Getting current time as output from “date” in awk script
Clash Royale CLAN TAG#URR8PPP
In an awk, script I am using a command
system(date)
to print the current date in a file, but after this command is executed, the next line is also added implicitly. Is there any way in awk to print the current date without the new line being added so that whatever I print next comes in the same line?
awk date string
edited Jan 28 at 10:28
Kusalananda
130k17246406
asked May 6 '11 at 18:36
nishannishan
7117
add a comment |
In an awk, script I am using a command
system(date)
to print the current date in a file, but after this command is executed, the next line is also added implicitly. Is there any way in awk to print the current date without the new line being added so that whatever I print next comes in the same line?
awk date string
edited Jan 28 at 10:28
Kusalananda
130k17246406
asked May 6 '11 at 18:36
nishannishan
7117
add a comment |
In an awk, script I am using a command
system(date)
to print the current date in a file, but after this command is executed, the next line is also added implicitly. Is there any way in awk to print the current date without the new line being added so that whatever I print next comes in the same line?
awk date string
edited Jan 28 at 10:28
Kusalananda
130k17246406
asked May 6 '11 at 18:36
nishannishan
7117
In an awk, script I am using a command
system(date)
to print the current date in a file, but after this command is executed, the next line is also added implicitly. Is there any way in awk to print the current date without the new line being added so that whatever I print next comes in the same line?
awk date string
awk date string
edited Jan 28 at 10:28
Kusalananda
130k17246406
asked May 6 '11 at 18:36
nishannishan
7117
edited Jan 28 at 10:28
Kusalananda
130k17246406
asked May 6 '11 at 18:36
nishannishan
7117
edited Jan 28 at 10:28
Kusalananda
130k17246406
edited Jan 28 at 10:28
Kusalananda
130k17246406
edited Jan 28 at 10:28
Kusalananda
130k17246406
130k17246406
asked May 6 '11 at 18:36
nishannishan
7117
asked May 6 '11 at 18:36
nishannishan
7117
asked May 6 '11 at 18:36
nishannishan
7117
7117
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The date command adds a newline at the end of its output. You can read the output into awk and make it print without appending a newline.
"date" | getline date; printf "%s", date
Unless your script is long-running, you could alternatively obtain the date when you start your script.
awk -v date="$(date)" '
… printf "%s", date …
'
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:-
– nishan
May 6 '11 at 19:36
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:- system("date"| getline date) printf("%s",date)
– nishan
May 6 '11 at 19:44
1
@nishan: The pipe executes its left-hand side as a command. So you're executing the result ofsystem(…)as a shell command. The right syntax is in my answer.
– Gilles
May 6 '11 at 20:00
add a comment |
The GNU awk and @ThomasDickey's mawk implementations of awk has some extensions relating to time and date functionality. With these, you could use
strftime("%+", systime())
to get a string representation in the same format as the date utility would produce.
Or, for a slightly different format, but more portable (works on non-BSD systems),
strftime("%c", systime())
Testing:
$ date
Mon Jan 28 11:22:22 CET 2019
$ gawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:27 CET 2019
$ mawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:33 CET 2019
If the %+ format is not supported on your system (it's not in glibc2), then %c would probably generate a close approximation to this. The exact format will depend on the implementation of strftime() in the C library, and on the current datetime-related locale settings. In the C/POSIX locale, you would get the same output as above, but with no time-zone abbreviation.
BSD awk implementation may not have these functions by default.
See also:
- The manuals for
awkandstrftime(for time/date-stamp formatting) on your system.
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
That would be @ThomasDickey'smawk(since 20121129). Note that the one that comes with Debian and derivatives doesn't have those extensions.%+support is also probably system dependant.
– Stéphane Chazelas
Jan 28 at 11:29
@StéphaneChazelas Some of that has now been addressed. Thanks.
– Kusalananda
Jan 28 at 12:12
add a comment |
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2 Answers
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active
oldest
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2 Answers
2
active
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The date command adds a newline at the end of its output. You can read the output into awk and make it print without appending a newline.
"date" | getline date; printf "%s", date
Unless your script is long-running, you could alternatively obtain the date when you start your script.
awk -v date="$(date)" '
… printf "%s", date …
'
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:-
– nishan
May 6 '11 at 19:36
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:- system("date"| getline date) printf("%s",date)
– nishan
May 6 '11 at 19:44
1
@nishan: The pipe executes its left-hand side as a command. So you're executing the result ofsystem(…)as a shell command. The right syntax is in my answer.
