56










            • @glen Really? How exactly?
              – rozcietrzewiacz
              Aug 30 '11 at 15:02










            • I missed the '%2d' in the next printf. If it had just been for i in 10..1..-1; do printf "r%d" $i; sleep 1; done then you would have seen 10, 90, 80, 70, etc
              – glenn jackman
              Aug 30 '11 at 15:34












            up vote
            1
            down vote










            up vote
            1
            down vote









            Are you looking for something like this?



            for i in 1..10; do 
             printf 'r%2d' $i
             sleep 1
            done
            printf 'n'





            share|improve this answer














            Are you looking for something like this?



            for i in 1..10; do 
             printf 'r%2d' $i
             sleep 1
            done
            printf 'n'






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Aug 31 '11 at 0:51

























            answered Aug 30 '11 at 14:07









            enzotib

            33k710292




            33k710292











            • Why the first printf?
              – rozcietrzewiacz
              Aug 30 '11 at 14:40










            • It would make sense if you were counting backwards from 10 to 1
              – glenn jackman
              Aug 30 '11 at 14:44










            • @rozcietrzewiacz and glenn jackman: I think i put it, without thinking too much, remembering a case where the numbers had different lengths, so that something old could be leaved on screen.
              – enzotib
              Aug 30 '11 at 14:56










            • @glen Really? How exactly?
              – rozcietrzewiacz
              Aug 30 '11 at 15:02










            • I missed the '%2d' in the next printf. If it had just been for i in 10..1..-1; do printf "r%d" $i; sleep 1; done then you would have seen 10, 90, 80, 70, etc
              – glenn jackman
              Aug 30 '11 at 15:34
















            • Why the first printf?
              – rozcietrzewiacz
              Aug 30 '11 at 14:40










            • It would make sense if you were counting backwards from 10 to 1
              – glenn jackman
              Aug 30 '11 at 14:44










            • @rozcietrzewiacz and glenn jackman: I think i put it, without thinking too much, remembering a case where the numbers had different lengths, so that something old could be leaved on screen.
              – enzotib
              Aug 30 '11 at 14:56










            • @glen Really? How exactly?
              – rozcietrzewiacz
              Aug 30 '11 at 15:02










            • I missed the '%2d' in the next printf. If it had just been for i in 10..1..-1; do printf "r%d" $i; sleep 1; done then you would have seen 10, 90, 80, 70, etc
              – glenn jackman
              Aug 30 '11 at 15:34















            Why the first printf?
            – rozcietrzewiacz
            Aug 30 '11 at 14:40




            Why the first printf?
            – rozcietrzewiacz
            Aug 30 '11 at 14:40












            It would make sense if you were counting backwards from 10 to 1
            – glenn jackman
            Aug 30 '11 at 14:44




            It would make sense if you were counting backwards from 10 to 1
            – glenn jackman
            Aug 30 '11 at 14:44












            @rozcietrzewiacz and glenn jackman: I think i put it, without thinking too much, remembering a case where the numbers had different lengths, so that something old could be leaved on screen.
            – enzotib
            Aug 30 '11 at 14:56




            @rozcietrzewiacz and glenn jackman: I think i put it, without thinking too much, remembering a case where the numbers had different lengths, so that something old could be leaved on screen.
            – enzotib
            Aug 30 '11 at 14:56












            @glen Really? How exactly?
            – rozcietrzewiacz
            Aug 30 '11 at 15:02




            @glen Really? How exactly?
            – rozcietrzewiacz
            Aug 30 '11 at 15:02












            I missed the '%2d' in the next printf. If it had just been for i in 10..1..-1; do printf "r%d" $i; sleep 1; done then you would have seen 10, 90, 80, 70, etc
            – glenn jackman
            Aug 30 '11 at 15:34




            I missed the '%2d' in the next printf. If it had just been for i in 10..1..-1; do printf "r%d" $i; sleep 1; done then you would have seen 10, 90, 80, 70, etc
            – glenn jackman
            Aug 30 '11 at 15:34










            up vote
            0
            down vote













            https://github.com/extensionsapp/progre.sh



            Create 48 percent progress: progreSh 48



            enter image description here






            share|improve this answer








            New contributor




            Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





















              up vote
              0
              down vote













              https://github.com/extensionsapp/progre.sh



              Create 48 percent progress: progreSh 48



              enter image description here






              share|improve this answer








              New contributor




              Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.



















                up vote
                0
                down vote










                up vote
                0
                down vote









                https://github.com/extensionsapp/progre.sh



                Create 48 percent progress: progreSh 48



                enter image description here






                share|improve this answer








                New contributor




                Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                https://github.com/extensionsapp/progre.sh



                Create 48 percent progress: progreSh 48



                enter image description here







                share|improve this answer








                New contributor




                Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                share|improve this answer



                share|improve this answer






                New contributor




                Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                answered 14 mins ago









                Art Pip

                101




                101




                New contributor




                Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                New contributor





                Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                Art Pip is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.



























                     

                    draft saved


                    draft discarded















































                     


                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f19756%2fdisplaying-and-updating-a-counter-in-bash%23new-answer', 'question_page');

                    );

                    Post as a guest
































































                    -

                    Popular posts from this blog

                    How to check contact read email or not when send email to Individual?

                    Image
                    Clash Royale CLAN TAG #URR8PPP up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this question asked Sep 26 at 0:12 ToanLuong 49 9 add a comment  |  up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this questi...
                    Read more

                    Displaying single band from multi-band raster using QGIS

                    Image
                    Clash Royale CLAN TAG #URR8PPP 1 How can I extract a single band from multi-band raster in QGIS? I have an remote sensed image which has 6 bands (including NDVI band), I want to display each band separately, but have no idea how to do. I have seen some questions similar here but none worked for me. The original image (has 6 bands) is: I want to display the band 6 which should be like this: But I tried gdal_translate, and couldn't get the correct result. What I have got is: qgis raster multi-band share | improve this question edited Mar 5 at 0:53 Summer asked Mar 4 at 6:42 Summer Summer 23 6 Is this any help gis.stackexchange.com/questions/220658/… ? if not gis.stackexchange.com/questions/62133/… might help. – Michael Stimson Mar 4 at 6:46 Thanks for answering but when I used gdal_translate, qgis showed that 'Error 4: Kayena.tif: No such file or directory". Would you know how to fi...
                    Read more

                    How many registers does an x86_64 CPU actually have?

                    Image
                    Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite I am currently learning reverse engineering and am studying the flags register. I had in my mind that rflags was just another name for one of the 16 general purpose registers, for example rax or rbx . But it looks like rflags is actually an additional register. So that makes 17 registers in total... how many more could there be? I have spent at least an hour on this and found numerous different answers. The best answer so far is this, which says that there are 40 registers in total. 16 General Purpose Registers 2 Status Registers 6 Code Segment Registers 16 SSE Registers 8 FPU/MMX Registers But if I add that up, I get 48. Could anybody provide an official answer on how many registers an x86_64 CPU has (e.g. an Intel i7). Additionally, I have seen references to 'hardware' and 'architectural' registers. What are those registers and how many are there? register x86-64 share | improve this...
                    Read more