mjhjmtu

I want to get the last update date of kernel in AIX & Solaris.

For Linux, the command is:

rpm -qa --last | grep kernel-`uname -r` | sed 's/^k.*ss//'

For this command I'm getting the output:

Wed 29 Nov 2017 03:26:48 PM EST

I need same replacement for AIX & Solaris as well.

I'm trying to execute this command for AIX, but it's not sophisticated proper output what I need:

lslpp -ha bos.adt.base | grep COMPLETE | sed 's/^k.*ss//'
Return Code: 0, 6.1.1.0 COMMIT COMPLETE 09/16/14 13:49:31 
 6.1.1.0 APPLY COMPLETE 09/16/14 13:49:31 
 6.1.8.16 COMMIT COMPLETE 09/16/14 13:59:18 
 6.1.8.16 APPLY COMPLETE 09/16/14 13:55:32 
 6.1.9.30 COMMIT COMPLETE 07/02/15 16:36:49 
 6.1.9.30 APPLY COMPLETE 07/02/15 16:33:22 
 6.1.9.45 COMMIT COMPLETE 09/04/15 15:45:19 
 6.1.9.45 APPLY COMPLETE 09/04/15 15:45:09 
 6.1.9.101 APPLY COMPLETE 09/14/17 16:44:44 
 6.1.1.0 COMMIT COMPLETE 09/16/14 13:49:36 
 6.1.1.0 APPLY COMPLETE 09/16/14 13:49:36 
 6.1.8.16 COMMIT COMPLETE 09/16/14 13:59:18 
 6.1.8.16 APPLY COMPLETE 09/16/14 13:55:32 
 6.1.9.30 COMMIT COMPLETE 07/02/15 16:36:49 
 6.1.9.30 APPLY COMPLETE 07/02/15 16:33:23 
 6.1.9.45 COMMIT COMPLETE 09/04/15 15:45:19 
 6.1.9.45 APPLY COMPLETE 09/04/15 15:45:10 
 6.1.9.101 APPLY COMPLETE 09/14/17 16:44:45 

Or else I need only last line of above output.

For the AIX part, instead of hard-coding the bos.adt.base fileset, and instead of asking for all of the updates -- applies and commits -- but instead just the commits, I would ask for the history of the fileset that owns the /unix symlink (which points to the kernel):

lslpp -q -c -h -Or $(lslpp -q -c -w /unix | cut -d: -f2) | tail -1 | cut -d: -f7-8

In pieces, that's:

• -q -- don't print column headings


• -c -- print output colon-delimited (easier to parse)


• -h -- fileset history


• -w -- which fileset owns the given file


• -Or -- only need one set; root or usr works here

From the inside out, we get the fileset name from lslpp ... -w and then ask for the history of that fileset; that's then piped to tail to get the last line (assumed to be the most recent), and then to cut to pull out the date and time fields.

For the Solaris part, perhaps the most recently applied patch to the kernel would suffice?

nawk -F: '/^PATCH_INFO/ sub(" From", ""); print $2":"$3":"$4; ' 
 /var/sadm/pkg/SUNWckr/pkginfo | 
 sort -k6n | tail -1

On Solaris, you'll see the kernel patch installed by running:
uname -v | awk -F_ 'print $2'

If you then run:
ls -lat /var/sadm/patch |grep <patch>

You'll see the timestamp of when it was installed. There will also be logs in that directory if you want further information.

You can get the last line of any output by piping it to tail -1. Try this:

lslpp -ha bos.adt.base | sed -n '/COMPLETE/ s/^k.*ss//p' | tail -1

I've also folded the grep command into the sed command - it wasn't doing anything that sed can't do itself.

NOTE: I'm not familiar with the AIX lslpp command, so I'm just assuming it's the right tool to use for this job, and that you've used the most appropriate options with it. It may be worth reading the man page to see if there are better ways of using it to get what you want.