– Gilles
May 6 '11 at 20:00
add a comment |
The date command adds a newline at the end of its output. You can read the output into awk and make it print without appending a newline.
"date" | getline date; printf "%s", date
Unless your script is long-running, you could alternatively obtain the date when you start your script.
awk -v date="$(date)" '
… printf "%s", date …
'
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:-
– nishan
May 6 '11 at 19:36
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:- system("date"| getline date) printf("%s",date)
– nishan
May 6 '11 at 19:44
1
@nishan: The pipe executes its left-hand side as a command. So you're executing the result ofsystem(…)as a shell command. The right syntax is in my answer.
– Gilles
May 6 '11 at 20:00
add a comment |
The date command adds a newline at the end of its output. You can read the output into awk and make it print without appending a newline.
"date" | getline date; printf "%s", date
Unless your script is long-running, you could alternatively obtain the date when you start your script.
awk -v date="$(date)" '
… printf "%s", date …
'
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
The date command adds a newline at the end of its output. You can read the output into awk and make it print without appending a newline.
"date" | getline date; printf "%s", date
Unless your script is long-running, you could alternatively obtain the date when you start your script.
awk -v date="$(date)" '
… printf "%s", date …
'
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
answered May 6 '11 at 18:59
GillesGilles
537k12810871604
537k12810871604
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:-
– nishan
May 6 '11 at 19:36
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:- system("date"| getline date) printf("%s",date)
– nishan
May 6 '11 at 19:44
1
@nishan: The pipe executes its left-hand side as a command. So you're executing the result ofsystem(…)as a shell command. The right syntax is in my answer.
– Gilles
May 6 '11 at 20:00
add a comment |
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:-
– nishan
May 6 '11 at 19:36
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:- system("date"| getline date) printf("%s",date)
– nishan
May 6 '11 at 19:44
1
@nishan: The pipe executes its left-hand side as a command. So you're executing the result ofsystem(…)as a shell command. The right syntax is in my answer.
– Gilles
May 6 '11 at 20:00
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:-
– nishan
May 6 '11 at 19:36
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:-
– nishan
May 6 '11 at 19:36
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:- system("date"| getline date) printf("%s",date)
– nishan
May 6 '11 at 19:44
@Gilles-every thing is working fine but it gives an error /bin/sh: 1 :not found .I am using it like this:- system("date"| getline date) printf("%s",date)
– nishan
May 6 '11 at 19:44
1
1
@nishan: The pipe executes its left-hand side as a command. So you're executing the result of
system(…) as a shell command. The right syntax is in my answer.– Gilles
May 6 '11 at 20:00
@nishan: The pipe executes its left-hand side as a command. So you're executing the result of
system(…) as a shell command. The right syntax is in my answer.– Gilles
May 6 '11 at 20:00
add a comment |
The GNU awk and @ThomasDickey's mawk implementations of awk has some extensions relating to time and date functionality. With these, you could use
strftime("%+", systime())
to get a string representation in the same format as the date utility would produce.
Or, for a slightly different format, but more portable (works on non-BSD systems),
strftime("%c", systime())
Testing:
$ date
Mon Jan 28 11:22:22 CET 2019
$ gawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:27 CET 2019
$ mawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:33 CET 2019
If the %+ format is not supported on your system (it's not in glibc2), then %c would probably generate a close approximation to this. The exact format will depend on the implementation of strftime() in the C library, and on the current datetime-related locale settings. In the C/POSIX locale, you would get the same output as above, but with no time-zone abbreviation.
BSD awk implementation may not have these functions by default.
See also:
- The manuals for
awkandstrftime(for time/date-stamp formatting) on your system.
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
That would be @ThomasDickey'smawk(since 20121129). Note that the one that comes with Debian and derivatives doesn't have those extensions.%+support is also probably system dependant.
– Stéphane Chazelas
Jan 28 at 11:29
@StéphaneChazelas Some of that has now been addressed. Thanks.
– Kusalananda
Jan 28 at 12:12
add a comment |
The GNU awk and @ThomasDickey's mawk implementations of awk has some extensions relating to time and date functionality. With these, you could use
strftime("%+", systime())
to get a string representation in the same format as the date utility would produce.
