Variable shows blank even if it's enclosed in double quotes

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0
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I have a simple question with you that I cannot answer myself.
I have a variable below which shows a blank after printing the result.



SCRIPT:



core_out=find coretst.*
echo "$core_out"
Result: No display *blank*
#tried to echo without double quotes as well but it has the same result


btw, I'm using putty on this.



Actual objective:
1. Check core.* in /opt/datintdv/Informatica/9.6.1/server/bin --dir1
- If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable.
- If core.* does not exist on dir1
then check /opt/datintdv/Informatica/9.6.1/tomcat/bin
If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable. *output is separated by a new line



  1. Get all the output then concatenate it as the e-mail body.

  2. Send it to the user via e-mail.
    *I'm currently writing a script for this but I'm having a hard time since this is my first time to do it.

Hopefully you can help me! Thanks!







share|improve this question






















  • It looks like you are trying to get the output of a command and store it in a variable. I'm assuming bash so try: core_out=$(find coretst.*)
    – pacmanwa
    Mar 5 at 14:37















up vote
0
down vote

favorite












I have a simple question with you that I cannot answer myself.
I have a variable below which shows a blank after printing the result.



SCRIPT:



core_out=find coretst.*
echo "$core_out"
Result: No display *blank*
#tried to echo without double quotes as well but it has the same result


btw, I'm using putty on this.



Actual objective:
1. Check core.* in /opt/datintdv/Informatica/9.6.1/server/bin --dir1
- If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable.
- If core.* does not exist on dir1
then check /opt/datintdv/Informatica/9.6.1/tomcat/bin
If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable. *output is separated by a new line



  1. Get all the output then concatenate it as the e-mail body.

  2. Send it to the user via e-mail.
    *I'm currently writing a script for this but I'm having a hard time since this is my first time to do it.

Hopefully you can help me! Thanks!







share|improve this question






















  • It looks like you are trying to get the output of a command and store it in a variable. I'm assuming bash so try: core_out=$(find coretst.*)
    – pacmanwa
    Mar 5 at 14:37













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a simple question with you that I cannot answer myself.
I have a variable below which shows a blank after printing the result.



SCRIPT:



core_out=find coretst.*
echo "$core_out"
Result: No display *blank*
#tried to echo without double quotes as well but it has the same result


btw, I'm using putty on this.



Actual objective:
1. Check core.* in /opt/datintdv/Informatica/9.6.1/server/bin --dir1
- If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable.
- If core.* does not exist on dir1
then check /opt/datintdv/Informatica/9.6.1/tomcat/bin
If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable. *output is separated by a new line



  1. Get all the output then concatenate it as the e-mail body.

  2. Send it to the user via e-mail.
    *I'm currently writing a script for this but I'm having a hard time since this is my first time to do it.

Hopefully you can help me! Thanks!







share|improve this question














I have a simple question with you that I cannot answer myself.
I have a variable below which shows a blank after printing the result.



SCRIPT:



core_out=find coretst.*
echo "$core_out"
Result: No display *blank*
#tried to echo without double quotes as well but it has the same result


btw, I'm using putty on this.



Actual objective:
1. Check core.* in /opt/datintdv/Informatica/9.6.1/server/bin --dir1
- If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable.
- If core.* does not exist on dir1
then check /opt/datintdv/Informatica/9.6.1/tomcat/bin
If core.* exist and more than 1, get 1 core.*
then execute strings (core.*) | grep “pmdtm(“ --script1
then store the output in a parameter
if script1 did not work
execute file (core filename) until all core. have been executed
then store the output in a variable. *output is separated by a new line



  1. Get all the output then concatenate it as the e-mail body.

  2. Send it to the user via e-mail.
    *I'm currently writing a script for this but I'm having a hard time since this is my first time to do it.

Hopefully you can help me! Thanks!









share|improve this question













share|improve this question




share|improve this question








edited Mar 6 at 21:00

























asked Mar 5 at 14:35









Jerome Sabareza

33




33











  • It looks like you are trying to get the output of a command and store it in a variable. I'm assuming bash so try: core_out=$(find coretst.*)
    – pacmanwa
    Mar 5 at 14:37

















  • It looks like you are trying to get the output of a command and store it in a variable. I'm assuming bash so try: core_out=$(find coretst.*)
    – pacmanwa
    Mar 5 at 14:37
















It looks like you are trying to get the output of a command and store it in a variable. I'm assuming bash so try: core_out=$(find coretst.*)
– pacmanwa
Mar 5 at 14:37





It looks like you are trying to get the output of a command and store it in a variable. I'm assuming bash so try: core_out=$(find coretst.*)
– pacmanwa
Mar 5 at 14:37











1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










Command substitution, which means using the result of a command for something in-line, is done with $( ... ).



