Use xargs to build and run a command list

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0















How to use xargs to build and run a command list such as these:



#1
cmd1 <arg1> && cmd2 <arg1> && cmd3 <arg1>
#2
cmd1 <arg1> ; cmd2 <arg1>









share|improve this question




























    0















    How to use xargs to build and run a command list such as these:



    #1
    cmd1 <arg1> && cmd2 <arg1> && cmd3 <arg1>
    #2
    cmd1 <arg1> ; cmd2 <arg1>









    share|improve this question
























      0












      0








      0


      1






      How to use xargs to build and run a command list such as these:



      #1
      cmd1 <arg1> && cmd2 <arg1> && cmd3 <arg1>
      #2
      cmd1 <arg1> ; cmd2 <arg1>









      share|improve this question














      How to use xargs to build and run a command list such as these:



      #1
      cmd1 <arg1> && cmd2 <arg1> && cmd3 <arg1>
      #2
      cmd1 <arg1> ; cmd2 <arg1>






      xargs






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 14 at 11:53









      Tran TrietTran Triet

      12610




      12610




















          1 Answer
          1






          active

          oldest

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          2














          By starting a child shell for each line of input to xargs:



          xargs -I sh -c 'cmd1 "$1" && cmd2 "$1" && cmd3 "$1"' sh 

          xargs -I sh -c 'cmd1 "$1"; cmd2 "$1"' sh


          This runs sh -c which executes the given string as a shell script. The arguments to sh -c, after the script itself, are given to $0 and $1 inside the script. The value of $0 should usually be the name of the shell, which is why we pass sh as this argument (it will be used in error messages).



          Alternatively,



          xargs sh -c '
          for arg do
          cmd1 "$arg" && cmd2 "$arg" && cmd3 "$arg"
          done' sh

          xargs sh -c '
          for arg do
          cmd1 "$arg"
          cmd2 "$arg"
          done' sh


          These variations will take as many arguments as possible and then apply the code to these in a loop inside the sh -c scripts.



          As always when using xargs, care must be taken so that the arguments supplied to the given utility (sh -c here) are delimited properly.






          share|improve this answer

























          • I'm actually using this method, but I wonder if there's any other ways that are more xargs native.

            – Tran Triet
            Mar 14 at 11:59






          • 1





            @TranTriet No, not really. This is a fairly common way of doing it. What are your issues with this way of doing it?

            – Kusalananda
            Mar 14 at 12:03












          • @TranTriet See updated answer.

            – Kusalananda
            Mar 14 at 12:08











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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

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          2














          By starting a child shell for each line of input to xargs:



          xargs -I sh -c 'cmd1 "$1" && cmd2 "$1" && cmd3 "$1"' sh 

          xargs -I sh -c 'cmd1 "$1"; cmd2 "$1"' sh


          This runs sh -c which executes the given string as a shell script. The arguments to sh -c, after the script itself, are given to $0 and $1 inside the script. The value of $0 should usually be the name of the shell, which is why we pass sh as this argument (it will be used in error messages).



          Alternatively,



          xargs sh -c '
          for arg do
          cmd1 "$arg" && cmd2 "$arg" && cmd3 "$arg"
          done' sh

          xargs sh -c '
          for arg do
          cmd1 "$arg"
          cmd2 "$arg"
          done' sh


          These variations will take as many arguments as possible and then apply the code to these in a loop inside the sh -c scripts.



          As always when using xargs, care must be taken so that the arguments supplied to the given utility (sh -c here) are delimited properly.






          share|improve this answer

























          • I'm actually using this method, but I wonder if there's any other ways that are more xargs native.

            – Tran Triet
            Mar 14 at 11:59






          • 1





            @TranTriet No, not really. This is a fairly common way of doing it. What are your issues with this way of doing it?

            – Kusalananda
            Mar 14 at 12:03












          • @TranTriet See updated answer.

            – Kusalananda
            Mar 14 at 12:08















          2














          By starting a child shell for each line of input to xargs:



          xargs -I sh -c 'cmd1 "$1" && cmd2 "$1" && cmd3 "$1"' sh 

          xargs -I sh -c 'cmd1 "$1"; cmd2 "$1"' sh


          This runs sh -c which executes the given string as a shell script. The arguments to sh -c, after the script itself, are given to $0 and $1 inside the script. The value of $0 should usually be the name of the shell, which is why we pass sh as this argument (it will be used in error messages).