Or, for a slightly different format, but more portable (works on non-BSD systems),
strftime("%c", systime())
Testing:
$ date
Mon Jan 28 11:22:22 CET 2019
$ gawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:27 CET 2019
$ mawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:33 CET 2019
If the %+ format is not supported on your system (it's not in glibc2), then %c would probably generate a close approximation to this. The exact format will depend on the implementation of strftime() in the C library, and on the current datetime-related locale settings. In the C/POSIX locale, you would get the same output as above, but with no time-zone abbreviation.
BSD awk implementation may not have these functions by default.
See also:
- The manuals for
awkandstrftime(for time/date-stamp formatting) on your system.
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
That would be @ThomasDickey'smawk(since 20121129). Note that the one that comes with Debian and derivatives doesn't have those extensions.%+support is also probably system dependant.
– Stéphane Chazelas
Jan 28 at 11:29
@StéphaneChazelas Some of that has now been addressed. Thanks.
– Kusalananda
Jan 28 at 12:12
add a comment |
The GNU awk and @ThomasDickey's mawk implementations of awk has some extensions relating to time and date functionality. With these, you could use
strftime("%+", systime())
to get a string representation in the same format as the date utility would produce.
Or, for a slightly different format, but more portable (works on non-BSD systems),
strftime("%c", systime())
Testing:
$ date
Mon Jan 28 11:22:22 CET 2019
$ gawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:27 CET 2019
$ mawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:33 CET 2019
If the %+ format is not supported on your system (it's not in glibc2), then %c would probably generate a close approximation to this. The exact format will depend on the implementation of strftime() in the C library, and on the current datetime-related locale settings. In the C/POSIX locale, you would get the same output as above, but with no time-zone abbreviation.
BSD awk implementation may not have these functions by default.
See also:
- The manuals for
awkandstrftime(for time/date-stamp formatting) on your system.
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
The GNU awk and @ThomasDickey's mawk implementations of awk has some extensions relating to time and date functionality. With these, you could use
strftime("%+", systime())
to get a string representation in the same format as the date utility would produce.
Or, for a slightly different format, but more portable (works on non-BSD systems),
strftime("%c", systime())
Testing:
$ date
Mon Jan 28 11:22:22 CET 2019
$ gawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:27 CET 2019
$ mawk 'BEGIN print strftime("%+", systime()) '
Mon Jan 28 11:22:33 CET 2019
If the %+ format is not supported on your system (it's not in glibc2), then %c would probably generate a close approximation to this. The exact format will depend on the implementation of strftime() in the C library, and on the current datetime-related locale settings. In the C/POSIX locale, you would get the same output as above, but with no time-zone abbreviation.
BSD awk implementation may not have these functions by default.
See also:
- The manuals for
awkandstrftime(for time/date-stamp formatting) on your system.
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
edited Jan 28 at 12:58
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
answered Jan 28 at 10:23
KusalanandaKusalananda
130k17246406
130k17246406
That would be @ThomasDickey'smawk(since 20121129). Note that the one that comes with Debian and derivatives doesn't have those extensions.%+support is also probably system dependant.
– Stéphane Chazelas
Jan 28 at 11:29
@StéphaneChazelas Some of that has now been addressed. Thanks.
– Kusalananda
Jan 28 at 12:12
add a comment |
That would be @ThomasDickey'smawk(since 20121129). Note that the one that comes with Debian and derivatives doesn't have those extensions.%+support is also probably system dependant.
– Stéphane Chazelas
Jan 28 at 11:29
@StéphaneChazelas Some of that has now been addressed. Thanks.
– Kusalananda
Jan 28 at 12:12
That would be @ThomasDickey's
mawk (since 20121129). Note that the one that comes with Debian and derivatives doesn't have those extensions. %+ support is also probably system dependant.– Stéphane Chazelas
Jan 28 at 11:29
That would be @ThomasDickey's
mawk (since 20121129). Note that the one that comes with Debian and derivatives doesn't have those extensions. %+ support is also probably system dependant.– Stéphane Chazelas
Jan 28 at 11:29
@StéphaneChazelas Some of that has now been addressed. Thanks.
– Kusalananda
Jan 28 at 12:12
@StéphaneChazelas Some of that has now been addressed. Thanks.
– Kusalananda
Jan 28 at 12:12
add a comment |
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