In your case,



core_out=$( find coretst.* )


However, this will prompt find to look in all paths that starts with anything that coretst.* expands to. What I assume you want to do is to look in the current directory or below for files that matches the pattern coretst.*. You would do that with



core_out=$( find . -type f -name 'coretst.*' )


Quoting the coretst.* pattern stops the shell from expanding it to names in the current directory.



Then, it's a question what you would like to do with the pathnames that are returned by this. If you just want to print them, then there is no need for the variable at all:



find . -type f -name 'coretst.*'


If you would like to remove these files, then you should do so from find:



find . -type f -name 'coretst.*' -exec rm +


Any other operation on the files can also be performed from within find.



See the question "Why is looping over find's output bad practice?" for reasons why using the paths that find returns may be a bad habit (the answers are about looping over the result of find, which is what I presume you might want to be doing later).




From comments:




I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep "pmdtm("




If I understand this correctly, this could be done with



find . -type f -name 'coretst.*' -exec strings + | grep -F 'pmdtm('


I.e., run strings on all found files and find the lines that contains the string pmdtm(.



If you want to know what file the match was found in:



find . -type f -name 'coretst.*' -exec sh -c '
for name; do
if strings "$name" | grep -qF "pmdtm("; then
printf "%sn" "$name"
fi
done' find-sh +





share|improve this answer






















  • Thanks Kusalananda! Your assumption is quite right. I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep “pmdtm(“
    – Jerome Sabareza
    Mar 5 at 14:57










  • @JeromeSabareza See updated answer.
    – Kusalananda
    Mar 5 at 15:04










  • +1. BTW, strings isn't needed here - it seems it's only being used to find which files contain a particular string. Instead, you can use grep's -a option to force it to search binary files as if they were text. e.g. find . -type f -name 'coretst.*' -exec grep -alF 'pmdtm(' +
    – cas
    Mar 6 at 3:14











  • Thanks Kunsalananda and cas, I'll try all your inputs and let you know the results. I edited my original question for a better understanding, actually that's the whole context why I'm writing script which is my first time - having a hard time though! :)
    – Jerome Sabareza
    Mar 6 at 21:02










  • Hi Kunsalananda/Cas, I almost completed my script. However, some of it were working as expected and some were not (specially the nested if statements). Can you help me check my script? ( Is there away to attach my script here?) Let me know if you have any questions. Thank you in advance. Regards, Jerome P.S. I tried this one: find . -type f -name 'coretst.*' -exec sh -c ' for name; do if strings "$name" | grep -qF "pmdtm("; then printf "%sn" "$name" fi done' find-sh + but it prompts/wait for an enter to generate the result.
    – Jerome Sabareza
    Apr 12 at 16:18










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










Command substitution, which means using the result of a command for something in-line, is done with $( ... ).



In your case,



core_out=$( find coretst.* )


However, this will prompt find to look in all paths that starts with anything that coretst.* expands to. What I assume you want to do is to look in the current directory or below for files that matches the pattern coretst.*. You would do that with



core_out=$( find . -type f -name 'coretst.*' )


Quoting the coretst.* pattern stops the shell from expanding it to names in the current directory.



Then, it's a question what you would like to do with the pathnames that are returned by this. If you just want to print them, then there is no need for the variable at all:



find . -type f -name 'coretst.*'


If you would like to remove these files, then you should do so from find:



find . -type f -name 'coretst.*' -exec rm +


Any other operation on the files can also be performed from within find.



See the question "Why is looping over find's output bad practice?" for reasons why using the paths that find returns may be a bad habit (the answers are about looping over the result of find, which is what I presume you might want to be doing later).




From comments:




I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep "pmdtm("




If I understand this correctly, this could be done with



find . -type f -name 'coretst.*' -exec strings + | grep -F 'pmdtm('


I.e., run strings on all found files and find the lines that contains the string pmdtm(.



