Can lftp get take in a variable name?

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I want to have a script that uses lftp to download a zip file with a variable name. Currently I have the following:



open server
user user pass
set ssl:verify-certificate no
ls -ltA1 | grep .zip$ | head -n 1


Executing this along side lsftp -f returns just the file name I need. Theoretically now I would run 



file="$(lftp -f get_minecraft_list)"
lftp -u user:pass server:21 -e "get $file; bye"


and it should work right? When doing this the lftp command ends up in a reconnect loop. So I tried to do the variable name thing in the first block of code but have no idea how to set the output of that ls command to work with the get command. Any ideas?






bash variable lftp






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    up vote
    0
    down vote

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    I want to have a script that uses lftp to download a zip file with a variable name. Currently I have the following:



    open server
    user user pass
    set ssl:verify-certificate no
    ls -ltA1 | grep .zip$ | head -n 1


    Executing this along side lsftp -f returns just the file name I need. Theoretically now I would run 



    file="$(lftp -f get_minecraft_list)"
    lftp -u user:pass server:21 -e "get $file; bye"


    and it should work right? When doing this the lftp command ends up in a reconnect loop. So I tried to do the variable name thing in the first block of code but have no idea how to set the output of that ls command to work with the get command. Any ideas?






    bash variable lftp






    share























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I want to have a script that uses lftp to download a zip file with a variable name. Currently I have the following:



      open server
      user user pass
      set ssl:verify-certificate no
      ls -ltA1 | grep .zip$ | head -n 1


      Executing this along side lsftp -f returns just the file name I need. Theoretically now I would run 



      file="$(lftp -f get_minecraft_list)"
      lftp -u user:pass server:21 -e "get $file; bye"


      and it should work right? When doing this the lftp command ends up in a reconnect loop. So I tried to do the variable name thing in the first block of code but have no idea how to set the output of that ls command to work with the get command. Any ideas?






      bash variable lftp






      share













      I want to have a script that uses lftp to download a zip file with a variable name. Currently I have the following:



      open server
      user user pass
      set ssl:verify-certificate no
      ls -ltA1 | grep .zip$ | head -n 1


      Executing this along side lsftp -f returns just the file name I need. Theoretically now I would run 



      file="$(lftp -f get_minecraft_list)"
      lftp -u user:pass server:21 -e "get $file; bye"


      and it should work right? When doing this the lftp command ends up in a reconnect loop. So I tried to do the variable name thing in the first block of code but have no idea how to set the output of that ls command to work with the get command. Any ideas?






      bash variable lftp




      bash variable lftp





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      asked 2 mins ago









      Andrei S.

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