How to apply `Length` in all elements

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2












$begingroup$


I want to apply Length in each element from a list.
For example:



My list is: 1,2,3,4,5,6



How to apply Length in each element of this list?



Length[1]
Length[2,3]
Length[4,5,6]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[1, 2, 3, 4, 5, 6]]

Out[235]= 3


The result that I want is some like:



1
2
3


Which is the number of elements in each element.










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$endgroup$







  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, 1, 2, 3, 4, 5, 6].
    $endgroup$
    – Carl Lange
    Jan 22 at 17:45















2












$begingroup$


I want to apply Length in each element from a list.
For example:



My list is: 1,2,3,4,5,6



How to apply Length in each element of this list?



Length[1]
Length[2,3]
Length[4,5,6]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[1, 2, 3, 4, 5, 6]]

Out[235]= 3


The result that I want is some like:



1
2
3


Which is the number of elements in each element.










share|improve this question









$endgroup$







  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, 1, 2, 3, 4, 5, 6].
    $endgroup$
    – Carl Lange
    Jan 22 at 17:45













2












2








2


1



$begingroup$


I want to apply Length in each element from a list.
For example:



My list is: 1,2,3,4,5,6



How to apply Length in each element of this list?



Length[1]
Length[2,3]
Length[4,5,6]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[1, 2, 3, 4, 5, 6]]

Out[235]= 3


The result that I want is some like:



1
2
3


Which is the number of elements in each element.










share|improve this question









$endgroup$




I want to apply Length in each element from a list.
For example:



My list is: 1,2,3,4,5,6



How to apply Length in each element of this list?



Length[1]
Length[2,3]
Length[4,5,6]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[1, 2, 3, 4, 5, 6]]

Out[235]= 3


The result that I want is some like:



1
2
3


Which is the number of elements in each element.







functions function-construction






share|improve this question













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asked Jan 22 at 17:40









MateusMateus

55117




55117







  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, 1, 2, 3, 4, 5, 6].
    $endgroup$
    – Carl Lange
    Jan 22 at 17:45












  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, 1, 2, 3, 4, 5, 6].
    $endgroup$
    – Carl Lange
    Jan 22 at 17:45







2




2




$begingroup$
What in your opinion is the Length of 1? You can use Map: Map[Length, 1, 2, 3, 4, 5, 6].
$endgroup$
– Carl Lange
Jan 22 at 17:45




$begingroup$
What in your opinion is the Length of 1? You can use Map: Map[Length, 1, 2, 3, 4, 5, 6].
$endgroup$
– Carl Lange
Jan 22 at 17:45










3 Answers
3






active

oldest

votes


















7












$begingroup$

If[AtomQ @ #, 1, Length @ #] & /@ 1, 2, 3, 4, 5, 6



1, 2, 3




If the input list does not contain (thanks: @corey979), you can also use:



Length /@ 1, 2, 3, 4, 5, 6 /. 0 -> 1
(* or Map[Length]@1, 2, 3, 4, 5, 6 /. 0 -> 1 *)



1, 2, 3







share|improve this answer











$endgroup$












  • $begingroup$
    Note that the first approach fails on 1, 2, 3, , 4, 5, 6. The second, however, works well.
    $endgroup$
    – corey979
    Jan 22 at 18:24










  • $begingroup$
    @corey979, very good point.
    $endgroup$
    – kglr
    Jan 22 at 18:30


















5












$begingroup$

Introduce Charting`padList to make a list for your element..



Length@*Charting`padList /@ 1, 2, 3, 4, 5, 6



1, 2, 3







share|improve this answer











$endgroup$








  • 1




    $begingroup$
    Brilliant. Care to elaborate more on Charting`padList?
    $endgroup$
    – corey979
    Jan 22 at 18:22


















0












$begingroup$

A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



Length@Flatten@List@#&/@1, 2, 3, 4, 5, 6





share|improve this answer









$endgroup$












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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7












    $begingroup$

    If[AtomQ @ #, 1, Length @ #] & /@ 1, 2, 3, 4, 5, 6



    1, 2, 3




    If the input list does not contain (thanks: @corey979), you can also use:



    Length /@ 1, 2, 3, 4, 5, 6 /. 0 -> 1
    (* or Map[Length]@1, 2, 3, 4, 5, 6 /. 0 -> 1 *)



    1, 2, 3







    share|improve this answer











    $endgroup$












    • $begingroup$
      Note that the first approach fails on 1, 2, 3, , 4, 5, 6. The second, however, works well.
      $endgroup$
      – corey979
      Jan 22 at 18:24