If you want to know what file the match was found in:



find . -type f -name 'coretst.*' -exec sh -c '
for name; do
if strings "$name" | grep -qF "pmdtm("; then
printf "%sn" "$name"
fi
done' find-sh +





share|improve this answer






















  • Thanks Kusalananda! Your assumption is quite right. I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep “pmdtm(“
    – Jerome Sabareza
    Mar 5 at 14:57










  • @JeromeSabareza See updated answer.
    – Kusalananda
    Mar 5 at 15:04










  • +1. BTW, strings isn't needed here - it seems it's only being used to find which files contain a particular string. Instead, you can use grep's -a option to force it to search binary files as if they were text. e.g. find . -type f -name 'coretst.*' -exec grep -alF 'pmdtm(' +
    – cas
    Mar 6 at 3:14











  • Thanks Kunsalananda and cas, I'll try all your inputs and let you know the results. I edited my original question for a better understanding, actually that's the whole context why I'm writing script which is my first time - having a hard time though! :)
    – Jerome Sabareza
    Mar 6 at 21:02










  • Hi Kunsalananda/Cas, I almost completed my script. However, some of it were working as expected and some were not (specially the nested if statements). Can you help me check my script? ( Is there away to attach my script here?) Let me know if you have any questions. Thank you in advance. Regards, Jerome P.S. I tried this one: find . -type f -name 'coretst.*' -exec sh -c ' for name; do if strings "$name" | grep -qF "pmdtm("; then printf "%sn" "$name" fi done' find-sh + but it prompts/wait for an enter to generate the result.
    – Jerome Sabareza
    Apr 12 at 16:18














up vote
2
down vote



accepted










Command substitution, which means using the result of a command for something in-line, is done with $( ... ).



In your case,



core_out=$( find coretst.* )


However, this will prompt find to look in all paths that starts with anything that coretst.* expands to. What I assume you want to do is to look in the current directory or below for files that matches the pattern coretst.*. You would do that with



core_out=$( find . -type f -name 'coretst.*' )


Quoting the coretst.* pattern stops the shell from expanding it to names in the current directory.



Then, it's a question what you would like to do with the pathnames that are returned by this. If you just want to print them, then there is no need for the variable at all:



find . -type f -name 'coretst.*'


If you would like to remove these files, then you should do so from find:



find . -type f -name 'coretst.*' -exec rm +


Any other operation on the files can also be performed from within find.



See the question "Why is looping over find's output bad practice?" for reasons why using the paths that find returns may be a bad habit (the answers are about looping over the result of find, which is what I presume you might want to be doing later).




From comments:




I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep "pmdtm("




If I understand this correctly, this could be done with



find . -type f -name 'coretst.*' -exec strings + | grep -F 'pmdtm('


I.e., run strings on all found files and find the lines that contains the string pmdtm(.



If you want to know what file the match was found in:



find . -type f -name 'coretst.*' -exec sh -c '
for name; do
if strings "$name" | grep -qF "pmdtm("; then
printf "%sn" "$name"
fi
done' find-sh +





share|improve this answer






















  • Thanks Kusalananda! Your assumption is quite right. I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep “pmdtm(“
    – Jerome Sabareza
    Mar 5 at 14:57










  • @JeromeSabareza See updated answer.
    – Kusalananda
    Mar 5 at 15:04










  • +1. BTW, strings isn't needed here - it seems it's only being used to find which files contain a particular string. Instead, you can use grep's -a option to force it to search binary files as if they were text. e.g. find . -type f -name 'coretst.*' -exec grep -alF 'pmdtm(' +
    – cas
    Mar 6 at 3:14











  • Thanks Kunsalananda and cas, I'll try all your inputs and let you know the results. I edited my original question for a better understanding, actually that's the whole context why I'm writing script which is my first time - having a hard time though! :)
    – Jerome Sabareza
    Mar 6 at 21:02










  • Hi Kunsalananda/Cas, I almost completed my script. However, some of it were working as expected and some were not (specially the nested if statements). Can you help me check my script? ( Is there away to attach my script here?) Let me know if you have any questions. Thank you in advance. Regards, Jerome P.S. I tried this one: find . -type f -name 'coretst.*' -exec sh -c ' for name; do if strings "$name" | grep -qF "pmdtm("; then printf "%sn" "$name" fi done' find-sh + but it prompts/wait for an enter to generate the result.
    – Jerome Sabareza
    Apr 12 at 16:18












up vote
2
down vote



accepted







up vote
2
down vote



accepted






Command substitution, which means using the result of a command for something in-line, is done with $( ... ).



