Salsa20 Implementation: Sum of 2 Words with Carries Suppressed

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I'm working on the 2nd part of the Salsa20 spec, and I want to implement a closure for the exclusive-or of two words(u32). The author defines the operation as the sum of two words with carries suppressed, but what does "carries suppressed" mean. Then I come across some summation notation:



$u=sum_i2^iu_i$



What does the variable "i" mean in this context exactly? I understand summation notation and the index variable, but the context of the spec doesn't elaborate enough for me to know what "i" indexes.



I realize this all may be very rudimentary, but I am a programmer first.










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    $begingroup$
    $$bigoplus$$
    $endgroup$
    – kelalaka
    Feb 27 at 16:43















4












$begingroup$


I'm working on the 2nd part of the Salsa20 spec, and I want to implement a closure for the exclusive-or of two words(u32). The author defines the operation as the sum of two words with carries suppressed, but what does "carries suppressed" mean. Then I come across some summation notation:



$u=sum_i2^iu_i$



What does the variable "i" mean in this context exactly? I understand summation notation and the index variable, but the context of the spec doesn't elaborate enough for me to know what "i" indexes.



I realize this all may be very rudimentary, but I am a programmer first.










share|improve this question











$endgroup$







  • 1




    $begingroup$
    $$bigoplus$$
    $endgroup$
    – kelalaka
    Feb 27 at 16:43













4












4








4


2



$begingroup$


I'm working on the 2nd part of the Salsa20 spec, and I want to implement a closure for the exclusive-or of two words(u32). The author defines the operation as the sum of two words with carries suppressed, but what does "carries suppressed" mean. Then I come across some summation notation:



$u=sum_i2^iu_i$



What does the variable "i" mean in this context exactly? I understand summation notation and the index variable, but the context of the spec doesn't elaborate enough for me to know what "i" indexes.



I realize this all may be very rudimentary, but I am a programmer first.










share|improve this question











$endgroup$




I'm working on the 2nd part of the Salsa20 spec, and I want to implement a closure for the exclusive-or of two words(u32). The author defines the operation as the sum of two words with carries suppressed, but what does "carries suppressed" mean. Then I come across some summation notation:



$u=sum_i2^iu_i$



What does the variable "i" mean in this context exactly? I understand summation notation and the index variable, but the context of the spec doesn't elaborate enough for me to know what "i" indexes.



I realize this all may be very rudimentary, but I am a programmer first.







modular-arithmetic xor salsa20






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edited Feb 27 at 6:46









DannyNiu

1,3331629




1,3331629










asked Feb 27 at 4:55









whole_lotta_coinswhole_lotta_coins

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232







  • 1




    $begingroup$
    $$bigoplus$$
    $endgroup$
    – kelalaka
    Feb 27 at 16:43












  • 1




    $begingroup$
    $$bigoplus$$
    $endgroup$
    – kelalaka
    Feb 27 at 16:43







1




1




$begingroup$
$$bigoplus$$
$endgroup$
– kelalaka
Feb 27 at 16:43




$begingroup$
$$bigoplus$$
$endgroup$
– kelalaka
Feb 27 at 16:43










1 Answer
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$begingroup$

The sum of two words with carries suppressed is just a convoluted way of saying XOR. You don't need to implement any kind of complicated summation operation. Just perform a bitwise-exclusive OR.



See also https://en.wikipedia.org/wiki/Exclusive_or#Computer_science






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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

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    10












    $begingroup$

    The sum of two words with carries suppressed is just a convoluted way of saying XOR. You don't need to implement any kind of complicated summation operation. Just perform a bitwise-exclusive OR.



    See also https://en.wikipedia.org/wiki/Exclusive_or#Computer_science






    share|improve this answer











    $endgroup$

















      10












      $begingroup$

      The sum of two words with carries suppressed is just a convoluted way of saying XOR. You don't need to implement any kind of complicated summation operation. Just perform a bitwise-exclusive OR.



      See also https://en.wikipedia.org/wiki/Exclusive_or#Computer_science






      share|improve this answer











      $endgroup$















        10












        10








        10





        $begingroup$

        The sum of two words with carries suppressed is just a convoluted way of saying XOR. You don't need to implement any kind of complicated summation operation. Just perform a bitwise-exclusive OR.



        See also https://en.wikipedia.org/wiki/Exclusive_or#Computer_science






        share|improve this answer











        $endgroup$



        The sum of two words with carries suppressed is just a convoluted way of saying XOR. You don't need to implement any kind of complicated summation operation. Just perform a bitwise-exclusive OR.



        See also https://en.wikipedia.org/wiki/Exclusive_or#Computer_science







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Feb 27 at 8:19

























        answered Feb 27 at 5:03









        forestforest

        4,51911641




        4,51911641



























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