Bash Command Not Found Error with $variable
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108 ps --ppid $process | while read -r line ; do
109 #echo $line | awk 'print $1;
110 child=$($line | awk 'print $1;')
111 echo $child
113 done
Running this code gives me the following error:
line 111: 3405: command not found
But if I uncomment line 109 it prints the correct value without an error
bash command-not-found
edited Nov 27 '16 at 1:44
techraf
4,303102243
asked Nov 27 '16 at 1:43
shav017shav017
41
add a comment |
108 ps --ppid $process | while read -r line ; do
109 #echo $line | awk 'print $1;
110 child=$($line | awk 'print $1;')
111 echo $child
113 done
Running this code gives me the following error:
line 111: 3405: command not found
But if I uncomment line 109 it prints the correct value without an error
bash command-not-found
edited Nov 27 '16 at 1:44
techraf
4,303102243
asked Nov 27 '16 at 1:43
shav017shav017
41
1
What are you expecting to happen? without theecho$linewill be treated as a command to run, apparently the command3405in your example.
– Eric Renouf
Nov 27 '16 at 1:52
3
This smacks of an XY problem to me, what is it that you're actually trying to do?
– Eric Renouf
Nov 27 '16 at 1:54
1
line 110 looks fishy to me (did you mean to 'echo $line' to awk?)
– Jeff Schaller♦
Nov 27 '16 at 2:00
Post complete code that reproduces the problem and explain what you want the script to do.
– Gilles
Nov 27 '16 at 21:19
add a comment |
108 ps --ppid $process | while read -r line ; do
109 #echo $line | awk 'print $1;
110 child=$($line | awk 'print $1;')
111 echo $child
113 done
Running this code gives me the following error:
line 111: 3405: command not found
But if I uncomment line 109 it prints the correct value without an error
bash command-not-found
edited Nov 27 '16 at 1:44
techraf
4,303102243
asked Nov 27 '16 at 1:43
shav017shav017
41
108 ps --ppid $process | while read -r line ; do
109 #echo $line | awk 'print $1;
110 child=$($line | awk 'print $1;')
111 echo $child
113 done
Running this code gives me the following error:
line 111: 3405: command not found
But if I uncomment line 109 it prints the correct value without an error
bash command-not-found
bash command-not-found
edited Nov 27 '16 at 1:44
techraf
4,303102243
asked Nov 27 '16 at 1:43
shav017shav017
41
edited Nov 27 '16 at 1:44
techraf
4,303102243
asked Nov 27 '16 at 1:43
shav017shav017
41
edited Nov 27 '16 at 1:44
techraf
4,303102243
edited Nov 27 '16 at 1:44
techraf
4,303102243
edited Nov 27 '16 at 1:44
techraf
4,303102243
4,303102243
asked Nov 27 '16 at 1:43
shav017shav017
41
asked Nov 27 '16 at 1:43
shav017shav017
41
asked Nov 27 '16 at 1:43
shav017shav017
41
41
1
What are you expecting to happen? without theecho$linewill be treated as a command to run, apparently the command3405in your example.
– Eric Renouf
Nov 27 '16 at 1:52
3
This smacks of an XY problem to me, what is it that you're actually trying to do?
– Eric Renouf
Nov 27 '16 at 1:54
1
line 110 looks fishy to me (did you mean to 'echo $line' to awk?)
– Jeff Schaller♦
Nov 27 '16 at 2:00
Post complete code that reproduces the problem and explain what you want the script to do.
– Gilles
Nov 27 '16 at 21:19
add a comment |
1
What are you expecting to happen? without theecho$linewill be treated as a command to run, apparently the command3405in your example.
– Eric Renouf
Nov 27 '16 at 1:52
3
This smacks of an XY problem to me, what is it that you're actually trying to do?
– Eric Renouf
Nov 27 '16 at 1:54
1
line 110 looks fishy to me (did you mean to 'echo $line' to awk?)
– Jeff Schaller♦
Nov 27 '16 at 2:00
Post complete code that reproduces the problem and explain what you want the script to do.
– Gilles
Nov 27 '16 at 21:19
1
1
What are you expecting to happen? without the
echo $line will be treated as a command to run, apparently the command 3405 in your example.– Eric Renouf
Nov 27 '16 at 1:52
What are you expecting to happen? without the
echo $line will be treated as a command to run, apparently the command 3405 in your example.– Eric Renouf
Nov 27 '16 at 1:52
3
3
This smacks of an XY problem to me, what is it that you're actually trying to do?