In your case,



core_out=$( find coretst.* )


However, this will prompt find to look in all paths that starts with anything that coretst.* expands to. What I assume you want to do is to look in the current directory or below for files that matches the pattern coretst.*. You would do that with



core_out=$( find . -type f -name 'coretst.*' )


Quoting the coretst.* pattern stops the shell from expanding it to names in the current directory.



Then, it's a question what you would like to do with the pathnames that are returned by this. If you just want to print them, then there is no need for the variable at all:



find . -type f -name 'coretst.*'


If you would like to remove these files, then you should do so from find:



find . -type f -name 'coretst.*' -exec rm +


Any other operation on the files can also be performed from within find.



See the question "Why is looping over find's output bad practice?" for reasons why using the paths that find returns may be a bad habit (the answers are about looping over the result of find, which is what I presume you might want to be doing later).




From comments:




I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep "pmdtm("




If I understand this correctly, this could be done with



find . -type f -name 'coretst.*' -exec strings + | grep -F 'pmdtm('


I.e., run strings on all found files and find the lines that contains the string pmdtm(.



If you want to know what file the match was found in:



find . -type f -name 'coretst.*' -exec sh -c '
for name; do
if strings "$name" | grep -qF "pmdtm("; then
printf "%sn" "$name"
fi
done' find-sh +





share|improve this answer














Command substitution, which means using the result of a command for something in-line, is done with $( ... ).



In your case,



core_out=$( find coretst.* )


However, this will prompt find to look in all paths that starts with anything that coretst.* expands to. What I assume you want to do is to look in the current directory or below for files that matches the pattern coretst.*. You would do that with



core_out=$( find . -type f -name 'coretst.*' )


Quoting the coretst.* pattern stops the shell from expanding it to names in the current directory.



Then, it's a question what you would like to do with the pathnames that are returned by this. If you just want to print them, then there is no need for the variable at all:



find . -type f -name 'coretst.*'


If you would like to remove these files, then you should do so from find:



find . -type f -name 'coretst.*' -exec rm +


Any other operation on the files can also be performed from within find.



See the question "Why is looping over find's output bad practice?" for reasons why using the paths that find returns may be a bad habit (the answers are about looping over the result of find, which is what I presume you might want to be doing later).




From comments:




I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep "pmdtm("




If I understand this correctly, this could be done with



find . -type f -name 'coretst.*' -exec strings + | grep -F 'pmdtm('


I.e., run strings on all found files and find the lines that contains the string pmdtm(.



If you want to know what file the match was found in:



find . -type f -name 'coretst.*' -exec sh -c '
for name; do
if strings "$name" | grep -qF "pmdtm("; then
printf "%sn" "$name"
fi
done' find-sh +






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 5 at 15:04

























answered Mar 5 at 14:50









Kusalananda

103k13202318




103k13202318











  • Thanks Kusalananda! Your assumption is quite right. I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep “pmdtm(“
    – Jerome Sabareza
    Mar 5 at 14:57










  • @JeromeSabareza See updated answer.
    – Kusalananda
    Mar 5 at 15:04










  • +1. BTW, strings isn't needed here - it seems it's only being used to find which files contain a particular string. Instead, you can use grep's -a option to force it to search binary files as if they were text. e.g. find . -type f -name 'coretst.*' -exec grep -alF 'pmdtm(' +
    – cas
    Mar 6 at 3:14











  • Thanks Kunsalananda and cas, I'll try all your inputs and let you know the results. I edited my original question for a better understanding, actually that's the whole context why I'm writing script which is my first time - having a hard time though! :)
    – Jerome Sabareza
    Mar 6 at 21:02










  • Hi Kunsalananda/Cas, I almost completed my script. However, some of it were working as expected and some were not (specially the nested if statements). Can you help me check my script? ( Is there away to attach my script here?) Let me know if you have any questions. Thank you in advance. Regards, Jerome P.S. I tried this one: find . -type f -name 'coretst.*' -exec sh -c ' for name; do if strings "$name" | grep -qF "pmdtm("; then printf "%sn" "$name" fi done' find-sh + but it prompts/wait for an enter to generate the result.
    – Jerome Sabareza
    Apr 12 at 16:18
