          Alternatively,



          xargs sh -c '
          for arg do
          cmd1 "$arg" && cmd2 "$arg" && cmd3 "$arg"
          done' sh

          xargs sh -c '
          for arg do
          cmd1 "$arg"
          cmd2 "$arg"
          done' sh


          These variations will take as many arguments as possible and then apply the code to these in a loop inside the sh -c scripts.



          As always when using xargs, care must be taken so that the arguments supplied to the given utility (sh -c here) are delimited properly.






          share|improve this answer

























          • I'm actually using this method, but I wonder if there's any other ways that are more xargs native.

            – Tran Triet
            Mar 14 at 11:59






          • 1





            @TranTriet No, not really. This is a fairly common way of doing it. What are your issues with this way of doing it?

            – Kusalananda
            Mar 14 at 12:03












          • @TranTriet See updated answer.

            – Kusalananda
            Mar 14 at 12:08













          2












          2








          2







          By starting a child shell for each line of input to xargs:



          xargs -I sh -c 'cmd1 "$1" && cmd2 "$1" && cmd3 "$1"' sh 

          xargs -I sh -c 'cmd1 "$1"; cmd2 "$1"' sh


          This runs sh -c which executes the given string as a shell script. The arguments to sh -c, after the script itself, are given to $0 and $1 inside the script. The value of $0 should usually be the name of the shell, which is why we pass sh as this argument (it will be used in error messages).



          Alternatively,



          xargs sh -c '
          for arg do
          cmd1 "$arg" && cmd2 "$arg" && cmd3 "$arg"
          done' sh

          xargs sh -c '
          for arg do
          cmd1 "$arg"
          cmd2 "$arg"
          done' sh


          These variations will take as many arguments as possible and then apply the code to these in a loop inside the sh -c scripts.



          As always when using xargs, care must be taken so that the arguments supplied to the given utility (sh -c here) are delimited properly.






          share|improve this answer















          By starting a child shell for each line of input to xargs:



          xargs -I sh -c 'cmd1 "$1" && cmd2 "$1" && cmd3 "$1"' sh 

          xargs -I sh -c 'cmd1 "$1"; cmd2 "$1"' sh


          This runs sh -c which executes the given string as a shell script. The arguments to sh -c, after the script itself, are given to $0 and $1 inside the script. The value of $0 should usually be the name of the shell, which is why we pass sh as this argument (it will be used in error messages).



          Alternatively,



          xargs sh -c '
          for arg do
          cmd1 "$arg" && cmd2 "$arg" && cmd3 "$arg"
          done' sh

          xargs sh -c '
          for arg do
          cmd1 "$arg"
          cmd2 "$arg"
          done' sh


          These variations will take as many arguments as possible and then apply the code to these in a loop inside the sh -c scripts.



          As always when using xargs, care must be taken so that the arguments supplied to the given utility (sh -c here) are delimited properly.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 14 at 12:08

























          answered Mar 14 at 11:57









          KusalanandaKusalananda

          141k17263439




          141k17263439












          • I'm actually using this method, but I wonder if there's any other ways that are more xargs native.

            – Tran Triet
            Mar 14 at 11:59






          • 1





            @TranTriet No, not really. This is a fairly common way of doing it. What are your issues with this way of doing it?

            – Kusalananda
            Mar 14 at 12:03












          • @TranTriet See updated answer.

            – Kusalananda
            Mar 14 at 12:08

















          • I'm actually using this method, but I wonder if there's any other ways that are more xargs native.

            – Tran Triet
            Mar 14 at 11:59






          • 1





            @TranTriet No, not really. This is a fairly common way of doing it. What are your issues with this way of doing it?

            – Kusalananda
            Mar 14 at 12:03












          • @TranTriet See updated answer.

            – Kusalananda
            Mar 14 at 12:08
















          I'm actually using this method, but I wonder if there's any other ways that are more xargs native.

          – Tran Triet
          Mar 14 at 11:59





          I'm actually using this method, but I wonder if there's any other ways that are more xargs native.

          – Tran Triet
          Mar 14 at 11:59




          1




          1





          @TranTriet No, not really. This is a fairly common way of doing it. What are your issues with this way of doing it?

          – Kusalananda
          Mar 14 at 12:03






          @TranTriet No, not really. This is a fairly common way of doing it. What are your issues with this way of doing it?

          – Kusalananda
          Mar 14 at 12:03














          @TranTriet See updated answer.

          – Kusalananda
          Mar 14 at 12:08





          @TranTriet See updated answer.

          – Kusalananda
          Mar 14 at 12:08

















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