– Eric Renouf
Nov 27 '16 at 1:54
This smacks of an XY problem to me, what is it that you're actually trying to do?
– Eric Renouf
Nov 27 '16 at 1:54
1
1
line 110 looks fishy to me (did you mean to 'echo $line' to awk?)
– Jeff Schaller♦
Nov 27 '16 at 2:00
line 110 looks fishy to me (did you mean to 'echo $line' to awk?)
– Jeff Schaller♦
Nov 27 '16 at 2:00
Post complete code that reproduces the problem and explain what you want the script to do.
– Gilles
Nov 27 '16 at 21:19
Post complete code that reproduces the problem and explain what you want the script to do.
– Gilles
Nov 27 '16 at 21:19
add a comment |
2 Answers
2
active
oldest
votes
Fix it...
ps --ppid $process | while read -r line ; do
child=$(echo $line | awk 'print $1')
done
answered Nov 27 '16 at 2:00
jas-jas-
73238
add a comment |
The issue is that you're not actually giving the value in $line to awk. Instead you try to execute it as a command.
If all you want to do is output the child processes of a process with a certain PID, then you don't need to loop:
ps --ppid "$process" -o pid=
This would get the list of processes that has $process as their PPID, and for each output their PID.
Also related:
- Why is using a shell loop to process text considered bad practice?
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
add a comment |
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2 Answers
2
active
oldest
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Fix it...
ps --ppid $process | while read -r line ; do
child=$(echo $line | awk 'print $1')
done
answered Nov 27 '16 at 2:00
jas-jas-
73238
add a comment |
Fix it...
ps --ppid $process | while read -r line ; do
child=$(echo $line | awk 'print $1')
done
answered Nov 27 '16 at 2:00
jas-jas-
73238
add a comment |
Fix it...
ps --ppid $process | while read -r line ; do
child=$(echo $line | awk 'print $1')
done
answered Nov 27 '16 at 2:00
jas-jas-
73238
Fix it...
ps --ppid $process | while read -r line ; do
child=$(echo $line | awk 'print $1')
done
answered Nov 27 '16 at 2:00
jas-jas-
73238
answered Nov 27 '16 at 2:00
jas-jas-
73238
answered Nov 27 '16 at 2:00
jas-jas-
73238
answered Nov 27 '16 at 2:00
jas-jas-
73238
73238
add a comment |
add a comment |
The issue is that you're not actually giving the value in $line to awk. Instead you try to execute it as a command.
If all you want to do is output the child processes of a process with a certain PID, then you don't need to loop:
ps --ppid "$process" -o pid=
This would get the list of processes that has $process as their PPID, and for each output their PID.
Also related:
- Why is using a shell loop to process text considered bad practice?
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
add a comment |
The issue is that you're not actually giving the value in $line to awk. Instead you try to execute it as a command.
If all you want to do is output the child processes of a process with a certain PID, then you don't need to loop:
ps --ppid "$process" -o pid=
This would get the list of processes that has $process as their PPID, and for each output their PID.
Also related:
- Why is using a shell loop to process text considered bad practice?
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
add a comment |
The issue is that you're not actually giving the value in $line to awk. Instead you try to execute it as a command.
If all you want to do is output the child processes of a process with a certain PID, then you don't need to loop:
ps --ppid "$process" -o pid=
This would get the list of processes that has $process as their PPID, and for each output their PID.
Also related:
- Why is using a shell loop to process text considered bad practice?
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
The issue is that you're not actually giving the value in $line to awk. Instead you try to execute it as a command.
If all you want to do is output the child processes of a process with a certain PID, then you don't need to loop:
ps --ppid "$process" -o pid=
This would get the list of processes that has $process as their PPID, and for each output their PID.
Also related:
- Why is using a shell loop to process text considered bad practice?
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
answered Mar 17 at 14:15
Kusalananda♦Kusalananda
142k18264440
142k18264440
add a comment |
add a comment |
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1
What are you expecting to happen? without the
echo$linewill be treated as a command to run, apparently the command3405in your example.– Eric Renouf
Nov 27 '16 at 1:52
3
This smacks of an XY problem to me, what is it that you're actually trying to do?
– Eric Renouf
Nov 27 '16 at 1:54
1
line 110 looks fishy to me (did you mean to 'echo $line' to awk?)
– Jeff Schaller♦
Nov 27 '16 at 2:00
Post complete code that reproduces the problem and explain what you want the script to do.
– Gilles
Nov 27 '16 at 21:19