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      Jan 22 at 18:30















    7












    $begingroup$

    If[AtomQ @ #, 1, Length @ #] & /@ 1, 2, 3, 4, 5, 6



    1, 2, 3




    If the input list does not contain (thanks: @corey979), you can also use:



    Length /@ 1, 2, 3, 4, 5, 6 /. 0 -> 1
    (* or Map[Length]@1, 2, 3, 4, 5, 6 /. 0 -> 1 *)



    1, 2, 3







    share|improve this answer











    $endgroup$












    • $begingroup$
      Note that the first approach fails on 1, 2, 3, , 4, 5, 6. The second, however, works well.
      $endgroup$
      – corey979
      Jan 22 at 18:24










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      Jan 22 at 18:30













    7












    7








    7





    $begingroup$

    If[AtomQ @ #, 1, Length @ #] & /@ 1, 2, 3, 4, 5, 6



    1, 2, 3




    If the input list does not contain (thanks: @corey979), you can also use:



    Length /@ 1, 2, 3, 4, 5, 6 /. 0 -> 1
    (* or Map[Length]@1, 2, 3, 4, 5, 6 /. 0 -> 1 *)



    1, 2, 3







    share|improve this answer











    $endgroup$



    If[AtomQ @ #, 1, Length @ #] & /@ 1, 2, 3, 4, 5, 6



    1, 2, 3




    If the input list does not contain (thanks: @corey979), you can also use:



    Length /@ 1, 2, 3, 4, 5, 6 /. 0 -> 1
    (* or Map[Length]@1, 2, 3, 4, 5, 6 /. 0 -> 1 *)



    1, 2, 3








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 22 at 19:16

























    answered Jan 22 at 17:44









    kglrkglr

    183k10201416




    183k10201416











    • $begingroup$
      Note that the first approach fails on 1, 2, 3, , 4, 5, 6. The second, however, works well.
      $endgroup$
      – corey979
      Jan 22 at 18:24










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      Jan 22 at 18:30
















    • $begingroup$
      Note that the first approach fails on 1, 2, 3, , 4, 5, 6. The second, however, works well.
      $endgroup$
      – corey979
      Jan 22 at 18:24










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      Jan 22 at 18:30















    $begingroup$
    Note that the first approach fails on 1, 2, 3, , 4, 5, 6. The second, however, works well.
    $endgroup$
    – corey979
    Jan 22 at 18:24




    $begingroup$
    Note that the first approach fails on 1, 2, 3, , 4, 5, 6. The second, however, works well.
    $endgroup$
    – corey979
    Jan 22 at 18:24












    $begingroup$
    @corey979, very good point.
    $endgroup$
    – kglr
    Jan 22 at 18:30




    $begingroup$
    @corey979, very good point.
    $endgroup$
    – kglr
    Jan 22 at 18:30











    5












    $begingroup$

    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ 1, 2, 3, 4, 5, 6



    1, 2, 3







    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      Jan 22 at 18:22















    5












    $begingroup$

    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ 1, 2, 3, 4, 5, 6



    1, 2, 3







    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      Jan 22 at 18:22













    5












    5








    5





    $begingroup$

    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ 1, 2, 3, 4, 5, 6



    1, 2, 3







    share|improve this answer











    $endgroup$



    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ 1, 2, 3, 4, 5, 6



    1, 2, 3








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 22 at 18:34

























    answered Jan 22 at 18:13









    yodeyode

    10.3k234100




    10.3k234100







    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      Jan 22 at 18:22












    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      Jan 22 at 18:22







    1




    1




    $begingroup$
    Brilliant. Care to elaborate more on Charting`padList?
    $endgroup$
    – corey979
    Jan 22 at 18:22




    $begingroup$
    Brilliant. Care to elaborate more on Charting`padList?
    $endgroup$
    – corey979
    Jan 22 at 18:22











    0












    $begingroup$

    A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



    Length@Flatten@List@#&/@1, 2, 3, 4, 5, 6





    share|improve this answer









    $endgroup$

















      0












      $begingroup$

      A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



      Length@Flatten@List@#&/@1, 2, 3, 4, 5, 6





      share|improve this answer









      $endgroup$















        0












        0








        0





        $begingroup$

        A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



        Length@Flatten@List@#&/@1, 2, 3, 4, 5, 6





        share|improve this answer









        $endgroup$



        A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



        Length@Flatten@List@#&/@1, 2, 3, 4, 5, 6






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 23 at 16:42









        Jordan MoxonJordan Moxon

        1




        1



























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