CSV processing: moving column/row value to different row where column value matches
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0
I have a csv file with around 50 columns, can be anywhere between 20 and 100 rows.
The individual records have IDs, and some records can be in a group of 2. Essentially what I need to do is add an ID to the same row that another ID in that group is in. Example:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,
2019-3 ,GRP2 ,
2019-4 ,GRP1 ,
2019-5 , ,
2019-6 ,GRP2 ,
And the output I would like is:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,2019-4
2019-3 ,GRP2 ,2019-6
2019-5 , ,
In my attempts using awk, I haven't had any luck. I either end up leaving out rows that have no group, or I end up repeating values.
text-processing awk csv
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
add a comment |
0
I have a csv file with around 50 columns, can be anywhere between 20 and 100 rows.
The individual records have IDs, and some records can be in a group of 2. Essentially what I need to do is add an ID to the same row that another ID in that group is in. Example:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,
2019-3 ,GRP2 ,
2019-4 ,GRP1 ,
2019-5 , ,
2019-6 ,GRP2 ,
And the output I would like is:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,2019-4
2019-3 ,GRP2 ,2019-6
2019-5 , ,
In my attempts using awk, I haven't had any luck. I either end up leaving out rows that have no group, or I end up repeating values.
text-processing awk csv
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
and what with a third line with GRP1 ?
– ctac_
Feb 11 at 19:15
add a comment |
0
0
0
I have a csv file with around 50 columns, can be anywhere between 20 and 100 rows.
The individual records have IDs, and some records can be in a group of 2. Essentially what I need to do is add an ID to the same row that another ID in that group is in. Example:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,
2019-3 ,GRP2 ,
2019-4 ,GRP1 ,
2019-5 , ,
2019-6 ,GRP2 ,
And the output I would like is:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,2019-4
2019-3 ,GRP2 ,2019-6
2019-5 , ,
In my attempts using awk, I haven't had any luck. I either end up leaving out rows that have no group, or I end up repeating values.
text-processing awk csv
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
I have a csv file with around 50 columns, can be anywhere between 20 and 100 rows.
The individual records have IDs, and some records can be in a group of 2. Essentially what I need to do is add an ID to the same row that another ID in that group is in. Example:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,
2019-3 ,GRP2 ,
2019-4 ,GRP1 ,
2019-5 , ,
2019-6 ,GRP2 ,
And the output I would like is:
ID ,group,blank column
2019-1 , ,
2019-2 ,GRP1 ,2019-4
2019-3 ,GRP2 ,2019-6
2019-5 , ,
In my attempts using awk, I haven't had any luck. I either end up leaving out rows that have no group, or I end up repeating values.
text-processing awk csv
text-processing awk csv
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
edited Feb 11 at 19:31
Rui F Ribeiro
41.1k1480138
41.1k1480138
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
asked Feb 11 at 18:52
Cody ThomasCody Thomas
21
21
and what with a third line with GRP1 ?
– ctac_
Feb 11 at 19:15
add a comment |
and what with a third line with GRP1 ?
– ctac_
Feb 11 at 19:15
and what with a third line with GRP1 ?
– ctac_
Feb 11 at 19:15
and what with a third line with GRP1 ?
– ctac_
Feb 11 at 19:15
add a comment |
1 Answer
1
active
oldest
votes
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perl -a -F, -ne 'if($F[1]=~/S/) push @$d$F[1], $F[0]; else print ;
END
for(keys %d)
print shift @$d$_,",$_, ",@$d$_,"n"
' my.csv
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
Thank you for the help. This absolutely does what is intended. I have next to no experience with perl however, and I am trying to implement this for use with a file that has 50+ columns. I'm not sure of the best way to accomplish this however. I basically need it to go in, and update the columns I've mentioned, but still print all the other information.
– Cody Thomas
Feb 11 at 21:07
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
1
perl -a -F, -ne 'if($F[1]=~/S/) push @$d$F[1], $F[0]; else print ;
END
for(keys %d)
print shift @$d$_,",$_, ",@$d$_,"n"
' my.csv
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
Thank you for the help. This absolutely does what is intended. I have next to no experience with perl however, and I am trying to implement this for use with a file that has 50+ columns. I'm not sure of the best way to accomplish this however. I basically need it to go in, and update the columns I've mentioned, but still print all the other information.
– Cody Thomas
Feb 11 at 21:07
add a comment |
1
perl -a -F, -ne 'if($F[1]=~/S/) push @$d$F[1], $F[0]; else print ;
END
for(keys %d)
print shift @$d$_,",$_, ",@$d$_,"n"
' my.csv
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
Thank you for the help. This absolutely does what is intended. I have next to no experience with perl however, and I am trying to implement this for use with a file that has 50+ columns. I'm not sure of the best way to accomplish this however. I basically need it to go in, and update the columns I've mentioned, but still print all the other information.
– Cody Thomas
Feb 11 at 21:07
add a comment |
1
1
1
perl -a -F, -ne 'if($F[1]=~/S/) push @$d$F[1], $F[0]; else print ;
END
for(keys %d)
print shift @$d$_,",$_, ",@$d$_,"n"
' my.csv
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
perl -a -F, -ne 'if($F[1]=~/S/) push @$d$F[1], $F[0]; else print ;
END
for(keys %d)
print shift @$d$_,",$_, ",@$d$_,"n"
' my.csv
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
edited Feb 11 at 19:18
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
answered Feb 11 at 19:10
Ole TangeOle Tange
12.7k1455105
12.7k1455105
Thank you for the help. This absolutely does what is intended. I have next to no experience with perl however, and I am trying to implement this for use with a file that has 50+ columns. I'm not sure of the best way to accomplish this however. I basically need it to go in, and update the columns I've mentioned, but still print all the other information.
– Cody Thomas
Feb 11 at 21:07
add a comment |
Thank you for the help. This absolutely does what is intended. I have next to no experience with perl however, and I am trying to implement this for use with a file that has 50+ columns. I'm not sure of the best way to accomplish this however. I basically need it to go in, and update the columns I've mentioned, but still print all the other information.
– Cody Thomas
Feb 11 at 21:07
Thank you for the help. This absolutely does what is intended. I have next to no experience with perl however, and I am trying to implement this for use with a file that has 50+ columns. I'm not sure of the best way to accomplish this however. I basically need it to go in, and update the columns I've mentioned, but still print all the other information.
– Cody Thomas
Feb 11 at 21:07
Thank you for the help. This absolutely does what is intended. I have next to no experience with perl however, and I am trying to implement this for use with a file that has 50+ columns. I'm not sure of the best way to accomplish this however. I basically need it to go in, and update the columns I've mentioned, but still print all the other information.
– Cody Thomas
Feb 11 at 21:07
add a comment |
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and what with a third line with GRP1 ?
– ctac_
Feb 11 at 19:15