  • Thanks Kusalananda! Your assumption is quite right. I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep “pmdtm(“
    – Jerome Sabareza
    Mar 5 at 14:57










  • @JeromeSabareza See updated answer.
    – Kusalananda
    Mar 5 at 15:04










  • +1. BTW, strings isn't needed here - it seems it's only being used to find which files contain a particular string. Instead, you can use grep's -a option to force it to search binary files as if they were text. e.g. find . -type f -name 'coretst.*' -exec grep -alF 'pmdtm(' +
    – cas
    Mar 6 at 3:14











  • Thanks Kunsalananda and cas, I'll try all your inputs and let you know the results. I edited my original question for a better understanding, actually that's the whole context why I'm writing script which is my first time - having a hard time though! :)
    – Jerome Sabareza
    Mar 6 at 21:02










  • Hi Kunsalananda/Cas, I almost completed my script. However, some of it were working as expected and some were not (specially the nested if statements). Can you help me check my script? ( Is there away to attach my script here?) Let me know if you have any questions. Thank you in advance. Regards, Jerome P.S. I tried this one: find . -type f -name 'coretst.*' -exec sh -c ' for name; do if strings "$name" | grep -qF "pmdtm("; then printf "%sn" "$name" fi done' find-sh + but it prompts/wait for an enter to generate the result.
    – Jerome Sabareza
    Apr 12 at 16:18















Thanks Kusalananda! Your assumption is quite right. I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep “pmdtm(“
– Jerome Sabareza
Mar 5 at 14:57




Thanks Kusalananda! Your assumption is quite right. I want to search it in a current folder, and the output on this will be used on a substring and consequently will be used on this: strings ($core_out) | grep “pmdtm(“
– Jerome Sabareza
Mar 5 at 14:57












@JeromeSabareza See updated answer.
– Kusalananda
Mar 5 at 15:04




@JeromeSabareza See updated answer.
– Kusalananda
Mar 5 at 15:04












+1. BTW, strings isn't needed here - it seems it's only being used to find which files contain a particular string. Instead, you can use grep's -a option to force it to search binary files as if they were text. e.g. find . -type f -name 'coretst.*' -exec grep -alF 'pmdtm(' +
– cas
Mar 6 at 3:14





+1. BTW, strings isn't needed here - it seems it's only being used to find which files contain a particular string. Instead, you can use grep's -a option to force it to search binary files as if they were text. e.g. find . -type f -name 'coretst.*' -exec grep -alF 'pmdtm(' +
– cas
Mar 6 at 3:14













Thanks Kunsalananda and cas, I'll try all your inputs and let you know the results. I edited my original question for a better understanding, actually that's the whole context why I'm writing script which is my first time - having a hard time though! :)
– Jerome Sabareza
Mar 6 at 21:02




Thanks Kunsalananda and cas, I'll try all your inputs and let you know the results. I edited my original question for a better understanding, actually that's the whole context why I'm writing script which is my first time - having a hard time though! :)
– Jerome Sabareza
Mar 6 at 21:02












Hi Kunsalananda/Cas, I almost completed my script. However, some of it were working as expected and some were not (specially the nested if statements). Can you help me check my script? ( Is there away to attach my script here?) Let me know if you have any questions. Thank you in advance. Regards, Jerome P.S. I tried this one: find . -type f -name 'coretst.*' -exec sh -c ' for name; do if strings "$name" | grep -qF "pmdtm("; then printf "%sn" "$name" fi done' find-sh + but it prompts/wait for an enter to generate the result.
– Jerome Sabareza
Apr 12 at 16:18




Hi Kunsalananda/Cas, I almost completed my script. However, some of it were working as expected and some were not (specially the nested if statements). Can you help me check my script? ( Is there away to attach my script here?) Let me know if you have any questions. Thank you in advance. Regards, Jerome P.S. I tried this one: find . -type f -name 'coretst.*' -exec sh -c ' for name; do if strings "$name" | grep -qF "pmdtm("; then printf "%sn" "$name" fi done' find-sh + but it prompts/wait for an enter to generate the result.
– Jerome Sabareza
Apr 12 at 16:18












 

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